We divide 534817 by 7
We want to figure out the number of times 534817 can be divided by 7.

Moving on to step 1:
The number 7 fits into 5 0 times, leaving a remainder of 5.
The number 0 becomes the next digit in our result. 
Result so far: 0.0
If we take 0 away from 5, we end up with 5.
Take the next digit (3) from the dividend and append it to 5, then repeat: 53 / 7

Going ahead to step 2:
The number 7 fits into 53 7 times, leaving a remainder of 4.
Use 7 as the next digit of our solution. 
Result so far: 7.0
Subtracting 49 from 53 leaves us with 4.
Include the next digit (4) from the dividend after 4, then repeat: 44 / 7

Step 3:
44 divided by 7 is 6 with a remainder of 2.
Use 6 as the next digit of our solution. 
Result so far: 76.0
If we take 42 away from 44, we end up with 2.
Fetch the next digit (8) from the dividend, attach it to 2 and continue: 28 / 7

Going ahead to step 4:
When dividing 28 by 7, we get 4 with a remainder of 0.
Put 4 as the next digit of the answer. 
Result so far: 764.0
The remainder is 0 after subtracting 28 from 28.
Append the next digit (1) from the dividend to 0 and continue with: 1 / 7

Let's proceed to step 5:
1 divided by 7 is 0 with a remainder of 1.
The next digit of our result is 0. 
Result so far: 7640.0
Subtracting 0 from 1 leaves us with 1.
Append the next digit (7) from the dividend to 1 and continue with: 17 / 7

Let's proceed to step 6:
When dividing 17 by 7, we get 2 with a remainder of 3.
The next digit of our result is 2. 
Result so far: 76402.0
If we subtract 14 from 17, we get 3.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

On to step 7:
30 divided by 7 is 4 with a remainder of 2.
The next digit of our result is 4. 
Result so far: 76402.4
Subtracting 28 from 30 leaves us with 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

On to step 8:
When dividing 20 by 7, we get 2 with a remainder of 6.
The number 2 becomes the next digit in our result. 
Result so far: 76402.42
If we take 14 away from 20, we end up with 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

Step 9:
7 can be fit into 60 8 times, resulting in a remainder of 4.
Put 8 as the next digit of the answer. 
Result so far: 76402.428
If we subtract 56 from 60, we get 4.
Since there are no more digits in the dividend, we add a zero to the remainder making it 40, and continue the process.

Let's proceed to step 10:
When dividing 40 by 7, we get 5 with a remainder of 5.
Write down 5 as next digit of the result. 
Result so far: 76402.4285
If we subtract 35 from 40, we get 5.
Since there are no more digits in the dividend, we add a zero to the remainder making it 50, and continue the process.

On to step 11:
50 divided by 7 is 7 with a remainder of 1.
Put 7 as the next digit of the answer. 
Result so far: 76402.42857
Subtract 49 from 50 to get 1.
Since there are no more digits in the dividend, we add a zero to the remainder making it 10, and continue the process.

Advancing to step 12:
7 can be fit into 10 1 times, resulting in a remainder of 3.
The next digit of our result is 1. 
Result so far: 76402.428571
The remainder is 3 after subtracting 7 from 10.
Since there are no more digits in the dividend, we add a zero to the remainder making it 30, and continue the process.

Going ahead to step 13:
The number 7 fits into 30 4 times, leaving a remainder of 2.
The number 4 becomes the next digit in our result. 
Result so far: 76402.4285714
If we subtract 28 from 30, we get 2.
Since there are no more digits in the dividend, we add a zero to the remainder making it 20, and continue the process.

Advancing to step 14:
20 divided by 7 is 2 with a remainder of 6.
The next digit of our result is 2. 
Result so far: 76402.42857142
Subtract 14 from 20 to get 6.
Since there are no more digits in the dividend, we add a zero to the remainder making it 60, and continue the process.

The final outcome is 76402.42857142, with a leftover of 6e-09.