<p><em>Note that the Sun here is point-like and there is no refraction.</em></p>
<h2 id="what-have-i-done-wrong">What have I done wrong?</h2>
<p>Your supposition that the altitude of the Sun is directly related to the length of the day is wrong. Proof with counterexample: observe the altitude of the Sun on the equator and in the Moscow on the equinox; but still, the lengths are the same.</p>
<hr />
<h2 id="and-what-is-the-correct-way-of-dealing-with-it">And what is the correct way of dealing with it?</h2>
<p>My images have helped to many people, I hope they will help you as well:</p>
<p><a href="https://i.sstatic.net/XBtK5.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/XBtK5.png" alt="Figure 1" /></a>
<em>where the first arabic number corresponds to the day of the month and the second roman number is the month (I for January, II for February ...)</em></p>
<p>Note that the altitude of the Sun on the June 21 is really larger in Tula than in Moscow, but the length of the Sun's trajectory across the sky in Tula is smaller than in Moscow. <em>So, this is a short graphical solution.</em></p>
<h2 id="but-astronomers-always-want-the-numerical-solutions">But astronomers always want the numerical solutions</h2>
<p>so here you have it: Such length is the so called <em>hour angle</em> <span class="math-container">$H$</span>, which is the angular distance between the celestial meridian and the setting Sun <a href="http://slittlefair.staff.shef.ac.uk/teaching/phy115/session3/page7/page7.html" rel="nofollow noreferrer">[derivation]</a>. The equation is</p>
<p><span class="math-container">$$\cos H=-\tan\delta\tan\phi$$</span>
where <span class="math-container">$\delta$</span> is the declination of Sun on date and <span class="math-container">$\phi$</span> is the latitude. So, with quick calculations for June 21 (<span class="math-container">$\delta=23.5°$</span>),</p>
<ul>
<li><span class="math-container">$H_{Tula}=127.1°$</span></li>
<li><span class="math-container">$H_{Moscow}=128.9°$</span></li>
</ul>
<p>So, really, the hour angle in Moscow is larger, which corresponds to longer day.</p>
<hr />
<h2 id="what-about-december-21">What about December 21?</h2>
<p>You can easily calculate it as well using <span class="math-container">$\delta=-23.5°$</span>.</p>

CC BY-SA 4.0
2021-07-14T05:58:24.073Z
I believe that 21 is the day and VI is month, so 21.VI means the 21 of June.
ALiCe P.
CC BY-SA 4.0
2021-07-14T12:34:31.730Z
@uhoh Oh, sorry, I edited it. (That's how it is shorted in central part of Europe.)
User123
CC BY-SA 4.0
2021-07-13T17:55:32.053Z
2021-07-14T12:36:45.313Z
2021-07-14T12:36:45.313Z
User123
<p>I'm trying to solve this task:</p>
<blockquote>
<p>Tula and Moscow are located on the same meridian. In which city length of the day is bigger on 22 of June? 22 of December?</p>
</blockquote>
<p>I was thinking like that: we need to calculate the height of the sun above the horizon and where it will be bigger there the length of a day is bigger. The formula of height is:</p>
<p><span class="math-container">$$\text{h = 90 - latitude + declination}.$$</span></p>
<p>On 22 June the declination of Sun is maximum and equals 23,5. Latitude of Tula - 54,2 , latitude of Moscow - 55,3. It seems like in Tula the height of the Sun is bigger than in Moscow, so bigger is the length of the day. But in reality it is the opposite. The further from equator a city is located the bigger the length of the day in this city.</p>
<p>Could you please tell me where am I wrong and how to solve this task correctly?</p>

CC BY-SA 4.0
2021-07-13T09:32:04.410Z
the premise that the max height of the sun determines the length of the day is wrong. On 21Mar all Earth has the same day length, but only in the equator the sun in Zenith.
d_e
CC BY-SA 4.0
2021-07-13T14:21:31.120Z
@d_e That is not true because the length of day is defined as the interval between when the top of the Sun first appears above the horizon and when the top of the Sun finally disappears below the horizon. An extreme example is the South Pole, where it takes several 24 hour days for the Sun to rise around September 22, and later it takes several 24 hour days for the Sun to set around March 21.
David Hammen
CC BY-SA 4.0
2021-07-13T14:36:01.417Z
@DavidHammen, I agree with you. Not sure what is the *that* that "is not true"? Other than that, my comment might not be 100% accurate, but basically it is, I think, and demonstrate that the length of the day is not a function of the max height of the sun in the that day, when comparing different locations.
d_e
<the-sun><orbital-mechanics><mathematics><solstice>
Confusion when calculating the length of the day
ALiCe P.
# Confusion when calculating the length of the day

(Asked by: username_0 on 2021-07-13)

I'm trying to solve this task:

> Tula and Moscow are located on the same meridian. In which city length of the day is bigger on 22 of June? 22 of December?

I was thinking like that: we need to calculate the height of the sun above the horizon and where it will be bigger there the length of a day is bigger. The formula of height is:

$$\text{h = 90 - latitude + declination}.$$

On 22 June the declination of Sun is maximum and equals 23,5. Latitude of Tula - 54,2 , latitude of Moscow - 55,3. It seems like in Tula the height of the Sun is bigger than in Moscow, so bigger is the length of the day. But in reality it is the opposite. The further from equator a city is located the bigger the length of the day in this city.

Could you please tell me where am I wrong and how to solve this task correctly?

**Tags:** the-sun, orbital-mechanics, mathematics, solstice

> **Comments:**
> **username_1**: the premise that the max height of the sun determines the length of the day is wrong. On 21Mar all Earth has the same day length, but only in the equator the sun in Zenith.  
> **username_2**: @username_1 That is not true because the length of day is defined as the interval between when the top of the Sun first appears above the horizon and when the top of the Sun finally disappears below the horizon. An extreme example is the South Pole, where it takes several 24 hour days for the Sun to rise around September 22, and later it takes several 24 hour days for the Sun to set around March 21.  
> **username_1**: @username_2, I agree with you. Not sure what is the *that* that "is not true"? Other than that, my comment might not be 100% accurate, but basically it is, I think, and demonstrate that the length of the day is not a function of the max height of the sun in the that day, when comparing different locations.  

---

## 1 answers

### Answer by username_3 on 2021-07-13. Score: 6 | Accepted answer

*Note that the Sun here is point-like and there is no refraction.*

## What have I done wrong?

Your supposition that the altitude of the Sun is directly related to the length of the day is wrong. Proof with counterexample: observe the altitude of the Sun on the equator and in the Moscow on the equinox; but still, the lengths are the same.

---

## And what is the correct way of dealing with it?

My images have helped to many people, I hope they will help you as well:

[![Figure 1](https://i.sstatic.net/XBtK5.png)](https://i.sstatic.net/XBtK5.png)
*where the first arabic number corresponds to the day of the month and the second roman number is the month (I for January, II for February ...)*

Note that the altitude of the Sun on the June 21 is really larger in Tula than in Moscow, but the length of the Sun's trajectory across the sky in Tula is smaller than in Moscow. *So, this is a short graphical solution.*

## But astronomers always want the numerical solutions

so here you have it: Such length is the so called *hour angle* $H$, which is the angular distance between the celestial meridian and the setting Sun [[derivation]](http://slittlefair.staff.shef.ac.uk/teaching/phy115/session3/page7/page7.html). The equation is

$$\cos H=-\tan\delta\tan\phi$$
where $\delta$ is the declination of Sun on date and $\phi$ is the latitude. So, with quick calculations for June 21 ($\delta=23.5°$),

* $H\_{Tula}=127.1°$
* $H\_{Moscow}=128.9°$

So, really, the hour angle in Moscow is larger, which corresponds to longer day.

---

## What about December 21?

You can easily calculate it as well using $\delta=-23.5°$.

> **Comments:**
> **username_0**: I believe that 21 is the day and VI is month, so 21.VI means the 21 of June.  
> **username_3**: @uhoh Oh, sorry, I edited it. (That's how it is shorted in central part of Europe.)  

---

