<p>The rate at which a clock ticks is a local property. There is no universal rate of time which could speed up, so the answer is no.</p>

<p>A clock stationary in the same frame of reference, and the same gravitational field as me will tick at the same rate, (one second every second) It is only clocks that are moving, or in different gravitational fields that that tick at a different rate. If I am falling into a black hole, and I stop the check the time, I wouldn't see my watch slow down.</p>

<p>So there is no standard clock rate. Clocks in the early universe (or at least things that depend on time, such as nuclear decay) ran at the same rate, in their local gravitational field (at one second per second)</p>

<p>If we were to observe a clock from the early universe, it would be receding at great velocity (and so it would be redshifted and time dilated) </p>

<p>Now, the gravitational time dilation does not depend on the amount of mass directly, but on the intensity of the gravitational field. A galaxy has huge mass, but the only place in which the gravitational field is significant (from a GR perspective) is in the neighbourhood of Neutron stars and black holes. </p>

<p>To get gravitational time dialtion you need an intense gravitational field. Just having a lot of mass is not enough. After the period of inflation, the universe was homogeneous, and there were no significant "lumps" to give a net gravitational field. As the gas in the universe collapsed into galaxies and stars, and eventually black holes regions of intense gravity formed, in which clocks would run slowly. </p>

<p>However there is no general speeding up of clocks in the universe.</p>

CC BY-SA 3.0
2015-11-23T19:07:11.020Z
2015-11-23T19:07:11.020Z
James K
<p>Gravitational time dilation applies to asymptotically flat static spacetimes, that is spacetime describing an isolated system in space, which is independent of time (does not change with time). The reason for this is that gravitational time dilation needs a stationary clock that is faraway from the gravitational influence of the system and the field must be static so that clocks can be stationary relative to the field.</p>

<p>The spacetime describing an expanding Universe is neither static nor asymptotically flat, so gravitational time dilation does not apply. Unfortunately we can't invoke an 'outside observer', the nearest thing to an "outside observer" in GR is a stationary observer faraway from an isolated system, which clearly cannot be invoked in this case.</p>

<p>As noted in the other question, when we look faraway we are also looking back in the past and the furthest, and therefore also furthest back in time, objects we see are red-shifted. When a clock is red-shifted it <em>appears</em> to run slower. We could define a new kind of time dilation based on this observation to say that clocks ran slower in the past, however this is not the standard way of looking at things (where we attribute red-shift as due to the expansion of space) and not a particularly useful way of looking at things either.</p>

CC BY-SA 3.0
2015-11-23T20:02:45.353Z
2015-11-23T20:02:45.353Z
John Davis
<p>Time moves more slowly near a mass than in relatively empty space.  For example, I get that an observer would see someone falling into a black hole to appear to move more slowly and get "stuck" on the event horizon, while the falling body would see the observer as aging more rapidly.</p>

<p>Additionally, an observer watching a passenger craft moving near the speed of light (high mass equivalent) might see a passenger who tripped falling in slow motion, because the forward momentum of the passenger + the speed of the craft must never exceed the speed of light, while the passenger would experience no effect of this time dilation, and would simply trip and fall.</p>

<p>Which brings me to my question...</p>

<p>Black holes, even supermassive black holes, are nowhere near the mass of the universe as a whole; so when the universe itself was much smaller and far more dense, then at a universal scale time itself would have progressed more "slowly" than it does today, and since the expansion of the universe is accelerating, doesn't it mean that time is also accelerating?</p>

<p>(Assuming, of course, there was some "outside" to observe this from).</p>

<p>This is not a duplicate of <a href="https://astronomy.stackexchange.com/questions/12401/does-time-slow-down-because-the-universe-is-expanding-at-an-accelerating-rate">Does time slow down because the universe is expanding at an accelerating rate?</a>.  That question and its answers seem more concerned with local, relativistic time (which is as malleable as space itself).  My question asks more about the effect across a universal scale as it relates to density of mass across that same universal scale.</p>

CC BY-SA 3.0
2015-11-23T08:24:49.170Z
Possible duplicate of [Does time slow down because the universe is expanding at an accelerating rate?](http://astronomy.stackexchange.com/questions/12401/does-time-slow-down-because-the-universe-is-expanding-at-an-accelerating-rate)
r2_d2
<universe><space-time><early-universe><time-dilation>
Is time itself speeding up universally?
M. Shawn Dillon
# Is time itself speeding up universally?

(Asked by: username_0 on 2015-11-23)

Time moves more slowly near a mass than in relatively empty space. For example, I get that an observer would see someone falling into a black hole to appear to move more slowly and get "stuck" on the event horizon, while the falling body would see the observer as aging more rapidly.

Additionally, an observer watching a passenger craft moving near the speed of light (high mass equivalent) might see a passenger who tripped falling in slow motion, because the forward momentum of the passenger + the speed of the craft must never exceed the speed of light, while the passenger would experience no effect of this time dilation, and would simply trip and fall.

Which brings me to my question...

Black holes, even supermassive black holes, are nowhere near the mass of the universe as a whole; so when the universe itself was much smaller and far more dense, then at a universal scale time itself would have progressed more "slowly" than it does today, and since the expansion of the universe is accelerating, doesn't it mean that time is also accelerating?

(Assuming, of course, there was some "outside" to observe this from).

This is not a duplicate of [Does time slow down because the universe is expanding at an accelerating rate?](https://astronomy.stackexchange.com/questions/12401/does-time-slow-down-because-the-universe-is-expanding-at-an-accelerating-rate). That question and its answers seem more concerned with local, relativistic time (which is as malleable as space itself). My question asks more about the effect across a universal scale as it relates to density of mass across that same universal scale.

**Tags:** universe, space-time, early-universe, time-dilation

> **Comments:**
> **username_1**: Possible duplicate of [Does time slow down because the universe is expanding at an accelerating rate?](http://astronomy.stackexchange.com/questions/12401/does-time-slow-down-because-the-universe-is-expanding-at-an-accelerating-rate)  

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## 2 answers

### Answer by username_2 on 2015-11-23. Score: 2

The rate at which a clock ticks is a local property. There is no universal rate of time which could speed up, so the answer is no.

A clock stationary in the same frame of reference, and the same gravitational field as me will tick at the same rate, (one second every second) It is only clocks that are moving, or in different gravitational fields that that tick at a different rate. If I am falling into a black hole, and I stop the check the time, I wouldn't see my watch slow down.

So there is no standard clock rate. Clocks in the early universe (or at least things that depend on time, such as nuclear decay) ran at the same rate, in their local gravitational field (at one second per second)

If we were to observe a clock from the early universe, it would be receding at great velocity (and so it would be redshifted and time dilated)

Now, the gravitational time dilation does not depend on the amount of mass directly, but on the intensity of the gravitational field. A galaxy has huge mass, but the only place in which the gravitational field is significant (from a GR perspective) is in the neighbourhood of Neutron stars and black holes.

To get gravitational time dialtion you need an intense gravitational field. Just having a lot of mass is not enough. After the period of inflation, the universe was homogeneous, and there were no significant "lumps" to give a net gravitational field. As the gas in the universe collapsed into galaxies and stars, and eventually black holes regions of intense gravity formed, in which clocks would run slowly.

However there is no general speeding up of clocks in the universe.


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### Answer by username_3 on 2015-11-23. Score: 1

Gravitational time dilation applies to asymptotically flat static spacetimes, that is spacetime describing an isolated system in space, which is independent of time (does not change with time). The reason for this is that gravitational time dilation needs a stationary clock that is faraway from the gravitational influence of the system and the field must be static so that clocks can be stationary relative to the field.

The spacetime describing an expanding Universe is neither static nor asymptotically flat, so gravitational time dilation does not apply. Unfortunately we can't invoke an 'outside observer', the nearest thing to an "outside observer" in GR is a stationary observer faraway from an isolated system, which clearly cannot be invoked in this case.

As noted in the other question, when we look faraway we are also looking back in the past and the furthest, and therefore also furthest back in time, objects we see are red-shifted. When a clock is red-shifted it *appears* to run slower. We could define a new kind of time dilation based on this observation to say that clocks ran slower in the past, however this is not the standard way of looking at things (where we attribute red-shift as due to the expansion of space) and not a particularly useful way of looking at things either.


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