<p>The equation for Doppler shifting towards the blue spectrum (i.e. when you are traveling towards it) is:</p>

<p>$\lambda_b = \lambda_c/(c + v_b)$</p>

<p>where $\lambda_b$ is the shifted wavelength, $\lambda_c$ is the original wavelength, $c$ is the speed of light and $v_b$ is your velocity towards the source.</p>

<p>BUT! When you get closer to the speed of light you need to go relativistic!  When moving closer to the speed of light you also need to take other effects into account like time dilation.  So we need to move to an equation that looks more like this:</p>

<p>$v_{ob} = v_{source}\times\sqrt{(1+B)/(1-B)}$</p>

<p>Where $v_{ob}$ is the observed wavelength, $v_{source}$ is the emitted source radiation and $B$ is your velocity/speed of light.</p>

<p>So lets say that someone is shining some UV light on us at about $4\times10^{-7}~\rm{m}$ and we want to see at what velocity this light is shifted into gamma i.e. about $1\times10^{-11}~\rm{m}$.  We can re-arange that formula to:</p>

<p>$B = [(\frac{v_o}{v_s})^2-1]/[(\frac{v_o}{v_s})^2+1]$</p>

<p>where $B$ will be a decimal of the speed of light.
The term $(v_o/v_s)^2$ is ridiculously small, we are talking magnitudes of $10^{-10}$.</p>

<p>Then when you add or subtract 1, you really dont move that far from 1. Just under 1/ just over 1 you get the answer that You have to be going ridiculously close to the speed of light for this to happen.  Like so ridiculously close MATLAB wont calculate the difference and just gives me the value of 1, i.e. the speed of light.</p>

<p>IN SUMMARY:</p>

<p>Yes but you have to be going so close to the speed of light it would be physically impossible.</p>

CC BY-SA 3.0
2014-07-30T09:18:33.487Z
2014-12-09T11:01:04.387Z
2014-12-09T11:01:04.387Z
James
<p>If a space ship travels at near the speed of light towards a star, wouldn't the light from the star doppler shift into gamma rays (or worse?) and become lethal to life and destructive to space ship structure?</p>

CC BY-SA 3.0
2014-07-20T15:17:46.947Z
Doppler shift will not actually make the spaceship emit Gamma rays. It's just a matter of reference frames.
Yashbhatt
CC BY-SA 3.0
2014-07-21T10:15:19.597Z
I think that going that fast you should be more worried about the atoms of hydrogen or helium and the grains of dust that you meet than about gamma rays.
Francesco Montesano
<light><speed><interstellar-travel>
Does near light-speed travel doppler-shift the light from the target into gamma rays?
LocalFluff
# Does near light-speed travel doppler-shift the light from the target into gamma rays?

(Asked by: username_0 on 2014-07-19)

If a space ship travels at near the speed of light towards a star, wouldn't the light from the star doppler shift into gamma rays (or worse?) and become lethal to life and destructive to space ship structure?

**Tags:** light, speed, interstellar-travel

> **Comments:**
> **username_1**: Doppler shift will not actually make the spaceship emit Gamma rays. It's just a matter of reference frames.  
> **username_2**: I think that going that fast you should be more worried about the atoms of hydrogen or helium and the grains of dust that you meet than about gamma rays.  

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## 1 answers

### Answer by username_3 on 2014-07-30. Score: 7 | Accepted answer

The equation for Doppler shifting towards the blue spectrum (i.e. when you are traveling towards it) is:

$\lambda\_b = \lambda\_c/(c + v\_b)$

where $\lambda\_b$ is the shifted wavelength, $\lambda\_c$ is the original wavelength, $c$ is the speed of light and $v\_b$ is your velocity towards the source.

BUT! When you get closer to the speed of light you need to go relativistic! When moving closer to the speed of light you also need to take other effects into account like time dilation. So we need to move to an equation that looks more like this:

$v\_{ob} = v\_{source}\times\sqrt{(1+B)/(1-B)}$

Where $v\_{ob}$ is the observed wavelength, $v\_{source}$ is the emitted source radiation and $B$ is your velocity/speed of light.

So lets say that someone is shining some UV light on us at about $4\times10^{-7}~\rm{m}$ and we want to see at what velocity this light is shifted into gamma i.e. about $1\times10^{-11}~\rm{m}$. We can re-arange that formula to:

$B = [(\frac{v\_o}{v\_s})^2-1]/[(\frac{v\_o}{v\_s})^2+1]$

where $B$ will be a decimal of the speed of light.
The term $(v\_o/v\_s)^2$ is ridiculously small, we are talking magnitudes of $10^{-10}$.

Then when you add or subtract 1, you really dont move that far from 1. Just under 1/ just over 1 you get the answer that You have to be going ridiculously close to the speed of light for this to happen. Like so ridiculously close MATLAB wont calculate the difference and just gives me the value of 1, i.e. the speed of light.

IN SUMMARY:

Yes but you have to be going so close to the speed of light it would be physically impossible.


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