198189 divided by 13 
We want to figure out the number of times 198189 can be divided by 13.

Advancing to step 1:
If we divide 1 by 13, we get 0 and a remainder of 1.
The next digit of our result is 0. 
Result so far: 0.0
If we take 0 away from 1, we end up with 1.
Bring next digit (9) of the dividend behind the 1 and repeat the process: 19 / 13

Advancing to step 2:
19 divided by 13 is 1 with a remainder of 6.
The number 1 becomes the next digit in our result. 
Result so far: 1.0
Deduct 13 from 19 and we're left with 6.
Grab the next digit (8) from the dividend, add it to 6, then carry on: 68 / 13

On to step 3:
13 can be fit into 68 5 times, resulting in a remainder of 3.
Record the quotient 5 as the next digit in the result. 
Result so far: 15.0
Subtracting 65 from 68 leaves us with 3.
Bring next digit (1) of the dividend behind the 3 and repeat the process: 31 / 13

Step 4:
13 goes into 31 2 times with a remainder of 5.
Use 2 as the next digit of our solution. 
Result so far: 152.0
Deduct 26 from 31 and we're left with 5.
Append the next digit (8) from the dividend to 5 and continue with: 58 / 13

Let's proceed to step 5:
When dividing 58 by 13, we get 4 with a remainder of 6.
Use 4 as the next digit of our solution. 
Result so far: 1524.0
Subtract 52 from 58 to get 6.
Bring next digit (9) of the dividend behind the 6 and repeat the process: 69 / 13

Step 6:
13 goes into 69 5 times with a remainder of 4.
Record the quotient 5 as the next digit in the result. 
Result so far: 15245.0
Subtract 65 from 69 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Moving on to step 7:
40 divided by 13 is 3 with a remainder of 1.
Record the quotient 3 as the next digit in the result. 
Result so far: 15245.3
If we subtract 39 from 40, we get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Moving on to step 8:
13 can be fit into 10 0 times, resulting in a remainder of 10.
The next digit of our result is 0. 
Result so far: 15245.3
If we subtract 0 from 10, we get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

On to step 9:
13 can be fit into 100 7 times, resulting in a remainder of 9.
Put 7 as the next digit of the answer. 
Result so far: 15245.307
If we subtract 91 from 100, we get 9.
Since there are no more digits in the dividend, we add a zero to the remainder making it 90, and continue the process.

Moving on to step 10:
13 can be fit into 90 6 times, resulting in a remainder of 12.
Write down 6 as next digit of the result. 
Result so far: 15245.3076
Subtract 78 from 90 to get 12.
Since there are no more digits in the dividend, we add a zero to the remainder making it 120, and continue the process.

Let's proceed to step 11:
13 goes into 120 9 times with a remainder of 3.
Use 9 as the next digit of our solution. 
Result so far: 15245.30769
Subtract 117 from 120 to get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 12:
When dividing 30 by 13, we get 2 with a remainder of 4.
Put 2 as the next digit of the answer. 
Result so far: 15245.307692
Deduct 26 from 30 and we're left with 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Advancing to step 13:
13 goes into 40 3 times with a remainder of 1.
Put 3 as the next digit of the answer. 
Result so far: 15245.3076923
The remainder is 1 after subtracting 39 from 40.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

On to step 14:
If we divide 10 by 13, we get 0 and a remainder of 10.
The next digit of our result is 0. 
Result so far: 15245.3076923
Subtract 0 from 10 to get 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 100, and continue the process.

The final outcome is 15245.3076923, with a leftover of 1e-08.