<p>Certainly, the figure only uses different masses because that's the more general possibility (after all, the two masses won't be <em>exactly</em> the same).  In fact, if you look at the distribution over mass ratio q in binary systems in Figure 1b in <a href="https://arxiv.org/pdf/1304.3123.pdf" rel="noreferrer">https://arxiv.org/pdf/1304.3123.pdf</a>, it seems that the cumulative number of binaries with mass ratio less than q is more or less equal to q (where q is smaller mass over larger mass).  That means the probability of mass ratio between any q and q+dq is about equal to dq and nearly independent of q.  So the chance of the mass ratio being between 0.9 and 1 is about the same as being between 0 and 0.1, for example.  In some sense, that's like saying all q are equally likely.  And of course if q is near 1, then the stars will have the same age and be in the same evolutionary state, so will be the same stellar type as well.</p>

CC BY-SA 3.0
2018-04-21T05:25:32.963Z
2018-04-21T05:25:32.963Z
Ken G
<p>There are roughly 100 billion stars (quite probably more) in the Milky Way galaxy (ours).  Of those it is thought that about 85% of them are in multi-star systems (binary, triplet, etc.).  There are thought to be of the order of 10 <em>trillion</em> galaxies in the visible universe (for this I used <a href="https://www.space.com/26078-how-many-stars-are-there.html" rel="nofollow noreferrer">this article on Space.com</a>).</p>

<p>So something like $100\times 10^9 \times 10 \times 10^{12} = 10^{24}$ stars in the universe.</p>

<p>Let's says about half of the stars in multi-star systems are in binary systems (not triplets, etc.).  That gives us a (ludicrously rough) estimate of about $4\times 10^{23}$ binary systems in the universe.</p>

<p>Which brings us back to :</p>

<blockquote>
  <p>But what about binary orbits of two identical stars--like our sun orbiting another G-type main-sequence star? Is this sort of orbit possible?</p>
</blockquote>

<p>Given the huge number it's hard to imagine not one of those binary systems being, for all intents and purposes, near identical stars and even near identical G-type stars.</p>

<p>The only really similar stars in a binary system I'm personally aware of are <a href="https://en.wikipedia.org/wiki/Zeta_Ursae_Majoris#Stellar_system" rel="nofollow noreferrer">Mizar Aa and Mizar Ab</a>.  These are A-type stars, not G-type stars, but they illustrate the idea is possible.</p>

CC BY-SA 3.0
2018-04-22T04:46:28.440Z
2018-04-22T04:46:28.440Z
StephenG - Help Ukraine
<p><a href="https://i.sstatic.net/sFTx2.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/sFTx2.png" alt="enter image description here"></a></p>

<p>This is a simple, textbook definition of a binary star orbit.  One low-mass star orbits a higher-mass star in a narrow but definitive center.  For example, the high-mass star would be our own sun--a G-type main sequence star--being orbited by a smaller dwarf, like a red dwarf or a brown dwarf.  But what about binary orbits of two identical stars--like our sun orbiting another G-type main-sequence star?  Is this sort of orbit possible?</p>

CC BY-SA 3.0
2018-04-22T20:39:35.460Z
Alpha Centauri A and B are very similar to each other. They're slightly different spectral classes (G and K), but they're about 1.1 and 0.9 solar masses, respectively.
Keith Thompson
CC BY-SA 3.0
2018-04-23T08:08:51.663Z
So when we see Sirius as the brightest star this is in reality the two? @Keith Thompson
Alchimista
<star><orbit><binary-star><orbital-mechanics><celestial-mechanics>
Can Two Stars of One Same Type Orbit Each Other?
JohnWDailey
# Can Two Stars of One Same Type Orbit Each Other?

(Asked by: username_0 on 2018-04-21)

[![enter image description here](https://i.sstatic.net/sFTx2.png)](https://i.sstatic.net/sFTx2.png)

This is a simple, textbook definition of a binary star orbit. One low-mass star orbits a higher-mass star in a narrow but definitive center. For example, the high-mass star would be our own sun--a G-type main sequence star--being orbited by a smaller dwarf, like a red dwarf or a brown dwarf. But what about binary orbits of two identical stars--like our sun orbiting another G-type main-sequence star? Is this sort of orbit possible?

**Tags:** star, orbit, binary-star, orbital-mechanics, celestial-mechanics

> **Comments:**
> **username_1**: Alpha Centauri A and B are very similar to each other. They're slightly different spectral classes (G and K), but they're about 1.1 and 0.9 solar masses, respectively.  
> **username_2**: So when we see Sirius as the brightest star this is in reality the two? @username_1  

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## 2 answers

### Answer by username_3 on 2018-04-21. Score: 4

Certainly, the figure only uses different masses because that's the more general possibility (after all, the two masses won't be *exactly* the same). In fact, if you look at the distribution over mass ratio q in binary systems in Figure 1b in <https://arxiv.org/pdf/1304.3123.pdf>, it seems that the cumulative number of binaries with mass ratio less than q is more or less equal to q (where q is smaller mass over larger mass). That means the probability of mass ratio between any q and q+dq is about equal to dq and nearly independent of q. So the chance of the mass ratio being between 0.9 and 1 is about the same as being between 0 and 0.1, for example. In some sense, that's like saying all q are equally likely. And of course if q is near 1, then the stars will have the same age and be in the same evolutionary state, so will be the same stellar type as well.


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### Answer by username_4 on 2018-04-22. Score: 1

There are roughly 100 billion stars (quite probably more) in the Milky Way galaxy (ours). Of those it is thought that about 85% of them are in multi-star systems (binary, triplet, etc.). There are thought to be of the order of 10 *trillion* galaxies in the visible universe (for this I used [this article on Space.com](https://www.space.com/26078-how-many-stars-are-there.html)).

So something like $100\times 10^9 \times 10 \times 10^{12} = 10^{24}$ stars in the universe.

Let's says about half of the stars in multi-star systems are in binary systems (not triplets, etc.). That gives us a (ludicrously rough) estimate of about $4\times 10^{23}$ binary systems in the universe.

Which brings us back to :

> But what about binary orbits of two identical stars--like our sun orbiting another G-type main-sequence star? Is this sort of orbit possible?

Given the huge number it's hard to imagine not one of those binary systems being, for all intents and purposes, near identical stars and even near identical G-type stars.

The only really similar stars in a binary system I'm personally aware of are [Mizar Aa and Mizar Ab](https://en.wikipedia.org/wiki/Zeta_Ursae_Majoris#Stellar_system). These are A-type stars, not G-type stars, but they illustrate the idea is possible.


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