<p>Well, asumming that Venus orbits the Sun at 0.7233 AU and its diameter is 12,104 km, I can conclude that its angular diameter seen from the earth is ~1', then its represents ~1/31 part of the angular diameter of solar disc, so that's represents only <span class="math-container">$1365Wm^{-2}/31 ~ 44 Wm^{-2}$</span> , hence that fraction represents just ~ 44/1365 ~ 0.0322... of the total radiation.</p>
<p>Did I reason correctly?</p>

CC BY-SA 4.0
2021-10-11T20:50:29.943Z
I think you have wrongly compared the ratios of the angular diameters, rather than the ratio of the area of the disks? So calculate ratio of pi*(angular radius)^2 for Venus/Sun... would give you a much smaller fraction.
lucas
CC BY-SA 4.0
2021-10-11T21:04:06.357Z
@lucas Ohhhh I get it, I get it, I passed off the fact that I was looking for the area of the disks
Esteban Vera
<the-sun><radiation><planetary-transits>
which fraction of the solar radiation corresponds the blocked part by Venus at its transit upon he sun?
Esteban Vera
# which fraction of the solar radiation corresponds the blocked part by Venus at its transit upon he sun?

(Asked by: username_0 on 2021-10-11)

Well, asumming that Venus orbits the Sun at 0.7233 AU and its diameter is 12,104 km, I can conclude that its angular diameter seen from the earth is ~1', then its represents ~1/31 part of the angular diameter of solar disc, so that's represents only $1365Wm^{-2}/31 ~ 44 Wm^{-2}$ , hence that fraction represents just ~ 44/1365 ~ 0.0322... of the total radiation.

Did I reason correctly?

**Tags:** the-sun, radiation, planetary-transits

> **Comments:**
> **username_1**: I think you have wrongly compared the ratios of the angular diameters, rather than the ratio of the area of the disks? So calculate ratio of pi*(angular radius)^2 for Venus/Sun... would give you a much smaller fraction.  
> **username_0**: @username_1 Ohhhh I get it, I get it, I passed off the fact that I was looking for the area of the disks  

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## 0 answers

