4923 ÷ 15 
We're looking to find how many times 15 goes into 4923.

Step 1:
If we divide 4 by 15, we get 0 and a remainder of 4.
Record the quotient 0 as the next digit in the result. 
Result so far: 0.0
The remainder is 4 after subtracting 0 from 4.
Grab the next digit (9) from the dividend, add it to 4, then carry on: 49 / 15

Going ahead to step 2:
If we divide 49 by 15, we get 3 and a remainder of 4.
The number 3 becomes the next digit in our result. 
Result so far: 3.0
The remainder is 4 after subtracting 45 from 49.
Append the next digit (2) from the dividend to 4 and continue with: 42 / 15

Moving on to step 3:
The number 15 fits into 42 2 times, leaving a remainder of 12.
The next digit of our result is 2. 
Result so far: 32.0
If we take 30 away from 42, we end up with 12.
Bring next digit (3) of the dividend behind the 12 and repeat the process: 123 / 15

Step 4:
15 can be fit into 123 8 times, resulting in a remainder of 3.
The next digit of our result is 8. 
Result so far: 328.0
If we subtract 120 from 123, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 5:
30 divided by 15 is 2 with a remainder of 0.
The next digit of our result is 2. 
Result so far: 328.2
If we subtract 30 from 30, we get 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Going ahead to step 6:
15 can be fit into 0 0 times, resulting in a remainder of 0.
Use 0 as the next digit of our solution. 
Result so far: 328.2
Subtracting 0 from 0 leaves us with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Step 7:
0 divided by 15 is 0 with a remainder of 0.
Use 0 as the next digit of our solution. 
Result so far: 328.2
Deduct 0 from 0 and we're left with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Our division results in 328.2 with a remaining 0.0.