<p>In general, you are weightless unless an electromagnetic force acts on you. (What we call &quot;contact&quot; with other matter like air or the ground is electromagnetic interaction of electron hulls. That is the reason you had to assume a vacuum in your question. An electrostatically or magnetically levitated body on Earth would also feel weight.)</p>
<p>That is more obvious and expected when you are far away from planets and stars, &quot;floating in space&quot;; even though there is still lots of gravity around from galaxies and stars, we would not feel it and would not perceive any motion with our bare senses due to the large distance of any reference points.</p>
<p>But it is no less true in close proximity to Earth, for example on the ISS (tidal forces due to an inhomogeneous gravitational field which pulls on some parts more than others aside). In both cases — far away or close by — you follow a <a href="https://en.wikipedia.org/wiki/Geodesics_in_general_relativity" rel="nofollow noreferrer">geodesic</a>, the equivalent of a straight line in curved spacetime. The line is &quot;straight&quot; because no forces act on you (and the gravitation is modeled as spacetime curvature).</p>
<p>In a way, this inverts the notion of &quot;acceleration&quot; because one could argue that one is &quot;unperturbed&quot; when following a geodesic; by contrast, when we stand on Earth, the ground constantly pushes us &quot;out of our natural way&quot;, accelerates us, if you want. That is the meaning of Einstein's elevator <em>Gedankenexperiment</em>. Inside a black box like the elevator you feel (and are, in the relativistic sense) accelerated when you stand still but feel (and are, in the relativistic sense) standing still when you free-fall in what appears an accelerated motion to an outside observer.</p>

CC BY-SA 4.0
2024-01-11T04:01:10.750Z
Good answer, but it's important to distinguish between spatial curvature and spacetime curvature. https://physics.stackexchange.com/a/587025/123208
PM 2Ring
CC BY-SA 4.0
2024-01-11T08:18:27.303Z
@PM2Ring And there is no space without time, so...
Peter - Reinstate Monica
CC BY-SA 4.0
2024-01-11T02:37:03.600Z
2024-01-12T08:41:00.280Z
2024-01-12T08:41:00.280Z
Peter - Reinstate Monica
<p>Any speed. If you free fall then you feel weightless. That begins at zero speed, when you start falling, and ends when you hit something at arbitrarily high speed.</p>

CC BY-SA 4.0
2024-01-12T13:40:26.817Z
If you're going fast enough sideways, you can keep missing the planet despite gravity accelerating you towards it, avoiding the sudden stop at the end.  (This is a fun way to describe orbiting.  How fast?  https://what-if.xkcd.com/58/ covers low orbit.)
Peter Cordes
CC BY-SA 4.0
2024-01-11T16:47:29.087Z
2024-01-11T16:47:29.087Z
ProfRob
<p>There isn't any velocity where the object would be &quot;weightless&quot;.</p>
<p>A simple example is riding in a lift/elevator, at the start and end of the lift's journey you experience a moment of increased and reduced gravity while accelerating and decelerating compared to the direction of gravity but during the middle when the lift is at a constant velocity you experience the same 1g as someone on the ground.</p>

CC BY-SA 4.0
2024-01-12T09:42:18.247Z
2024-01-12T09:42:18.247Z
Alex Dawn
<p>Weightlessness isn't something you experience when you're falling by yourself. The fact that you're falling means that gravity is pulling you down, and that's due to your weight. Instead, you feel weightless when you're falling at the same rate as whatever container you're in.</p>
<p>If you were in an airplane and its wings fell off, it would start falling. But air resistance would limit it to some terminal velocity, so it won't fall as fast as gravity is trying to accelerate the plane and its passengers. So you would still experience some upward force from the floor and seat, and wouldn't be weightless.</p>
<p>You may feel almost weightless when you ride a roller coaster. The designer should minimize the friction of the wheels, so you accelerate at near 1G during the big drop.</p>
<p>To experience weightlessness, the Vomit Comet uses a powered nosedive to accelerate down at the same rate as gravity. And a roller coaster could make you feel this by powering the car at high speed rather than just allowing it to drop down the track; it might even go faster than gravity would have accelerated it, and you'll experience <em>negative</em> weight -- you'll feel a push against the belt or bar that's holding you in your seat.</p>
<p>In these cases you notice the weightlessness because there's nothing keeping you pressed against the floor of the aircraft or car. Your fall due to gravity is the same as the descent of the container, so you can float freely relative to it.</p>

CC BY-SA 4.0
2024-01-12T21:08:31.973Z
(slightly more than) half of the 0g time in a parabolic flight is on the ascending path of the parabola. Going down is by no means a prerequisite for weigthlessness (yet another very common misconception).
planetmaker
CC BY-SA 4.0
2024-01-12T21:14:20.127Z
Good point. When the plane's upward velocity slows down at the same rate as gravity, the passenger's upward velocity reduces at the same rate due to gravity.
Barmar
CC BY-SA 4.0
2024-01-11T16:08:03.877Z
2024-01-11T16:08:03.877Z
Barmar
<p>~8km/s as close to Earth as practical, less when higher.</p>
<p>This is how orbital motion works. It is essentially a freefall, so in orbit you feel weightless.</p>
<p>But the essence is not the speed. It is the acceleration. See the other answers.</p>

CC BY-SA 4.0
2024-01-12T08:44:48.800Z
When the trajectory is straight you'll feel just normal gravity. Speed is not only not the essence: It is irrelevant.
Peter - Reinstate Monica
CC BY-SA 4.0
2024-01-11T16:38:41.970Z
2024-01-11T16:38:41.970Z
fraxinus
<p>There's no speed at which you experience weightlessness; to stay weightless, you need to keep getting faster and faster all the time.</p>
<p>From our perspective on Earth, everything accelerates downward at about 9.8<span class="math-container">$\frac{m}{s^2}$</span> (<span class="math-container">$32\frac{ft}{s^2}$</span>). Weightlessness is what happens when you're accelerating at exactly that rate, whether it's because you jumped off a rock or you're in orbit (which is just falling while moving forward fast enough to keep missing the planet). As long as you're accelerating downward as fast as gravity will let you, you're in freefall and experience weightlessness.</p>
<p>That's pretty difficult, though. A skydiver starts out in freefall, and they feel weightless for a few seconds, but the wind resistance (or &quot;drag&quot;) on their body quickly grows, reducing their acceleration and increasing their apparent weight until they're eventually not accelerating at all. We call that &quot;terminal velocity&quot;, and it's usually around 53 meters per second (120 miles per hour) in the spread-eagle position. At that point they're not weightless anymore; their body is experiencing the same weight as if they were laying face-down on a bed, just with a lot more wind.</p>
<p>There are ways to make it work, though. The famous &quot;Vomit Comet&quot; aircraft are designed to fly in an arc that lets them maintain that perfect acceleration for a short period despite the drag trying to slow them down, and inside the cabin, the passengers can float around as if they're weightless. (The name comes from the fact that weightlessness often makes people feel sick at first, as their body isn't used to that feeling lasting for an extended time.)</p>
<p>If there were no air and you were to bring yourself to a perfect stop many miles above the surface, you'd be weightless all the way down, getting faster and faster without limit until you hit the ground at some incredible speed and left quite a crater behind.</p>

CC BY-SA 4.0
2024-01-10T22:32:20.503Z
Thank you Darth. This clears up my misconceptions. The light bulb went off as soon as I read your second paragraph. I appreciate you all.
Sedumjoy
CC BY-SA 4.0
2024-01-10T23:46:48.133Z
The'vomit comet'offers about 20s of zero gravity per parabola. Been there, done that. For minutes you need either a supersonic jet or a sub-orbital  sounding rocket which reaches heights of about 300km. (100km usually is called the border to space, the iss is at 400km)
planetmaker
CC BY-SA 4.0
2024-01-10T23:53:53.407Z
See also https://www.airzerog.com/scientific-research-services/
planetmaker
CC BY-SA 4.0
2024-01-11T03:54:18.140Z
If you fell to an airless Earth from a height of 100 km, you'd land with a speed of ~1400 m/s ~= 5000 km/h
PM 2Ring
CC BY-SA 4.0
2024-01-11T17:17:52.123Z
@planetmaker: That's the commercial parabolic flights.  NASA's aircraft (the original 'Vomit Comet') sometimes did substantially longer parabolas, but still under a minute.
Ben Voigt
CC BY-SA 4.0
2024-01-11T17:31:21.797Z
@BenVoigt you can do the math: the flight capability's of NASA's 747 or ESA's A-310 (and that's what I linked to) are quite comparable. The flight maneuver lasts about one minute, but the zero-g time is about 20...25 seconds. One can stretch it to maybe 30 seconds if you manage to gain a few km/h on horizontal cruise speed and start with a speed a bit closer to sound speed which allows to point the nose of the airplane more than 48° into the sky at the start of the 0g phase. But a minute is not possible with a commercial airliner; if you disagree, please do show me the math or a credible link.
planetmaker
CC BY-SA 4.0
2024-01-11T17:38:29.637Z
https://en.wikipedia.org/wiki/Reduced-gravity_aircraft also states for NASA's zero-g plane "This aircraft is used to train astronauts in zero-g maneuvers, giving them about 25 seconds of weightlessness out of 65 seconds of flight in each parabola." - thus the same.
planetmaker
CC BY-SA 4.0
2024-01-11T17:44:22.510Z
@planetmaker: I didn't say a minute was possible, in fact I said "still under a minute".  I worked with a team that did many "zero-G" experiments on these craft, and I do remember that NASA discontinuing their service in favor of the commercial offering caused some major problems because it reduced the freefall time. I'm fuzzy on the exact numbers. 25 seconds sounds like the routine parabolas, and I think by special arrangement they'd do somewhere in the 32-35 range. Made a huge difference when the experiment was "can you do CPR in zero-G?" since seconds are wasted just to get into position.
Ben Voigt
CC BY-SA 4.0
2024-01-11T17:51:19.543Z
One can "stretch" it by not flying 0g but 'cheat' a little bit without jeopardizing the result of such medical experiments overly, e.g. by flying 0.05g or 0.1g or similar. The quality of µg is anyway "only" around 0.01g rms IIRC, and 0.001g on good days / flights. The duration of each parabola in the flight with lunar (0.16g) and marsian (0.35g) parabolas was considerably longer. But evidently 20...25 seconds already suffized for people to practise stitching wounds.
planetmaker
CC BY-SA 4.0
2024-01-11T18:53:27.907Z
"to stay weightless, you need to keep getting faster and faster all the time" is probably not the best wording. A more careful wording would be "to stay weightless, your speed needs to keep changing all the time." After all, the ISS isn't constantly increasing its speed, it's just constantly changing its velocity by moving in a circle (due to the influence of gravity).
zephyr
CC BY-SA 4.0
2024-01-12T00:27:53.780Z
@zephyr There's a point where communicating clearly is more important than being precisely accurate. "Lies to children". Since the question is talking about falling towards the ground, it's easier to say that you have to get faster rather than try to explain orbital mechanics to somebody who's still struggling with the basics.
Darth Pseudonym
CC BY-SA 4.0
2024-01-12T00:29:09.597Z
@planetmaker I changed it to just say 'for a short time'.  I think I was misremembering the length of each cycle as the length of the weightless period.
Darth Pseudonym
CC BY-SA 4.0
2024-01-12T13:34:48.453Z
@zephyr: In a circular orbit, your velocity is changing but your speed isn't, so if you're trying to avoid technically inaccurate statements while keeping the language simple, that doesn't work either.  Perhaps "Your acceleration towards the Earth needs to be about 9.8m/s^2, matching the local gravity field, but you can start out going upwards, or you can be going so fast sideways you continuously miss the planet (orbit)."  Not great, the layman interpretation of "accelerate toward" includes already moving towards, and a speed that's increasing.
Peter Cordes
CC BY-SA 4.0
2024-01-12T13:43:52.363Z
(At orbital altitudes, gravity is a bit weaker, about 90% the surface strength at ISS altitudes: https://what-if.xkcd.com/58/)
Peter Cordes
CC BY-SA 4.0
2024-01-10T21:37:47.537Z
2024-01-12T19:19:08.423Z
2024-01-12T19:19:08.423Z
Darth Pseudonym
<p>Assume an object is falling toward the earth then at what velocity would the object be weightless? Taking the air resistance into account might be a factor here so lets assume no air resistance to simplify matters.</p>

CC BY-SA 4.0
2024-01-10T18:10:50.063Z
Weightlessness occurs when you are in freefall - that is, when your acceleration is equal to the acceleration due to gravity. Speed is irrelevant - a base jumper becomes weightless the instant they jump, when they're moving at 0m/s. If they were falling in a vacuum, they'd accelerate until they hit the ground, and would experience weightlessness the entire time regardless of their speed. I don't really see any connection to escape velocity or how this is a "reverse".
Nuclear Hoagie
CC BY-SA 4.0
2024-01-10T18:53:10.537Z
Iv'e voted to close, you clearly have a big misconception about what "weightless" means.  I think Nuclear Hoagie has started to unpack this, but I don't think an answer is possible to the question as written.
James K
CC BY-SA 4.0
2024-01-10T22:33:37.080Z
I edited my question to make it more clear and remove misconceptions and other problems. Thank you.
Sedumjoy
CC BY-SA 4.0
2024-01-10T23:44:09.087Z
Even when the question is by its wording based on false assumptions, you should not delete it. This misconception is reasonably common. This having it here and an answer is helpful.
planetmaker
CC BY-SA 4.0
2024-01-11T04:51:02.833Z
A note on comment reply. Please don't put space between @ and the name. Otherwise, that person won't be notified.
Nilay Ghosh
CC BY-SA 4.0
2024-01-11T14:27:34.487Z
Thank you Nuclear Hoagie. You have cleared this up for me. Stackexchange is a great resource.
Sedumjoy
CC BY-SA 4.0
2024-01-11T14:29:19.947Z
Thank you planetmaker. I did not know this. Maybe my question maybe helpful afterall.  I will not delete it and I have learned a lot from the responses.
Sedumjoy
CC BY-SA 4.0
2024-01-11T14:30:04.937Z
Thank you Nilay Ghosh. I will remove the space. Thank you for the heads up.
Sedumjoy
CC BY-SA 4.0
2024-01-11T23:51:07.957Z
Here on Earth, you can become weightless by falling sideways at about 28,500 km/h.
Mark
CC BY-SA 4.0
2024-01-12T19:05:16.637Z
Surprised nobody answered flippantly with a velocity that's a function of time.
user121330
<gravity>
At what velocity would an object have to fall in order to become weightless?
Sedumjoy
# At what velocity would an object have to fall in order to become weightless?

(Asked by: username_0 on 2024-01-10)

Assume an object is falling toward the earth then at what velocity would the object be weightless? Taking the air resistance into account might be a factor here so lets assume no air resistance to simplify matters.

**Tags:** gravity

> **Comments:**
> **username_1**: Weightlessness occurs when you are in freefall - that is, when your acceleration is equal to the acceleration due to gravity. Speed is irrelevant - a base jumper becomes weightless the instant they jump, when they're moving at 0m/s. If they were falling in a vacuum, they'd accelerate until they hit the ground, and would experience weightlessness the entire time regardless of their speed. I don't really see any connection to escape velocity or how this is a "reverse".  
> **username_2**: Iv'e voted to close, you clearly have a big misconception about what "weightless" means.  I think username_1 username_1 has started to unpack this, but I don't think an answer is possible to the question as written.  
> **username_0**: I edited my question to make it more clear and remove misconceptions and other problems. Thank you.  
> **username_3**: Even when the question is by its wording based on false assumptions, you should not delete it. This misconception is reasonably common. This having it here and an answer is helpful.  
> **username_4**: A note on comment reply. Please don't put space between @ and the name. Otherwise, that person won't be notified.  
> **username_0**: Thank you username_1 username_1. You have cleared this up for me. Stackexchange is a great resource.  
> **username_0**: Thank you username_3. I did not know this. Maybe my question maybe helpful afterall.  I will not delete it and I have learned a lot from the responses.  
> **username_0**: Thank you username_4 username_4. I will remove the space. Thank you for the heads up.  
> **username_5**: Here on Earth, you can become weightless by falling sideways at about 28,500 km/h.  
> **username_6**: Surprised nobody answered flippantly with a velocity that's a function of time.  

---

## 6 answers

### Answer by username_14 on 2024-01-10. Score: 34 | Accepted answer

There's no speed at which you experience weightlessness; to stay weightless, you need to keep getting faster and faster all the time.

From our perspective on Earth, everything accelerates downward at about 9.8$\frac{m}{s^2}$ ($32\frac{ft}{s^2}$). Weightlessness is what happens when you're accelerating at exactly that rate, whether it's because you jumped off a rock or you're in orbit (which is just falling while moving forward fast enough to keep missing the planet). As long as you're accelerating downward as fast as gravity will let you, you're in freefall and experience weightlessness.

That's pretty difficult, though. A skydiver starts out in freefall, and they feel weightless for a few seconds, but the wind resistance (or "drag") on their body quickly grows, reducing their acceleration and increasing their apparent weight until they're eventually not accelerating at all. We call that "terminal velocity", and it's usually around 53 meters per second (120 miles per hour) in the spread-eagle position. At that point they're not weightless anymore; their body is experiencing the same weight as if they were laying face-down on a bed, just with a lot more wind.

There are ways to make it work, though. The famous "Vomit Comet" aircraft are designed to fly in an arc that lets them maintain that perfect acceleration for a short period despite the drag trying to slow them down, and inside the cabin, the passengers can float around as if they're weightless. (The name comes from the fact that weightlessness often makes people feel sick at first, as their body isn't used to that feeling lasting for an extended time.)

If there were no air and you were to bring yourself to a perfect stop many miles above the surface, you'd be weightless all the way down, getting faster and faster without limit until you hit the ground at some incredible speed and left quite a crater behind.

> **Comments:**
> **username_0**: Thank you username_14. This clears up my misconceptions. The light bulb went off as soon as I read your second paragraph. I appreciate you all.  
> **username_3**: The'vomit comet'offers about 20s of zero gravity per parabola. Been there, done that. For minutes you need either a supersonic jet or a sub-orbital  sounding rocket which reaches heights of about 300km. (100km usually is called the border to space, the iss is at 400km)  
> **username_3**: See also https://www.airzerog.com/scientific-research-services/  
> **username_8**: If you fell to an airless Earth from a height of 100 km, you'd land with a speed of ~1400 m/s ~= 5000 km/h  
> **username_15**: @username_3: That's the commercial parabolic flights.  NASA's aircraft (the original 'Vomit Comet') sometimes did substantially longer parabolas, but still under a minute.  
> **username_3**: @username_15 you can do the math: the flight capability's of NASA's 747 or ESA's A-310 (and that's what I linked to) are quite comparable. The flight maneuver lasts about one minute, but the zero-g time is about 20...25 seconds. One can stretch it to maybe 30 seconds if you manage to gain a few km/h on horizontal cruise speed and start with a speed a bit closer to sound speed which allows to point the nose of the airplane more than 48° into the sky at the start of the 0g phase. But a minute is not possible with a commercial airliner; if you disagree, please do show me the math or a credible link.  
> **username_3**: https://en.wikipedia.org/wiki/Reduced-gravity_aircraft also states for NASA's zero-g plane "This aircraft is used to train astronauts in zero-g maneuvers, giving them about 25 seconds of weightlessness out of 65 seconds of flight in each parabola." - thus the same.  
> **username_15**: @username_3: I didn't say a minute was possible, in fact I said "still under a minute".  I worked with a team that did many "zero-G" experiments on these craft, and I do remember that NASA discontinuing their service in favor of the commercial offering caused some major problems because it reduced the freefall time. I'm fuzzy on the exact numbers. 25 seconds sounds like the routine parabolas, and I think by special arrangement they'd do somewhere in the 32-35 range. Made a huge difference when the experiment was "can you do CPR in zero-G?" since seconds are wasted just to get into position.  
> **username_3**: One can "stretch" it by not flying 0g but 'cheat' a little bit without jeopardizing the result of such medical experiments overly, e.g. by flying 0.05g or 0.1g or similar. The quality of µg is anyway "only" around 0.01g rms IIRC, and 0.001g on good days / flights. The duration of each parabola in the flight with lunar (0.16g) and marsian (0.35g) parabolas was considerably longer. But evidently 20...25 seconds already suffized for people to practise stitching wounds.  
> **username_16**: "to stay weightless, you need to keep getting faster and faster all the time" is probably not the best wording. A more careful wording would be "to stay weightless, your speed needs to keep changing all the time." After all, the ISS isn't constantly increasing its speed, it's just constantly changing its velocity by moving in a circle (due to the influence of gravity).  
> **username_14**: @username_16 There's a point where communicating clearly is more important than being precisely accurate. "Lies to children". Since the question is talking about falling towards the ground, it's easier to say that you have to get faster rather than try to explain orbital mechanics to somebody who's still struggling with the basics.  
> **username_14**: @username_3 I changed it to just say 'for a short time'.  I think I was misremembering the length of each cycle as the length of the weightless period.  
> **username_10**: @username_16: In a circular orbit, your velocity is changing but your speed isn't, so if you're trying to avoid technically inaccurate statements while keeping the language simple, that doesn't work either.  Perhaps "Your acceleration towards the Earth needs to be about 9.8m/s^2, matching the local gravity field, but you can start out going upwards, or you can be going so fast sideways you continuously miss the planet (orbit)."  Not great, the layman interpretation of "accelerate toward" includes already moving towards, and a speed that's increasing.  
> **username_10**: (At orbital altitudes, gravity is a bit weaker, about 90% the surface strength at ISS altitudes: https://what-if.xkcd.com/58/)  

---

### Answer by username_9 on 2024-01-11. Score: 8

Any speed. If you free fall then you feel weightless. That begins at zero speed, when you start falling, and ends when you hit something at arbitrarily high speed.

> **Comments:**
> **username_10**: If you're going fast enough sideways, you can keep missing the planet despite gravity accelerating you towards it, avoiding the sudden stop at the end.  (This is a fun way to describe orbiting.  How fast?  https://what-if.xkcd.com/58/ covers low orbit.)  

---

### Answer by username_7 on 2024-01-11. Score: 6

In general, you are weightless unless an electromagnetic force acts on you. (What we call "contact" with other matter like air or the ground is electromagnetic interaction of electron hulls. That is the reason you had to assume a vacuum in your question. An electrostatically or magnetically levitated body on Earth would also feel weight.)

That is more obvious and expected when you are far away from planets and stars, "floating in space"; even though there is still lots of gravity around from galaxies and stars, we would not feel it and would not perceive any motion with our bare senses due to the large distance of any reference points.

But it is no less true in close proximity to Earth, for example on the ISS (tidal forces due to an inhomogeneous gravitational field which pulls on some parts more than others aside). In both cases — far away or close by — you follow a [geodesic](https://en.wikipedia.org/wiki/Geodesics_in_general_relativity), the equivalent of a straight line in curved spacetime. The line is "straight" because no forces act on you (and the gravitation is modeled as spacetime curvature).

In a way, this inverts the notion of "acceleration" because one could argue that one is "unperturbed" when following a geodesic; by contrast, when we stand on Earth, the ground constantly pushes us "out of our natural way", accelerates us, if you want. That is the meaning of Einstein's elevator *Gedankenexperiment*. Inside a black box like the elevator you feel (and are, in the relativistic sense) accelerated when you stand still but feel (and are, in the relativistic sense) standing still when you free-fall in what appears an accelerated motion to an outside observer.

> **Comments:**
> **username_8**: Good answer, but it's important to distinguish between spatial curvature and spacetime curvature. https://physics.stackexchange.com/a/587025/123208  
> **username_7**: @username_8 And there is no space without time, so...  

---

### Answer by username_11 on 2024-01-12. Score: 2

There isn't any velocity where the object would be "weightless".

A simple example is riding in a lift/elevator, at the start and end of the lift's journey you experience a moment of increased and reduced gravity while accelerating and decelerating compared to the direction of gravity but during the middle when the lift is at a constant velocity you experience the same 1g as someone on the ground.


---

### Answer by username_12 on 2024-01-11. Score: 2

Weightlessness isn't something you experience when you're falling by yourself. The fact that you're falling means that gravity is pulling you down, and that's due to your weight. Instead, you feel weightless when you're falling at the same rate as whatever container you're in.

If you were in an airplane and its wings fell off, it would start falling. But air resistance would limit it to some terminal velocity, so it won't fall as fast as gravity is trying to accelerate the plane and its passengers. So you would still experience some upward force from the floor and seat, and wouldn't be weightless.

You may feel almost weightless when you ride a roller coaster. The designer should minimize the friction of the wheels, so you accelerate at near 1G during the big drop.

To experience weightlessness, the Vomit Comet uses a powered nosedive to accelerate down at the same rate as gravity. And a roller coaster could make you feel this by powering the car at high speed rather than just allowing it to drop down the track; it might even go faster than gravity would have accelerated it, and you'll experience *negative* weight -- you'll feel a push against the belt or bar that's holding you in your seat.

In these cases you notice the weightlessness because there's nothing keeping you pressed against the floor of the aircraft or car. Your fall due to gravity is the same as the descent of the container, so you can float freely relative to it.

> **Comments:**
> **username_3**: (slightly more than) half of the 0g time in a parabolic flight is on the ascending path of the parabola. Going down is by no means a prerequisite for weigthlessness (yet another very common misconception).  
> **username_12**: Good point. When the plane's upward velocity slows down at the same rate as gravity, the passenger's upward velocity reduces at the same rate due to gravity.  

---

### Answer by username_13 on 2024-01-11. Score: 2

~8km/s as close to Earth as practical, less when higher.

This is how orbital motion works. It is essentially a freefall, so in orbit you feel weightless.

But the essence is not the speed. It is the acceleration. See the other answers.

> **Comments:**
> **username_7**: When the trajectory is straight you'll feel just normal gravity. Speed is not only not the essence: It is irrelevant.  

---

