We divide 38833 by 74
We want to figure out the number of times 38833 can be divided by 74.

Moving on to step 1:
When dividing 3 by 74, we get 0 with a remainder of 3.
Write down 0 as next digit of the result. 
Result so far: 0.0
Subtracting 0 from 3 leaves us with 3.
Bring next digit (8) of the dividend behind the 3 and repeat the process: 38 / 74

On to step 2:
74 goes into 38 0 times with a remainder of 38.
The next digit of our result is 0. 
Result so far: 0.0
If we subtract 0 from 38, we get 38.
Include the next digit (8) from the dividend after 38, then repeat: 388 / 74

On to step 3:
When dividing 388 by 74, we get 5 with a remainder of 18.
Write down 5 as next digit of the result. 
Result so far: 5.0
If we subtract 370 from 388, we get 18.
Fetch the next digit (3) from the dividend, attach it to 18 and continue: 183 / 74

Going ahead to step 4:
74 can be fit into 183 2 times, resulting in a remainder of 35.
The number 2 becomes the next digit in our result. 
Result so far: 52.0
If we subtract 148 from 183, we get 35.
Include the next digit (3) from the dividend after 35, then repeat: 353 / 74

On to step 5:
74 can be fit into 353 4 times, resulting in a remainder of 57.
Put 4 as the next digit of the answer. 
Result so far: 524.0
Subtracting 296 from 353 leaves us with 57.
Since there are no more digits in the dividend, we add a zero to the remainder making it 570, and continue the process.

Step 6:
If we divide 570 by 74, we get 7 and a remainder of 52.
Use 7 as the next digit of our solution. 
Result so far: 524.7
Subtract 518 from 570 to get 52.
Since there are no more digits in the dividend, we add a zero to the remainder making it 520, and continue the process.

Going ahead to step 7:
74 goes into 520 7 times with a remainder of 2.
The number 7 becomes the next digit in our result. 
Result so far: 524.77
Subtract 518 from 520 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Our division results in 524.77 with a remaining 0.002.