<p>Yes and no. The question @JohnRennie links to in his comment  <a href="https://physics.stackexchange.com/questions/30261/analogy-between-magnetic-bottle-and-van-allens-radiation-belt">Analogy between magnetic bottle and Van Allen's radiation belt</a> contains a lot of relevant information, but packaged as an answer to this question.</p>

<p>The question correctly concludes that, at least in the plane perpendicular to the magnetic field, particles will travel in circles, and those circles will be in opposite directions, but they do not, generally simply circle around the Earth as you suggest. There are two reasons for this: firstly the magnetic fields are too strong, or the particles too light, so the circles you get are much smaller and secondly because they are also moving in the third direction. So you should think of them travelling in fairly tight spirals around the magnetic field lines, which, roughly speaking run between the North and South magnetic poles. </p>

<p>As they approach the poles, the field gets stronger (the lines bunch up) and it turns out that this repels the particles, so they end up bouncing back and forth between the two poles (all in spirals around the magnetic field lines).  The protons and electrons do spiral in opposite directions.</p>

CC BY-SA 4.0
2019-10-20T20:00:04.687Z
"turns out that this repels the particles" Why is that so?
SpaceCore
CC BY-SA 4.0
2019-10-20T20:30:49.653Z
Theres an answer at https://en.wikipedia.org/wiki/Magnetic_mirror#Mathematical_derivation but i don't have the time or the depth of knowledge to precis it. If someone does, feel free to edit my answer or add a supplementary
Steve Linton
CC BY-SA 4.0
2019-10-21T15:40:28.233Z
@SpaceBread Basically, charged particles are accelerated perpendicular to the mag field direction, so when field lines are nonparallel *and* the strength changes, the trajectory ends up being one of $\pi$ radians net curvature, more or less
Carl Witthoft
CC BY-SA 4.0
2019-10-20T19:23:07.787Z
2019-10-20T19:23:07.787Z
Steve Linton
<p>The Wikipedia Article on <a href="https://en.wikipedia.org/wiki/Van_Allen_radiation_belt" rel="nofollow noreferrer">Van Allen Radiation Belt</a> gives the following explanation:</p>

<blockquote>
  <p>A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetic field.</p>
</blockquote>

<p>The term "energetic charged particles" hinted to me that these charges are in motion and in very large velocities. </p>

<p>Let us assume, a small portion of space in the Van Allen Radiation Belt, compared to the size of Earth. We can assume the magnetic field in this space to be uniform due to our previous assumption. From the formula for finding <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/movchg.html" rel="nofollow noreferrer">Magnetic force on moving charges</a>, <span class="math-container">$$\vec{F}=q(\vec{v}\times\vec{B})$$</span> where <span class="math-container">$\vec{F}$</span> is the magnetic force on the charged particle, <span class="math-container">$q$</span> is the electric charge of the particle with an appropriate sign, <span class="math-container">$\vec{v}$</span> is the velocity vector and <span class="math-container">$\vec{B}$</span> is the magnetic field vector.</p>

<p>As per the above formula, the direction of force is dependant on the nature of charge as well as the direction given by the cross product. If we consider the charged particles to move with uniform speed, the net force acting on the charge must be equal to zero. I think we must neglect the gravitational force exerted by Earth on the charges since the mass of charges is negligible. The two forces, <a href="https://en.wikipedia.org/wiki/Centrifugal_force" rel="nofollow noreferrer">Centrifugal force</a> and the magnetic force (exerted by Earth's magnetic field due to the motion of the charged particles) cancel each other when they have the same magnitude but opposite direction. From the formula, it is also evident that the direction of force changes with the sign of the charge. It must be opposite for positive and negative charges. </p>

<p>So, based on this is it correct to assume, if the positive charges orbit the earth in one direction the negative charges orbit the earth in the opposite direction? Do they really orbit Earth in opposite directions?</p>

<p>The following image (a view from the top of poles of Earth) depicts my idea on the sense (clockwise or anticlockwise) of rotation of charges in the Van Allen Radiation Belt:</p>

<p><a href="https://i.sstatic.net/PmFNv.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/PmFNv.png" alt="enter image description here"></a></p>

<p>Image Source : My own work :)</p>

CC BY-SA 4.0
2019-10-20T10:52:19.560Z
See the question [Analogy between magnetic bottle and Van Allen's radiation belt](https://physics.stackexchange.com/questions/30261/analogy-between-magnetic-bottle-and-van-allens-radiation-belt) on the Physics SE for a related question.
John Rennie
CC BY-SA 4.0
2021-11-24T15:37:35.223Z
Useful and related:  https://physics.stackexchange.com/a/671288/59023
honeste_vivere
<radiation><solar-wind>
Do Electric Charges in the Van Allen Radiation belt move in Opposite Directions?
Vishnu
# Do Electric Charges in the Van Allen Radiation belt move in Opposite Directions?

(Asked by: username_0 on 2019-10-20)

The Wikipedia Article on [Van Allen Radiation Belt](https://en.wikipedia.org/wiki/Van_Allen_radiation_belt) gives the following explanation:

> A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetic field.

The term "energetic charged particles" hinted to me that these charges are in motion and in very large velocities.

Let us assume, a small portion of space in the Van Allen Radiation Belt, compared to the size of Earth. We can assume the magnetic field in this space to be uniform due to our previous assumption. From the formula for finding [Magnetic force on moving charges](http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/movchg.html), $$\vec{F}=q(\vec{v}\times\vec{B})$$ where $\vec{F}$ is the magnetic force on the charged particle, $q$ is the electric charge of the particle with an appropriate sign, $\vec{v}$ is the velocity vector and $\vec{B}$ is the magnetic field vector.

As per the above formula, the direction of force is dependant on the nature of charge as well as the direction given by the cross product. If we consider the charged particles to move with uniform speed, the net force acting on the charge must be equal to zero. I think we must neglect the gravitational force exerted by Earth on the charges since the mass of charges is negligible. The two forces, [Centrifugal force](https://en.wikipedia.org/wiki/Centrifugal_force) and the magnetic force (exerted by Earth's magnetic field due to the motion of the charged particles) cancel each other when they have the same magnitude but opposite direction. From the formula, it is also evident that the direction of force changes with the sign of the charge. It must be opposite for positive and negative charges.

So, based on this is it correct to assume, if the positive charges orbit the earth in one direction the negative charges orbit the earth in the opposite direction? Do they really orbit Earth in opposite directions?

The following image (a view from the top of poles of Earth) depicts my idea on the sense (clockwise or anticlockwise) of rotation of charges in the Van Allen Radiation Belt:

[![enter image description here](https://i.sstatic.net/PmFNv.png)](https://i.sstatic.net/PmFNv.png)

Image Source : My own work :)

**Tags:** radiation, solar-wind

> **Comments:**
> **username_1**: See the question [Analogy between magnetic bottle and Van Allen's radiation belt](https://physics.stackexchange.com/questions/30261/analogy-between-magnetic-bottle-and-van-allens-radiation-belt) on the Physics SE for a related question.  
> **username_2**: Useful and related:  https://physics.stackexchange.com/a/671288/59023  

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## 1 answers

### Answer by username_3 on 2019-10-20. Score: 4 | Accepted answer

Yes and no. The question @JohnRennie links to in his comment [Analogy between magnetic bottle and Van Allen's radiation belt](https://physics.stackexchange.com/questions/30261/analogy-between-magnetic-bottle-and-van-allens-radiation-belt) contains a lot of relevant information, but packaged as an answer to this question.

The question correctly concludes that, at least in the plane perpendicular to the magnetic field, particles will travel in circles, and those circles will be in opposite directions, but they do not, generally simply circle around the Earth as you suggest. There are two reasons for this: firstly the magnetic fields are too strong, or the particles too light, so the circles you get are much smaller and secondly because they are also moving in the third direction. So you should think of them travelling in fairly tight spirals around the magnetic field lines, which, roughly speaking run between the North and South magnetic poles.

As they approach the poles, the field gets stronger (the lines bunch up) and it turns out that this repels the particles, so they end up bouncing back and forth between the two poles (all in spirals around the magnetic field lines). The protons and electrons do spiral in opposite directions.

> **Comments:**
> **username_4**: "turns out that this repels the particles" Why is that so?  
> **username_3**: Theres an answer at https://en.wikipedia.org/wiki/Magnetic_mirror#Mathematical_derivation but i don't have the time or the depth of knowledge to precis it. If someone does, feel free to edit my answer or add a supplementary  
> **username_5**: @SpaceBread Basically, charged particles are accelerated perpendicular to the mag field direction, so when field lines are nonparallel *and* the strength changes, the trajectory ends up being one of $\pi$ radians net curvature, more or less  

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