<p>Can anyone check the logic of this proposed workflow and/or point me in the direction of a guide and example to check my work?</p>
<p>Proposed procedure to construct a spectral energy distribution and bolometric light curve of supernovae:</p>
<ol>
<li>Correct magnitude values for extinction (galactic and host)</li>
<li>Convert magnitude to flux</li>
<li>Plot flux against wavelength</li>
<li>Integrate the SED over the wavelength range as a Planck function</li>
</ol>

CC BY-SA 4.0
2021-08-28T05:13:32.963Z
I don't understand your last point. What do you mean by integrating the SED _as a Planck function_?
Prallax
CC BY-SA 4.0
2021-08-28T08:52:38.567Z
My understanding is that the SED needs to be integrated over the wavelength range to find the bolometric flux. Therefore, it should not be integrated as I said at all...

It should be integrated as FLambda dLambda over all wavelengths?
ames
CC BY-SA 4.0
2021-08-28T10:20:25.397Z
Yes, the bolometric flux is $F=\int F_\lambda d\lambda$
Prallax
<astrophysics><supernova><photometry><light-curve>
Procedure to construct a spectral energy distribution and bolometric light curve of supernovae?
ames
# Procedure to construct a spectral energy distribution and bolometric light curve of supernovae?

(Asked by: username_0 on 2021-08-27)

Can anyone check the logic of this proposed workflow and/or point me in the direction of a guide and example to check my work?

Proposed procedure to construct a spectral energy distribution and bolometric light curve of supernovae:

1. Correct magnitude values for extinction (galactic and host)
2. Convert magnitude to flux
3. Plot flux against wavelength
4. Integrate the SED over the wavelength range as a Planck function

**Tags:** astrophysics, supernova, photometry, light-curve

> **Comments:**
> **username_1**: I don't understand your last point. What do you mean by integrating the SED _as a Planck function_?  
> **username_0**: My understanding is that the SED needs to be integrated over the wavelength range to find the bolometric flux. Therefore, it should not be integrated as I said at all...  It should be integrated as FLambda dLambda over all wavelengths?  
> **username_1**: Yes, the bolometric flux is $F=\int F_\lambda d\lambda$  

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## 0 answers

