123813 ÷ 7 
Let's see how many times 7 fits into 123813.

Moving on to step 1:
7 can be fit into 1 0 times, resulting in a remainder of 1.
Use 0 as the next digit of our solution. 
Result so far: 0.0
Subtract 0 from 1 to get 1.
Grab the next digit (2) from the dividend, add it to 1, then carry on: 12 / 7

Let's proceed to step 2:
7 can be fit into 12 1 times, resulting in a remainder of 5.
The number 1 becomes the next digit in our result. 
Result so far: 1.0
If we subtract 7 from 12, we get 5.
Bring next digit (3) of the dividend behind the 5 and repeat the process: 53 / 7

Advancing to step 3:
The number 7 fits into 53 7 times, leaving a remainder of 4.
Use 7 as the next digit of our solution. 
Result so far: 17.0
Deduct 49 from 53 and we're left with 4.
Grab the next digit (8) from the dividend, add it to 4, then carry on: 48 / 7

Let's proceed to step 4:
48 divided by 7 is 6 with a remainder of 6.
Use 6 as the next digit of our solution. 
Result so far: 176.0
Subtracting 42 from 48 leaves us with 6.
Grab the next digit (1) from the dividend, add it to 6, then carry on: 61 / 7

Going ahead to step 5:
61 divided by 7 is 8 with a remainder of 5.
Use 8 as the next digit of our solution. 
Result so far: 1768.0
Deduct 56 from 61 and we're left with 5.
Grab the next digit (3) from the dividend, add it to 5, then carry on: 53 / 7

Let's proceed to step 6:
If we divide 53 by 7, we get 7 and a remainder of 4.
The next digit of our result is 7. 
Result so far: 17687.0
If we subtract 49 from 53, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Going ahead to step 7:
40 divided by 7 is 5 with a remainder of 5.
The next digit of our result is 5. 
Result so far: 17687.5
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 8:
7 can be fit into 50 7 times, resulting in a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 17687.57
Deduct 49 from 50 and we're left with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Let's proceed to step 9:
When dividing 10 by 7, we get 1 with a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 17687.571
The remainder is 3 after subtracting 7 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Step 10:
The number 7 fits into 30 4 times, leaving a remainder of 2.
Record the quotient 4 as the next digit in the result. 
Result so far: 17687.5714
If we take 28 away from 30, we end up with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 11:
20 divided by 7 is 2 with a remainder of 6.
Use 2 as the next digit of our solution. 
Result so far: 17687.57142
Subtract 14 from 20 to get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Going ahead to step 12:
When dividing 60 by 7, we get 8 with a remainder of 4.
Use 8 as the next digit of our solution. 
Result so far: 17687.571428
Subtract 56 from 60 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 13:
40 divided by 7 is 5 with a remainder of 5.
The next digit of our result is 5. 
Result so far: 17687.5714285
The remainder is 5 after subtracting 35 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Step 14:
If we divide 50 by 7, we get 7 and a remainder of 1.
Record the quotient 7 as the next digit in the result. 
Result so far: 17687.57142857
Deduct 49 from 50 and we're left with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The final result is 17687.57142857 with a remainder of 1e-09.