<p>Here is the illustrate of both equation</p>

<p><img src="https://i.sstatic.net/vuRwS.png" alt="Illustration of both equation"></p>

<p>To make them visible at same time, I changed 100 to 1 and set memory strength as 1. They look alike.</p>

CC BY-SA 3.0
2014-10-14T13:46:04.410Z
2014-10-14T13:46:04.410Z
pinxue
<p>The question <em>which of these two descriptions is correct?</em> is perhaps natural in the context of, say, someone studying for an examination. Epistemologists might suggest that a better formulation would be is <em>either</em> of these  correct?</p>

<p>However, as stated here there are clear reasons for preferring the first formulation to the second. I shall first explain why, and then attempt to reconstruct a more useful form for the second approach. </p>

<p>By substituting the value $t=0$, a time value (however the time variable is scaled) at which we would expect retention to be a maximum, we obtain:
$$ R_0 = 1 \\
b_0 = 0
$$
Another peculiarity of the second equation is that if $T=0.4297...$ we have:
$$
b_T = \pm \infty
$$
The latter is shorthand for the fact that as $t$ approaches $T$ from below then $b_t \rightarrow -\infty$, whilst $b$ then flips to $+\infty$ as soon as $t \gt T$ and thereafter decreases.</p>

<p>The factor of $100$ in the numerator of the fraction in equation $2$ suggests this was intended to be adapted to percentage correct, and should be dropped to make the two formulations more easily comparable.</p>

<p>The least changed version of eq. $2$ which makes some kind of sense would be:
$$ R_t = \frac1{1 + a \; ln(1+ \lambda t)}$$</p>

<p>This yields $R_0 = 1$, whilst $R_t$ is now a convex, strictly decreasing function of $t$. Surely both of these features are desiderata for <em>any</em> expression for retention. </p>

<p>Note that now (what we may term) model $1$ ($M1$) is a 1-parameter model, whereas $M2$ has two parameters, which might be preferred for an empirical data-fitting exercise. Both models have a linear approximation for small values of the time variable, namely:</p>

<p>$$ (M1) \; \; \; R_t = 1 -\frac{t}{s} $$</p>

<p>$$(M2)  \; \; \;  R_t = 1 - a \lambda t $$</p>

<p>So that we require $ \frac1s = a \lambda$ for compatibility. This suggests that a more useful form of $M2$, retaining the <em>strength</em> factor from the first model, is:
$$ R_t = \frac1{1 + \frac1{\lambda s} ln(1 + \lambda t)}$$</p>

<p>Where now $\lambda$ is clearly seen to be a <em>scaling factor</em> which must be applied to both variables, time and strength. This is perhaps a slight conceptual clarification, since the intervening variable <em>strength</em> is shown to be <em>dimensionally equivalent to time</em>. A strong memory is one that lasts for years, whereas, with the possible exception of the type of mnemonist studied by Professor Luria, few of Ebbinghaus' experimental subjects would retain any memory of his deliberately unmemorable nonsense syllables after the passage of more than a few weeks.</p>

<p>This observation also has a bearing on experimental methodology. Some nonsense syllables might be more memorable for a given subject - for example if, by chance, the syllable happened to match the subject's own initials etc. Such effects should, however, merely contribute a small addition of random noise to the experimental data.</p>

CC BY-SA 3.0
2013-12-25T02:08:34.487Z
2016-07-25T12:09:29.510Z
2016-07-25T12:09:29.510Z
David Holden
<p>First off, I've come across two different forgetting curve equations.  </p>

<p>$$R = e^{-\large \frac{t}{s}}$$ where $R$ is retention, $t$ is time and $s$ is strength can be found on <a href="http://en.wikipedia.org/wiki/Forgetting_curve">Wikipedia</a>. And $$b = \frac{100k}{c\log(t) +k}$$ where $b$ is retention, $t$ is time, $k = 1.48$ and $c = 1.25$, can be found in <a href="http://psychclassics.yorku.ca/Ebbinghaus/memory7.htm">Ebbinghaus's study chapter 7</a>.  I've also seen it <a href="http://www.ideationizing.com/2009/06/brief-synopsis-of-long-history-of.html">here</a> and <a href="http://books.google.com/books?id=ePBfcz7dnuwC&amp;pg=PA197&amp;lpg=PA197&amp;dq=1.84%20and%201.25,%20ebbinghaus&amp;source=bl&amp;ots=usfbEh0puj&amp;sig=4EkyYh6jcrXNkACoruxcS5azjwo&amp;hl=en&amp;sa=X&amp;ei=seu5UqbnCojlsASQ-YKwCw&amp;ved=0CFEQ6AEwBA#v=onepage&amp;q=1.84%20and%201.25,%20ebbinghaus&amp;f=false">here also.</a>  </p>

<p>My first question is which forgetting curve is correct?  And if both or the latter is, where did the constants $k$ or $c$ come from?  What do they represent?    </p>

CC BY-SA 3.0
2015-04-15T07:27:10.557Z
clog(t) should be log(t)^c
steveyang
<memory><cognitive-modeling><mathematical-psychology>
Which equation is Ebbinghaus's forgetting curve and what do the constants represent?
Squirrl
# Which equation is Ebbinghaus's forgetting curve and what do the constants represent?

(Asked by: username_0 on 2013-12-24)

First off, I've come across two different forgetting curve equations.

$$R = e^{-\large \frac{t}{s}}$$ where $R$ is retention, $t$ is time and $s$ is strength can be found on [Wikipedia](http://en.wikipedia.org/wiki/Forgetting_curve). And $$b = \frac{100k}{c\log(t) +k}$$ where $b$ is retention, $t$ is time, $k = 1.48$ and $c = 1.25$, can be found in [Ebbinghaus's study chapter 7](http://psychclassics.yorku.ca/Ebbinghaus/memory7.htm). I've also seen it [here](http://www.ideationizing.com/2009/06/brief-synopsis-of-long-history-of.html) and [here also.](http://books.google.com/books?id=ePBfcz7dnuwC&pg=PA197&lpg=PA197&dq=1.84%20and%201.25,%20ebbinghaus&source=bl&ots=usfbEh0puj&sig=4EkyYh6jcrXNkACoruxcS5azjwo&hl=en&sa=X&ei=seu5UqbnCojlsASQ-YKwCw&ved=0CFEQ6AEwBA#v=onepage&q=1.84%20and%201.25,%20ebbinghaus&f=false)

My first question is which forgetting curve is correct? And if both or the latter is, where did the constants $k$ or $c$ come from? What do they represent?

**Tags:** memory, cognitive-modeling, mathematical-psychology

> **Comments:**
> **username_1**: clog(t) should be log(t)^c  

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## 2 answers

### Answer by username_3 on 2013-12-25. Score: 10 | Accepted answer

The question *which of these two descriptions is correct?* is perhaps natural in the context of, say, someone studying for an examination. Epistemologists might suggest that a better formulation would be is *either* of these correct?

However, as stated here there are clear reasons for preferring the first formulation to the second. I shall first explain why, and then attempt to reconstruct a more useful form for the second approach.

By substituting the value $t=0$, a time value (however the time variable is scaled) at which we would expect retention to be a maximum, we obtain:
$$ R\_0 = 1 \\
b\_0 = 0
$$
Another peculiarity of the second equation is that if $T=0.4297...$ we have:
$$
b\_T = \pm \infty
$$
The latter is shorthand for the fact that as $t$ approaches $T$ from below then $b\_t \rightarrow -\infty$, whilst $b$ then flips to $+\infty$ as soon as $t \gt T$ and thereafter decreases.

The factor of $100$ in the numerator of the fraction in equation $2$ suggests this was intended to be adapted to percentage correct, and should be dropped to make the two formulations more easily comparable.

The least changed version of eq. $2$ which makes some kind of sense would be:
$$ R\_t = \frac1{1 + a \; ln(1+ \lambda t)}$$

This yields $R\_0 = 1$, whilst $R\_t$ is now a convex, strictly decreasing function of $t$. Surely both of these features are desiderata for *any* expression for retention.

Note that now (what we may term) model $1$ ($M1$) is a 1-parameter model, whereas $M2$ has two parameters, which might be preferred for an empirical data-fitting exercise. Both models have a linear approximation for small values of the time variable, namely:

$$ (M1) \; \; \; R\_t = 1 -\frac{t}{s} $$

$$(M2) \; \; \; R\_t = 1 - a \lambda t $$

So that we require $ \frac1s = a \lambda$ for compatibility. This suggests that a more useful form of $M2$, retaining the *strength* factor from the first model, is:
$$ R\_t = \frac1{1 + \frac1{\lambda s} ln(1 + \lambda t)}$$

Where now $\lambda$ is clearly seen to be a *scaling factor* which must be applied to both variables, time and strength. This is perhaps a slight conceptual clarification, since the intervening variable *strength* is shown to be *dimensionally equivalent to time*. A strong memory is one that lasts for years, whereas, with the possible exception of the type of mnemonist studied by Professor Luria, few of Ebbinghaus' experimental subjects would retain any memory of his deliberately unmemorable nonsense syllables after the passage of more than a few weeks.

This observation also has a bearing on experimental methodology. Some nonsense syllables might be more memorable for a given subject - for example if, by chance, the syllable happened to match the subject's own initials etc. Such effects should, however, merely contribute a small addition of random noise to the experimental data.


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### Answer by username_2 on 2014-10-14. Score: 2

Here is the illustrate of both equation

![Illustration of both equation](https://i.sstatic.net/vuRwS.png)

To make them visible at same time, I changed 100 to 1 and set memory strength as 1. They look alike.


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