<p>A black hole (BH) <strong>never sucks anything in</strong>. '<em>Sucking</em>' requires gas pressure, but a black hole only acts via its gravity. A non-rotating (=Schwarzschild) black hole attracts all massive objects, very much like the Sun attracts the planets.
Yet, the planets are not falling into the Sun. This is because the planets move on near-circular orbits when the centrifugal force balances the gravitational attraction. The planets orbital <em>angular momemtum</em> is conserved (because the Solar force field is purely radial [to good approximation]) and these orbits are stable.</p>

<p>The difference to a black hole is that very close to the event horizon no such stable circular orbits exist anymore. At those distances, nothing can orbit the BH without <em>falling</em> in.</p>

<p>However, an object orbiting a BH on a stable orbit (including passing trajectories) is still subjected to the BH's <em>tidal forces</em>. These distort the object, very much like the Moon's gravity distorts the Earth, generating tides.
In case, the trajectory passes sufficiently close to the BH and the object is rather big and fluffy, like (some) stars, the tidal forces may not merely distort the object, but rip it apart.</p>

<p>Such tidal disruption of stars must happen if a star passes close to a supermassive BH. This can hardly be directly observed, but the it is thought that some of the stellar matter forms an <em>accretion disc</em> around the BH and produces a characteristic light curve. An observed light curve in agreement with this model is often interpreted as circumstantial evidence for a stellar disruption event.</p>

CC BY-SA 3.0
2015-04-30T04:10:41.103Z
You talked about non-rotating black holes, what happens with the *rotating* ones? And what happens after a black hole rips apart an object? Does it simply drift in space or get pulled in the black hole.
Swapnil Rastogi
CC BY-SA 3.0
2015-05-02T10:39:28.673Z
Rotating BHs will make things a bit more complicated but the explanations given above remain valid. Once the object is ripped apart, as you say, the same phenomena, again, apply for every individual part: stable versus non-stable orbita, tidal disruption etc.
onekiloparsec
CC BY-SA 3.0
2015-05-03T17:25:03.330Z
@SwapnilRastogi As I said in the answer, *some of the stellar matter* [from the star ripped apart] *forms an accretion disc around the BH*. This is essentially all matter that is gravitationally bound to the BH. The remainder escapes. If the star was initially on a parabolic orbit (which to good approximation is the typical situation), half of the gas from the star will accrete and the other half escape.
Walter
CC BY-SA 3.0
2015-05-05T06:57:59.207Z
Alright, that sums up my doubt, thanks for the explanation!
Swapnil Rastogi
CC BY-SA 3.0
2015-04-29T11:36:28.850Z
2015-04-29T11:36:28.850Z
Walter
<p>I'm making a simplified animation for college project on how a star reacts with a black hole. I had known that a black hole sucks in everything and thus should be doing the same for stars. But upon my research I found out that recently a discovery was made that a super-massive black hole <em>ripped</em> apart a star. Now I've always been curious about cosmology and this took my attention and also worried me for my assignment. There were two conditions with the above mentioned calamity - one, the black was a super-massive one and second, the victim star was possibly already stripped off it's outer gaseous by the same black hole. My question is that the <em>ripping</em> apart happens in all conditions and the sucking in thing was wrong or it happens only in mentioned circumstances?</p>

CC BY-SA 3.0
2015-04-29T10:11:06.617Z
NOTE: I'm not asking for help for the animation. My question is for the science only.
Swapnil Rastogi
CC BY-SA 3.0
2015-04-30T01:50:53.730Z
You might want to look at Shoemaker Levy crashing into Jupiter (videos and simulations of that shouldn't be hard to find).    The main things to consider are the Roche limit of the black hole and the size ratio, star to black hole.   A super-massive black hole would likely be larger than most stars.    Once inside the Roche limit, the stars gravity loses and it crumbles like an 8 day old biscuit in a hungry dog's mouth, or, well, more accurately, what happened to shoemaker levy happens to the star.   What that looks like - well, it would put on quite a show.  The angle of approach matters too.
userLTK
<star><black-hole><cosmology><supermassive-black-hole>
Star versus Black Hole
Swapnil Rastogi
# Star versus Black Hole

(Asked by: username_0 on 2015-04-29)

I'm making a simplified animation for college project on how a star reacts with a black hole. I had known that a black hole sucks in everything and thus should be doing the same for stars. But upon my research I found out that recently a discovery was made that a super-massive black hole *ripped* apart a star. Now I've always been curious about cosmology and this took my attention and also worried me for my assignment. There were two conditions with the above mentioned calamity - one, the black was a super-massive one and second, the victim star was possibly already stripped off it's outer gaseous by the same black hole. My question is that the *ripping* apart happens in all conditions and the sucking in thing was wrong or it happens only in mentioned circumstances?

**Tags:** star, black-hole, cosmology, supermassive-black-hole

> **Comments:**
> **username_0**: NOTE: I'm not asking for help for the animation. My question is for the science only.  
> **username_1**: You might want to look at Shoemaker Levy crashing into Jupiter (videos and simulations of that shouldn't be hard to find).    The main things to consider are the Roche limit of the black hole and the size ratio, star to black hole.   A super-massive black hole would likely be larger than most stars.    Once inside the Roche limit, the stars gravity loses and it crumbles like an 8 day old biscuit in a hungry dog's mouth, or, well, more accurately, what happened to shoemaker levy happens to the star.   What that looks like - well, it would put on quite a show.  The angle of approach matters too.  

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## 1 answers

### Answer by username_2 on 2015-04-29. Score: 6 | Accepted answer

A black hole (BH) **never sucks anything in**. '*Sucking*' requires gas pressure, but a black hole only acts via its gravity. A non-rotating (=Schwarzschild) black hole attracts all massive objects, very much like the Sun attracts the planets.
Yet, the planets are not falling into the Sun. This is because the planets move on near-circular orbits when the centrifugal force balances the gravitational attraction. The planets orbital *angular momemtum* is conserved (because the Solar force field is purely radial [to good approximation]) and these orbits are stable.

The difference to a black hole is that very close to the event horizon no such stable circular orbits exist anymore. At those distances, nothing can orbit the BH without *falling* in.

However, an object orbiting a BH on a stable orbit (including passing trajectories) is still subjected to the BH's *tidal forces*. These distort the object, very much like the Moon's gravity distorts the Earth, generating tides.
In case, the trajectory passes sufficiently close to the BH and the object is rather big and fluffy, like (some) stars, the tidal forces may not merely distort the object, but rip it apart.

Such tidal disruption of stars must happen if a star passes close to a supermassive BH. This can hardly be directly observed, but the it is thought that some of the stellar matter forms an *accretion disc* around the BH and produces a characteristic light curve. An observed light curve in agreement with this model is often interpreted as circumstantial evidence for a stellar disruption event.

> **Comments:**
> **username_0**: You talked about non-rotating black holes, what happens with the *rotating* ones? And what happens after a black hole rips apart an object? Does it simply drift in space or get pulled in the black hole.  
> **username_3**: Rotating BHs will make things a bit more complicated but the explanations given above remain valid. Once the object is ripped apart, as you say, the same phenomena, again, apply for every individual part: stable versus non-stable orbita, tidal disruption etc.  
> **username_2**: @SwapnilRastogi As I said in the answer, *some of the stellar matter* [from the star ripped apart] *forms an accretion disc around the BH*. This is essentially all matter that is gravitationally bound to the BH. The remainder escapes. If the star was initially on a parabolic orbit (which to good approximation is the typical situation), half of the gas from the star will accrete and the other half escape.  
> **username_0**: Alright, that sums up my doubt, thanks for the explanation!  

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