307713 divided by 13 
Let's see how many times 13 fits into 307713.

Step 1:
13 can be fit into 3 0 times, resulting in a remainder of 3.
The next digit of our result is 0. 
Result so far: 0.0
Subtract 0 from 3 to get 3.
Fetch the next digit (0) from the dividend, attach it to 3 and continue: 30 / 13

Moving on to step 2:
30 divided by 13 is 2 with a remainder of 4.
Record the quotient 2 as the next digit in the result. 
Result so far: 2.0
If we subtract 26 from 30, we get 4.
Take the next digit (7) from the dividend and append it to 4, then repeat: 47 / 13

Let's proceed to step 3:
If we divide 47 by 13, we get 3 and a remainder of 8.
The next digit of our result is 3. 
Result so far: 23.0
Deduct 39 from 47 and we're left with 8.
Take the next digit (7) from the dividend and append it to 8, then repeat: 87 / 13

Going ahead to step 4:
The number 13 fits into 87 6 times, leaving a remainder of 9.
The next digit of our result is 6. 
Result so far: 236.0
If we take 78 away from 87, we end up with 9.
Fetch the next digit (1) from the dividend, attach it to 9 and continue: 91 / 13

Advancing to step 5:
13 goes into 91 7 times with a remainder of 0.
The next digit of our result is 7. 
Result so far: 2367.0
If we subtract 91 from 91, we get 0.
Take the next digit (3) from the dividend and append it to 0, then repeat: 3 / 13

Moving on to step 6:
When dividing 3 by 13, we get 0 with a remainder of 3.
Put 0 as the next digit of the answer. 
Result so far: 23670.0
Subtracting 0 from 3 leaves us with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 7:
30 divided by 13 is 2 with a remainder of 4.
Put 2 as the next digit of the answer. 
Result so far: 23670.2
If we subtract 26 from 30, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 8:
13 goes into 40 3 times with a remainder of 1.
Record the quotient 3 as the next digit in the result. 
Result so far: 23670.23
If we subtract 39 from 40, we get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Let's proceed to step 9:
The number 13 fits into 10 0 times, leaving a remainder of 10.
The next digit of our result is 0. 
Result so far: 23670.23
If we take 0 away from 10, we end up with 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

Let's proceed to step 10:
13 goes into 100 7 times with a remainder of 9.
Use 7 as the next digit of our solution. 
Result so far: 23670.2307
If we subtract 91 from 100, we get 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

Advancing to step 11:
The number 13 fits into 90 6 times, leaving a remainder of 12.
Put 6 as the next digit of the answer. 
Result so far: 23670.23076
Subtract 78 from 90 to get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Moving on to step 12:
13 goes into 120 9 times with a remainder of 3.
Use 9 as the next digit of our solution. 
Result so far: 23670.230769
If we subtract 117 from 120, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Advancing to step 13:
If we divide 30 by 13, we get 2 and a remainder of 4.
Put 2 as the next digit of the answer. 
Result so far: 23670.2307692
Subtract 26 from 30 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 14:
The number 13 fits into 40 3 times, leaving a remainder of 1.
Put 3 as the next digit of the answer. 
Result so far: 23670.23076923
Subtracting 39 from 40 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The quotient of the division is 23670.23076923, and the remainder is 1e-09.