878330 divided by 7 
We want to figure out the number of times 878330 can be divided by 7.

On to step 1:
7 can be fit into 8 1 times, resulting in a remainder of 1.
Use 1 as the next digit of our solution. 
Result so far: 1.0
Deduct 7 from 8 and we're left with 1.
Bring next digit (7) of the dividend behind the 1 and repeat the process: 17 / 7

Let's proceed to step 2:
7 goes into 17 2 times with a remainder of 3.
Put 2 as the next digit of the answer. 
Result so far: 12.0
Deduct 14 from 17 and we're left with 3.
Include the next digit (8) from the dividend after 3, then repeat: 38 / 7

On to step 3:
7 goes into 38 5 times with a remainder of 3.
Use 5 as the next digit of our solution. 
Result so far: 125.0
The remainder is 3 after subtracting 35 from 38.
Include the next digit (3) from the dividend after 3, then repeat: 33 / 7

On to step 4:
7 can be fit into 33 4 times, resulting in a remainder of 5.
The number 4 becomes the next digit in our result. 
Result so far: 1254.0
Deduct 28 from 33 and we're left with 5.
Take the next digit (3) from the dividend and append it to 5, then repeat: 53 / 7

Advancing to step 5:
When dividing 53 by 7, we get 7 with a remainder of 4.
The next digit of our result is 7. 
Result so far: 12547.0
If we subtract 49 from 53, we get 4.
Grab the next digit (0) from the dividend, add it to 4, then carry on: 40 / 7

Step 6:
40 divided by 7 is 5 with a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 125475.0
Subtract 35 from 40 to get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Advancing to step 7:
If we divide 50 by 7, we get 7 and a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 125475.7
If we take 49 away from 50, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 8:
10 divided by 7 is 1 with a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 125475.71
If we subtract 7 from 10, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 9:
30 divided by 7 is 4 with a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 125475.714
Subtract 28 from 30 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 10:
If we divide 20 by 7, we get 2 and a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 125475.7142
Deduct 14 from 20 and we're left with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 11:
The number 7 fits into 60 8 times, leaving a remainder of 4.
Use 8 as the next digit of our solution. 
Result so far: 125475.71428
Subtracting 56 from 60 leaves us with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 12:
7 goes into 40 5 times with a remainder of 5.
Put 5 as the next digit of the answer. 
Result so far: 125475.714285
Deduct 35 from 40 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 13:
The number 7 fits into 50 7 times, leaving a remainder of 1.
Use 7 as the next digit of our solution. 
Result so far: 125475.7142857
If we subtract 49 from 50, we get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 14:
7 can be fit into 10 1 times, resulting in a remainder of 3.
Use 1 as the next digit of our solution. 
Result so far: 125475.71428571
The remainder is 3 after subtracting 7 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Our division results in 125475.71428571 with a remaining 3e-09.