93918 divided by 9 
We want to figure out the number of times 93918 can be divided by 9.

Step 1:
9 goes into 9 1 times with a remainder of 0.
The next digit of our result is 1. 
Result so far: 1.0
Deduct 9 from 9 and we're left with 0.
Bring next digit (3) of the dividend behind the 0 and repeat the process: 3 / 9

Going ahead to step 2:
The number 9 fits into 3 0 times, leaving a remainder of 3.
Put 0 as the next digit of the answer. 
Result so far: 10.0
The remainder is 3 after subtracting 0 from 3.
Take the next digit (9) from the dividend and append it to 3, then repeat: 39 / 9

Going ahead to step 3:
When dividing 39 by 9, we get 4 with a remainder of 3.
Write down 4 as next digit of the result. 
Result so far: 104.0
Subtract 36 from 39 to get 3.
Bring next digit (1) of the dividend behind the 3 and repeat the process: 31 / 9

On to step 4:
If we divide 31 by 9, we get 3 and a remainder of 4.
Put 3 as the next digit of the answer. 
Result so far: 1043.0
Subtract 27 from 31 to get 4.
Grab the next digit (8) from the dividend, add it to 4, then carry on: 48 / 9

Advancing to step 5:
9 goes into 48 5 times with a remainder of 3.
The next digit of our result is 5. 
Result so far: 10435.0
The remainder is 3 after subtracting 45 from 48.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 6:
If we divide 30 by 9, we get 3 and a remainder of 3.
The number 3 becomes the next digit in our result. 
Result so far: 10435.3
Deduct 27 from 30 and we're left with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Let's proceed to step 7:
9 goes into 30 3 times with a remainder of 3.
The next digit of our result is 3. 
Result so far: 10435.33
If we take 27 away from 30, we end up with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

After the division, we end up with 10435.33 and a remainder of 0.003.