<p>First, to measure the angle accurately, you need a point of reference at approximately infinite distance. In astronomy, this is in the form of very distant stars; for your earthly example, perhaps it can be an even more distant building almost on the horizon.</p>
<p>Next, we look at the angular separation between the object with significant parallax, and the object at &quot;infinite&quot; distance, at two different observer locations. We assume the reference object doesn't move at all from our viewpoint as it is so far away. We look at the difference between these two angular separations to deduce the parallax angle.</p>
<p>The rest is just a bit of trigonometry: for the parallax angle <span class="math-container">$\theta$</span>, you can show easily that <span class="math-container">$\tan\theta = d/D$</span>, where <span class="math-container">$d$</span> is half of the distance between the two points at which we took the measurements, and <span class="math-container">$D$</span> is the distance to that building (or star) we are measuring the parallax of. From this, we can easily calculate <span class="math-container">$D$</span>.</p>
<p>Note that in astronomy the formula <span class="math-container">$D\approx 1/p$</span> is used instead, where <span class="math-container">$D$</span> is in parsecs and <span class="math-container">$p$</span> is in arcseconds. This simplification is because of the definition of the parsec together with the small angle approximation <span class="math-container">$\tan p \approx p$</span>.</p>

CC BY-SA 4.0
2021-06-03T05:40:47.770Z
Is it possible to use the angle from the north or some other reference to deduce separation?
Himanshu
CC BY-SA 4.0
2021-06-03T06:10:35.643Z
@YoungKindaichi Yup, that would be a possibility as well! In astronomy though, where we require ultra precise measurements, especially with telescopes not on the earth's surface (like Hubble Space Telescope), the method of comparing to distant stars has proven to be more reliable and precise. Otherwise, for "everyday" purposes like measuring distances to buildings, using the earth's magnetic field to find north and referencing that is good enough too.
YiFan
CC BY-SA 4.0
2021-06-03T06:13:32.610Z
@YoungKindaichi for the case of measuring stars, using north also presents another problem, which is it's dependent on the earth and it's relative positioning throughout its orbit. In particular its orbit precesses, has a certain axial tilt, is not perfectly circular, etc. which could make earthly references (like the magnetic north pole from which we deduce the direction of "north") a poor reference.
YiFan
CC BY-SA 4.0
2021-06-03T06:49:56.887Z
I got it. Thanks a lot
Himanshu
CC BY-SA 4.0
2021-06-03T05:27:46.190Z
2021-06-03T05:27:46.190Z
YiFan
<p>Surveyors do this in their sleep, and have been doing it for centuries. That has been a standard technique for mapmaking until at least the late 20th century (before laser rangefinders, satellites and GPS).</p>
<p>They typically use an instrument called a theodolite for this, which is basically a telescope with crosshairs/bullseye mounted on a leveling tripod, with vertical and horizontal precision angle scales. You might have seen theodolites around construction zones.</p>
<p>If they can, they’ll have an assistant hold a graduated staff(1) at the place they want to measure for extra precision. If they can’t, they will seek an easily distinguishable feature of the object/place.</p>
<p>Just like in astronomy, in order to make this type of measurement they need a reference landmark to measure the angles with precision. In astronomy we use very distant or “background” stars; in surveying they can use a staff on each of the observing spots as viewed from the other.</p>
<p>You start from one viewing spot, level the theodolite, aim it at the leveled staff placed at the other spot, and write down the angle on the horizontal scale. Then you “sweep” the theodolite until it points at the site of interest, and note the second horizontal angle measurement. Subtract the two and you have the angle at that corner. Notice that you don’t even have to align the theodolite with the North. Swap places with your staff, and repeat from the other viewing spot, and you have a second angle. With two angles and one known distance (between the two observing spots, you need to measure that too) you can use use trigonometry (compute the third angle and use the sine law) to calculate the distance to the site of interest. With the coordinates of both viewing spots you even have the full coordinates of the site.</p>
<p>If you can’t or don’t want to go back and forth for whatever reason, you could use a third object as a reference point. The reference object must be one for which you know the distance and location so you can adjust for the reference’s own parallax. The trigonometry is obviously more complicated. Or the reference must be so far away that its own parallax can be considered negligible (like it happens in astronomy with background stars)</p>
<p>Surveyors will often make several measurements from different locations, including previously known and accessible landmarks. These measurements are then chained together, for error correction.</p>
<p>(1) If you can get someone at the spot with a graduated staff, the fastest way to measure the distance is to compare the apparent size of the graduations through the scope against the graduated crosshairs (you must adjust for the vertical angle to the site; the staff is kept vertical with the help of a bubble level so you know the angle); this technique does not use parallax. But you usually can’t do this when surveying mountaintops for example. This might also be more demanding on the optics and I don’t know when it became feasible.</p>
<hr />
<p>(*) I studied basic surveying in college but it’s been decades. I might (probably) have some details wrong. Hopefully others can chime in if corrections are needed.</p>

CC BY-SA 4.0
2021-06-03T19:07:56.807Z
2021-06-04T23:46:20.703Z
2021-06-04T23:46:20.703Z
Euro Micelli
<p>Whenever someone starts telling about finding distances in astronomy, it all starts with a <a href="https://en.wikipedia.org/wiki/Stellar_parallax" rel="nofollow noreferrer">parallax</a>. The example they give is straightening your hand and see how your thumb changes its location while you switch your eyes from one to another. How does this work?</p>
<p><a href="https://i.sstatic.net/2jrB2.jpg" rel="nofollow noreferrer"><img src="https://i.sstatic.net/2jrB2.jpg" alt="Geometric sketch" /></a></p>
<p>What I don't understand: How can you practically in trivial cases (where parallax is significant and easily observable), can you use this to find distances?</p>
<p>For example, assume there is a tower which I can see from my roof: How can I find its distance using parallax? It's about <span class="math-container">$70-80$</span> meters from the roof so I think I can get significant parallax if I move across the roof but how to take that angle and how do I proceed then?</p>

<amateur-observing><distances><parallax>
How can I find the distance of the tower while standing at my roof?
Himanshu
# How can I find the distance of the tower while standing at my roof?

(Asked by: username_0 on 2021-06-03)

Whenever someone starts telling about finding distances in astronomy, it all starts with a [parallax](https://en.wikipedia.org/wiki/Stellar_parallax). The example they give is straightening your hand and see how your thumb changes its location while you switch your eyes from one to another. How does this work?

[![Geometric sketch](https://i.sstatic.net/2jrB2.jpg)](https://i.sstatic.net/2jrB2.jpg)

What I don't understand: How can you practically in trivial cases (where parallax is significant and easily observable), can you use this to find distances?

For example, assume there is a tower which I can see from my roof: How can I find its distance using parallax? It's about $70-80$ meters from the roof so I think I can get significant parallax if I move across the roof but how to take that angle and how do I proceed then?

**Tags:** amateur-observing, distances, parallax


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## 2 answers

### Answer by username_1 on 2021-06-03. Score: 4

First, to measure the angle accurately, you need a point of reference at approximately infinite distance. In astronomy, this is in the form of very distant stars; for your earthly example, perhaps it can be an even more distant building almost on the horizon.

Next, we look at the angular separation between the object with significant parallax, and the object at "infinite" distance, at two different observer locations. We assume the reference object doesn't move at all from our viewpoint as it is so far away. We look at the difference between these two angular separations to deduce the parallax angle.

The rest is just a bit of trigonometry: for the parallax angle $\theta$, you can show easily that $\tan\theta = d/D$, where $d$ is half of the distance between the two points at which we took the measurements, and $D$ is the distance to that building (or star) we are measuring the parallax of. From this, we can easily calculate $D$.

Note that in astronomy the formula $D\approx 1/p$ is used instead, where $D$ is in parsecs and $p$ is in arcseconds. This simplification is because of the definition of the parsec together with the small angle approximation $\tan p \approx p$.

> **Comments:**
> **username_0**: Is it possible to use the angle from the north or some other reference to deduce separation?  
> **username_1**: @YoungKindaichi Yup, that would be a possibility as well! In astronomy though, where we require ultra precise measurements, especially with telescopes not on the earth's surface (like Hubble Space Telescope), the method of comparing to distant stars has proven to be more reliable and precise. Otherwise, for "everyday" purposes like measuring distances to buildings, using the earth's magnetic field to find north and referencing that is good enough too.  
> **username_1**: @YoungKindaichi for the case of measuring stars, using north also presents another problem, which is it's dependent on the earth and it's relative positioning throughout its orbit. In particular its orbit precesses, has a certain axial tilt, is not perfectly circular, etc. which could make earthly references (like the magnetic north pole from which we deduce the direction of "north") a poor reference.  
> **username_0**: I got it. Thanks a lot  

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### Answer by username_2 on 2021-06-03. Score: 2

Surveyors do this in their sleep, and have been doing it for centuries. That has been a standard technique for mapmaking until at least the late 20th century (before laser rangefinders, satellites and GPS).

They typically use an instrument called a theodolite for this, which is basically a telescope with crosshairs/bullseye mounted on a leveling tripod, with vertical and horizontal precision angle scales. You might have seen theodolites around construction zones.

If they can, they’ll have an assistant hold a graduated staff(1) at the place they want to measure for extra precision. If they can’t, they will seek an easily distinguishable feature of the object/place.

Just like in astronomy, in order to make this type of measurement they need a reference landmark to measure the angles with precision. In astronomy we use very distant or “background” stars; in surveying they can use a staff on each of the observing spots as viewed from the other.

You start from one viewing spot, level the theodolite, aim it at the leveled staff placed at the other spot, and write down the angle on the horizontal scale. Then you “sweep” the theodolite until it points at the site of interest, and note the second horizontal angle measurement. Subtract the two and you have the angle at that corner. Notice that you don’t even have to align the theodolite with the North. Swap places with your staff, and repeat from the other viewing spot, and you have a second angle. With two angles and one known distance (between the two observing spots, you need to measure that too) you can use use trigonometry (compute the third angle and use the sine law) to calculate the distance to the site of interest. With the coordinates of both viewing spots you even have the full coordinates of the site.

If you can’t or don’t want to go back and forth for whatever reason, you could use a third object as a reference point. The reference object must be one for which you know the distance and location so you can adjust for the reference’s own parallax. The trigonometry is obviously more complicated. Or the reference must be so far away that its own parallax can be considered negligible (like it happens in astronomy with background stars)

Surveyors will often make several measurements from different locations, including previously known and accessible landmarks. These measurements are then chained together, for error correction.

(1) If you can get someone at the spot with a graduated staff, the fastest way to measure the distance is to compare the apparent size of the graduations through the scope against the graduated crosshairs (you must adjust for the vertical angle to the site; the staff is kept vertical with the help of a bubble level so you know the angle); this technique does not use parallax. But you usually can’t do this when surveying mountaintops for example. This might also be more demanding on the optics and I don’t know when it became feasible.

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(\*) I studied basic surveying in college but it’s been decades. I might (probably) have some details wrong. Hopefully others can chime in if corrections are needed.


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