<p>The distances to the two main bodies are not only equal, they are equal to the distance between the two main bodies. In other words, the two main bodies and L4 (or L5) form an equilateral triangle.</p>

CC BY-SA 3.0
2015-02-11T06:25:55.693Z
2015-02-11T06:25:55.693Z
ganbustein
<p>I know that, in L4&amp;L5, the distances to the two main bodies should be equal. Still, how can I calculate that distance with accuracy? How can I know that that distance is inside the equipotential surface?
Let's take, as an example, the Sun-Earth system and the Earth-Moon system.
Thank you in advance!</p>

<distances><lagrange-point>
L4&L5 positions?
altair
# L4&L5 positions?

(Asked by: username_0 on 2015-02-10)

I know that, in L4&L5, the distances to the two main bodies should be equal. Still, how can I calculate that distance with accuracy? How can I know that that distance is inside the equipotential surface?
Let's take, as an example, the Sun-Earth system and the Earth-Moon system.
Thank you in advance!

**Tags:** distances, lagrange-point


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## 1 answers

### Answer by username_1 on 2015-02-11. Score: 1 | Accepted answer

The distances to the two main bodies are not only equal, they are equal to the distance between the two main bodies. In other words, the two main bodies and L4 (or L5) form an equilateral triangle.


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