<p>If you're not opposed to a bit of Python, you can easily compute this with astropy.</p>
<pre><code>import astropy.time
import astropy.coordinates

moon = astropy.coordinates.get_moon(astropy.time.Time.now())
print(moon.ra)
</code></pre>
<p>Which outputs</p>
<pre><code>&lt;Longitude 115.085153 deg&gt;
</code></pre>

CC BY-SA 4.0
2023-02-03T18:11:02.463Z
2023-02-03T18:32:21.077Z
2023-02-03T18:32:21.077Z
Roy Smart
<p>Is there any approximate way to calculate the right ascension of the Moon? I already got declination but still, need the right ascension to calculate the final position of the moon. Thanks for all your answers!</p>

CC BY-SA 4.0
2023-02-03T02:25:41.613Z
Can you explain how or where you found how to calculate the declination?  Also, how accurate or appropriate do you want the Right Ascension?
JohnHoltz
CC BY-SA 4.0
2023-02-03T03:15:03.603Z
The astronomical almanac has a low precision moon position, accurate to .5 deg from 1900-2100.  Example implementation here: https://www.celestialprogramming.com/lowprecisionmoonposition.html
Greg Miller
CC BY-SA 4.0
2023-02-03T03:16:17.610Z
A more accurate method is to use VSOP 87: https://github.com/gmiller123456/vsop87-multilang.  Highest precision can be obtained from using JPL's Development Ephemeris.
Greg Miller
<the-moon><solar-system><astrophysics><right-ascension>
How to get the right ascension of the Moon?
Misaki
# How to get the right ascension of the Moon?

(Asked by: username_0 on 2023-02-03)

Is there any approximate way to calculate the right ascension of the Moon? I already got declination but still, need the right ascension to calculate the final position of the moon. Thanks for all your answers!

**Tags:** the-moon, solar-system, astrophysics, right-ascension

> **Comments:**
> **username_1**: Can you explain how or where you found how to calculate the declination?  Also, how accurate or appropriate do you want the Right Ascension?  
> **username_2**: The astronomical almanac has a low precision moon position, accurate to .5 deg from 1900-2100.  Example implementation here: https://www.celestialprogramming.com/lowprecisionmoonposition.html  
> **username_2**: A more accurate method is to use VSOP 87: https://github.com/gmiller123456/vsop87-multilang.  Highest precision can be obtained from using JPL's Development Ephemeris.  

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## 1 answers

### Answer by username_3 on 2023-02-03. Score: 1

If you're not opposed to a bit of Python, you can easily compute this with astropy.
import astropy.time
import astropy.coordinates

moon = astropy.coordinates.get_moon(astropy.time.Time.now())
print(moon.ra)

Which outputs


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