<p>So our arc day starts at 20°41'32 which is midnight (0:00) and ends 24 hours later at 21°42'42. According to my calculations it traveled 0 degrees, 59 minutes, and 30 seconds or 3570 arc seconds in 24 hours. What I am looking for is, what time it will reach 21°15'30.32. For the love of God I have a brain freeze on how to get this.</p>
<p>This is what I came up with:</p>
<pre><code>3570 arcseconds / 24 hours = 148.75 arcseconds/hour
1758.32 arcseconds / 148.75 arcseconds/hour ≈ 11.82 hours
</code></pre>
<p>but I do not think its accurate as the time I am looking for is 13:19:43.</p>

CC BY-SA 4.0
2024-01-14T23:24:57.977Z
The difference betwee 21°15'30.32 and 20°41'32 is 21*3600+15*60+30.32- (20*3600+41*60+32) = 2038.32 arcseconds.  Not 1758.32 arcseconds.
James K
CC BY-SA 4.0
2024-01-15T00:20:04.243Z
Try converting those angles to decimal degrees first.
Mike G
CC BY-SA 4.0
2024-01-15T00:23:46.223Z
21.7117−20.6922=1.0195  which makes my arcseconds also wrong as it comes to 3682.2 arcseconds
dimitri33
CC BY-SA 4.0
2024-01-15T11:43:28.877Z
1.0195° = 3670″. Are you doing the arithmetic by hand?
Mike G
CC BY-SA 4.0
2024-01-15T14:59:29.940Z
online calculator... got it now, thanks
dimitri33
CC BY-SA 4.0
2024-01-15T18:12:36.647Z
I’m voting to close this question because there doesn't appear to be an astronomical problem, only difficulty using an online calculator to calculate sexagesimal.
James K
CC BY-SA 4.0
2024-01-15T19:31:34.160Z
this conversation helped me <3 so thank you everyone, I wanted to know, are there other ways to determine the time ?
dimitri33
CC BY-SA 4.0
2024-01-18T21:55:06.263Z
A good clock is often effective !
James K
<the-sun><orbit><astrophysics><time>
Determining Time Based on Arc Seconds
dimitri33
# Determining Time Based on Arc Seconds

(Asked by: username_0 on 2024-01-14)

So our arc day starts at 20°41'32 which is midnight (0:00) and ends 24 hours later at 21°42'42. According to my calculations it traveled 0 degrees, 59 minutes, and 30 seconds or 3570 arc seconds in 24 hours. What I am looking for is, what time it will reach 21°15'30.32. For the love of God I have a brain freeze on how to get this.

This is what I came up with:

```
3570 arcseconds / 24 hours = 148.75 arcseconds/hour
1758.32 arcseconds / 148.75 arcseconds/hour ≈ 11.82 hours

```

but I do not think its accurate as the time I am looking for is 13:19:43.

**Tags:** the-sun, orbit, astrophysics, time

> **Comments:**
> **username_1**: The difference betwee 21°15'30.32 and 20°41'32 is 21*3600+15*60+30.32- (20*3600+41*60+32) = 2038.32 arcseconds.  Not 1758.32 arcseconds.  
> **username_2**: Try converting those angles to decimal degrees first.  
> **username_0**: 21.7117−20.6922=1.0195  which makes my arcseconds also wrong as it comes to 3682.2 arcseconds  
> **username_2**: 1.0195° = 3670″. Are you doing the arithmetic by hand?  
> **username_0**: online calculator... got it now, thanks  
> **username_1**: I’m voting to close this question because there doesn't appear to be an astronomical problem, only difficulty using an online calculator to calculate sexagesimal.  
> **username_0**: this conversation helped me <3 so thank you everyone, I wanted to know, are there other ways to determine the time ?  
> **username_1**: A good clock is often effective !  

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## 0 answers

