<p>Yes. Radiation may be polarized when it is scattered, and different media scatter different wavelengths differently.</p>
<p>For instance, neutral hydrogen scatters Lyman <span class="math-container">$\alpha$</span> radiation (i.e. photons coming from the <span class="math-container">$2$$\rightarrow$$1$</span> transition of hydrogen). The degree of polarization is coupled to the &quot;phase function&quot; which determines in which direction it is scattered. If a Ly<span class="math-container">$\alpha$</span> photon is close to the line center (which is at 1215.67 Ångström), it is scattered isotropically (i.e. equal probability of being scattered in any given direction), and will not be polarized, but if it is more than a few Doppler widths from the line center, it is scattered <em>an</em>isotropically, and will then be polarized. Maximum polarization occurs at 90º scattering, where <span class="math-container">$3/7 \simeq 43\%$</span> of the light will be polarized.</p>
<p>If the photons are even farther from the line center, they won't be scattered at all (because they're no longer in <em>resonance</em> with the <span class="math-container">$2$$\rightarrow$$1$</span> transition), and the radiation is hence unpolarized.</p>
<strong>Example of polarization at a particular wavelength</strong>
<p>The figure below, taken from <a href="http://arxiv.org/abs/1108.3332" rel="nofollow noreferrer">Hayes et al. (2011)</a>, shows a so-called &quot;Lyman <span class="math-container">$\alpha$</span> blob&quot;, which is a source of Lyman <span class="math-container">$\alpha$</span> that is quite a lot larger than a galaxy. There was some debate whether the radiation is created outside a central galaxy from gas accreting onto the galaxy and cooling — a signature of galaxy formation — or whether it is centrally produced (from stars) radiation that escapes the galaxy and subsequently scatters on the surrounding gas. If the latter scenario is true, you would expect the Lyman <span class="math-container">$\alpha$</span> to be polarized to some degree in sort of a ring around the center, because this light would be scattered at roughly 90º toward you. In the figure, the blue cross marks the center, and the red lines' direction mark the direction of polarization and their length mark the degree of polarization (if it were fully polarized, they would have the length of the red bar in the upper right corner).</p>
<p>Indeed it seems that the light is polarized around a central source.</p>
<p><a href="https://i.sstatic.net/5eB9G.png" rel="nofollow noreferrer"><img src="https://i.sstatic.net/5eB9G.png" alt="LAB1" /></a></p>

CC BY-SA 3.0
2016-09-07T04:00:33.340Z
Just because you started out with the word "radiation" instead of "photon", I must ask if massive particles are polarized too? Electrons, neutrons, protons, helium and heavier nuclei.
LocalFluff
CC BY-SA 3.0
2016-09-07T05:44:16.347Z
I guess I mostly used the two different terms for having some variation in the language. In general, I would say "photon" about single particles, and "radiation" about an ensemble of photons. I'm no quantum mechanic, but there is something called [spin polarization](https://en.wikipedia.org/wiki/Spin_polarization) which I suppose can apply to all particles that have spin $\ne0$.
pela
CC BY-SA 3.0
2016-09-06T16:17:00.460Z
2016-09-06T16:33:31.393Z
2020-06-17T09:47:40.653Z
pela
<p>Yes, astronomers call it <a href="https://en.wikipedia.org/wiki/Faraday_effect#Faraday_rotation_in_the_interstellar_medium" rel="nofollow">Faraday rotation</a>. The polarization angle of radio waves changes dependent on the wavelength because of the galactic magnetic field. </p>

<p>Sunglasses do not polarize radio waves, the wavelength is too large. You can polarize radio waves with a wire mesh.</p>

CC BY-SA 3.0
2016-09-06T13:25:03.757Z
Would it be fair to say that each photon (stream) captured represents 6 dimensions? 2D as in its direction. And then its timing, its wavelength, its amplitude and its polarization?
LocalFluff
CC BY-SA 3.0
2016-09-06T10:45:02.377Z
2016-09-06T10:45:02.377Z
Alex
<p>Is it possible, and does it occur naturally, that the light from the same source is simultaneously polarized differently at different wavelengths? Light can be polarized by interstellar magnetic fields. Could it polarize light of different wavelengths differently? Does a pair of polarized sunglasses polarize radio waves and UV in the same way as visible light?</p>

CC BY-SA 3.0
2016-09-06T12:47:37.940Z
Observing this is called _spectropolarimetry_.
mtewes
<light><optics><polarization>
Is there a spectrum of polarization? Does polarization vary depending on wavelength, from one and the same source?
LocalFluff
# Is there a spectrum of polarization? Does polarization vary depending on wavelength, from one and the same source?

(Asked by: username_0 on 2016-09-06)

Is it possible, and does it occur naturally, that the light from the same source is simultaneously polarized differently at different wavelengths? Light can be polarized by interstellar magnetic fields. Could it polarize light of different wavelengths differently? Does a pair of polarized sunglasses polarize radio waves and UV in the same way as visible light?

**Tags:** light, optics, polarization

> **Comments:**
> **username_1**: Observing this is called _spectropolarimetry_.  

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## 2 answers

### Answer by username_2 on 2016-09-06. Score: 3 | Accepted answer

Yes. Radiation may be polarized when it is scattered, and different media scatter different wavelengths differently.

For instance, neutral hydrogen scatters Lyman $\alpha$ radiation (i.e. photons coming from the $2$$\rightarrow$$1$ transition of hydrogen). The degree of polarization is coupled to the "phase function" which determines in which direction it is scattered. If a Ly$\alpha$ photon is close to the line center (which is at 1215.67 Ångström), it is scattered isotropically (i.e. equal probability of being scattered in any given direction), and will not be polarized, but if it is more than a few Doppler widths from the line center, it is scattered *an*isotropically, and will then be polarized. Maximum polarization occurs at 90º scattering, where $3/7 \simeq 43\%$ of the light will be polarized.

If the photons are even farther from the line center, they won't be scattered at all (because they're no longer in *resonance* with the $2$$\rightarrow$$1$ transition), and the radiation is hence unpolarized.

**Example of polarization at a particular wavelength**

The figure below, taken from [Hayes et al. (2011)](http://arxiv.org/abs/1108.3332), shows a so-called "Lyman $\alpha$ blob", which is a source of Lyman $\alpha$ that is quite a lot larger than a galaxy. There was some debate whether the radiation is created outside a central galaxy from gas accreting onto the galaxy and cooling — a signature of galaxy formation — or whether it is centrally produced (from stars) radiation that escapes the galaxy and subsequently scatters on the surrounding gas. If the latter scenario is true, you would expect the Lyman $\alpha$ to be polarized to some degree in sort of a ring around the center, because this light would be scattered at roughly 90º toward you. In the figure, the blue cross marks the center, and the red lines' direction mark the direction of polarization and their length mark the degree of polarization (if it were fully polarized, they would have the length of the red bar in the upper right corner).

Indeed it seems that the light is polarized around a central source.

[![LAB1](https://i.sstatic.net/5eB9G.png)](https://i.sstatic.net/5eB9G.png)

> **Comments:**
> **username_0**: Just because you started out with the word "radiation" instead of "photon", I must ask if massive particles are polarized too? Electrons, neutrons, protons, helium and heavier nuclei.  
> **username_2**: I guess I mostly used the two different terms for having some variation in the language. In general, I would say "photon" about single particles, and "radiation" about an ensemble of photons. I'm no quantum mechanic, but there is something called [spin polarization](https://en.wikipedia.org/wiki/Spin_polarization) which I suppose can apply to all particles that have spin $\ne0$.  

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### Answer by username_3 on 2016-09-06. Score: 2

Yes, astronomers call it [Faraday rotation](https://en.wikipedia.org/wiki/Faraday_effect#Faraday_rotation_in_the_interstellar_medium). The polarization angle of radio waves changes dependent on the wavelength because of the galactic magnetic field.

Sunglasses do not polarize radio waves, the wavelength is too large. You can polarize radio waves with a wire mesh.

> **Comments:**
> **username_0**: Would it be fair to say that each photon (stream) captured represents 6 dimensions? 2D as in its direction. And then its timing, its wavelength, its amplitude and its polarization?  

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