<p>What is W in the brightness (intensity) distribution, please?
Alpha is the position of the star; lambda, the wavelength; t, the time; P, the polarization.
Thank you</p>
<p><a href="https://i.sstatic.net/nKxIE.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/nKxIE.png" alt="enter image description here" /></a></p>

CC BY-SA 4.0
2023-11-13T14:58:22.517Z
If you can tell us where you found this, and perhaps provide some more context, it will be easier to help you.
pela
CC BY-SA 4.0
2023-11-13T15:03:15.497Z
Context is essential... there are some rough conventions of which symbols are used for which physical properties - but that is anything but a given. That is more true the less common a formula is. And this is not even a formula, but just a function call, so that no-one can even draw conclusions from the formula.
planetmaker
CC BY-SA 4.0
2023-11-14T06:10:09.053Z
It was in a lecture about interferometry that in this all astrophysicists are interested. However, then it was talked just about the other variables as I described above.
Anna-Kat
<interferometry>
W in the brightness distribution
Anna-Kat
# W in the brightness distribution

(Asked by: username_0 on 2023-11-13)

What is W in the brightness (intensity) distribution, please?
Alpha is the position of the star; lambda, the wavelength; t, the time; P, the polarization.
Thank you

[![enter image description here](https://i.sstatic.net/nKxIE.png)](https://i.sstatic.net/nKxIE.png)

**Tags:** interferometry

> **Comments:**
> **username_1**: If you can tell us where you found this, and perhaps provide some more context, it will be easier to help you.  
> **username_2**: Context is essential... there are some rough conventions of which symbols are used for which physical properties - but that is anything but a given. That is more true the less common a formula is. And this is not even a formula, but just a function call, so that no-one can even draw conclusions from the formula.  
> **username_0**: It was in a lecture about interferometry that in this all astrophysicists are interested. However, then it was talked just about the other variables as I described above.  

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## 0 answers

