<p>The azimuth of moonrise and moonset can be determined from the observer’s latitude and the Moon’s declination.</p>
<p>The azimuth of a celestial body can be given by
<span class="math-container">$$
\cos A = \frac{{\sin \delta  - \sin \phi \sin h}}{{\cos \phi \cos h}},
$$</span>
where <span class="math-container">$\delta$</span> is the body’s declination, <span class="math-container">$\phi$</span> is the observer’s latitude, and <span class="math-container">$h$</span> is the altitude of the body.
At rise or set, <span class="math-container">$h$</span> = 0, <span class="math-container">$\sin h$</span> = 0, and <span class="math-container">$\cos h$</span> = 1, so this reduces to
<span class="math-container">$$
\cos A = \frac{\sin \delta}{\cos \phi}.
$$</span>
Because <span class="math-container">$\cos (360° − x) = \cos x$</span>, there are two possible values for <span class="math-container">$A$</span>.
The azimuth at rise is
<span class="math-container">$$
A_\mathrm{r} = \cos^{-1} \frac{\sin \delta}{\cos \phi};
$$</span>
the azimuth at set is
<span class="math-container">$$
A_\mathrm{s} = 360° – A_\mathrm{r}.
$$</span>
For observing, the declination must be topocentric and the effect of atmospheric refraction must be included.</p>

CC BY-SA 4.0
2023-10-31T01:40:31.457Z
2023-10-31T01:40:31.457Z
JeffC
<p>Moonrise azimuth... The Moon travels around the Ecliptic over a months time, so its azimuth angle at rising will be "comparable" to the Sun's rising azimuth angle pn each day - equal to the Sun's at times but other times with a sizable "offset" in  angle as large as +/- 30 degrees. </p>

CC BY-SA 3.0
2015-05-24T05:26:12.997Z
2015-05-24T05:26:12.997Z
user7323
<p>The monthly variations are caused by the change in declination of the Moon as it travels (roughly) along the ecliptic.  This is caused by the tilt of the Earth's rotation axis, which results in an angle of about 23&deg; between the equator (declination = 0&deg;) and the ecliptic.  Around the constellations of Taurus and Gemini the ecliptic lies at much higher declination than near Saggitarius or Ophiuchus.  The same effect causes the change in rise and set times of the Sun during a year.</p>

<p>When you're in the northern hemisphere, a higher declination means that the transit altitude of the Moon or Sun is higher.  In fact, their whole daily (apparent - caused by the Earth's rotation) paths lie closer to the North star.  Because of that, the points where a daily path intersects with your local horizon lie further north, which you see as a change in rise/set azimuth of the Moon.</p>

<p>All this is true even without the 5&deg; inclination of the Moon's orbit w.r.t. the ecliptic.  That inclination only mitigates the effect; the Moons declination does not exactly vary between -23 and +23&deg; every month, but these extreme values themselves can lie between +/-18&deg; or +/-28&deg;, depending on whether the inclination effect increases (23+5&deg;) or decreases (23-5&deg;) the effect of the motion along the ecliptic.</p>

<p>Lastly, the rise/set azimuths do not correlate to lunar phase, as do the rise/set times.  Both phases and rise/set times are defined based on the Sun's position; we roughly define "noon" as the moment when the Sun is transiting in the south, and call the Moon "New" when it's in the same direction as the Sun, so there's no wonder that the New Moon transits around noon.  This is not true for the effects described above, and hence the corresponding periods are different.  The mean lunar period between twice the same equinox point (e.g. Aries) is called the Tropical month and lasts ~27.3d (this is roughly the same as the siderial month, but influenced by precession).  The effect of the inclination of the Moon's orbit has a mean period of one Draconic month, with a period of ~27.2d.  Instead, the Synodic month, the mean period between two cases of New Moon, lasts 29.5d, about 2.2d longer.  Hence, the declination and rise/set azimuths of the Moon do not correlate with the phases. </p>

CC BY-SA 3.0
2013-10-20T12:00:52.737Z
2013-10-20T12:00:52.737Z
AstroFloyd
<p>In my tenacious attempts to observe moonrise (surprisingly difficult in a poor weather heavily urbanized hilly area with frequent bad smog, with busy work schedule and a bicycle) I was frequently trying to find good observation spots that would provide view to open distant horizon at specific azimuth.</p>

<p>While generally similar moon phases correlated with similar moonrise times I found the azimuth to vary in a way I have a difficult time to put my finger on. Sure there's a <em>roughly</em> monthly cycle of "wobble" between deviating about +/- 30 degrees north or south from "pure east" but while the mechanics of correlation between hour when the Moon is visible from behind the horizon and the degree it's lit by the sun are quite clear to me, the way its - or is it Earth's? - orbital plane is "off" relative to the ecliptic plane and Earth rotation plane eludes me. Could someone provide a sort of guide - preferably something that acts more as help in understanding the mechanics, as opposed to providing raw mathematical solutions, what does this deviation depend on, and how it changes with time?</p>

<the-moon><azimuth>
How does moonrise/moonset azimuth vary with time?
SF.
# How does moonrise/moonset azimuth vary with time?

(Asked by: username_0 on 2013-09-26)

In my tenacious attempts to observe moonrise (surprisingly difficult in a poor weather heavily urbanized hilly area with frequent bad smog, with busy work schedule and a bicycle) I was frequently trying to find good observation spots that would provide view to open distant horizon at specific azimuth.

While generally similar moon phases correlated with similar moonrise times I found the azimuth to vary in a way I have a difficult time to put my finger on. Sure there's a *roughly* monthly cycle of "wobble" between deviating about +/- 30 degrees north or south from "pure east" but while the mechanics of correlation between hour when the Moon is visible from behind the horizon and the degree it's lit by the sun are quite clear to me, the way its - or is it Earth's? - orbital plane is "off" relative to the ecliptic plane and Earth rotation plane eludes me. Could someone provide a sort of guide - preferably something that acts more as help in understanding the mechanics, as opposed to providing raw mathematical solutions, what does this deviation depend on, and how it changes with time?

**Tags:** the-moon, azimuth


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## 3 answers

### Answer by username_3 on 2013-10-20. Score: 9 | Accepted answer

The monthly variations are caused by the change in declination of the Moon as it travels (roughly) along the ecliptic. This is caused by the tilt of the Earth's rotation axis, which results in an angle of about 23° between the equator (declination = 0°) and the ecliptic. Around the constellations of Taurus and Gemini the ecliptic lies at much higher declination than near Saggitarius or Ophiuchus. The same effect causes the change in rise and set times of the Sun during a year.

When you're in the northern hemisphere, a higher declination means that the transit altitude of the Moon or Sun is higher. In fact, their whole daily (apparent - caused by the Earth's rotation) paths lie closer to the North star. Because of that, the points where a daily path intersects with your local horizon lie further north, which you see as a change in rise/set azimuth of the Moon.

All this is true even without the 5° inclination of the Moon's orbit w.r.t. the ecliptic. That inclination only mitigates the effect; the Moons declination does not exactly vary between -23 and +23° every month, but these extreme values themselves can lie between +/-18° or +/-28°, depending on whether the inclination effect increases (23+5°) or decreases (23-5°) the effect of the motion along the ecliptic.

Lastly, the rise/set azimuths do not correlate to lunar phase, as do the rise/set times. Both phases and rise/set times are defined based on the Sun's position; we roughly define "noon" as the moment when the Sun is transiting in the south, and call the Moon "New" when it's in the same direction as the Sun, so there's no wonder that the New Moon transits around noon. This is not true for the effects described above, and hence the corresponding periods are different. The mean lunar period between twice the same equinox point (e.g. Aries) is called the Tropical month and lasts ~27.3d (this is roughly the same as the siderial month, but influenced by precession). The effect of the inclination of the Moon's orbit has a mean period of one Draconic month, with a period of ~27.2d. Instead, the Synodic month, the mean period between two cases of New Moon, lasts 29.5d, about 2.2d longer. Hence, the declination and rise/set azimuths of the Moon do not correlate with the phases.


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### Answer by username_1 on 2023-10-31. Score: 1

The azimuth of moonrise and moonset can be determined from the observer’s latitude and the Moon’s declination.

The azimuth of a celestial body can be given by
$$
\cos A = \frac{{\sin \delta - \sin \phi \sin h}}{{\cos \phi \cos h}},
$$
where $\delta$ is the body’s declination, $\phi$ is the observer’s latitude, and $h$ is the altitude of the body.
At rise or set, $h$ = 0, $\sin h$ = 0, and $\cos h$ = 1, so this reduces to
$$
\cos A = \frac{\sin \delta}{\cos \phi}.
$$
Because $\cos (360° − x) = \cos x$, there are two possible values for $A$.
The azimuth at rise is
$$
A\_\mathrm{r} = \cos^{-1} \frac{\sin \delta}{\cos \phi};
$$
the azimuth at set is
$$
A\_\mathrm{s} = 360° – A\_\mathrm{r}.
$$
For observing, the declination must be topocentric and the effect of atmospheric refraction must be included.


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### Answer by username_2 on 2015-05-24. Score: 0

Moonrise azimuth... The Moon travels around the Ecliptic over a months time, so its azimuth angle at rising will be "comparable" to the Sun's rising azimuth angle pn each day - equal to the Sun's at times but other times with a sizable "offset" in angle as large as +/- 30 degrees.


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