Let's divide 93830 by 6
Our goal is to divide 93830 by 6.

Moving on to step 1:
6 can be fit into 9 1 times, resulting in a remainder of 3.
Put 1 as the next digit of the answer. 
Result so far: 1.0
The remainder is 3 after subtracting 6 from 9.
Bring next digit (3) of the dividend behind the 3 and repeat the process: 33 / 6

Let's proceed to step 2:
The number 6 fits into 33 5 times, leaving a remainder of 3.
The next digit of our result is 5. 
Result so far: 15.0
If we take 30 away from 33, we end up with 3.
Grab the next digit (8) from the dividend, add it to 3, then carry on: 38 / 6

On to step 3:
6 can be fit into 38 6 times, resulting in a remainder of 2.
Put 6 as the next digit of the answer. 
Result so far: 156.0
Deduct 36 from 38 and we're left with 2.
Take the next digit (3) from the dividend and append it to 2, then repeat: 23 / 6

Let's proceed to step 4:
6 can be fit into 23 3 times, resulting in a remainder of 5.
Record the quotient 3 as the next digit in the result. 
Result so far: 1563.0
Subtract 18 from 23 to get 5.
Take the next digit (0) from the dividend and append it to 5, then repeat: 50 / 6

Advancing to step 5:
6 can be fit into 50 8 times, resulting in a remainder of 2.
Use 8 as the next digit of our solution. 
Result so far: 15638.0
If we subtract 48 from 50, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Step 6:
20 divided by 6 is 3 with a remainder of 2.
Use 3 as the next digit of our solution. 
Result so far: 15638.3
The remainder is 2 after subtracting 18 from 20.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 7:
20 divided by 6 is 3 with a remainder of 2.
Put 3 as the next digit of the answer. 
Result so far: 15638.33
Deduct 18 from 20 and we're left with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Our division results in 15638.33 with a remaining 0.002.