<p>The <a href="https://en.wikipedia.org/wiki/Chandrasekhar_limit" rel="nofollow">Chandrasekhar limit</a> applies only for white dwarfs. Stars on the main sequence (or even off the main sequence) can easily surpass it, but if a white dwarf's mass is greater than the Chandrasekhar limit ($1.39 M_{\odot}$), it will undergo some sort of collapse.</p>

<p>First, though, in response to</p>

<blockquote>
  <p>Or has it already undergone supernova explosion?</p>
</blockquote>

<p>White dwarfs are <em>not</em> formed from supernovae, but from stars that (relatively) gently shed their outer layers to form planetary nebulae. So no, the stellar remnant will not have gone supernova already.</p>

<p>Back to the main question. If a white dwarf exists, its mass is less than the Chandrasekhar limit. To surpass that, it needs to gain mass. This can happen in binary systems where the white dwarf accretes matter from the more massive star (generally a giant). The white dwarf can then undergo a <a href="https://en.wikipedia.org/wiki/Type_Ia_supernova" rel="nofollow">Type Ia supernova</a> and explode. The light curve will look a bit like this:</p>

<p><a href="https://upload.wikimedia.org/wikipedia/commons/8/88/SNIacurva.png" rel="nofollow"><img src="https://upload.wikimedia.org/wikipedia/commons/8/88/SNIacurva.png" alt=""></a></p>

<p>A second (but far less likely) scenario is that two white dwarfs merge. The result? A Type Ia supernova and, possibly, a neutron star.</p>

CC BY-SA 3.0
2015-03-08T17:29:06.660Z
2015-03-08T17:29:06.660Z
HDE 226868
<p>The Chandrasekhar limit in general does not pertain to the mass of the star as a whole. It addresses the mass of the degenerate core. It's only in white dwarfs where the Chandrasekhar limit applies to the mass of white dwarf as a whole, but that's because white dwarfs are almost entirely degenerate matter.</p>

<p>Consider a 1.6 solar mass that is not a member of a multiple star system. Even though this star's total mass exceeds the Chandrasekhar limit, this star will never go supernova. This star will instead live for billions of year on the main sequence, then a bit longer as a post-main sequence star, and finally end it's life as a white dwarf with considerably less mass than that original 1.6 solar masses (and considerably less than Chandrasekhar limit).</p>

<p>The star leaves the main sequence when it burns all of the hydrogen in its core. Two things happen at this point. One is that it starts burning hydrogen in a shell around an inert core of helium. The other is that it expands into a red giant. (Note: Some people are taught that a star becomes a red giant when it starts burning helium. This is not the case. This post-main sequence star is a red giant that is not yet burning helium.)</p>

<p>That inert core of helium increases in mass as hydrogen shell burning proceeds. A funny thing begins to happen with this increase in mass: The inert core becomes degenerate. An even funnier thing happens next: Adding even more mass makes the degenerate core shrink in size. The star is poised on the next phase of its evolution, which is helium burning. The formerly inert, degenerate core of helium is no longer inert or degenerate at this stage. Think of this phase of a star's life as a main sequence helium burning star. It's definitely not on the main sequence, but much of the physics is the same. One thing that is different: The shell burning of hydrogen is still occurring.</p>

<p>This phase doesn't last long. The star will soon consume all of the helium in its core. At this point, the star becomes a red giant for a second time. This is the asymptotic red giant branch. The star has an inert core of carbon and oxygen surrounded by a shell of fusing helium, which in turn is surrounded by a shell of fusing hydrogen.</p>

<p>These end of life convulsions are not good for the stuff that surrounds the shell of fusing hydrogen. The star expels a lot of that gas into nearby space. Eventually it will expel most of the burning shells of hydrogen and helium, leaving an inert, degenerate core of mostly carbon and oxygen. This is a white dwarf. A planetary nebula of expelled gases surrounds the white dwarf. The white dwarf itself has but a fraction of the star's initial mass. Most of the mass is in that planetary nebula.</p>

<p>Larger stars are even more proficient at expelling mass than was this 1.6 solar mass star. For stars with an initial mass of about eight solar masses or less, the white dwarfs left behind at the end of the stars' lives will be less than the Chandrasekhar limit.</p>

<p>The fate of stars over ten solar masses is much more violent. At the end of their lives, they have lurking inside them a series of burning shells that surround an inert, degenerate core of iron. A star has about five days to live once that core of iron starts forming. That's about how long it takes to create (from scratch) a degenerate iron core that approaches the Chandrasekhar limit. At or near the limit, the core starts to collapse, and the star forms a type II supernova.</p>

<p>A white dwarf can form a type Ia supernova with a little help from a binary neighbor from which the white dwarf is stealing mass. Conditions have to be just right for this to happen, but when it does, the white dwarf can gradually accumulate mass and go supernova. Since white dwarfs have expelled all of their hydrogen, there won't be any signatures of hydrogen in the supernova explosion. In fact, it's the lack or presence of hydrogen in the supernova signature that distinguishes type I from type II supernova.</p>

CC BY-SA 3.0
2015-03-08T21:14:51.547Z
2015-03-08T21:14:51.547Z
David Hammen
<p>A nearby star has crossed Chandrasekhar's limit. How do we come to know when it will undergo supernova explosion? 
Or has it already undergone supernova explosion?</p>

CC BY-SA 3.0
2015-03-08T21:56:18.140Z
Not clear what you are asking. Can you clarify? If it has undergone a supernova explosion there wouldn't be a star there at all - except possibly a neutron star. If the core of a star exceeds the Chandrasekhar mass then a supernova is imminent - i.e. the core collapse in seconds and within minutes a supernova explosion is underway. If a white dwarf accretes mass beyond the Chandrasekhar limit it will explode (again within minutes) to leave behind nothing at all.
ProfRob
<star><supernova><explosion>
Supernova explosion nearby
Aditya Kumar
# Supernova explosion nearby

(Asked by: username_0 on 2015-03-08)

A nearby star has crossed Chandrasekhar's limit. How do we come to know when it will undergo supernova explosion?
Or has it already undergone supernova explosion?

**Tags:** star, supernova, explosion

> **Comments:**
> **username_1**: Not clear what you are asking. Can you clarify? If it has undergone a supernova explosion there wouldn't be a star there at all - except possibly a neutron star. If the core of a star exceeds the Chandrasekhar mass then a supernova is imminent - i.e. the core collapse in seconds and within minutes a supernova explosion is underway. If a white dwarf accretes mass beyond the Chandrasekhar limit it will explode (again within minutes) to leave behind nothing at all.  

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## 2 answers

### Answer by username_2 on 2015-03-08. Score: 2 | Accepted answer

The [Chandrasekhar limit](https://en.wikipedia.org/wiki/Chandrasekhar_limit) applies only for white dwarfs. Stars on the main sequence (or even off the main sequence) can easily surpass it, but if a white dwarf's mass is greater than the Chandrasekhar limit ($1.39 M\_{\odot}$), it will undergo some sort of collapse.

First, though, in response to

> Or has it already undergone supernova explosion?

White dwarfs are *not* formed from supernovae, but from stars that (relatively) gently shed their outer layers to form planetary nebulae. So no, the stellar remnant will not have gone supernova already.

Back to the main question. If a white dwarf exists, its mass is less than the Chandrasekhar limit. To surpass that, it needs to gain mass. This can happen in binary systems where the white dwarf accretes matter from the more massive star (generally a giant). The white dwarf can then undergo a [Type Ia supernova](https://en.wikipedia.org/wiki/Type_Ia_supernova) and explode. The light curve will look a bit like this:

[![](https://upload.wikimedia.org/wikipedia/commons/8/88/SNIacurva.png)](https://upload.wikimedia.org/wikipedia/commons/8/88/SNIacurva.png)

A second (but far less likely) scenario is that two white dwarfs merge. The result? A Type Ia supernova and, possibly, a neutron star.


---

### Answer by username_3 on 2015-03-08. Score: 2

The Chandrasekhar limit in general does not pertain to the mass of the star as a whole. It addresses the mass of the degenerate core. It's only in white dwarfs where the Chandrasekhar limit applies to the mass of white dwarf as a whole, but that's because white dwarfs are almost entirely degenerate matter.

Consider a 1.6 solar mass that is not a member of a multiple star system. Even though this star's total mass exceeds the Chandrasekhar limit, this star will never go supernova. This star will instead live for billions of year on the main sequence, then a bit longer as a post-main sequence star, and finally end it's life as a white dwarf with considerably less mass than that original 1.6 solar masses (and considerably less than Chandrasekhar limit).

The star leaves the main sequence when it burns all of the hydrogen in its core. Two things happen at this point. One is that it starts burning hydrogen in a shell around an inert core of helium. The other is that it expands into a red giant. (Note: Some people are taught that a star becomes a red giant when it starts burning helium. This is not the case. This post-main sequence star is a red giant that is not yet burning helium.)

That inert core of helium increases in mass as hydrogen shell burning proceeds. A funny thing begins to happen with this increase in mass: The inert core becomes degenerate. An even funnier thing happens next: Adding even more mass makes the degenerate core shrink in size. The star is poised on the next phase of its evolution, which is helium burning. The formerly inert, degenerate core of helium is no longer inert or degenerate at this stage. Think of this phase of a star's life as a main sequence helium burning star. It's definitely not on the main sequence, but much of the physics is the same. One thing that is different: The shell burning of hydrogen is still occurring.

This phase doesn't last long. The star will soon consume all of the helium in its core. At this point, the star becomes a red giant for a second time. This is the asymptotic red giant branch. The star has an inert core of carbon and oxygen surrounded by a shell of fusing helium, which in turn is surrounded by a shell of fusing hydrogen.

These end of life convulsions are not good for the stuff that surrounds the shell of fusing hydrogen. The star expels a lot of that gas into nearby space. Eventually it will expel most of the burning shells of hydrogen and helium, leaving an inert, degenerate core of mostly carbon and oxygen. This is a white dwarf. A planetary nebula of expelled gases surrounds the white dwarf. The white dwarf itself has but a fraction of the star's initial mass. Most of the mass is in that planetary nebula.

Larger stars are even more proficient at expelling mass than was this 1.6 solar mass star. For stars with an initial mass of about eight solar masses or less, the white dwarfs left behind at the end of the stars' lives will be less than the Chandrasekhar limit.

The fate of stars over ten solar masses is much more violent. At the end of their lives, they have lurking inside them a series of burning shells that surround an inert, degenerate core of iron. A star has about five days to live once that core of iron starts forming. That's about how long it takes to create (from scratch) a degenerate iron core that approaches the Chandrasekhar limit. At or near the limit, the core starts to collapse, and the star forms a type II supernova.

A white dwarf can form a type Ia supernova with a little help from a binary neighbor from which the white dwarf is stealing mass. Conditions have to be just right for this to happen, but when it does, the white dwarf can gradually accumulate mass and go supernova. Since white dwarfs have expelled all of their hydrogen, there won't be any signatures of hydrogen in the supernova explosion. In fact, it's the lack or presence of hydrogen in the supernova signature that distinguishes type I from type II supernova.


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