We divide 140239 by 7
We want to figure out the number of times 140239 can be divided by 7.

Step 1:
1 divided by 7 is 0 with a remainder of 1.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
The remainder is 1 after subtracting 0 from 1.
Bring next digit (4) of the dividend behind the 1 and repeat the process: 14 / 7

Let's proceed to step 2:
7 goes into 14 2 times with a remainder of 0.
Record the quotient 2 as the next digit in the result. 
Result so far: 2.0
Subtracting 14 from 14 leaves us with 0.
Include the next digit (0) from the dividend after 0, then repeat: 0 / 7

Let's proceed to step 3:
The number 7 fits into 0 0 times, leaving a remainder of 0.
Put 0 as the next digit of the answer. 
Result so far: 20.0
Subtract 0 from 0 to get 0.
Bring next digit (2) of the dividend behind the 0 and repeat the process: 2 / 7

Moving on to step 4:
The number 7 fits into 2 0 times, leaving a remainder of 2.
The next digit of our result is 0. 
Result so far: 200.0
If we subtract 0 from 2, we get 2.
Fetch the next digit (3) from the dividend, attach it to 2 and continue: 23 / 7

Advancing to step 5:
If we divide 23 by 7, we get 3 and a remainder of 2.
The next digit of our result is 3. 
Result so far: 2003.0
Subtract 21 from 23 to get 2.
Take the next digit (9) from the dividend and append it to 2, then repeat: 29 / 7

Advancing to step 6:
7 can be fit into 29 4 times, resulting in a remainder of 1.
Write down 4 as next digit of the result. 
Result so far: 20034.0
If we take 28 away from 29, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

On to step 7:
If we divide 10 by 7, we get 1 and a remainder of 3.
Write down 1 as next digit of the result. 
Result so far: 20034.1
If we take 7 away from 10, we end up with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 8:
7 can be fit into 30 4 times, resulting in a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 20034.14
Deduct 28 from 30 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 9:
7 goes into 20 2 times with a remainder of 6.
The next digit of our result is 2. 
Result so far: 20034.142
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 10:
If we divide 60 by 7, we get 8 and a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 20034.1428
If we subtract 56 from 60, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Advancing to step 11:
7 goes into 40 5 times with a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 20034.14285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Let's proceed to step 12:
When dividing 50 by 7, we get 7 with a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 20034.142857
Subtract 49 from 50 to get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Let's proceed to step 13:
7 goes into 10 1 times with a remainder of 3.
The next digit of our result is 1. 
Result so far: 20034.1428571
Subtracting 7 from 10 leaves us with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Advancing to step 14:
30 divided by 7 is 4 with a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 20034.14285714
If we take 28 away from 30, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

The final outcome is 20034.14285714, with a leftover of 2e-09.