<p>It's likely that the &quot;existence of a proton&quot; has no meaning inside the event horizon.  But if it does somehow, and the protons eventually decay, that would be invisible outside the black-hole.  In proton decay, charge, spin and mass-energy are conserved, so no externally visible properties of the black-hole would be affected at all.</p>

CC BY-SA 4.0
2023-08-24T10:14:02.147Z
Thank you for your answer. So if an internal observer somehow observe the singularity, will the laws of physics apply and proton decay is observed
Arjun
CC BY-SA 4.0
2023-08-24T12:27:40.067Z
@Arjun You can't observe the singularity, even if you're inside the event horizon. Light rays go towards the singularity, not away from it. That is, the singularity is *never* in the past light-cone of any observer. So it can never be the cause of any events outside itself. See https://astronomy.stackexchange.com/q/44316/16685
PM 2Ring
CC BY-SA 4.0
2023-08-23T19:08:51.573Z
2023-08-23T19:08:51.573Z
antlersoft
<p>According to GUT (The Grand Unified Theory), the half life of protons is 1.67×10^34 years if the standard model is incorrect and the time black holes take to evaporate due to hawking radiation is more than Googol years (for stellar mass black holes it is more than 10^67 years to evaporate, this figures refers to higher mass black holes like supermassive and ultramassive), so shouldn't the protons fade first? and if so would the protons in the singularity, decay leaving only other subatomic particles in the singularity like quarks or it would not effect the singularity at all because the laws of physics and CPT symettry does not apply inside the event horizon?</p>
<p>I mean that if the proton decay is faster than the singularity decay, proton decay would already occur, so what would happen to the singularity?</p>
<p>I know that only quantum gravity can give us the ultimate answer, but still are there any estimates by other theories.</p>
<p>(Sorry, This was a Astrophysics question so I did not know to put it into Astronomy SE or Physics SE)</p>
<p>Thanks!</p>

<hawking-radiation><singularity><proton>
In the case of heat death of our universe, would proton decay overtake the singularity decay due to Hawking radiation?
Arjun
# In the case of heat death of our universe, would proton decay overtake the singularity decay due to Hawking radiation?

(Asked by: username_0 on 2023-08-23)

According to GUT (The Grand Unified Theory), the half life of protons is 1.67×10^34 years if the standard model is incorrect and the time black holes take to evaporate due to hawking radiation is more than Googol years (for stellar mass black holes it is more than 10^67 years to evaporate, this figures refers to higher mass black holes like supermassive and ultramassive), so shouldn't the protons fade first? and if so would the protons in the singularity, decay leaving only other subatomic particles in the singularity like quarks or it would not effect the singularity at all because the laws of physics and CPT symettry does not apply inside the event horizon?

I mean that if the proton decay is faster than the singularity decay, proton decay would already occur, so what would happen to the singularity?

I know that only quantum gravity can give us the ultimate answer, but still are there any estimates by other theories.

(Sorry, This was a Astrophysics question so I did not know to put it into Astronomy SE or Physics SE)

Thanks!

**Tags:** hawking-radiation, singularity, proton


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## 1 answers

### Answer by username_1 on 2023-08-23. Score: 1 | Accepted answer

It's likely that the "existence of a proton" has no meaning inside the event horizon. But if it does somehow, and the protons eventually decay, that would be invisible outside the black-hole. In proton decay, charge, spin and mass-energy are conserved, so no externally visible properties of the black-hole would be affected at all.

> **Comments:**
> **username_0**: Thank you for your answer. So if an internal observer somehow observe the singularity, will the laws of physics apply and proton decay is observed  
> **username_2**: @username_0 You can't observe the singularity, even if you're inside the event horizon. Light rays go towards the singularity, not away from it. That is, the singularity is *never* in the past light-cone of any observer. So it can never be the cause of any events outside itself. See https://astronomy.stackexchange.com/q/44316/16685  

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