<p>I similarly thought that the difference in mass between a proton and an electron was minuscule. I think the proton is like 3x10^(-27) kg and electron is 3x10^(-31) kg.</p>
<p>But the way you think about it is that the proton is 10,000 times bigger (10x^-27/10^(-31) = 10^4 = 10,000).</p>
<p>So in your case, the universe has 10^56 times more atoms than a human. So if my networth is 1 cent, Apple's networth is 1 trillion dollars which is 10^14 times more than mine.</p>
<p>I guess that's a poor analogy but the idea is that if something is 10^56 times more than something else, there is a inconceivably big difference between the amounts.</p>

CC BY-SA 4.0
2021-06-27T18:39:49.783Z
The proton/electron mass ratio is more like 1836.  But your point stands.  10^56 is an inconceivable number.
Jirka Hanika
CC BY-SA 4.0
2021-06-27T02:43:45.083Z
2021-06-27T02:43:45.083Z
Ahmed Anwer
<p>Yes, the number is reasonable for our observable universe. The problem with imagining the decimal notations of numbers is that every added digit can represent approximately 10 times numbers more.</p>
<hr />
<p>Most of the other answers just say that this number is huge and give representations with abstract numbers. But I would like to give some physical meaning. If you don't understand the following, just skip to the end.</p>
<hr />
<p>The neutron is not a fundamental particle. It is made of the three quarks, which have their own bounding sphere. It's radius is <span class="math-container">$r_n=8.5\cdot 10^{-14}m$</span>. Its volume is equal to
<span class="math-container">$$V_n=4\pi r^3/3=2.57\cdot10^{-45}m^3$$</span>
If we just add the volume of such neutrons, we get
<span class="math-container">$$V'=10^{83}\cdot 2.57\cdot10^{-45}m^3=2.57\cdot10^{38}m^3$$</span>
But this is only valid if we could &quot;melt&quot; the neutrons, which we can't. Therefore, we need to use the densest sphere packing possible:
<span class="math-container">$$V=V'/0.74048=3.47\cdot10^{38}m^3$$</span>
Using that volume and the formula for volume of sphere, we can find a radius for such neutron packing
<span class="math-container">$$R=4.36\cdot10^{12}m=29.1 AU$$</span>
For comparison, <span class="math-container">$10^{27}$</span> neutrons densely packed give a radius of about <span class="math-container">$0.85\mu m$</span>.</p>
<hr />
<p><strong>Physical meaning:</strong> The radius we got is the approximate distance between the Sun and the Neptune. The neutron is very small. And imagine bunch of them stacked into the sphere with the radius of the Neptune's orbit.</p>
<p><strong>Wow.</strong></p>

CC BY-SA 4.0
2021-06-27T18:43:43.770Z
While its true that the number of volumes you added have the large volume you have calculated of is not true that the neutrons can be stacked that way. Al particles are point like and all particles can be stacked in a planck size volume. So this doesnt make the distinction very clear. The distance to Saturn aint that big.
Deschele Schilder
CC BY-SA 4.0
2021-06-27T21:12:03.507Z
@DescheleSchilder Neutrons are composed from the fundamental particle,  and between them there is a measurable distance. Therefore, we can approximate the neutron by the bounding sphere. And we are here looking just the volume for the approximation. I might also know where does the downvote come from and why, but I am not mad at you :)
User123
CC BY-SA 4.0
2021-06-27T21:30:15.283Z
It came from me. Because of the reason I gave. Your answer gived a good feeling for the amount of small volumes you can put in the big volume but I think it would have been better to put it the other way round. So to start at the volume of the universe and look how big the volume would be if you divide it by 10exp83 Like that you have an idea how much volume each particle has and at the same time how big the number 10exp83 is. The number 10exp27 isnt mentioned at all. The number of neutrons is not 10exp83. The total of quarks and leptons and photons is the total number.
Deschele Schilder
CC BY-SA 4.0
2021-06-27T21:44:03.167Z
@DescheleSchilder First, we don't know the volume of our universe. Second, I wanted to go away from 10^27 because why would I include it? The other answers tell enough about it and OP just used it as a reference for his misunderstanding. Maybe I want clear enough when I said that I want the physical representation, but I can include it if you want.
User123
CC BY-SA 4.0
2021-06-27T21:48:08.860Z
Im not saying its  a bad answer. But it could have been better. I meant the observable universe. And the number of neutrons is not 10exp83.
Deschele Schilder
CC BY-SA 4.0
2021-06-27T21:55:55.250Z
@DescheleSchilder The neutrons are used here just because of their smallness.
User123
CC BY-SA 4.0
2021-06-27T22:03:47.160Z
I know but particles are almost nothing but empty space. You could have used any volume and then comparing it with the volume 10exp83 as large. Thats why I said it would be more compelling to start from the observable universe and divide its volume in 10exp83 pieces. But the start from the small is just as good.
Deschele Schilder
CC BY-SA 4.0
2021-06-28T06:43:37.330Z
@DescheleSchilder By the standard model, every fundamental particle is pointlike, could we then say that the universe has zero volume? No, because you are looking bounding sphere.
User123
CC BY-SA 4.0
2021-06-28T11:33:04.933Z
@DescheleSchilder Your points are not reasonable at all. The universe is almost nothing but empty space as well.
User123
CC BY-SA 4.0
2021-06-27T15:03:12.727Z
2021-06-27T22:01:31.460Z
2021-06-27T22:01:31.460Z
User123
<p>Compare</p>
<pre><code>1 000 000 000 000 000 000 000 000 000 (10^27)
1 00 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 (10^83)
</code></pre>
<p>For reference, a thousand and a million</p>
<pre><code>1 000
1 000 000
</code></pre>
<p>You probably are aware that a million is quite much more than a thousand but the visual difference between them, if you compare to the first example, is quite small.</p>

CC BY-SA 4.0
2021-06-27T15:06:07.327Z
It would be more appropriate if this were a comment.
User123
CC BY-SA 4.0
2021-06-27T13:06:12.580Z
2021-06-28T09:13:54.680Z
2021-06-28T09:13:54.680Z
d-b
<p>Another way of looking at it. The number with 27 zeros  can be laid <span class="math-container">$10^{56}$</span> times behind each other. I guess you'll arrive somewhere on Pluto). First guess though and it of course depends on how big you write the one and 27 zeros.If you write 1mm numbers the row of numbers 0 and 1 would even be bigger than the observable universe...(thanks to @User123)</p>
<p>So 27 and 83 seem pretty close to one another but the exponentials are. absolutely not.</p>
<p>There simply could not have been another number. If it was bigger or smaller(relatively spoken) the universe would not be our universe anymore. Every elementary particle(so not atom, as the question poses), every one of the <span class="math-container">$10^{83}$</span>, has the optimum amount of space at it's disposal for life to come about.</p>

CC BY-SA 4.0
2021-06-27T17:29:20.343Z
Comments are not for extended discussion; this conversation has been [moved to chat](https://chat.stackexchange.com/rooms/126924/discussion-on-answer-by-deschele-schilder-are-there-only-1083-atoms-in-the-univ).
Connor Garcia
CC BY-SA 4.0
2021-06-27T13:02:34.403Z
2021-06-28T06:15:44.360Z
2021-06-28T06:15:44.360Z
Deschele Schilder
<p>This is a reasonable estimate for the number of atoms in the observable universe.</p>
<p>It might seem like a small number, compared with the number of atoms in a human only as a result of our brain's inability to have an intuition about very large numbers and exponential scales.</p>
<p>There is a very very big difference between <span class="math-container">$10^{27}$</span> and <span class="math-container">$10^{83}$</span>.  How big is the difference? Well <span class="math-container">$10^{83}- 10^{27}= 9.9999999999999999999999999999999999999999999999999999999\times10^{82}$</span></p>
<p>A human is only a very small part of the universe.</p>
<p>Note two things, firstly this is for the observable universe, the Universe may be isotropic, open and unbounded and if so the total number of atoms in the universe is infinite. Secondly most of the estimates of the number of atoms in the universe that I've seen put the value at about <span class="math-container">$10^{80}$</span></p>

CC BY-SA 4.0
2021-06-26T15:14:02.193Z
@Alexa If you don't know what is observable universe: we can't see beyond its boundary because the light hasn't reached us yet. Therefore we don't know what's beyond the observable, visible universe. As JamesK said, the whole universe could be open, infinite.
User123
CC BY-SA 4.0
2021-06-26T15:33:56.037Z
I think saying that 10^83-10^27 is more than 10^82 would be more helpful than spelling the number out with all of its nines (I didn't count them).
Nobody
CC BY-SA 4.0
2021-06-26T17:32:42.610Z
@nobody it is a rhetorical florish.  It is, of course, well beyond the accuracy in the value 10^83, but it is intended as an illustration of just what a small fraction of 10^83 is 10^27
James K
CC BY-SA 4.0
2021-06-26T19:14:05.480Z
@nobody actually saying that "10^83-10^27 is more than 10^82" is about as useful as saying "there is more than one grain of sand on Earth". True, but utterly useless in estimating how much sand is on Earth.
PcMan
CC BY-SA 4.0
2021-06-26T19:53:34.463Z
Yet another way to see how much larger 10^83 is than 10^27 is to divide both numbers by 10^27: 10^27/10^83 is 0.000000000000000000000000000000000000000000000000000000000000000001, which is pretty tiny :)
fish
CC BY-SA 4.0
2021-06-26T22:09:57.037Z
@fish HA! You just estimated how much percentage a single human is part of the universe :)
slebetman
CC BY-SA 4.0
2021-06-27T12:54:36.220Z
@Nobody: 10^83 - 10^27 is not just "more than 10^82", it's basically still 10^83. It's like the old joke : "What's the difference between a dollar and a ruble? ................. a dollar."
Eric Duminil
CC BY-SA 4.0
2021-06-27T14:49:55.273Z
The way you write it out does not make it clear that the difference is that big. You just write the same number again!
Deschele Schilder
CC BY-SA 4.0
2021-06-27T20:41:46.973Z
1000 000 000 000 000-1=999 999 999 999 999. This doesnt tell me how big or small both numbers are. Its an absolute difference while the ratio gives the relative diffference between the two. Of course both give  useful information.
Deschele Schilder
CC BY-SA 4.0
2021-06-26T07:29:03.540Z
2021-06-26T07:44:50.237Z
2021-06-26T07:44:50.237Z
James K
<p>I'm a high school junior. I assumed there would be an incredibly huge number of atoms in the universe if not infinite. Recently, I've come across a few articles which claim that scientists believe there are 10<sup>83</sup> atoms in the universe. I'm not sure if I should believe in this, to me, this seems like a small number. In average, a human alone has 10<sup>27</sup> atoms, so, it's kind of unconvincing to me that there's only 10<sup>83</sup> atoms in the whole universe.</p>

CC BY-SA 4.0
2021-06-26T15:10:13.763Z
Imagine this: for every atom in human ($10^{27}$), there exist $10^{27}$ atoms, but for every such atom, there exist $10^{27}$ atoms, but for every such atom, there exist 100 atoms. Huge, right?
User123
CC BY-SA 4.0
2021-06-26T16:14:41.583Z
I think you really must not understand exponential notation. 10^83 is 10^27 * 100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 (if I counted right), which is a rather large number :-)
jamesqf
CC BY-SA 4.0
2021-06-26T19:08:31.870Z
"**only** 10^83"... Surely that a least deserves an upper-case "Only"? This is the most mindbogglingly huge usage of "only" that one is likely to every encounter in the real universe outside of abstract mathematics, a number so large that calling it "infinity" might be more accurate than "only"
PcMan
CC BY-SA 4.0
2021-06-26T20:23:00.370Z
I'm curious: what number of atoms would have sounded about right?
Robert
CC BY-SA 4.0
2021-06-26T20:56:38.953Z
Get yourself one million small ball bearings. They can be arranged in a square of 1000 by 1000 – that doesn't sound impossible, does it? – do that. Now imagine doing that a thousand times. And then a thousand times more.
Andrew Morton
CC BY-SA 4.0
2021-06-26T23:43:12.767Z
@Andrew Morton: Quite easy - just arrange 1000 layers in a cube.  (OK, they're probably going to arrange themselves in a cubic close packed lattice, unless you somehow glue them in place.)
jamesqf
CC BY-SA 4.0
2021-06-27T13:14:11.793Z
I'm just going to tell you something. $10^{n}$ is 10 times as big as $10^{n - 1}$. And if you consider that a human is made out of $10^{27}$ atoms, then 10 people are made out of $10^{28}$ atoms. 10 billion people are made out of $10^{37}$ atoms - and this number isn't even close to $10^{83}$! In the entire universe, $10^{83}$ / $10^{27}$ = $10^{56}$ people could fit. Well, maybe a little bit less because some people are overweight  <BR>
So, what am I trying to say? I am trying to say that $10^{83}$ is not "only". It's a huge, huge number.
LeopardL GD
CC BY-SA 4.0
2021-06-27T18:54:11.787Z
One more thing to consider: A human-sized volume of the universe contains, on average, *much much* less than a single atom of ordinary matter.  (https://en.wikipedia.org/wiki/Friedmann_equations#:~:text=To%20date%2C%20the%20critical%20density,0.25%20atoms%20per%20cubic%20metre.)  That means that human bodies are inconceivably more dense than the Universe - alongside being even much more dramatically smaller as well.
Jirka Hanika
CC BY-SA 4.0
2021-06-27T23:47:33.130Z
Orders of magnitude are very helpful in understanding but they can also be very deceiving. The universe is 13.8 billion years old, or $4.35\times10^{17}$ seconds old. Seventeen (or eighteen, rounded up) doesn't sound like much. 13.8 billion years -- that sounds like a lot.
David Hammen
CC BY-SA 4.0
2021-06-28T09:25:34.097Z
See the [Wheat and chessboard problem](https://en.m.wikipedia.org/wiki/Wheat_and_chessboard_problem). You will get an idea of how deceiving numbers can be.
zdf
<universe>
Are there only $10^{83}$ atoms in the universe?
Alexa
# Are there only $10^{83}$ atoms in the universe?

(Asked by: username_0 on 2021-06-26)

I'm a high school junior. I assumed there would be an incredibly huge number of atoms in the universe if not infinite. Recently, I've come across a few articles which claim that scientists believe there are 1083 atoms in the universe. I'm not sure if I should believe in this, to me, this seems like a small number. In average, a human alone has 1027 atoms, so, it's kind of unconvincing to me that there's only 1083 atoms in the whole universe.

**Tags:** universe

> **Comments:**
> **username_1**: Imagine this: for every atom in human ($10^{27}$), there exist $10^{27}$ atoms, but for every such atom, there exist $10^{27}$ atoms, but for every such atom, there exist 100 atoms. Huge, right?  
> **username_2**: I think you really must not understand exponential notation. 10^83 is 10^27 * 100,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000 (if I counted right), which is a rather large number :-)  
> **username_3**: "**only** 10^83"... Surely that a least deserves an upper-case "Only"? This is the most mindbogglingly huge usage of "only" that one is likely to every encounter in the real universe outside of abstract mathematics, a number so large that calling it "infinity" might be more accurate than "only"  
> **username_4**: I'm curious: what number of atoms would have sounded about right?  
> **username_5**: Get yourself one million small ball bearings. They can be arranged in a square of 1000 by 1000 – that doesn't sound impossible, does it? – do that. Now imagine doing that a thousand times. And then a thousand times more.  
> **username_2**: @username_5: Quite easy - just arrange 1000 layers in a cube.  (OK, they're probably going to arrange themselves in a cubic close packed lattice, unless you somehow glue them in place.)  
> **username_6**: I'm just going to tell you something. $10^{n}$ is 10 times as big as $10^{n - 1}$. And if you consider that a human is made out of $10^{27}$ atoms, then 10 people are made out of $10^{28}$ atoms. 10 billion people are made out of $10^{37}$ atoms - and this number isn't even close to $10^{83}$! In the entire universe, $10^{83}$ / $10^{27}$ = $10^{56}$ people could fit. Well, maybe a little bit less because some people are overweight  <BR> So, what am I trying to say? I am trying to say that $10^{83}$ is not "only". It's a huge, huge number.  
> **username_7**: One more thing to consider: A human-sized volume of the universe contains, on average, *much much* less than a single atom of ordinary matter.  (https://en.wikipedia.org/wiki/Friedmann_equations#:~:text=To%20date%2C%20the%20critical%20density,0.25%20atoms%20per%20cubic%20metre.)  That means that human bodies are inconceivably more dense than the Universe - alongside being even much more dramatically smaller as well.  
> **username_8**: Orders of magnitude are very helpful in understanding but they can also be very deceiving. The universe is 13.8 billion years old, or $4.35\times10^{17}$ seconds old. Seventeen (or eighteen, rounded up) doesn't sound like much. 13.8 billion years -- that sounds like a lot.  
> **username_9**: See the [Wheat and chessboard problem](https://en.m.wikipedia.org/wiki/Wheat_and_chessboard_problem). You will get an idea of how deceiving numbers can be.  

---

## 5 answers

### Answer by username_14 on 2021-06-26. Score: 32 | Accepted answer

This is a reasonable estimate for the number of atoms in the observable universe.

It might seem like a small number, compared with the number of atoms in a human only as a result of our brain's inability to have an intuition about very large numbers and exponential scales.

There is a very very big difference between $10^{27}$ and $10^{83}$. How big is the difference? Well $10^{83}- 10^{27}= 9.9999999999999999999999999999999999999999999999999999999\times10^{82}$

A human is only a very small part of the universe.

Note two things, firstly this is for the observable universe, the Universe may be isotropic, open and unbounded and if so the total number of atoms in the universe is infinite. Secondly most of the estimates of the number of atoms in the universe that I've seen put the value at about $10^{80}$

> **Comments:**
> **username_1**: @username_0 If you don't know what is observable universe: we can't see beyond its boundary because the light hasn't reached us yet. Therefore we don't know what's beyond the observable, visible universe. As username_14 said, the whole universe could be open, infinite.  
> **username_15**: I think saying that 10^83-10^27 is more than 10^82 would be more helpful than spelling the number out with all of its nines (I didn't count them).  
> **username_14**: @username_15 it is a rhetorical florish.  It is, of course, well beyond the accuracy in the value 10^83, but it is intended as an illustration of just what a small fraction of 10^83 is 10^27  
> **username_3**: @username_15 actually saying that "10^83-10^27 is more than 10^82" is about as useful as saying "there is more than one grain of sand on Earth". True, but utterly useless in estimating how much sand is on Earth.  
> **username_16**: Yet another way to see how much larger 10^83 is than 10^27 is to divide both numbers by 10^27: 10^27/10^83 is 0.000000000000000000000000000000000000000000000000000000000000000001, which is pretty tiny :)  
> **username_17**: @username_16 HA! You just estimated how much percentage a single human is part of the universe :)  
> **username_18**: @username_15: 10^83 - 10^27 is not just "more than 10^82", it's basically still 10^83. It's like the old joke : "What's the difference between a dollar and a ruble? ................. a dollar."  
> **username_11**: The way you write it out does not make it clear that the difference is that big. You just write the same number again!  
> **username_11**: 1000 000 000 000 000-1=999 999 999 999 999. This doesnt tell me how big or small both numbers are. Its an absolute difference while the ratio gives the relative diffference between the two. Of course both give  useful information.  

---

### Answer by username_10 on 2021-06-27. Score: 15

I similarly thought that the difference in mass between a proton and an electron was minuscule. I think the proton is like 3x10^(-27) kg and electron is 3x10^(-31) kg.

But the way you think about it is that the proton is 10,000 times bigger (10x^-27/10^(-31) = 10^4 = 10,000).

So in your case, the universe has 10^56 times more atoms than a human. So if my networth is 1 cent, Apple's networth is 1 trillion dollars which is 10^14 times more than mine.

I guess that's a poor analogy but the idea is that if something is 10^56 times more than something else, there is a inconceivably big difference between the amounts.

> **Comments:**
> **username_7**: The proton/electron mass ratio is more like 1836.  But your point stands.  10^56 is an inconceivable number.  

---

### Answer by username_1 on 2021-06-27. Score: 3

Yes, the number is reasonable for our observable universe. The problem with imagining the decimal notations of numbers is that every added digit can represent approximately 10 times numbers more.

---

Most of the other answers just say that this number is huge and give representations with abstract numbers. But I would like to give some physical meaning. If you don't understand the following, just skip to the end.

---

The neutron is not a fundamental particle. It is made of the three quarks, which have their own bounding sphere. It's radius is $r\_n=8.5\cdot 10^{-14}m$. Its volume is equal to
$$V\_n=4\pi r^3/3=2.57\cdot10^{-45}m^3$$
If we just add the volume of such neutrons, we get
$$V'=10^{83}\cdot 2.57\cdot10^{-45}m^3=2.57\cdot10^{38}m^3$$
But this is only valid if we could "melt" the neutrons, which we can't. Therefore, we need to use the densest sphere packing possible:
$$V=V'/0.74048=3.47\cdot10^{38}m^3$$
Using that volume and the formula for volume of sphere, we can find a radius for such neutron packing
$$R=4.36\cdot10^{12}m=29.1 AU$$
For comparison, $10^{27}$ neutrons densely packed give a radius of about $0.85\mu m$.

---

**Physical meaning:** The radius we got is the approximate distance between the Sun and the Neptune. The neutron is very small. And imagine bunch of them stacked into the sphere with the radius of the Neptune's orbit.

**Wow.**

> **Comments:**
> **username_11**: While its true that the number of volumes you added have the large volume you have calculated of is not true that the neutrons can be stacked that way. Al particles are point like and all particles can be stacked in a planck size volume. So this doesnt make the distinction very clear. The distance to Saturn aint that big.  
> **username_1**: @username_11 Neutrons are composed from the fundamental particle,  and between them there is a measurable distance. Therefore, we can approximate the neutron by the bounding sphere. And we are here looking just the volume for the approximation. I might also know where does the downvote come from and why, but I am not mad at you :)  
> **username_11**: It came from me. Because of the reason I gave. Your answer gived a good feeling for the amount of small volumes you can put in the big volume but I think it would have been better to put it the other way round. So to start at the volume of the universe and look how big the volume would be if you divide it by 10exp83 Like that you have an idea how much volume each particle has and at the same time how big the number 10exp83 is. The number 10exp27 isnt mentioned at all. The number of neutrons is not 10exp83. The total of quarks and leptons and photons is the total number.  
> **username_1**: @username_11 First, we don't know the volume of our universe. Second, I wanted to go away from 10^27 because why would I include it? The other answers tell enough about it and OP just used it as a reference for his misunderstanding. Maybe I want clear enough when I said that I want the physical representation, but I can include it if you want.  
> **username_11**: Im not saying its  a bad answer. But it could have been better. I meant the observable universe. And the number of neutrons is not 10exp83.  
> **username_1**: @username_11 The neutrons are used here just because of their smallness.  
> **username_11**: I know but particles are almost nothing but empty space. You could have used any volume and then comparing it with the volume 10exp83 as large. Thats why I said it would be more compelling to start from the observable universe and divide its volume in 10exp83 pieces. But the start from the small is just as good.  
> **username_1**: @username_11 By the standard model, every fundamental particle is pointlike, could we then say that the universe has zero volume? No, because you are looking bounding sphere.  
> **username_1**: @username_11 Your points are not reasonable at all. The universe is almost nothing but empty space as well.  

---

### Answer by username_12 on 2021-06-27. Score: -2

Compare

```
1 000 000 000 000 000 000 000 000 000 (10^27)
1 00 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 (10^83)

```

For reference, a thousand and a million

```
1 000
1 000 000

```

You probably are aware that a million is quite much more than a thousand but the visual difference between them, if you compare to the first example, is quite small.

> **Comments:**
> **username_1**: It would be more appropriate if this were a comment.  

---

### Answer by username_11 on 2021-06-27. Score: -4

Another way of looking at it. The number with 27 zeros can be laid $10^{56}$ times behind each other. I guess you'll arrive somewhere on Pluto). First guess though and it of course depends on how big you write the one and 27 zeros.If you write 1mm numbers the row of numbers 0 and 1 would even be bigger than the observable universe...(thanks to @username_1)

So 27 and 83 seem pretty close to one another but the exponentials are. absolutely not.

There simply could not have been another number. If it was bigger or smaller(relatively spoken) the universe would not be our universe anymore. Every elementary particle(so not atom, as the question poses), every one of the $10^{83}$, has the optimum amount of space at it's disposal for life to come about.

> **Comments:**
> **username_13**: Comments are not for extended discussion; this conversation has been [moved to chat](https://chat.stackexchange.com/rooms/126924/discussion-on-answer-by-username_11-username_11-are-there-only-1083-atoms-in-the-univ).  

---

