<p><a href="https://en.wikipedia.org/wiki/Brown_dwarf" rel="nofollow noreferrer">Brown dwarf 'stars'</a> are too small (13 to 80 Jupiter masses) to burn hydrogen, but burn (for awhile, there isn't much of the stuff available) deuterium.  Larger (over 65 Jupiter masses) brown dwarfs can also burn lithium.</p>

CC BY-SA 4.0
2021-08-24T22:51:06.937Z
2021-08-24T22:51:06.937Z
AlaskaRon
<p>For nuclear fusion to occur, there must be a certain temperature and pressure.  Generally for heavier elements, higher temperatures and pressures are needed, because the nuclei have a greater electric charge, and so more energy is needed to get them close enough together to fuse.</p>
<p>In the centre of a main sequence star there is hydrogen and helium. The energy released by the fusion of hydrogen prevents further collapse and so keeps the star from reaching the temperatures and pressures needed for helium fusion.</p>
<p>In a star like the Sun, as the amount of helium builds up, an inert core of helium forms, until (and if) it reaches the required temperature when it will start burning -- as the core has become degenerate matter at this point, the burning will increase the temperature without causing the core to expand and lower the pressure, so the core explodes. There can then be a period with shells of helium burning and hydrogen burning.  By this point the star has become an <a href="https://en.wikipedia.org/wiki/Asymptotic_giant_branch" rel="nofollow noreferrer">&quot;asymptotic red giant branch&quot;</a> star.</p>
<p>In stars heavier than the sun, the process can continue further with carbon, oxygen and heavier elements fusing.  However the extreme temperatures at which these processes occur mean that they don't last long, and the star will eventually become unstable and blow itself apart.</p>
<p>So, in main sequence stars it is not hot enough to fuse other elements.  In evolved giant stars it is hot enough, but it is so hot that the process doesn't last long.</p>

CC BY-SA 4.0
2021-08-24T14:52:37.453Z
seem to be missing a word in "without causing the core to and lower the pressure" (core to expand?)
llama
CC BY-SA 4.0
2021-08-24T23:24:08.693Z
Note to OP: the third paragraph of this answer is describing the Sun, or any star around solar mass. The details of the exact processes will differ for much more massive stars (which become supergiants) and much less massive stars (red dwarves).
YiFan
CC BY-SA 4.0
2021-08-25T12:41:56.027Z
_"don't last long"_ — long at what scale: human or star? Does it take less than a few earthly years or even days?
Ruslan
CC BY-SA 4.0
2021-08-25T12:53:45.460Z
There is an answer on that somewhere on here, the later stages in which there are shells of burning C, Ne, O, Si, Mg, Si can be very short:  days .   [what-is-the-length-of-time-for-each-fusion-process-in-a-massive-star](https://astronomy.stackexchange.com/questions/40412/what-is-the-length-of-time-for-each-fusion-process-in-a-massive-star)
James K
CC BY-SA 4.0
2021-08-25T18:13:53.210Z
`so the core explodes. There can then be a period with shells of helium burning and hydrogen burning.`  Wait, what?  I must have missed the part where our star will at some point have the core *explode* but then continue the fusion process.
Michael
CC BY-SA 4.0
2021-08-25T21:31:42.857Z
Yes that happens.  The inert helium core will become electron degenerate, Until such time as when the temperature/pressure is sufficient for triple alpha process, and then much of the helium will burn to carbon at once. It is called the "[Helium flash](https://en.wikipedia.org/wiki/Helium_flash)"  Once the thermal pressure exceeds degeneracy pressure, the core can expand, and this thermal expansion will absorb nearly all the energy of the flash, so there is little effect on the star at the surface.
James K
CC BY-SA 4.0
2021-08-24T08:00:56.773Z
2021-08-25T09:58:27.313Z
2021-08-25T09:58:27.313Z
James K
<p>Are there any stars that use any other elements as its fuel besides hydrogen? If not why not?</p>

CC BY-SA 4.0
2021-08-24T06:00:30.423Z
Certainly. See https://en.wikipedia.org/wiki/Stellar_nucleosynthesis But all stars start out burning hydrogen (well, deuterium) because it has the lowest fusion temperature. And of course, hydrogen & helium are far more abundant than any other element. See https://en.wikipedia.org/wiki/Abundance_of_the_chemical_elements
PM 2Ring
CC BY-SA 4.0
2021-08-24T10:25:36.837Z
You might be interested in this: https://astronomy.stackexchange.com/questions/28274/does-a-star-fuse-helium-to-beryllium-on-the-main-sequence
Nilay Ghosh
CC BY-SA 4.0
2021-08-25T19:08:27.397Z
That's where all those other elements _come from_, isn't it?
mattdm
<star>
Why nuclear fusion with hydrogen alone, why not with others?
Kavin Ishwaran
# Why nuclear fusion with hydrogen alone, why not with others?

(Asked by: username_0 on 2021-08-24)

Are there any stars that use any other elements as its fuel besides hydrogen? If not why not?

**Tags:** star

> **Comments:**
> **username_1**: Certainly. See https://en.wikipedia.org/wiki/Stellar_nucleosynthesis But all stars start out burning hydrogen (well, deuterium) because it has the lowest fusion temperature. And of course, hydrogen & helium are far more abundant than any other element. See https://en.wikipedia.org/wiki/Abundance_of_the_chemical_elements  
> **username_2**: You might be interested in this: https://astronomy.stackexchange.com/questions/28274/does-a-star-fuse-helium-to-beryllium-on-the-main-sequence  
> **username_3**: That's where all those other elements _come from_, isn't it?  

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## 2 answers

### Answer by username_5 on 2021-08-24. Score: 26 | Accepted answer

For nuclear fusion to occur, there must be a certain temperature and pressure. Generally for heavier elements, higher temperatures and pressures are needed, because the nuclei have a greater electric charge, and so more energy is needed to get them close enough together to fuse.

In the centre of a main sequence star there is hydrogen and helium. The energy released by the fusion of hydrogen prevents further collapse and so keeps the star from reaching the temperatures and pressures needed for helium fusion.

In a star like the Sun, as the amount of helium builds up, an inert core of helium forms, until (and if) it reaches the required temperature when it will start burning -- as the core has become degenerate matter at this point, the burning will increase the temperature without causing the core to expand and lower the pressure, so the core explodes. There can then be a period with shells of helium burning and hydrogen burning. By this point the star has become an ["asymptotic red giant branch"](https://en.wikipedia.org/wiki/Asymptotic_giant_branch) star.

In stars heavier than the sun, the process can continue further with carbon, oxygen and heavier elements fusing. However the extreme temperatures at which these processes occur mean that they don't last long, and the star will eventually become unstable and blow itself apart.

So, in main sequence stars it is not hot enough to fuse other elements. In evolved giant stars it is hot enough, but it is so hot that the process doesn't last long.

> **Comments:**
> **username_6**: seem to be missing a word in "without causing the core to and lower the pressure" (core to expand?)  
> **username_7**: Note to OP: the third paragraph of this answer is describing the Sun, or any star around solar mass. The details of the exact processes will differ for much more massive stars (which become supergiants) and much less massive stars (red dwarves).  
> **username_8**: _"don't last long"_ — long at what scale: human or star? Does it take less than a few earthly years or even days?  
> **username_5**: There is an answer on that somewhere on here, the later stages in which there are shells of burning C, Ne, O, Si, Mg, Si can be very short:  days .   [what-is-the-length-of-time-for-each-fusion-process-in-a-massive-star](https://astronomy.stackexchange.com/questions/40412/what-is-the-length-of-time-for-each-fusion-process-in-a-massive-star)  
> **username_9**: `so the core explodes. There can then be a period with shells of helium burning and hydrogen burning.`  Wait, what?  I must have missed the part where our star will at some point have the core *explode* but then continue the fusion process.  
> **username_5**: Yes that happens.  The inert helium core will become electron degenerate, Until such time as when the temperature/pressure is sufficient for triple alpha process, and then much of the helium will burn to carbon at once. It is called the "[Helium flash](https://en.wikipedia.org/wiki/Helium_flash)"  Once the thermal pressure exceeds degeneracy pressure, the core can expand, and this thermal expansion will absorb nearly all the energy of the flash, so there is little effect on the star at the surface.  

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### Answer by username_4 on 2021-08-24. Score: 2

[Brown dwarf 'stars'](https://en.wikipedia.org/wiki/Brown_dwarf) are too small (13 to 80 Jupiter masses) to burn hydrogen, but burn (for awhile, there isn't much of the stuff available) deuterium. Larger (over 65 Jupiter masses) brown dwarfs can also burn lithium.


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