<p>To prevent star trailing, there are two different methods in general use. One is the <strong>500 Rule</strong> which can be done in your head, or quickly with a calculator.  The other is the <strong>NPF</strong> rule which is more accurate, but generally requires a program on hand, but many can be found with a simple search.</p>
<p><strong>500 Rule</strong></p>
<p><span class="math-container">$$
t=\frac{500}{f}
$$</span></p>
<p><span class="math-container">$ t $</span> is the time in seconds of the exposure, and <span class="math-container">$ f $</span> is the focal length of the telescope/lens.  It is common for other numbers such as 600 or 400 to be used.  This is just a general rule of thumb, and results will vary depending on the resolution the final result will be displayed at.</p>
<p><strong>NPF Rule</strong>
<span class="math-container">$$
t=k \frac{16.9N + 0.1f + 13.7p}{f \cos\delta}
$$</span></p>
<p><span class="math-container">$ t $</span> is the exposure time in seconds, <span class="math-container">$k$</span> is the acceptable number of pixels of trailing, <span class="math-container">$N$</span> is the focal ratio (f-stop), <span class="math-container">$f$</span> is the focal length (in mm), <span class="math-container">$p$</span> is the pixel size (in microns), and <span class="math-container">$\delta$</span> is the declination of the object/area.</p>
<p>To compute <span class="math-container">$p$</span>, you will need to look up the size of your sensor and it's resolution.  Then compute <span class="math-container">$ p = \frac{sensor\ width\ in\ microns}{image\ width\ in\ pixels} $</span></p>
<p>For a wide angle image, use the declination closest to the celestial equator within the field of view.</p>

CC BY-SA 4.0
2022-10-09T19:12:26.790Z
Is focal length f in mm? Seems reasonable that a scope with a 1000 mm focal length would require exposures less than 0.5 seconds.
JohnHoltz
CC BY-SA 4.0
2022-10-09T21:37:52.873Z
@JohnHoltz indeed, have you ever look through a telescope with a decent amount of magnification and no tracking? Stuff moves quite fast; exposures may need to be even shorter than that.
uhoh
CC BY-SA 4.0
2022-10-09T22:00:37.100Z
@JohnHoltz, yes it is in mm, I put the units in the description of each variable under the equation.
Greg Miller
CC BY-SA 4.0
2022-10-09T15:46:52.607Z
2022-10-09T15:46:52.607Z
Greg Miller
<blockquote>
<p>Motorized scopes don't have this problem...</p>
</blockquote>
<p>Not necessarily!</p>
<p>Depending on the type of mount, they might have the second order problem of field rotation. For properly aligned <a href="https://en.wikipedia.org/wiki/Equatorial_mount" rel="nofollow noreferrer">equatorial mounts</a> the telescope tube is also rotated about its axis when it is rotated around the polar axis of the mount, so for example north is always pointing in the same direction at the focal plane of your camera.</p>
<p>For telescopes on <a href="https://en.wikipedia.org/wiki/Altazimuth_mount" rel="nofollow noreferrer">alt-az or &quot;azimuth&quot; mounts</a> this doesn't happen, so on the scale of hours any object that's not in the center of the field of view of a properly aligned telescope will execute a circular arc around the center of the exposed field.</p>
<blockquote>
<p>What is the optimal exposure time for photography with an unmotorized telescope?</p>
</blockquote>
<p>It depends on what you define as &quot;exposure time&quot;. There's total integrated time used to produce your image which can be quite long, and your frame rate, how frequently you dump one &quot;exposure&quot; to memory and start recording a new one, for later recombination into a single final image.</p>
<p>Most astrophotography both pro and amateur relies on the latter technique to avoid overexposing bright objects in the field that might only need a few seconds or minutes to saturate, while still capturing dim objects.</p>
<p>Saturation can cause some CCDs to produce other artifacts in other areas of the frame, so you really do want to avoid it.</p>
<p><strong>So if you don't have tracking</strong>, you may need to make your frame rate of the order of one per second or even less, depending on the scale and resolution. I think <strong>other answers here will go into more detail</strong> on that, or at least link to other questions and answers here that already address this.</p>
<p><strong>Note:</strong> Once you are making many shorter exposures, you can then pause to move your object back to keep them near the center of the field at regular intervals. The software you use to combine images will do the realignment as long as there is not appreciable <a href="https://en.wikipedia.org/wiki/Distortion_(optics)" rel="nofollow noreferrer">field distortion</a>. If there is, then you'll need to work harder to keep your object centered, or include a complicated model for it in your image-combining software.</p>
<p>Modern DLSRs, astrophotography cameras and even some cell phone models will have ways to program regular frame dumps for image accumulation.</p>
<p>There are numerous programs you can buy or get for free to reassemble those images into a single final image. These automatically align all of your exposures before adding them, and have features to lower the resulting noise.</p>

CC BY-SA 4.0
2022-10-09T03:02:46.340Z
2022-10-09T03:32:27.337Z
2022-10-09T03:32:27.337Z
uhoh
<p>Since celestial objects move along the sky, taking long exposure shots with an unmotorized telescope will show a straight or slightly curved line of light instead of the still object (<a href="https://en.wikipedia.org/wiki/Star_trail" rel="nofollow noreferrer">star trail</a>).</p>
<p>Motorized scopes don't have this problem because they can be set to follow the rotation of the earth or objects in the sky. Unmotorized scopes can't do this, so long exposures are not practical. What is the optimal exposure time for photography with an unmotorized telescope?</p>

<photography>
Optimal exposure time for photography with unmotorized telescope
chowder
# Optimal exposure time for photography with unmotorized telescope

(Asked by: username_0 on 2022-10-09)

Since celestial objects move along the sky, taking long exposure shots with an unmotorized telescope will show a straight or slightly curved line of light instead of the still object ([star trail](https://en.wikipedia.org/wiki/Star_trail)).

Motorized scopes don't have this problem because they can be set to follow the rotation of the earth or objects in the sky. Unmotorized scopes can't do this, so long exposures are not practical. What is the optimal exposure time for photography with an unmotorized telescope?

**Tags:** photography


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## 2 answers

### Answer by username_1 on 2022-10-09. Score: 3 | Accepted answer

To prevent star trailing, there are two different methods in general use. One is the **500 Rule** which can be done in your head, or quickly with a calculator. The other is the **NPF** rule which is more accurate, but generally requires a program on hand, but many can be found with a simple search.

**500 Rule**

$$
t=\frac{500}{f}
$$

$ t $ is the time in seconds of the exposure, and $ f $ is the focal length of the telescope/lens. It is common for other numbers such as 600 or 400 to be used. This is just a general rule of thumb, and results will vary depending on the resolution the final result will be displayed at.

**NPF Rule**
$$
t=k \frac{16.9N + 0.1f + 13.7p}{f \cos\delta}
$$

$ t $ is the exposure time in seconds, $k$ is the acceptable number of pixels of trailing, $N$ is the focal ratio (f-stop), $f$ is the focal length (in mm), $p$ is the pixel size (in microns), and $\delta$ is the declination of the object/area.

To compute $p$, you will need to look up the size of your sensor and it's resolution. Then compute $ p = \frac{sensor\ width\ in\ microns}{image\ width\ in\ pixels} $

For a wide angle image, use the declination closest to the celestial equator within the field of view.

> **Comments:**
> **username_2**: Is focal length f in mm? Seems reasonable that a scope with a 1000 mm focal length would require exposures less than 0.5 seconds.  
> **username_3**: @username_2 indeed, have you ever look through a telescope with a decent amount of magnification and no tracking? Stuff moves quite fast; exposures may need to be even shorter than that.  
> **username_1**: @username_2, yes it is in mm, I put the units in the description of each variable under the equation.  

---

### Answer by username_3 on 2022-10-09. Score: 3

> Motorized scopes don't have this problem...

Not necessarily!

Depending on the type of mount, they might have the second order problem of field rotation. For properly aligned [equatorial mounts](https://en.wikipedia.org/wiki/Equatorial_mount) the telescope tube is also rotated about its axis when it is rotated around the polar axis of the mount, so for example north is always pointing in the same direction at the focal plane of your camera.

For telescopes on [alt-az or "azimuth" mounts](https://en.wikipedia.org/wiki/Altazimuth_mount) this doesn't happen, so on the scale of hours any object that's not in the center of the field of view of a properly aligned telescope will execute a circular arc around the center of the exposed field.

> What is the optimal exposure time for photography with an unmotorized telescope?

It depends on what you define as "exposure time". There's total integrated time used to produce your image which can be quite long, and your frame rate, how frequently you dump one "exposure" to memory and start recording a new one, for later recombination into a single final image.

Most astrophotography both pro and amateur relies on the latter technique to avoid overexposing bright objects in the field that might only need a few seconds or minutes to saturate, while still capturing dim objects.

Saturation can cause some CCDs to produce other artifacts in other areas of the frame, so you really do want to avoid it.

**So if you don't have tracking**, you may need to make your frame rate of the order of one per second or even less, depending on the scale and resolution. I think **other answers here will go into more detail** on that, or at least link to other questions and answers here that already address this.

**Note:** Once you are making many shorter exposures, you can then pause to move your object back to keep them near the center of the field at regular intervals. The software you use to combine images will do the realignment as long as there is not appreciable [field distortion](https://en.wikipedia.org/wiki/Distortion_(optics)). If there is, then you'll need to work harder to keep your object centered, or include a complicated model for it in your image-combining software.

Modern DLSRs, astrophotography cameras and even some cell phone models will have ways to program regular frame dumps for image accumulation.

There are numerous programs you can buy or get for free to reassemble those images into a single final image. These automatically align all of your exposures before adding them, and have features to lower the resulting noise.


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