<p>The escape velocity is c at the event horizon of a black hole. Above the event horizon the escape velocity is below c. Escaping particles of the Hawking radiation form above the event horizon; that's why they can escape, if they are pointing towards a sufficiently narrow angle to vertical upward, and if they are sufficiently energetic.</p>

<p>Escaping particles form as virtual particle-antiparticle pairs in the "infalling" coordinate system: One of the two particles forms outside the event horizon; the counterpart forms below the event horizon. Thus the originally virtual particles cannot annihilate, and therefore become real particles; one particle can escape; the counterpart falls toward the singularity.</p>

<p>The energy needed to form the escaping particle, and its remaining kinetic energy after escape, is subtracted from the mass of the black hole.</p>

<p>The described mechanism probably works also for both particles forming very close above the event horizon if the tidal forces are high enough to separate the virtual particle pair, before it can annihilate.</p>

<p>Formation of virtual particles is due to the Heisenberg uncertainty applied to time and energy: Very short time intervals require energy uncertainty, leading to short-lived particle-antiparticle pairs.</p>

CC BY-SA 3.0
2014-01-07T13:47:38.630Z
But, when the Hawking radiation is on the inside, everything else coming form inside, how can a particle, even if it is virtual, form on the outside? Also, how exactly are they 'virtual'?
user748
CC BY-SA 3.0
2014-01-07T17:07:47.147Z
Virtual particles form spontaneously and usually live for a very short time, less than about 1e-22 seconds, details see http://en.wikipedia.org/wiki/Virtual_particle. Only half of the radiation is in the inside, the outside (anti-)particle can become Hawking radiation. A particle looking virtual from an infalling coordiante system can look real from outside, because of extreme time dilation near the event horizon.
Gerald
CC BY-SA 3.0
2014-01-06T16:31:25.357Z
2014-01-06T16:31:25.357Z
Gerald
<p>The real explanation for Hawking Radiation does not concern virtual particles. My simplified version of the real explanation is that curved space-time has a different minimum energy amount for a moving object than normal "flat" space. Therefore, energy flows outward from the warped area. </p>

<p>Because of this explanation, it has been determined that smaller black holes evaporate faster because they curve space more than the larger ones. </p>

<p>Personally, I do not believe in virtual particles, simply because you can't get something from nothing. </p>

CC BY-SA 4.0
2020-05-26T23:55:30.367Z
The virtual particle explanation of Hawking radiation is a simplified "cartoon", it shouldn't be taken too literally. Your answer is better, but please see https://physics.stackexchange.com/a/252236/123208 Virtual particles are a useful mathematical device, but they don't have the same physical status as real particles. You may enjoy https://profmattstrassler.com/articles-and-posts/particle-physics-basics/virtual-particles-what-are-they/
PM 2Ring
CC BY-SA 4.0
2020-05-27T09:08:00.860Z
I'm sure there is a great answer here, but the phrasing and detail could be improved.  Can you give some details on how "curved spacetime has a different minimum energy for a moving object than flat spacetime." What is the moving object here? The black hole? but HR doesn't require the BH to move (relative to what?)  Is HR predicted around other massive objects, or is the event horizon significant in some way. If it is just "energy flowing out of curved spacetime" then surely everything with mass would produce HR. Saying "I don't believe" greatly weakens the answer, belief doesn't count.
James K
CC BY-SA 4.0
2020-05-26T23:32:46.073Z
2020-05-26T23:32:46.073Z
Mr.555
<p>I've read that even light cannot escape from black holes.<br>
The speed of light is theoretically predicted to be the escape velocity of a black hole.<br>
I've also read that the general notion that nothing can escape from a black hole is wrong.  Even black holes emit particles and radiation known as the Hawking radiation.<br>
My question is: How can black holes emit <em>any</em> kind of radiation?
If they even do emit, wouldn't the speed of the radiation be less than or equal to velocity of light?<br>
If the escape velocity of a black hole is <em>c</em>, then how can the Hawking radiation even escape the black hole? Wouldn't it be pulled back into the black hole? Then, how is it even 
<em>emitting</em> anything?</p>

CC BY-SA 4.0
2020-05-26T23:57:06.507Z
Hawking radiation is emitted from the general vicinity of the black hole, it doesn't have to escape the event horizon.
PM 2Ring
<black-hole><hawking-radiation>
Black Holes emitting Hawking radiation
user748
# Black Holes emitting Hawking radiation

(Asked by: username_0 on 2014-01-06)

I've read that even light cannot escape from black holes.  
The speed of light is theoretically predicted to be the escape velocity of a black hole.  
I've also read that the general notion that nothing can escape from a black hole is wrong. Even black holes emit particles and radiation known as the Hawking radiation.  
My question is: How can black holes emit *any* kind of radiation?
If they even do emit, wouldn't the speed of the radiation be less than or equal to velocity of light?  
If the escape velocity of a black hole is *c*, then how can the Hawking radiation even escape the black hole? Wouldn't it be pulled back into the black hole? Then, how is it even
*emitting* anything?

**Tags:** black-hole, hawking-radiation

> **Comments:**
> **username_1**: Hawking radiation is emitted from the general vicinity of the black hole, it doesn't have to escape the event horizon.  

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## 2 answers

### Answer by username_2 on 2014-01-06. Score: 4

The escape velocity is c at the event horizon of a black hole. Above the event horizon the escape velocity is below c. Escaping particles of the Hawking radiation form above the event horizon; that's why they can escape, if they are pointing towards a sufficiently narrow angle to vertical upward, and if they are sufficiently energetic.

Escaping particles form as virtual particle-antiparticle pairs in the "infalling" coordinate system: One of the two particles forms outside the event horizon; the counterpart forms below the event horizon. Thus the originally virtual particles cannot annihilate, and therefore become real particles; one particle can escape; the counterpart falls toward the singularity.

The energy needed to form the escaping particle, and its remaining kinetic energy after escape, is subtracted from the mass of the black hole.

The described mechanism probably works also for both particles forming very close above the event horizon if the tidal forces are high enough to separate the virtual particle pair, before it can annihilate.

Formation of virtual particles is due to the Heisenberg uncertainty applied to time and energy: Very short time intervals require energy uncertainty, leading to short-lived particle-antiparticle pairs.

> **Comments:**
> **username_0**: But, when the Hawking radiation is on the inside, everything else coming form inside, how can a particle, even if it is virtual, form on the outside? Also, how exactly are they 'virtual'?  
> **username_2**: Virtual particles form spontaneously and usually live for a very short time, less than about 1e-22 seconds, details see http://en.wikipedia.org/wiki/Virtual_particle. Only half of the radiation is in the inside, the outside (anti-)particle can become Hawking radiation. A particle looking virtual from an infalling coordiante system can look real from outside, because of extreme time dilation near the event horizon.  

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### Answer by username_3 on 2020-05-26. Score: 1

The real explanation for Hawking Radiation does not concern virtual particles. My simplified version of the real explanation is that curved space-time has a different minimum energy amount for a moving object than normal "flat" space. Therefore, energy flows outward from the warped area.

Because of this explanation, it has been determined that smaller black holes evaporate faster because they curve space more than the larger ones.

Personally, I do not believe in virtual particles, simply because you can't get something from nothing.

> **Comments:**
> **username_1**: The virtual particle explanation of Hawking radiation is a simplified "cartoon", it shouldn't be taken too literally. Your answer is better, but please see https://physics.stackexchange.com/a/252236/123208 Virtual particles are a useful mathematical device, but they don't have the same physical status as real particles. You may enjoy https://profmattstrassler.com/articles-and-posts/particle-physics-basics/virtual-particles-what-are-they/  
> **username_4**: I'm sure there is a great answer here, but the phrasing and detail could be improved.  Can you give some details on how "curved spacetime has a different minimum energy for a moving object than flat spacetime." What is the moving object here? The black hole? but HR doesn't require the BH to move (relative to what?)  Is HR predicted around other massive objects, or is the event horizon significant in some way. If it is just "energy flowing out of curved spacetime" then surely everything with mass would produce HR. Saying "I don't believe" greatly weakens the answer, belief doesn't count.  

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