We're dividing 811530 by 7 
We're looking to find how many times 7 goes into 811530.

On to step 1:
The number 7 fits into 8 1 times, leaving a remainder of 1.
Use 1 as the next digit of our solution. 
Result so far: 1.0
If we subtract 7 from 8, we get 1.
Take the next digit (1) from the dividend and append it to 1, then repeat: 11 / 7

Advancing to step 2:
11 divided by 7 is 1 with a remainder of 4.
Write down 1 as next digit of the result. 
Result so far: 11.0
Subtract 7 from 11 to get 4.
Grab the next digit (1) from the dividend, add it to 4, then carry on: 41 / 7

Step 3:
7 goes into 41 5 times with a remainder of 6.
The number 5 becomes the next digit in our result. 
Result so far: 115.0
Subtract 35 from 41 to get 6.
Fetch the next digit (5) from the dividend, attach it to 6 and continue: 65 / 7

Let's proceed to step 4:
65 divided by 7 is 9 with a remainder of 2.
Use 9 as the next digit of our solution. 
Result so far: 1159.0
Subtracting 63 from 65 leaves us with 2.
Append the next digit (3) from the dividend to 2 and continue with: 23 / 7

On to step 5:
The number 7 fits into 23 3 times, leaving a remainder of 2.
Use 3 as the next digit of our solution. 
Result so far: 11593.0
Deduct 21 from 23 and we're left with 2.
Grab the next digit (0) from the dividend, add it to 2, then carry on: 20 / 7

Let's proceed to step 6:
20 divided by 7 is 2 with a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 115932.0
If we subtract 14 from 20, we get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Let's proceed to step 7:
When dividing 60 by 7, we get 8 with a remainder of 4.
Use 8 as the next digit of our solution. 
Result so far: 115932.8
If we subtract 56 from 60, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 8:
The number 7 fits into 40 5 times, leaving a remainder of 5.
The next digit of our result is 5. 
Result so far: 115932.85
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Moving on to step 9:
When dividing 50 by 7, we get 7 with a remainder of 1.
The number 7 becomes the next digit in our result. 
Result so far: 115932.857
If we subtract 49 from 50, we get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

On to step 10:
7 can be fit into 10 1 times, resulting in a remainder of 3.
Use 1 as the next digit of our solution. 
Result so far: 115932.8571
If we subtract 7 from 10, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 11:
The number 7 fits into 30 4 times, leaving a remainder of 2.
Write down 4 as next digit of the result. 
Result so far: 115932.85714
The remainder is 2 after subtracting 28 from 30.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Going ahead to step 12:
If we divide 20 by 7, we get 2 and a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 115932.857142
If we take 14 away from 20, we end up with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Going ahead to step 13:
When dividing 60 by 7, we get 8 with a remainder of 4.
Write down 8 as next digit of the result. 
Result so far: 115932.8571428
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 14:
7 goes into 40 5 times with a remainder of 5.
The next digit of our result is 5. 
Result so far: 115932.85714285
If we subtract 35 from 40, we get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Our division results in 115932.85714285 with a remaining 5e-09.