<p>Yes, in an expanding universe there is an increase in potential energy (with same caveats).</p>

<p>The (Friedmann) equations of a homogeneous and isotropic universe with no spatial curvature or cosmological constant can, in fact, be derived very easily from nonrelativistic Newtonian gravity. (This derivation is shown, e.g., in Mukhanov's <em>Physical Foundations of Cosmology</em>.) So it is actually valid to think of such a cosmos in Newtonian terms, using randomly but approximately homogeneously distributed point masses. At early times, the point masses are flying apart at high speed but the average distance between them is small. At late times, they will have slowed down, but the average distance between them will have increased. All that kinetic energy is converted into gravitational potential energy. This also remains true if we take into account Newtonian perturbation theory (the growth of overdense and underdense regions from initial perturbations).</p>

<p>As for the caveats: First, as I mentioned above, when spatial curvature is present, the Newtonian solution is no longer valid. Second, there is a century of literature with a variety of attempts to define a meaningful stress-energy tensor for the gravitational field in general relativity, none completely satisfying. Last but not least, a cosmological constant/dark energy term adds its own interesting twist to the story, as its energy density remains constant in an expanding universe, causing the expansion to accelerate: in this case, both the kinetic and the potential energy increase, thanks to the role played by dark energy's negative pressure.</p>

CC BY-SA 3.0
2015-07-31T04:53:49.783Z
2015-07-31T04:53:49.783Z
Viktor Toth
<p>Not within general relativity.</p>

<p>Except in special circumstances, such as an asymptotically flat spacetime, there is no definable total energy in general relativity. The Friedmann–Roberston–Walker family of spacetimes that describe a homogeneous and isotropic universe are not an exception, although there's a separate argument that can be made for the case of spatially compact universes towards their total energy being exactly zero, no matter how they expand or contract.</p>

<p>For the matter distributions, gravitational potential can be useful in the weak-field limit of general relativity when the matter covers a finite region of space, but in general it's not present in general relativity. Or rather, the metric itself can be thought of as taking the role of a 'gravitational potential', but the way it does so is very different from the Newtonian theory.</p>

<p>A Newtonian cosmology having formally analogous behavior to the pressureless FRW cosmology with kinetic and potential terms can be done:
$$E = \frac{1}{2}\sum_k m_k\dot{r}_k^2 - G\sum_{j\neq k}\frac{m_jm_k}{|\mathbf{r}_j-\mathbf{r}_k|} - \frac{1}{6}\Lambda\sum_k m_kr_k^2\text{.}$$
However, this is incompatible with an infinite universe, and is neither homogeneous nor isotropic (being rather spherically symmetric with a distinguished center), and therefore violates the cosmological principle. That issue <em>can</em> be fixed by introducing a potential for the scale factor itself, but in that case interpreting it as the gravitational potential of the individual gravitating masses is problematic.</p>

CC BY-SA 3.0
2015-08-01T14:58:07.890Z
2015-08-01T14:58:07.890Z
Stan Liou
<p>Universe is <a href="http://darkmatterdarkenergy.com/tag/integrated-sachs-wolfe-effect/" rel="nofollow">picking up kinetic energy due to the expansion of space</a>: </p>

<blockquote>
  <p>A photon will gain energy (blueshift) when it heads into a supercluster on its way to the Earth. This is an effect of general relativity. And as it leaves the other side of the supercluster as it continues its journey, it will lose energy (redshift) as it climbs out of the gravitational potential well. But while it is passing through the supercluster, that structure is spreading out due to the Big Bang overall expansion, and its gravitational potential is weakening. So the redshift or energy loss is smaller than the original energy gain or blueshift. So net-net, photons gain energy passing through a supercluster.</p>
</blockquote>

<p>Potential energy on that scale, not so much.</p>

CC BY-SA 4.0
2022-04-03T17:42:00.863Z
but in the article you linked it says that "Now all of this is relative to the overall redshift that all photons experience as they travel from the Big Bang last scattering surface to the Earth. During each period that the universe doubles in size, the Big Bang radiation doubles in wavelength, or halves in temperature". @WayfaringStranger
vengaq
CC BY-SA 4.0
2022-04-03T17:42:09.190Z
Then, if this gain of energy is relative to the redshift, which increases with time, wouldn't that mean that even if photons can gain energy they will have less net energy over time? If all photons loose energy due to spacetime expansion, then isn't the universe loosing energy rather than picking up energy as you said? @WayfaringStranger
vengaq
CC BY-SA 3.0
2015-07-26T18:22:25.477Z
2015-07-26T18:22:25.477Z
Wayfaring Stranger
<p>A gravitationally or otherwise bound system does not expand together with the universe. The effect of the expansion is much too small to affect such systems. Our solar system had the same size as today a few billion years ago. Atoms have not changed their size either.</p>
<p>See <a href="https://en.wikipedia.org/wiki/Expansion_of_the_universe#Effects_of_expansion_on_small_scales" rel="nofollow noreferrer">Wikipedia</a> or <a href="https://arxiv.org/abs/gr-qc/0508052" rel="nofollow noreferrer">this paper</a></p>

CC BY-SA 4.0
2021-03-18T18:58:32.650Z
2021-03-18T18:58:32.650Z
Thomas
<p>A system with two massive bodies has potential energy proportional to their separation. Since the universe is expanding, is the potential (and total?) energy of such a system slowly increasing? What is the scale of this effect if it exists?</p>

<gravity><expansion>
Is expanding universe adding potential energy?
user7779
# Is expanding universe adding potential energy?

(Asked by: username_0 on 2015-07-26)

A system with two massive bodies has potential energy proportional to their separation. Since the universe is expanding, is the potential (and total?) energy of such a system slowly increasing? What is the scale of this effect if it exists?

**Tags:** gravity, expansion


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## 4 answers

### Answer by username_1 on 2015-07-31. Score: 3

Yes, in an expanding universe there is an increase in potential energy (with same caveats).

The (Friedmann) equations of a homogeneous and isotropic universe with no spatial curvature or cosmological constant can, in fact, be derived very easily from nonrelativistic Newtonian gravity. (This derivation is shown, e.g., in Mukhanov's *Physical Foundations of Cosmology*.) So it is actually valid to think of such a cosmos in Newtonian terms, using randomly but approximately homogeneously distributed point masses. At early times, the point masses are flying apart at high speed but the average distance between them is small. At late times, they will have slowed down, but the average distance between them will have increased. All that kinetic energy is converted into gravitational potential energy. This also remains true if we take into account Newtonian perturbation theory (the growth of overdense and underdense regions from initial perturbations).

As for the caveats: First, as I mentioned above, when spatial curvature is present, the Newtonian solution is no longer valid. Second, there is a century of literature with a variety of attempts to define a meaningful stress-energy tensor for the gravitational field in general relativity, none completely satisfying. Last but not least, a cosmological constant/dark energy term adds its own interesting twist to the story, as its energy density remains constant in an expanding universe, causing the expansion to accelerate: in this case, both the kinetic and the potential energy increase, thanks to the role played by dark energy's negative pressure.


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### Answer by username_2 on 2015-08-01. Score: 3

Not within general relativity.

Except in special circumstances, such as an asymptotically flat spacetime, there is no definable total energy in general relativity. The Friedmann–Roberston–Walker family of spacetimes that describe a homogeneous and isotropic universe are not an exception, although there's a separate argument that can be made for the case of spatially compact universes towards their total energy being exactly zero, no matter how they expand or contract.

For the matter distributions, gravitational potential can be useful in the weak-field limit of general relativity when the matter covers a finite region of space, but in general it's not present in general relativity. Or rather, the metric itself can be thought of as taking the role of a 'gravitational potential', but the way it does so is very different from the Newtonian theory.

A Newtonian cosmology having formally analogous behavior to the pressureless FRW cosmology with kinetic and potential terms can be done:
$$E = \frac{1}{2}\sum\_k m\_k\dot{r}\_k^2 - G\sum\_{j\neq k}\frac{m\_jm\_k}{|\mathbf{r}\_j-\mathbf{r}\_k|} - \frac{1}{6}\Lambda\sum\_k m\_kr\_k^2\text{.}$$
However, this is incompatible with an infinite universe, and is neither homogeneous nor isotropic (being rather spherically symmetric with a distinguished center), and therefore violates the cosmological principle. That issue *can* be fixed by introducing a potential for the scale factor itself, but in that case interpreting it as the gravitational potential of the individual gravitating masses is problematic.


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### Answer by username_3 on 2015-07-26. Score: 1

Universe is [picking up kinetic energy due to the expansion of space](http://darkmatterdarkenergy.com/tag/integrated-sachs-wolfe-effect/):

> A photon will gain energy (blueshift) when it heads into a supercluster on its way to the Earth. This is an effect of general relativity. And as it leaves the other side of the supercluster as it continues its journey, it will lose energy (redshift) as it climbs out of the gravitational potential well. But while it is passing through the supercluster, that structure is spreading out due to the Big Bang overall expansion, and its gravitational potential is weakening. So the redshift or energy loss is smaller than the original energy gain or blueshift. So net-net, photons gain energy passing through a supercluster.

Potential energy on that scale, not so much.

> **Comments:**
> **username_4**: but in the article you linked it says that "Now all of this is relative to the overall redshift that all photons experience as they travel from the Big Bang last scattering surface to the Earth. During each period that the universe doubles in size, the Big Bang radiation doubles in wavelength, or halves in temperature". @WayfaringStranger  
> **username_4**: Then, if this gain of energy is relative to the redshift, which increases with time, wouldn't that mean that even if photons can gain energy they will have less net energy over time? If all photons loose energy due to spacetime expansion, then isn't the universe loosing energy rather than picking up energy as you said? @WayfaringStranger  

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### Answer by username_5 on 2021-03-18. Score: 1

A gravitationally or otherwise bound system does not expand together with the universe. The effect of the expansion is much too small to affect such systems. Our solar system had the same size as today a few billion years ago. Atoms have not changed their size either.

See [Wikipedia](https://en.wikipedia.org/wiki/Expansion_of_the_universe#Effects_of_expansion_on_small_scales) or [this paper](https://arxiv.org/abs/gr-qc/0508052)


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