22214 ÷ 9 
Let's see how many times 9 fits into 22214.

Moving on to step 1:
2 divided by 9 is 0 with a remainder of 2.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
If we subtract 0 from 2, we get 2.
Append the next digit (2) from the dividend to 2 and continue with: 22 / 9

On to step 2:
22 divided by 9 is 2 with a remainder of 4.
The number 2 becomes the next digit in our result. 
Result so far: 2.0
Subtracting 18 from 22 leaves us with 4.
Bring next digit (2) of the dividend behind the 4 and repeat the process: 42 / 9

Advancing to step 3:
The number 9 fits into 42 4 times, leaving a remainder of 6.
Use 4 as the next digit of our solution. 
Result so far: 24.0
Deduct 36 from 42 and we're left with 6.
Append the next digit (1) from the dividend to 6 and continue with: 61 / 9

Moving on to step 4:
61 divided by 9 is 6 with a remainder of 7.
Record the quotient 6 as the next digit in the result. 
Result so far: 246.0
The remainder is 7 after subtracting 54 from 61.
Fetch the next digit (4) from the dividend, attach it to 7 and continue: 74 / 9

On to step 5:
The number 9 fits into 74 8 times, leaving a remainder of 2.
The number 8 becomes the next digit in our result. 
Result so far: 2468.0
The remainder is 2 after subtracting 72 from 74.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Let's proceed to step 6:
When dividing 20 by 9, we get 2 with a remainder of 2.
The number 2 becomes the next digit in our result. 
Result so far: 2468.2
If we subtract 18 from 20, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 7:
When dividing 20 by 9, we get 2 with a remainder of 2.
The next digit of our result is 2. 
Result so far: 2468.22
Deduct 18 from 20 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The final result is 2468.22 with a remainder of 0.002.