<p>It's the same, but not:</p>
<p>Disk-integrated is used when the object is not resolved. Disk-averaged photometry tries to obtain the same data as disk-integrated by averaging over spatially-resolved data.</p>
<p>The paper dedicates the whole paragraph §3.2 in explaining what they do when they say &quot;disk avaraged photometry&quot;: take the information from all pixels in the narrow view camera where the captured intensity exceeds a certain threshold and average the information (thus some tiny piece of information at the fringes is left-out). They do use some of the very same images to do disk-resolved photometry, taking into account rotation state, time and shape model.</p>
<p>They use disk-integrated photometry during the first stages of the approach when taking images with the wide-angle camera which are not yet over-exposed when still at a distance to 67/P.</p>

CC BY-SA 4.0
2021-08-30T07:06:17.223Z
2021-08-30T07:06:17.223Z
planetmaker
<p>I have already read <a href="https://astronomy.stackexchange.com/questions/41976/disk-integrated-vs-disk-resolved-what-is-the-difference">this question</a> about the difference between disk-integrated and disk-resolved photometry. But what exactly is the difference between disk-resolved and disk-averaged photometry?
I am referring to <a href="https://www.aanda.org/articles/aa/pdf/2015/11/aa25901-15.pdf" rel="nofollow noreferrer">tables 3 and 4 here</a>, where they show disk-averaged parameters for the hapke model and disk-resolved parameters.</p>
<p><strong>EDIT</strong>:
I understand that disk-resolved photometry has a higher resolution whereas disk-integrated is somehow averaged - but I do not understand what disk-averaged means - is it a synonym to disk-integrated?</p>

CC BY-SA 4.0
2021-08-29T16:23:16.503Z
Hi! What is exactly that you do not understand in the answer to the question you linked? If you edit this information into the question, someone that wants to answer it can go straight to the point
Prallax
CC BY-SA 4.0
2021-08-30T05:04:39.007Z
@Prallax Thanks, I edited the question.
lazerlini
<comets><photometry>
Disk-resolved vs disk-averaged photometry?
lazerlini
# Disk-resolved vs disk-averaged photometry?

(Asked by: username_0 on 2021-08-29)

I have already read [this question](https://astronomy.stackexchange.com/questions/41976/disk-integrated-vs-disk-resolved-what-is-the-difference) about the difference between disk-integrated and disk-resolved photometry. But what exactly is the difference between disk-resolved and disk-averaged photometry?
I am referring to [tables 3 and 4 here](https://www.aanda.org/articles/aa/pdf/2015/11/aa25901-15.pdf), where they show disk-averaged parameters for the hapke model and disk-resolved parameters.

**EDIT**:
I understand that disk-resolved photometry has a higher resolution whereas disk-integrated is somehow averaged - but I do not understand what disk-averaged means - is it a synonym to disk-integrated?

**Tags:** comets, photometry

> **Comments:**
> **username_1**: Hi! What is exactly that you do not understand in the answer to the question you linked? If you edit this information into the question, someone that wants to answer it can go straight to the point  
> **username_0**: @username_1 Thanks, I edited the question.  

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## 1 answers

### Answer by username_2 on 2021-08-30. Score: 3 | Accepted answer

It's the same, but not:

Disk-integrated is used when the object is not resolved. Disk-averaged photometry tries to obtain the same data as disk-integrated by averaging over spatially-resolved data.

The paper dedicates the whole paragraph §3.2 in explaining what they do when they say "disk avaraged photometry": take the information from all pixels in the narrow view camera where the captured intensity exceeds a certain threshold and average the information (thus some tiny piece of information at the fringes is left-out). They do use some of the very same images to do disk-resolved photometry, taking into account rotation state, time and shape model.

They use disk-integrated photometry during the first stages of the approach when taking images with the wide-angle camera which are not yet over-exposed when still at a distance to 67/P.


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