<p>Use bulk densities of water and the ground in question.</p>
<p>Density, ρ, is mass divided by volume.</p>
<p><span class="math-container">$\ \ \rho \ = \ \frac{m}{V}$</span></p>
<p>Rearrange the equation to get mass, density times volume.</p>
<p>Depending on how fancy you want get, by making allowances for temperature and impurities, the density of water of 1 g/cm<sup>3</sup> (1 t/m<sup>3</sup> or 1000 kg/m<sup>3</sup>).</p>
<p>You next need to know the basic geology of the region in question and use appropriate values of <a href="https://www.structx.com/Soil_Properties_002.html" rel="nofollow noreferrer">density</a>.</p>

CC BY-SA 4.0
2023-02-08T11:44:32.200Z
2023-02-08T11:44:32.200Z
Fred
<p>I have a dataset from ERA LAND with a Volumetric Soil Water (m3 m<sup>-3</sup>), How I could convert to a Gravimetric Moisture content (kg kg<sup>-1</sup>)?</p>

<soil-moisture>
Volumetric Soil Water to Gravimetric Moisture
SergioMontana
# Volumetric Soil Water to Gravimetric Moisture

(Asked by: username_0 on 2023-02-08)

I have a dataset from ERA LAND with a Volumetric Soil Water (m3 m-3), How I could convert to a Gravimetric Moisture content (kg kg-1)?

**Tags:** soil-moisture


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## 1 answers

### Answer by username_1 on 2023-02-08. Score: 1

Use bulk densities of water and the ground in question.

Density, ρ, is mass divided by volume.

$\ \ \rho \ = \ \frac{m}{V}$

Rearrange the equation to get mass, density times volume.

Depending on how fancy you want get, by making allowances for temperature and impurities, the density of water of 1 g/cm3 (1 t/m3 or 1000 kg/m3).

You next need to know the basic geology of the region in question and use appropriate values of [density](https://www.structx.com/Soil_Properties_002.html).


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