Let's divide 47810 by 5
We want to figure out the number of times 47810 can be divided by 5.

On to step 1:
5 can be fit into 4 0 times, resulting in a remainder of 4.
Put 0 as the next digit of the answer. 
Result so far: 0.0
Subtract 0 from 4 to get 4.
Take the next digit (7) from the dividend and append it to 4, then repeat: 47 / 5

Moving on to step 2:
5 goes into 47 9 times with a remainder of 2.
Put 9 as the next digit of the answer. 
Result so far: 9.0
The remainder is 2 after subtracting 45 from 47.
Bring next digit (8) of the dividend behind the 2 and repeat the process: 28 / 5

Going ahead to step 3:
5 goes into 28 5 times with a remainder of 3.
Use 5 as the next digit of our solution. 
Result so far: 95.0
Subtracting 25 from 28 leaves us with 3.
Append the next digit (1) from the dividend to 3 and continue with: 31 / 5

Step 4:
5 can be fit into 31 6 times, resulting in a remainder of 1.
Record the quotient 6 as the next digit in the result. 
Result so far: 956.0
Subtracting 30 from 31 leaves us with 1.
Include the next digit (0) from the dividend after 1, then repeat: 10 / 5

Moving on to step 5:
If we divide 10 by 5, we get 2 and a remainder of 0.
The number 2 becomes the next digit in our result. 
Result so far: 9562.0
The remainder is 0 after subtracting 10 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Moving on to step 6:
5 goes into 0 0 times with a remainder of 0.
Write down 0 as next digit of the result. 
Result so far: 9562.0
If we take 0 away from 0, we end up with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

Moving on to step 7:
0 divided by 5 is 0 with a remainder of 0.
Record the quotient 0 as the next digit in the result. 
Result so far: 9562.0
Subtracting 0 from 0 leaves us with 0.
Since there are no more digits in the dividend, we add a zero to the remainder making it 0, and continue the process.

After the division, we end up with 9562.0 and a remainder of 0.0.