<p>Welcome to Astronomy Stack Exchange!<br>
Let the star which is farther away be A, and the fainter one be B.<br>Since this perceived brightness is something called flux density (sometimes referred to as just flux), which the following formula holds its own for: <span class="math-container">$F = \frac{L}{4\pi r^2}$</span> 
(<span class="math-container">$L$</span> is the luminosity, and <span class="math-container">$r$</span> is the distance) it would mean the luminosity ratio can be calculated in the following manner:<br>
<span class="math-container">$F_A = F_B$</span><br>
<span class="math-container">$\frac{L_A}{4\pi r_A^2} = \frac{L_B}{4\pi r_B^2}$</span><br>Substituting for <span class="math-container">$r_A = 8r_B$</span>:<br>
<span class="math-container">$\frac{L_A}{64r_B^2} = \frac{L_B}{r_B^2}$</span><br>
<span class="math-container">$L_A = 64L_B$</span>
<br>The farther star is much more luminous than the closer one.<br>
P.S. This is only if there is no extinction, if it is present, I cannot make an estimate without more details.</p>

CC BY-SA 4.0
2019-02-01T22:37:49.437Z
2019-02-01T22:37:49.437Z
Tosic
<p>Suppose two stars have the same apparent brightness, but one star is 8 times further away than the other. What is the ratio of their luminosities? Which one is more luminous, the closer or the further star?</p>

CC BY-SA 4.0
2019-02-02T07:47:34.220Z
Why don't you do your own homework? The answer is readily resolved using the ideas presented to you in the previous homework question you asked.
ProfRob
<fundamental-astronomy>
Luminosities and Apparent Brightness of Two Stars of which one is 8 times the distance of the first star
James 9779
# Luminosities and Apparent Brightness of Two Stars of which one is 8 times the distance of the first star

(Asked by: username_0 on 2019-02-01)

Suppose two stars have the same apparent brightness, but one star is 8 times further away than the other. What is the ratio of their luminosities? Which one is more luminous, the closer or the further star?

**Tags:** fundamental-astronomy

> **Comments:**
> **username_1**: Why don't you do your own homework? The answer is readily resolved using the ideas presented to you in the previous homework question you asked.  

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## 1 answers

### Answer by username_2 on 2019-02-01. Score: 1

Welcome to Astronomy Stack Exchange!  
Let the star which is farther away be A, and the fainter one be B.  
Since this perceived brightness is something called flux density (sometimes referred to as just flux), which the following formula holds its own for: $F = \frac{L}{4\pi r^2}$
($L$ is the luminosity, and $r$ is the distance) it would mean the luminosity ratio can be calculated in the following manner:  
$F\_A = F\_B$  
$\frac{L\_A}{4\pi r\_A^2} = \frac{L\_B}{4\pi r\_B^2}$  
Substituting for $r\_A = 8r\_B$:  
$\frac{L\_A}{64r\_B^2} = \frac{L\_B}{r\_B^2}$  
$L\_A = 64L\_B$
  
The farther star is much more luminous than the closer one.  
P.S. This is only if there is no extinction, if it is present, I cannot make an estimate without more details.


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