<p>The main thing is Signal to Noise ratio and also a bit of statistical stuff. It increases the SNR (Signal to Noise Ratio) which is of course good. It also provides noise averaging on similar note. Since noise is generally random, squared visibility allows to remove a significant portion of it. Going to the statistical side, you can assume a Guassian distribution and therefore simplify noise treatment. Squared visibility lets you have a larger brightness range by getting all the intensities and also is more accurate. Additionally, its easier to fix astromephric issues, systematic errors, or instrumental effects.</p>

CC BY-SA 4.0
2023-06-20T08:00:20.443Z
Thank you very much. Could you please add some examples or equations that demonstrate this to your answer? I cannot exactly imagine that.
Elena Greg
CC BY-SA 4.0
2023-06-22T12:05:27.270Z
What that are you refering too @ElenaGreg
Starship
CC BY-SA 4.0
2023-06-22T14:39:59.763Z
I meant how exactly squared visibility allows to remove a significant portion of noise, please?
Anna-Kat
CC BY-SA 4.0
2023-06-19T15:19:07.360Z
2023-06-19T15:19:07.360Z
Starship
<p>Why is preffered to use squared visibility instead of visibility in long-baseline interferometry, please?</p>

<interferometry>
Squared visibility in astronomy
Elena Greg
# Squared visibility in astronomy

(Asked by: username_0 on 2023-06-19)

Why is preffered to use squared visibility instead of visibility in long-baseline interferometry, please?

**Tags:** interferometry


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## 1 answers

### Answer by username_1 on 2023-06-19. Score: 1

The main thing is Signal to Noise ratio and also a bit of statistical stuff. It increases the SNR (Signal to Noise Ratio) which is of course good. It also provides noise averaging on similar note. Since noise is generally random, squared visibility allows to remove a significant portion of it. Going to the statistical side, you can assume a Guassian distribution and therefore simplify noise treatment. Squared visibility lets you have a larger brightness range by getting all the intensities and also is more accurate. Additionally, its easier to fix astromephric issues, systematic errors, or instrumental effects.

> **Comments:**
> **username_0**: Thank you very much. Could you please add some examples or equations that demonstrate this to your answer? I cannot exactly imagine that.  
> **username_1**: What that are you refering too @username_0  
> **username_2**: I meant how exactly squared visibility allows to remove a significant portion of noise, please?  

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