<p>There are two fundamental gas laws that need to be understood:</p>

<p>Boyle's Law which states     ${P_1.V_1 = P_2.V_2}$ </p>

<p>From this formula if volume increases pressure decreases and vice versa</p>

<p>The second law is Charles's Law which states ${V_1/V_2 = T_1/T_2}$   or    ${V_1/T_1 = V_2/T_2}$</p>

<p>This law states that if the temperature increases there must be a corresponding increase in volume of the gas and vice versa. Another way of looking at it is if the volume drops so must the temperature and vice versa.</p>

<p>The ideal gas law that you mention in your question can be also be written as:</p>

<p>${PV = mRT}$</p>

<p>Where:</p>

<ul>
<li>P is pressure,</li>
<li>V is volume</li>
<li>m is mass</li>
<li>R is the universal gas constant</li>
<li>T is temperature</li>
</ul>

<p>Now, density, ${ρ = m/V}$</p>

<p>Which leads to the equation you used:</p>

<p>${P = ρRT}$</p>

<p>One of the primary ways the atmosphere changes is via changes in temperature. The atmosphere on the side of the Earth facing the Sun warms up, while the atmosphere of the other side of the Earth cools.</p>

<p>According to Charles's Law, for the side facing the Sun, the increase in temperature will cause the volume to increase. An increase in volume will reduce the density, because mass doesn't change. With an increase in temperature and a decrease in density the pressure will remain unchanged.</p>

CC BY-SA 3.0
2015-02-24T13:47:31.340Z
@Shan the pressure is effectively dictated by the force of gravity of the Earth
f.thorpe
CC BY-SA 3.0
2015-02-24T16:17:04.953Z
@farrenthrope True! I figured that out when I looked at the F = Gmm/r^2 formula and how it related to the distance away from the surface of the Earth, etc.
Shan
CC BY-SA 3.0
2015-02-24T12:49:28.993Z
2015-02-24T13:53:03.457Z
2015-02-24T13:53:03.457Z
Fred
<p>I am slightly confused as to how the following statement is true:</p>

<p>As the density of the Earth’s atmosphere decreases, the average atmospheric surface pressure remains the same</p>

<p>As dictated by the equation $P = \rho R_mT$, where P is pressure ρ is density, T is temperature, and Rm is the univeral gas constant divided by the molar mass, there should be a relationship between density and pressure. What is incorrect about my understanding of fundamental concepts?</p>

CC BY-SA 3.0
2015-02-24T04:58:31.693Z
Where are you reading that statement from?
casey
CC BY-SA 3.0
2015-02-24T16:16:00.033Z
@casey this statement in given as a true/false question on a practice test. The answer is true but I was not sure earlier as to why that was the case.
Shan
<barometric-pressure>
Relationship between atmospheric density and atmospheric pressure?
Shan
# Relationship between atmospheric density and atmospheric pressure?

(Asked by: username_0 on 2015-02-24)

I am slightly confused as to how the following statement is true:

As the density of the Earth’s atmosphere decreases, the average atmospheric surface pressure remains the same

As dictated by the equation $P = \rho R\_mT$, where P is pressure ρ is density, T is temperature, and Rm is the univeral gas constant divided by the molar mass, there should be a relationship between density and pressure. What is incorrect about my understanding of fundamental concepts?

**Tags:** barometric-pressure

> **Comments:**
> **username_1**: Where are you reading that statement from?  
> **username_0**: @username_1 this statement in given as a true/false question on a practice test. The answer is true but I was not sure earlier as to why that was the case.  

---

## 1 answers

### Answer by username_2 on 2015-02-24. Score: 5 | Accepted answer

There are two fundamental gas laws that need to be understood:

Boyle's Law which states ${P\_1.V\_1 = P\_2.V\_2}$

From this formula if volume increases pressure decreases and vice versa

The second law is Charles's Law which states ${V\_1/V\_2 = T\_1/T\_2}$ or ${V\_1/T\_1 = V\_2/T\_2}$

This law states that if the temperature increases there must be a corresponding increase in volume of the gas and vice versa. Another way of looking at it is if the volume drops so must the temperature and vice versa.

The ideal gas law that you mention in your question can be also be written as:

${PV = mRT}$

Where:

* P is pressure,
* V is volume
* m is mass
* R is the universal gas constant
* T is temperature

Now, density, ${ρ = m/V}$

Which leads to the equation you used:

${P = ρRT}$

One of the primary ways the atmosphere changes is via changes in temperature. The atmosphere on the side of the Earth facing the Sun warms up, while the atmosphere of the other side of the Earth cools.

According to Charles's Law, for the side facing the Sun, the increase in temperature will cause the volume to increase. An increase in volume will reduce the density, because mass doesn't change. With an increase in temperature and a decrease in density the pressure will remain unchanged.

> **Comments:**
> **username_3**: @username_0 the pressure is effectively dictated by the force of gravity of the Earth  
> **username_0**: @farrenthrope True! I figured that out when I looked at the F = Gmm/r^2 formula and how it related to the distance away from the surface of the Earth, etc.  

---

