<p>Perlin noise, by default, is not self-similar the way we would expect a fractal to be.  Ken Perlin seems to imply that it is not a fractal, but that it can be usefully used to make fractals!  See his slide here: <a href="http://www.noisemachine.com/talk1/21.html" rel="nofollow">http://www.noisemachine.com/talk1/21.html</a> where he briefly mentions how one might do that.</p>

CC BY-SA 2.5
2010-12-19T05:06:09.080Z
2010-12-19T05:06:09.080Z
Peter Boothe
<p>I have an old Spanish CG book that calls Perlin Noise a "fractal structure". After reading <a href="http://webstaff.itn.liu.se/~stegu/TNM022-2005/perlinnoiselinks/perlin-noise-math-faq.html" rel="nofollow">this</a> I couldn't deny it or confirm it. Is it a fractal structure? What would it Hausdorff dimension be?</p>

CC BY-SA 2.5
2010-12-19T02:33:22.433Z
This seems like a question for http://math.stackexchange.com/.
Per Vognsen
CC BY-SA 2.5
2010-12-19T05:29:45.913Z
definitely out of scope.
Suresh Venkat
<terminology>
Is Perlin Noise a "fractal"?
andandandand
# Is Perlin Noise a "fractal"?

(Asked by: username_0 on 2010-12-19)

I have an old Spanish CG book that calls Perlin Noise a "fractal structure". After reading [this](http://webstaff.itn.liu.se/~stegu/TNM022-2005/perlinnoiselinks/perlin-noise-math-faq.html) I couldn't deny it or confirm it. Is it a fractal structure? What would it Hausdorff dimension be?

**Tags:** terminology
> **Comments:**
> **username_1**: This seems like a question for http://math.stackexchange.com/.  
> **username_2**: definitely out of scope.  

---

## 1 answers

### Answer by username_3 on 2010-12-19. Score: 1

Perlin noise, by default, is not self-similar the way we would expect a fractal to be. Ken Perlin seems to imply that it is not a fractal, but that it can be usefully used to make fractals! See his slide here: <http://www.noisemachine.com/talk1/21.html> where he briefly mentions how one might do that.


---

