<p>I found a <a href="https://twitter.com/s3nsi/status/716737246662148096?lang=en" rel="noreferrer">twitter post</a> answering this exact same question and it appears that Crunchyroll merely split the one-hour episode in two parts. You should start with A, then continue to B, and then continue chronologically. </p>

CC BY-SA 3.0
2017-09-19T02:29:14.790Z
2017-09-19T02:29:14.790Z
giraffesyo
<p>Episode 1 is an extended 50-minute episode, which is double the length of a typical anime episode. So they split it into two parts, so that both parts would be the length of one episode.</p>

CC BY-SA 4.0
2020-10-20T07:42:06.093Z
The existing answer from three years ago already says basically the same thing. I don't see what this adds.
F1Krazy
CC BY-SA 4.0
2020-10-20T00:17:42.440Z
2020-10-20T00:17:42.440Z
David Kim
<p>I'm starting the series Re: Zero on <a href="http://www.crunchyroll.com/rezero-starting-life-in-another-world-" rel="noreferrer">Crunchyroll</a> and I noticed theres an episode 1A and 1B, what is this about?</p>

<re-zero><crunchyroll>
Why is there an episode 1A and 1B on Crunchyroll?
# Why is there an episode 1A and 1B on Crunchyroll?
Posted by: username_0 on 2017-09-19
I'm starting the series Re: Zero on [Crunchyroll](http://www.crunchyroll.com/rezero-starting-life-in-another-world-) and I noticed theres an episode 1A and 1B, what is this about?
**Tags:** re-zero crunchyroll
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## 2 answers
### Answer by username_0 on 2017-09-19. Score: 8 | Accepted answer
I found a [twitter post](https://twitter.com/s3nsi/status/716737246662148096?lang=en) answering this exact same question and it appears that Crunchyroll merely split the one-hour episode in two parts. You should start with A, then continue to B, and then continue chronologically.
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### Answer by username_1 on 2020-10-20. Score: 0
Episode 1 is an extended 50-minute episode, which is double the length of a typical anime episode. So they split it into two parts, so that both parts would be the length of one episode.
> **Comments:**
> **username_2** (2020-10-20): The existing answer from three years ago already says basically the same thing. I don't see what this adds.  
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