887555 divided by 7 
We want to figure out the number of times 887555 can be divided by 7.

Step 1:
The number 7 fits into 8 1 times, leaving a remainder of 1.
The next digit of our result is 1. 
Result so far: 1.0
Deduct 7 from 8 and we're left with 1.
Fetch the next digit (8) from the dividend, attach it to 1 and continue: 18 / 7

Let's proceed to step 2:
7 goes into 18 2 times with a remainder of 4.
The next digit of our result is 2. 
Result so far: 12.0
If we take 14 away from 18, we end up with 4.
Append the next digit (7) from the dividend to 4 and continue with: 47 / 7

On to step 3:
7 goes into 47 6 times with a remainder of 5.
The next digit of our result is 6. 
Result so far: 126.0
Deduct 42 from 47 and we're left with 5.
Include the next digit (5) from the dividend after 5, then repeat: 55 / 7

Advancing to step 4:
7 can be fit into 55 7 times, resulting in a remainder of 6.
Put 7 as the next digit of the answer. 
Result so far: 1267.0
If we subtract 49 from 55, we get 6.
Take the next digit (5) from the dividend and append it to 6, then repeat: 65 / 7

Advancing to step 5:
7 can be fit into 65 9 times, resulting in a remainder of 2.
The number 9 becomes the next digit in our result. 
Result so far: 12679.0
Deduct 63 from 65 and we're left with 2.
Take the next digit (5) from the dividend and append it to 2, then repeat: 25 / 7

Step 6:
25 divided by 7 is 3 with a remainder of 4.
Use 3 as the next digit of our solution. 
Result so far: 126793.0
Subtract 21 from 25 to get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Step 7:
When dividing 40 by 7, we get 5 with a remainder of 5.
Use 5 as the next digit of our solution. 
Result so far: 126793.5
Deduct 35 from 40 and we're left with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 8:
50 divided by 7 is 7 with a remainder of 1.
Write down 7 as next digit of the result. 
Result so far: 126793.57
If we take 49 away from 50, we end up with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Going ahead to step 9:
10 divided by 7 is 1 with a remainder of 3.
Use 1 as the next digit of our solution. 
Result so far: 126793.571
Subtracting 7 from 10 leaves us with 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 10:
When dividing 30 by 7, we get 4 with a remainder of 2.
Put 4 as the next digit of the answer. 
Result so far: 126793.5714
Subtract 28 from 30 to get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Moving on to step 11:
When dividing 20 by 7, we get 2 with a remainder of 6.
Record the quotient 2 as the next digit in the result. 
Result so far: 126793.57142
The remainder is 6 after subtracting 14 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Advancing to step 12:
60 divided by 7 is 8 with a remainder of 4.
The next digit of our result is 8. 
Result so far: 126793.571428
The remainder is 4 after subtracting 56 from 60.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

On to step 13:
7 can be fit into 40 5 times, resulting in a remainder of 5.
Record the quotient 5 as the next digit in the result. 
Result so far: 126793.5714285
Subtracting 35 from 40 leaves us with 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

Going ahead to step 14:
7 goes into 50 7 times with a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 126793.57142857
Subtracting 49 from 50 leaves us with 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

The final result is 126793.57142857 with a remainder of 1e-09.