We divide 37015 by 15
We're looking to find how many times 15 goes into 37015.

Step 1:
15 can be fit into 3 0 times, resulting in a remainder of 3.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtracting 0 from 3 leaves us with 3.
Fetch the next digit (7) from the dividend, attach it to 3 and continue: 37 / 15

Step 2:
15 can be fit into 37 2 times, resulting in a remainder of 7.
Use 2 as the next digit of our solution. 
Result so far: 2.0
If we take 30 away from 37, we end up with 7.
Bring next digit (0) of the dividend behind the 7 and repeat the process: 70 / 15

Let's proceed to step 3:
15 goes into 70 4 times with a remainder of 10.
Put 4 as the next digit of the answer. 
Result so far: 24.0
If we take 60 away from 70, we end up with 10.
Grab the next digit (1) from the dividend, add it to 10, then carry on: 101 / 15

Step 4:
If we divide 101 by 15, we get 6 and a remainder of 11.
Put 6 as the next digit of the answer. 
Result so far: 246.0
Subtracting 90 from 101 leaves us with 11.
Bring next digit (5) of the dividend behind the 11 and repeat the process: 115 / 15

Advancing to step 5:
15 goes into 115 7 times with a remainder of 10.
The next digit of our result is 7. 
Result so far: 2467.0
Subtract 105 from 115 to get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Moving on to step 6:
The number 15 fits into 100 6 times, leaving a remainder of 10.
Use 6 as the next digit of our solution. 
Result so far: 2467.6
Deduct 90 from 100 and we're left with 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Step 7:
If we divide 100 by 15, we get 6 and a remainder of 10.
Put 6 as the next digit of the answer. 
Result so far: 2467.66
The remainder is 10 after subtracting 90 from 100.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

The final outcome is 2467.66, with a leftover of 0.01.