<p>There's two different effects here, and they're both related to viscuous forces in the accreting matter.</p>

<p>First, if the infalling matter has some nonzero angular momentum vector $\mathbf{L}$, then consider a plane perpendicular to this vector. Due to its conservation, we can't get rid of rotation along this plane, but the component of angular momentum orthogonal to the plane is zero. As the accreting matter heats up and radiates away energy, that energy is taken from the gravitational potential, which is lessened by bringing the matter particles closer together. Thus, such interactions tend to flatten the matter into the plane orthogonal to its angular momentum.</p>

<p>But there's something more that happens for rotating black holes, as a combination of its gravitomagnetic field and viscous forces in the matter, that drives the matter to the plane of the black hole's rotation, regardless of its initial angular momentum. This is called the <em>Bardeen–Petterson effect</em> <sup>[1]</sup>:</p>

<blockquote>
  <p>In an accretion disk, viscosity causes each ring of gas to spiral inward toward the hole with a radial speed $|u^r|\ll\text{(orbital velocity)} = (M/r)^{1/2}$. If this were the only effect of viscosity, the warping of the disk would consist of a differential precession. Successive rings, each of smaller radius than the preceding, would have interacting longer with the [gravitomagnetic] field and thus would have precessed through successively larger angles... . As a result the disk would be radially twisted, but it would not be driven into the equatorial plane. However, the precession changes the disk's shear $\sigma_{jk}$ and thus changes the viscous forces; and these altered forces drive the disk toward the equatorial plane of the black hole.</p>
</blockquote>

<p>This is only significant closer to the black hole, at $r\lesssim 100M$. At larger radii, the disk shape is due to the direction of the angular momentum of the matter instead.</p>

<hr>

<p><sub>[1] <em>Black Holes: The Membrane Paradigm</em>, ed. by Kip S. Thorne, Richard H. Price, and Douglas A. Macdonald.</sub></p>

CC BY-SA 3.0
2014-12-17T16:47:47.197Z
2014-12-17T16:47:47.197Z
Stan Liou
<p>So, the theory (briefly) about accretion disks is that stuff falling into the black hole will most likely not fall straight into it but will miss it and go into orbit, perhaps for a long time, perhaps for a short time, before finally falling in.  That makes sense.</p>

<p>But, why disks?  Wouldn't the matter falling into the BH be coming from all directions, and thus fall into orbits in all planes around the BH, not just one?  Or, is it that once there's a hint of "plane preference" in the debris, this will tend to be self-reinforcing, and anything subsequently falling into orbit around the BH will hit something in the disk, and so end up (perhaps after many collisions) being swept around in the disk as well?</p>

CC BY-SA 3.0
2014-12-18T09:55:52.007Z
aha - physics.  I did search before posting but just on astronomy.  thanks!
Max Williams
CC BY-SA 3.0
2014-12-17T18:59:16.643Z
loads of good answers on Physics SE e.g. http://physics.stackexchange.com/questions/73964/accretion-disk-physics-stellar-formation  http://physics.stackexchange.com/questions/8502/why-do-all-the-planets-of-the-solar-system-orbit-in-roughly-the-same-2d-plane
ProfRob
<black-hole><accretion-discs>
Accretion disks - why are they disk-shaped, rather than spherical?
Max Williams
# Accretion disks - why are they disk-shaped, rather than spherical?

(Asked by: username_0 on 2014-12-17)

So, the theory (briefly) about accretion disks is that stuff falling into the black hole will most likely not fall straight into it but will miss it and go into orbit, perhaps for a long time, perhaps for a short time, before finally falling in. That makes sense.

But, why disks? Wouldn't the matter falling into the BH be coming from all directions, and thus fall into orbits in all planes around the BH, not just one? Or, is it that once there's a hint of "plane preference" in the debris, this will tend to be self-reinforcing, and anything subsequently falling into orbit around the BH will hit something in the disk, and so end up (perhaps after many collisions) being swept around in the disk as well?

**Tags:** black-hole, accretion-discs

> **Comments:**
> **username_1**: loads of good answers on Physics SE e.g. http://physics.stackexchange.com/questions/73964/accretion-disk-physics-stellar-formation  http://physics.stackexchange.com/questions/8502/why-do-all-the-planets-of-the-solar-system-orbit-in-roughly-the-same-2d-plane  
> **username_0**: aha - physics.  I did search before posting but just on astronomy.  thanks!  

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## 1 answers

### Answer by username_2 on 2014-12-17. Score: 5 | Accepted answer

There's two different effects here, and they're both related to viscuous forces in the accreting matter.

First, if the infalling matter has some nonzero angular momentum vector $\mathbf{L}$, then consider a plane perpendicular to this vector. Due to its conservation, we can't get rid of rotation along this plane, but the component of angular momentum orthogonal to the plane is zero. As the accreting matter heats up and radiates away energy, that energy is taken from the gravitational potential, which is lessened by bringing the matter particles closer together. Thus, such interactions tend to flatten the matter into the plane orthogonal to its angular momentum.

But there's something more that happens for rotating black holes, as a combination of its gravitomagnetic field and viscous forces in the matter, that drives the matter to the plane of the black hole's rotation, regardless of its initial angular momentum. This is called the *Bardeen–Petterson effect* [1]:

> In an accretion disk, viscosity causes each ring of gas to spiral inward toward the hole with a radial speed $|u^r|\ll\text{(orbital velocity)} = (M/r)^{1/2}$. If this were the only effect of viscosity, the warping of the disk would consist of a differential precession. Successive rings, each of smaller radius than the preceding, would have interacting longer with the [gravitomagnetic] field and thus would have precessed through successively larger angles... . As a result the disk would be radially twisted, but it would not be driven into the equatorial plane. However, the precession changes the disk's shear $\sigma\_{jk}$ and thus changes the viscous forces; and these altered forces drive the disk toward the equatorial plane of the black hole.

This is only significant closer to the black hole, at $r\lesssim 100M$. At larger radii, the disk shape is due to the direction of the angular momentum of the matter instead.

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[1] *Black Holes: The Membrane Paradigm*, ed. by Kip S. Thorne, Richard H. Price, and Douglas A. Macdonald.


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