<p>There are 2 main kinds of supernova.  The kind you are referring to is a <strong>type 2</strong> supernova.  There are also type 1a, type 1b, and type 1c supernova.  Type 1a supernova are not caused by the implosion of huge stars, but rather, a white dwarf accumulating ever greater amounts of mass from a companion star until the <a href="https://en.wikipedia.org/wiki/Chandrasekhar_limit" rel="nofollow noreferrer">Chandrasekhar limit</a> for mass is reached.  Then we get the type 1a supernova, which leaves little core remnant and is more or less constant sized explosion with standard luminosity.  This is the reason type 1a supernova are used as standard candles to gauge the distance of objects in the universe.</p>

<p>As <a href="https://astronomy.stackexchange.com/questions/21641/why-do-medium-stars-collapse-to-form-supernovae-while-big-stars-collapse-to-form/21643#21643">David Hammen's answer</a> has pointed out, type 2 supernova endings occur only for stars that are more than 8x our sun's mass. Neutron stars and black holes are remnants left post-supernova, after the outer layers and majority of star has has blown off.  The size of the remnant is  predictable to an extent pre-supernova and depends on the mass of the star.  However this is only an approximation and there are always exceptions as the physics is complex and depends on too many variables. Type 1 supernovas leave little of no remnant.</p>

<p><strong>Cause of Type 2 Supernova:</strong></p>

<p>So what causes a dying star of said mass or greater to blow itself up to smitherines in such a way that more energy is released in the short span of the explosion that that of an entire galaxy for same time period.  This is in contrast to the much more docile, gradual, and protracted conclusion of stars whose mass is less than 8xSun;  planetary nebula after a red giant collapse and leaves white dwarf as remnant.</p>

<p><strong>Massive Star Pre-Supernova</strong>(type 2) and implosion:</p>

<p>The core of a massive star will accumulate iron and heavier elements which are not exo-thermically fusible.  Iron is the end of the exothermic fusion chain. Any fusion to heavier nuclei will be endothermic.  Endothermic fusion absorbs energy from the surrounding layer causing it to cool down and condense around the core further.  This added inward pressure is in addition to the inward pressure of gravity and causes a gradient where the core continues to collapse and get denser while exothermic fusion maintains expansive outward pressure above the gradient.   </p>

<p>When the density of the inner core reaches a point where the pressure overcomes <a href="https://en.wikipedia.org/wiki/Electron_degeneracy_pressure" rel="nofollow noreferrer">electron degeneration pressure</a>.  Then another gradient is formed where inside the gradient atoms no longer exists because the electrons of the atoms will join their nucleus. The protons in the nucleus combine with the electrons to become neutrons, and release neutrinos.  There will be no more individual atoms inside of this gradient.  The sudden collapse inside the electron degeneration pressure gradient of the core triggers the initial supernova implosion as said core collapses in a few seconds to a tiny point object of nuclear density (3×10<sup>17</sup> kg/m<sup>3</sup>) no bigger than <a href="http://xtreme.as.arizona.edu/NeutronStars/index.php/neutron-star-radii/" rel="nofollow noreferrer">Manhattan</a>.</p>

<p><strong>Supernova Explosion:</strong>  </p>

<p>The sudden in-rush of both the heavy element core outside the electron degeneration gradient, and the exotherimically fusible outer layers of the star cause immense heat and pressure in a few seconds period of time causing much of the lighter than iron elements to simultaneously fuse all at once.</p>

<pre><code>**Anti-Matter:**
</code></pre>

<p>Also, the extremely dense and energetic neutrino flux would be rushing outward from the mentioned EDP core collapse.  When the neutrinos encounter head on the equally energetic atomic nuclei rushing  inwards the following occurs:</p>

<p>When a neutron absorbs a neutrino, antimatter is formed as neutrons become anti-protons and positrons.
When this Anti-Matter encounters normal matter, we have the most efficient and complete mass to energy conversion possible: 
Matter-AntiMatter Annihilation  (MAMA).</p>

<p>The combination of the simultaneous fusion and the MAMA causes all hell to break loose in the greatest release of energy in the shortest time, 2nd only to the gamma ray burst, known in the universe.</p>

<p><strong>Remnant Post-Supernova:</strong></p>

<p>What is left behind after most of the star has blown off is a solid extremely dense mass of neutrons around the size of Manhattan.  Thus the term neutron star.</p>

<p>There is nothing denser than a neutron star. (See note below) It is just pure mass with no empty space left. To get a perspective what we are taking about here, our normal atom on earth is almost all empty space. If we take the simplest atom which is hydrogen, and the nucleus (one proton) was scaled up to the size of a pea sized marble in the middle of a football stadium, the orbital of the single electron would extend all the way at the outer edge of the stadium, the electron no bigger than a grain of sand; almost all empty space.</p>

<p>Now just imagine a sphere of solid mass of such marbles filling the stadium with no space left. That is how we can picture the density of a neutron star, and it is the density limit of the universe. A black hole has this same density, just more massive.</p>

<p>"A neutron star is so dense that one teaspoon (5 milliliters) of its material would have a mass over 5.5×10<sup>12</sup> kg (that is 1100 tonnes per 1 nanolitre), about 900 times the mass of the Great Pyramid of Giza."</p>

<p>With the density limit constant, a neutron star can only get larger, occupy a greater volume, as it gains more mass. The mass and surface area determine the escape velocity, the velocity needed for an object to escape the host's gravity from the surface. The immense gravity causes the smallest neutron star to have an escape velocity of 100,000 km/s, or one third of the speed of light.</p>

<p>When the mass of the neutron star surpasses the level at which the <a href="https://en.wikipedia.org/wiki/Escape_velocity" rel="nofollow noreferrer">escape velocity</a> for the neutron star exceeds the speed of light, then even light cannot escape its gravitation, thus becoming a <strong>black hole</strong>.</p>

<p>Note: There is theoretically a point where the gravity and density of a neutron star will reach a threshold called the neutron degeneracy pressure.  This was hypothesized by Tolman–Oppenheimer–Volkoff, and limit by same name.  This would result in greater density called baryonic density.  Then if we go denser, we can get quark density, and so on.  These are all speculative theories since the sub-nuclear interactions are not well understood, and we can't look inside a black hole to see the evidence.</p>

CC BY-SA 3.0
2017-07-15T08:37:14.107Z
Cleared all my doubts, thanks to you and @Cody for awesome answers
GypsyCosmonaut
CC BY-SA 3.0
2017-07-15T09:00:26.247Z
Re "There is nothing denser than a neutron star": The hypothetical [quark stars](https://en.wikipedia.org/wiki/Quark_star), if they exist, would be even denser.
David Hammen
CC BY-SA 3.0
2017-07-15T09:04:26.040Z
Really lots of problematic statements here. The Chandrasekhar mass for an iron core is not 1.4 solar masses. The Pauli exclusion principle does not "break down". Your density for neutron star cores is too low, your number might be an average density. Generally speaking, if you add mass to a neutron star it gets smaller (quark stars might be an exception). Collapse to a black hole would occur well before the escape velocity became equal to the speed of light.
ProfRob
CC BY-SA 3.0
2017-07-15T16:44:36.693Z
@RobJeffries  Corrected.
0tyranny0poverty
CC BY-SA 3.0
2017-07-15T17:00:11.887Z
Partly. But your basic answer to the question is incorrect/incomplete, since you assert that the pre-supernova stellar mass is irrelevant, when in fact it is thought to be the dominant factor in determining the remnant left behind.
ProfRob
CC BY-SA 3.0
2017-07-16T11:38:11.633Z
"Type 1 supernova are not caused by the implosion of huge stars, but rather, a white dwarf (type 1a) or similar (1b, 1c), accumulating ever greater amounts of mass from a companion star until the Chandrasekhar limit for mass is reached." This is incorrect. Type Ib/c supernovae are thought to be caused by core collapse but in stars that have lost their hydrogen envelopes.
Warrick
CC BY-SA 3.0
2017-07-15T05:21:08.310Z
2017-07-16T20:58:59.873Z
2017-07-16T20:58:59.873Z
0tyranny0poverty
<p>A supernova is caused by the sudden (less than 1 second) collapse of the core of a massive (initially more than 8 solar masses in total) star. Less massive stars do not undergo core collapse and do not produce core-collapse supernovae.</p>

<p>The thing that determines whether a supernova remnant is a neutron star or black hole is largely the mass of the core at the onset of core collapse, but may also depend on how effectively the rest of the star is blown into space by the supernova explosion and how much material falls back onto the collapsed core.</p>

<p>If the collapsed core has a mass of less than about 2 solar masses (and perhaps up to 3, though there is no observational evidence for this), then the collapsed core, consisting mainly of neutrons, can be supported against its gravitational weight and stabilised as a "neutron star". The support is provided by neutron degeneracy pressure and the extreme repulsion between neutrons when they are squeezed together, which is caused by the strong nuclear force.</p>

<p>If the collapsed core is more massive, or if more material from the exploding star falls back onto the collapsed core, then even this strong nuclear repulsion will be unable to support its weight. In fact, above about 3 solar masses, General Relativity dictates that no force can possibly support the weight of the compact remnant and it will collapse further to become a black hole. No light (or anything else) can emerge from <em>inside</em> a black hole; so-called Hawking radiation will be negligible; so the only light received from such objects (after any supernova has faded), will be due to material being accreted into the black hole that is heated as it spirals towards it.</p>

<p>A third possibility exists, which is direct collapse to a black hole. It is possible that for very massive stars (at least 25-30 solar masses), that the collapsing core is never stabilised even as a proto neutron star, that no bright supernova is produced and that much of the mass of the star directly collapses into a black hole. This is a very active research topic since the discovery of 20-30 solar mass black holes by the LIGO gravitational wave experiment.</p>

<p>To summarise, I can do no better than quote from an excellent review paper by <a href="http://iopscience.iop.org/article/10.1086/307647/fulltext/" rel="noreferrer">Fryer (1999)</a>:
"Thus for core collapse models we can define three regimes of compact object formation: (1) low-mass, core-collapse stars drive strong explosions with little fallback and produce neutron stars; (2) moderate-mass stars produce explosions, but the fallback is sufficient to form black holes; and (3) high-mass stars are unable to launch shocks and collapse directly to black holes. The question for core-collapse theorists, then, is to determine the limits for these regimes.",
where the separation between these regimes is (1) $\geq 8$ up to perhaps 20 solar masses; (2) 20-40 solar masses and (3) more than about 30-40 solar masses, but these boundaries depend on metallicity, rotation and a correct understanding of supernova and neutrino physics.</p>

CC BY-SA 3.0
2017-07-15T09:43:00.303Z
At the time I asked the question, my understanding of Supernova was that it's actually a thing that exists in the universe like stars, planets, or comets. I understood with answers that Supernova are just the explosions we see that happen when a star collapses millions of years away. So yes you're right, my question makes no sense. I just wanted to clear the relationship between Supernova and Black hole. The only question that remains now is if Supernova are less than 1 second blasts, then how can we see them for extended periods of time which are more than 1 second.
GypsyCosmonaut
CC BY-SA 3.0
2017-07-15T11:08:30.977Z
The core collapse takes less than a second. The released (gravitational) potential energy then emerges in a variety of ways over seconds, hours, days and weeks.
ProfRob
CC BY-SA 3.0
2017-07-15T11:20:34.493Z
So it means that I would not be able to see the Supernova scientists discovered merely 2 years ago because it's light has already crossed beyond our planet in the universe?
GypsyCosmonaut
CC BY-SA 3.0
2017-07-15T12:05:24.460Z
What is the time scale for material from the exploding star falling back onto the collapsed core? Minutes? Days? Million of years?
Peter Mortensen
CC BY-SA 3.0
2017-07-15T12:48:52.610Z
@PeterMortensen That would depend where it started. Material just outside the core could fall back in seconds, but some of the material incorporated into a black hole could take hours to accrete..
ProfRob
CC BY-SA 3.0
2017-07-15T09:33:29.513Z
2017-07-15T12:49:10.167Z
2017-07-15T12:49:10.167Z
ProfRob
<p>Small stars do not collapse to become supernovae. Our Sun, which is a not quite a small star, will not become a supernova. It will eventually become a red giant, shrink a bit, become a red giant again, and eventually become a white dwarf. In its end life it will go through some upheavals which will be rather minor compared to a supernova. This is the fate for stars between 1/2 of a solar mass and 8 or so solar masses. Stars smaller than 1/2 of a solar mass die extremely slowly, never even becoming a red giant.</p>

<p>Only very large stars become supernova. The smaller ones leave neutron stars as remnants, the larger ones, black holes. A tiny fraction of the very largest stars are thought to bypass the supernova stage and directly collapse to become black holes. These <a href="https://en.wikipedia.org/wiki/Failed_supernova" rel="nofollow noreferrer">failed supernovae</a> form because those stars are so massive they collapse before they have consumed all of their fuel.</p>

CC BY-SA 3.0
2017-07-15T00:09:12.673Z
2017-07-15T00:09:12.673Z
David Hammen
<p>I understand that a star runs out of fuel slowly and gradually by fusing heavier and heavier particles (because of pressure by gravity) until the last heaviest particle is not able to fuse at the core of the star. This is where gravity takes over, and mass collapses (emitting gases out) to become a smaller dense star (with no energy left to give, just the gravity to absorb). </p>

<p>What I don't understand is why medium stars collapse to become a supernova which emits light while big stars collapse to form black holes which absorb all light.</p>

CC BY-SA 3.0
2017-07-14T23:36:08.157Z
I don't have a time for a full answer, hence comment. Small stars don't supernova at all, they fizzle out into a white dwarf. Medium-large stars supernova, with medium stars forming a neutron star at the end, and large ones forming a black hole. Supernova happens in both cases. Also, fusion might end because a star can't fuse the next heaviest atom, but it might end because it started fusing iron, which absorbs the energy from the productive fusion and causes the collapse into a supernova.
Cody
CC BY-SA 3.0
2017-07-14T23:48:45.393Z
Thank you for your time @Cody but what I didn't get from your answer was that why do these Supernova forming medium-big stars emit these beautiful light patterns while it's not the same case for big stars Black Hole Supernova which do not emit any light ?
GypsyCosmonaut
CC BY-SA 3.0
2017-07-14T23:51:35.440Z
The supernova forming a black hole does emit light.  In fact, a tremendous amount of it.  After the fact, when the supernova fades, the resulting BH doesn't emit light (although the accretion disk that may form around it will).  I hope someone who has time to find proper sources comes by soon, its a very complex topic.  Bottom line, I think your premise, that a BH forming supernova doesn't emit light, is false.
Cody
CC BY-SA 3.0
2017-07-15T09:08:20.783Z
Your question makes no sense. Black holes don't emit light because they are black. Both black holes and neutron stars are formed at the cores of supernova events. In some circumstances, collapse directly to a black hole, without a spectacular supernova may be possible. Is it the latter process you are asking about?
ProfRob
<black-hole><supernova>
Why do medium stars collapse to form supernovae while big stars collapse to form black holes?
GypsyCosmonaut
# Why do medium stars collapse to form supernovae while big stars collapse to form black holes?

(Asked by: username_0 on 2017-07-14)

I understand that a star runs out of fuel slowly and gradually by fusing heavier and heavier particles (because of pressure by gravity) until the last heaviest particle is not able to fuse at the core of the star. This is where gravity takes over, and mass collapses (emitting gases out) to become a smaller dense star (with no energy left to give, just the gravity to absorb).

What I don't understand is why medium stars collapse to become a supernova which emits light while big stars collapse to form black holes which absorb all light.

**Tags:** black-hole, supernova

> **Comments:**
> **username_1**: I don't have a time for a full answer, hence comment. Small stars don't supernova at all, they fizzle out into a white dwarf. Medium-large stars supernova, with medium stars forming a neutron star at the end, and large ones forming a black hole. Supernova happens in both cases. Also, fusion might end because a star can't fuse the next heaviest atom, but it might end because it started fusing iron, which absorbs the energy from the productive fusion and causes the collapse into a supernova.  
> **username_0**: Thank you for your time @username_1 but what I didn't get from your answer was that why do these Supernova forming medium-big stars emit these beautiful light patterns while it's not the same case for big stars Black Hole Supernova which do not emit any light ?  
> **username_1**: The supernova forming a black hole does emit light.  In fact, a tremendous amount of it.  After the fact, when the supernova fades, the resulting BH doesn't emit light (although the accretion disk that may form around it will).  I hope someone who has time to find proper sources comes by soon, its a very complex topic.  Bottom line, I think your premise, that a BH forming supernova doesn't emit light, is false.  
> **username_2**: Your question makes no sense. Black holes don't emit light because they are black. Both black holes and neutron stars are formed at the cores of supernova events. In some circumstances, collapse directly to a black hole, without a spectacular supernova may be possible. Is it the latter process you are asking about?  

---

## 3 answers

### Answer by username_3 on 2017-07-15. Score: 2 | Accepted answer

There are 2 main kinds of supernova.  The kind you are referring to is a type 2 supernova.  There are also type 1a, type 1b, and type 1c supernova.  Type 1a supernova are not caused by the implosion of huge stars, but rather, a white dwarf accumulating ever greater amounts of mass from a companion star until the Chandrasekhar limit for mass is reached.  Then we get the type 1a supernova, which leaves little core remnant and is more or less constant sized explosion with standard luminosity.  This is the reason type 1a supernova are used as standard candles to gauge the distance of objects in the universe.
As username_4's answer has pointed out, type 2 supernova endings occur only for stars that are more than 8x our sun's mass. Neutron stars and black holes are remnants left post-supernova, after the outer layers and majority of star has has blown off.  The size of the remnant is  predictable to an extent pre-supernova and depends on the mass of the star.  However this is only an approximation and there are always exceptions as the physics is complex and depends on too many variables. Type 1 supernovas leave little of no remnant.
Cause of Type 2 Supernova:
So what causes a dying star of said mass or greater to blow itself up to smitherines in such a way that more energy is released in the short span of the explosion that that of an entire galaxy for same time period.  This is in contrast to the much more docile, gradual, and protracted conclusion of stars whose mass is less than 8xSun;  planetary nebula after a red giant collapse and leaves white dwarf as remnant.
Massive Star Pre-Supernova(type 2) and implosion:
The core of a massive star will accumulate iron and heavier elements which are not exo-thermically fusible.  Iron is the end of the exothermic fusion chain. Any fusion to heavier nuclei will be endothermic.  Endothermic fusion absorbs energy from the surrounding layer causing it to cool down and condense around the core further.  This added inward pressure is in addition to the inward pressure of gravity and causes a gradient where the core continues to collapse and get denser while exothermic fusion maintains expansive outward pressure above the gradient.   
When the density of the inner core reaches a point where the pressure overcomes electron degeneration pressure.  Then another gradient is formed where inside the gradient atoms no longer exists because the electrons of the atoms will join their nucleus. The protons in the nucleus combine with the electrons to become neutrons, and release neutrinos.  There will be no more individual atoms inside of this gradient.  The sudden collapse inside the electron degeneration pressure gradient of the core triggers the initial supernova implosion as said core collapses in a few seconds to a tiny point object of nuclear density (3×1017 kg/m3) no bigger than Manhattan.
Supernova Explosion: 
The sudden in-rush of both the heavy element core outside the electron degeneration gradient, and the exotherimically fusible outer layers of the star cause immense heat and pressure in a few seconds period of time causing much of the lighter than iron elements to simultaneously fuse all at once.
**Anti-Matter:**

Also, the extremely dense and energetic neutrino flux would be rushing outward from the mentioned EDP core collapse.  When the neutrinos encounter head on the equally energetic atomic nuclei rushing  inwards the following occurs:
When a neutron absorbs a neutrino, antimatter is formed as neutrons become anti-protons and positrons.
When this Anti-Matter encounters normal matter, we have the most efficient and complete mass to energy conversion possible: 
Matter-AntiMatter Annihilation  (MAMA).
The combination of the simultaneous fusion and the MAMA causes all hell to break loose in the greatest release of energy in the shortest time, 2nd only to the gamma ray burst, known in the universe.
Remnant Post-Supernova:
What is left behind after most of the star has blown off is a solid extremely dense mass of neutrons around the size of Manhattan.  Thus the term neutron star.
There is nothing denser than a neutron star. (See note below) It is just pure mass with no empty space left. To get a perspective what we are taking about here, our normal atom on earth is almost all empty space. If we take the simplest atom which is hydrogen, and the nucleus (one proton) was scaled up to the size of a pea sized marble in the middle of a football stadium, the orbital of the single electron would extend all the way at the outer edge of the stadium, the electron no bigger than a grain of sand; almost all empty space.
Now just imagine a sphere of solid mass of such marbles filling the stadium with no space left. That is how we can picture the density of a neutron star, and it is the density limit of the universe. A black hole has this same density, just more massive.
"A neutron star is so dense that one teaspoon (5 milliliters) of its material would have a mass over 5.5×1012 kg (that is 1100 tonnes per 1 nanolitre), about 900 times the mass of the Great Pyramid of Giza."
With the density limit constant, a neutron star can only get larger, occupy a greater volume, as it gains more mass. The mass and surface area determine the escape velocity, the velocity needed for an object to escape the host's gravity from the surface. The immense gravity causes the smallest neutron star to have an escape velocity of 100,000 km/s, or one third of the speed of light.
When the mass of the neutron star surpasses the level at which the escape velocity for the neutron star exceeds the speed of light, then even light cannot escape its gravitation, thus becoming a black hole.
Note: There is theoretically a point where the gravity and density of a neutron star will reach a threshold called the neutron degeneracy pressure.  This was hypothesized by Tolman–Oppenheimer–Volkoff, and limit by same name.  This would result in greater density called baryonic density.  Then if we go denser, we can get quark density, and so on.  These are all speculative theories since the sub-nuclear interactions are not well understood, and we can't look inside a black hole to see the evidence.

> **Comments:**
> **username_0**: Cleared all my doubts, thanks to you and @username_1 for awesome answers  
> **username_4**: Re "There is nothing denser than a neutron star": The hypothetical [quark stars](https://en.wikipedia.org/wiki/Quark_star), if they exist, would be even denser.  
> **username_2**: Really lots of problematic statements here. The Chandrasekhar mass for an iron core is not 1.4 solar masses. The Pauli exclusion principle does not "break down". Your density for neutron star cores is too low, your number might be an average density. Generally speaking, if you add mass to a neutron star it gets smaller (quark stars might be an exception). Collapse to a black hole would occur well before the escape velocity became equal to the speed of light.  
> **username_3**: @RobJeffries  Corrected.  
> **username_2**: Partly. But your basic answer to the question is incorrect/incomplete, since you assert that the pre-supernova stellar mass is irrelevant, when in fact it is thought to be the dominant factor in determining the remnant left behind.  
> **username_5**: "Type 1 supernova are not caused by the implosion of huge stars, but rather, a white dwarf (type 1a) or similar (1b, 1c), accumulating ever greater amounts of mass from a companion star until the Chandrasekhar limit for mass is reached." This is incorrect. Type Ib/c supernovae are thought to be caused by core collapse but in stars that have lost their hydrogen envelopes.  

---

### Answer by username_2 on 2017-07-15. Score: 8

A supernova is caused by the sudden (less than 1 second) collapse of the core of a massive (initially more than 8 solar masses in total) star. Less massive stars do not undergo core collapse and do not produce core-collapse supernovae.

The thing that determines whether a supernova remnant is a neutron star or black hole is largely the mass of the core at the onset of core collapse, but may also depend on how effectively the rest of the star is blown into space by the supernova explosion and how much material falls back onto the collapsed core.

If the collapsed core has a mass of less than about 2 solar masses (and perhaps up to 3, though there is no observational evidence for this), then the collapsed core, consisting mainly of neutrons, can be supported against its gravitational weight and stabilised as a "neutron star". The support is provided by neutron degeneracy pressure and the extreme repulsion between neutrons when they are squeezed together, which is caused by the strong nuclear force.

If the collapsed core is more massive, or if more material from the exploding star falls back onto the collapsed core, then even this strong nuclear repulsion will be unable to support its weight. In fact, above about 3 solar masses, General Relativity dictates that no force can possibly support the weight of the compact remnant and it will collapse further to become a black hole. No light (or anything else) can emerge from *inside* a black hole; so-called Hawking radiation will be negligible; so the only light received from such objects (after any supernova has faded), will be due to material being accreted into the black hole that is heated as it spirals towards it.

A third possibility exists, which is direct collapse to a black hole. It is possible that for very massive stars (at least 25-30 solar masses), that the collapsing core is never stabilised even as a proto neutron star, that no bright supernova is produced and that much of the mass of the star directly collapses into a black hole. This is a very active research topic since the discovery of 20-30 solar mass black holes by the LIGO gravitational wave experiment.

To summarise, I can do no better than quote from an excellent review paper by [Fryer (1999)](http://iopscience.iop.org/article/10.1086/307647/fulltext/):
"Thus for core collapse models we can define three regimes of compact object formation: (1) low-mass, core-collapse stars drive strong explosions with little fallback and produce neutron stars; (2) moderate-mass stars produce explosions, but the fallback is sufficient to form black holes; and (3) high-mass stars are unable to launch shocks and collapse directly to black holes. The question for core-collapse theorists, then, is to determine the limits for these regimes.",
where the separation between these regimes is (1) $\geq 8$ up to perhaps 20 solar masses; (2) 20-40 solar masses and (3) more than about 30-40 solar masses, but these boundaries depend on metallicity, rotation and a correct understanding of supernova and neutrino physics.

> **Comments:**
> **username_0**: At the time I asked the question, my understanding of Supernova was that it's actually a thing that exists in the universe like stars, planets, or comets. I understood with answers that Supernova are just the explosions we see that happen when a star collapses millions of years away. So yes you're right, my question makes no sense. I just wanted to clear the relationship between Supernova and Black hole. The only question that remains now is if Supernova are less than 1 second blasts, then how can we see them for extended periods of time which are more than 1 second.  
> **username_2**: The core collapse takes less than a second. The released (gravitational) potential energy then emerges in a variety of ways over seconds, hours, days and weeks.  
> **username_0**: So it means that I would not be able to see the Supernova scientists discovered merely 2 years ago because it's light has already crossed beyond our planet in the universe?  
> **username_6**: What is the time scale for material from the exploding star falling back onto the collapsed core? Minutes? Days? Million of years?  
> **username_2**: @PeterMortensen That would depend where it started. Material just outside the core could fall back in seconds, but some of the material incorporated into a black hole could take hours to accrete..  

---

### Answer by username_4 on 2017-07-15. Score: 4

Small stars do not collapse to become supernovae. Our Sun, which is a not quite a small star, will not become a supernova. It will eventually become a red giant, shrink a bit, become a red giant again, and eventually become a white dwarf. In its end life it will go through some upheavals which will be rather minor compared to a supernova. This is the fate for stars between 1/2 of a solar mass and 8 or so solar masses. Stars smaller than 1/2 of a solar mass die extremely slowly, never even becoming a red giant.

Only very large stars become supernova. The smaller ones leave neutron stars as remnants, the larger ones, black holes. A tiny fraction of the very largest stars are thought to bypass the supernova stage and directly collapse to become black holes. These [failed supernovae](https://en.wikipedia.org/wiki/Failed_supernova) form because those stars are so massive they collapse before they have consumed all of their fuel.


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