Let's divide 173521 by 58
Let's see how many times 58 fits into 173521.

On to step 1:
58 goes into 1 0 times with a remainder of 1.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
Deduct 0 from 1 and we're left with 1.
Grab the next digit (7) from the dividend, add it to 1, then carry on: 17 / 58

Advancing to step 2:
58 can be fit into 17 0 times, resulting in a remainder of 17.
The next digit of our result is 0. 
Result so far: 0.0
If we subtract 0 from 17, we get 17.
Fetch the next digit (3) from the dividend, attach it to 17 and continue: 173 / 58

Step 3:
When dividing 173 by 58, we get 2 with a remainder of 57.
The next digit of our result is 2. 
Result so far: 2.0
If we subtract 116 from 173, we get 57.
Fetch the next digit (5) from the dividend, attach it to 57 and continue: 575 / 58

Let's proceed to step 4:
If we divide 575 by 58, we get 9 and a remainder of 53.
Put 9 as the next digit of the answer. 
Result so far: 29.0
The remainder is 53 after subtracting 522 from 575.
Grab the next digit (2) from the dividend, add it to 53, then carry on: 532 / 58

Moving on to step 5:
532 divided by 58 is 9 with a remainder of 10.
Record the quotient 9 as the next digit in the result. 
Result so far: 299.0
Subtract 522 from 532 to get 10.
Append the next digit (1) from the dividend to 10 and continue with: 101 / 58

Advancing to step 6:
58 goes into 101 1 times with a remainder of 43.
Put 1 as the next digit of the answer. 
Result so far: 2991.0
Subtract 58 from 101 to get 43.
Since there are no more digits in the dividend, we add a zero to the remainder making it 430, and continue the process.

On to step 7:
58 goes into 430 7 times with a remainder of 24.
The next digit of our result is 7. 
Result so far: 2991.7
Subtract 406 from 430 to get 24.
Since there are no more digits in the dividend, we add a zero to the remainder making it 240, and continue the process.

Moving on to step 8:
The number 58 fits into 240 4 times, leaving a remainder of 8.
Put 4 as the next digit of the answer. 
Result so far: 2991.74
The remainder is 8 after subtracting 232 from 240.
Since there are no more digits in the dividend, we add a zero to the remainder making it 80, and continue the process.

Advancing to step 9:
When dividing 80 by 58, we get 1 with a remainder of 22.
Use 1 as the next digit of our solution. 
Result so far: 2991.741
Subtract 58 from 80 to get 22.
Since there are no more digits in the dividend, we add a zero to the remainder making it 220, and continue the process.

Going ahead to step 10:
The number 58 fits into 220 3 times, leaving a remainder of 46.
Write down 3 as next digit of the result. 
Result so far: 2991.7413
If we subtract 174 from 220, we get 46.
Since there are no more digits in the dividend, we add a zero to the remainder making it 460, and continue the process.

On to step 11:
58 goes into 460 7 times with a remainder of 54.
Put 7 as the next digit of the answer. 
Result so far: 2991.74137
Deduct 406 from 460 and we're left with 54.
Since there are no more digits in the dividend, we add a zero to the remainder making it 540, and continue the process.

Let's proceed to step 12:
58 goes into 540 9 times with a remainder of 18.
The number 9 becomes the next digit in our result. 
Result so far: 2991.741379
Subtracting 522 from 540 leaves us with 18.
Since there are no more digits in the dividend, we add a zero to the remainder making it 180, and continue the process.

On to step 13:
180 divided by 58 is 3 with a remainder of 6.
The next digit of our result is 3. 
Result so far: 2991.7413793
Subtracting 174 from 180 leaves us with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

On to step 14:
60 divided by 58 is 1 with a remainder of 2.
Put 1 as the next digit of the answer. 
Result so far: 2991.74137931
Subtracting 58 from 60 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

After the division, we end up with 2991.74137931 and a remainder of 2e-09.