We divide 81339 by 27
Let's see how many times 27 fits into 81339.

Going ahead to step 1:
27 goes into 8 0 times with a remainder of 8.
Put 0 as the next digit of the answer. 
Result so far: 0.0
The remainder is 8 after subtracting 0 from 8.
Grab the next digit (1) from the dividend, add it to 8, then carry on: 81 / 27

Step 2:
The number 27 fits into 81 3 times, leaving a remainder of 0.
Write down 3 as next digit of the result. 
Result so far: 3.0
The remainder is 0 after subtracting 81 from 81.
Append the next digit (3) from the dividend to 0 and continue with: 3 / 27

Let's proceed to step 3:
The number 27 fits into 3 0 times, leaving a remainder of 3.
The number 0 becomes the next digit in our result. 
Result so far: 30.0
Subtracting 0 from 3 leaves us with 3.
Bring next digit (3) of the dividend behind the 3 and repeat the process: 33 / 27

Step 4:
When dividing 33 by 27, we get 1 with a remainder of 6.
Write down 1 as next digit of the result. 
Result so far: 301.0
Subtract 27 from 33 to get 6.
Append the next digit (9) from the dividend to 6 and continue with: 69 / 27

On to step 5:
If we divide 69 by 27, we get 2 and a remainder of 15.
Put 2 as the next digit of the answer. 
Result so far: 3012.0
If we take 54 away from 69, we end up with 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Going ahead to step 6:
The number 27 fits into 150 5 times, leaving a remainder of 15.
Write down 5 as next digit of the result. 
Result so far: 3012.5
If we subtract 135 from 150, we get 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

Step 7:
When dividing 150 by 27, we get 5 with a remainder of 15.
Write down 5 as next digit of the result. 
Result so far: 3012.55
Subtracting 135 from 150 leaves us with 15.
Since there are no more digits in the dividend, we add a zero to the remainder making it 150, and continue the process.

In conclusion, the division gives 3012.55 with a balance of 0.015.