Let's divide 74338 by 65
We're looking to find how many times 65 goes into 74338.

Let's proceed to step 1:
65 can be fit into 7 0 times, resulting in a remainder of 7.
Put 0 as the next digit of the answer. 
Result so far: 0.0
Subtracting 0 from 7 leaves us with 7.
Fetch the next digit (4) from the dividend, attach it to 7 and continue: 74 / 65

On to step 2:
74 divided by 65 is 1 with a remainder of 9.
Put 1 as the next digit of the answer. 
Result so far: 1.0
The remainder is 9 after subtracting 65 from 74.
Append the next digit (3) from the dividend to 9 and continue with: 93 / 65

Let's proceed to step 3:
93 divided by 65 is 1 with a remainder of 28.
The number 1 becomes the next digit in our result. 
Result so far: 11.0
If we subtract 65 from 93, we get 28.
Append the next digit (3) from the dividend to 28 and continue with: 283 / 65

On to step 4:
65 goes into 283 4 times with a remainder of 23.
Record the quotient 4 as the next digit in the result. 
Result so far: 114.0
If we subtract 260 from 283, we get 23.
Include the next digit (8) from the dividend after 23, then repeat: 238 / 65

On to step 5:
The number 65 fits into 238 3 times, leaving a remainder of 43.
Write down 3 as next digit of the result. 
Result so far: 1143.0
Subtracting 195 from 238 leaves us with 43.
Since there are no more digits in the dividend, we add a zero to the remainder making it 430, and continue the process.

On to step 6:
65 goes into 430 6 times with a remainder of 40.
Write down 6 as next digit of the result. 
Result so far: 1143.6
If we subtract 390 from 430, we get 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 400, and continue the process.

Moving on to step 7:
When dividing 400 by 65, we get 6 with a remainder of 10.
Put 6 as the next digit of the answer. 
Result so far: 1143.66
Subtract 390 from 400 to get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

After the division, we end up with 1143.66 and a remainder of 0.01.