We look at the division of 1952 by 10 
Let's see how many times 10 fits into 1952.

On to step 1:
The number 10 fits into 1 0 times, leaving a remainder of 1.
Write down 0 as next digit of the result. 
Result so far: 0.0
If we take 0 away from 1, we end up with 1.
Include the next digit (9) from the dividend after 1, then repeat: 19 / 10

Moving on to step 2:
If we divide 19 by 10, we get 1 and a remainder of 9.
The next digit of our result is 1. 
Result so far: 1.0
If we take 10 away from 19, we end up with 9.
Take the next digit (5) from the dividend and append it to 9, then repeat: 95 / 10

Step 3:
The number 10 fits into 95 9 times, leaving a remainder of 5.
Write down 9 as next digit of the result. 
Result so far: 19.0
Deduct 90 from 95 and we're left with 5.
Include the next digit (2) from the dividend after 5, then repeat: 52 / 10

On to step 4:
52 divided by 10 is 5 with a remainder of 2.
The number 5 becomes the next digit in our result. 
Result so far: 195.0
If we take 50 away from 52, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Going ahead to step 5:
20 divided by 10 is 2 with a remainder of 0.
Put 2 as the next digit of the answer. 
Result so far: 195.2
Deduct 20 from 20 and we're left with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

On to step 6:
The number 10 fits into 0 0 times, leaving a remainder of 0.
Put 0 as the next digit of the answer. 
Result so far: 195.2
Subtract 0 from 0 to get 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Step 7:
If we divide 0 by 10, we get 0 and a remainder of 0.
Put 0 as the next digit of the answer. 
Result so far: 195.2
The remainder is 0 after subtracting 0 from 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

The final outcome is 195.2, with a leftover of 0.0.