92487 ÷ 9 
We want to figure out the number of times 92487 can be divided by 9.

Moving on to step 1:
9 divided by 9 is 1 with a remainder of 0.
The next digit of our result is 1. 
Result so far: 1.0
The remainder is 0 after subtracting 9 from 9.
Take the next digit (2) from the dividend and append it to 0, then repeat: 2 / 9

On to step 2:
If we divide 2 by 9, we get 0 and a remainder of 2.
The next digit of our result is 0. 
Result so far: 10.0
Deduct 0 from 2 and we're left with 2.
Append the next digit (4) from the dividend to 2 and continue with: 24 / 9

Let's proceed to step 3:
If we divide 24 by 9, we get 2 and a remainder of 6.
Put 2 as the next digit of the answer. 
Result so far: 102.0
If we subtract 18 from 24, we get 6.
Bring next digit (8) of the dividend behind the 6 and repeat the process: 68 / 9

Going ahead to step 4:
The number 9 fits into 68 7 times, leaving a remainder of 5.
Put 7 as the next digit of the answer. 
Result so far: 1027.0
Subtract 63 from 68 to get 5.
Bring next digit (7) of the dividend behind the 5 and repeat the process: 57 / 9

Advancing to step 5:
When dividing 57 by 9, we get 6 with a remainder of 3.
Write down 6 as next digit of the result. 
Result so far: 10276.0
The remainder is 3 after subtracting 54 from 57.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Let's proceed to step 6:
When dividing 30 by 9, we get 3 with a remainder of 3.
The next digit of our result is 3. 
Result so far: 10276.3
Subtract 27 from 30 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 7:
The number 9 fits into 30 3 times, leaving a remainder of 3.
Record the quotient 3 as the next digit in the result. 
Result so far: 10276.33
Subtract 27 from 30 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

After the division, we end up with 10276.33 and a remainder of 0.003.