<p>One thing that I would add is a discussion of a physical parameter that is a simple measure of whether a wave is going to topple or not. The Froude number is defined as the ratio of the maximum absolute fluid velocity, $U$, and the wavespeed, $c$:</p>

<p>$F = U/c$</p>

<p>Because of the mechanism explained by IRO-bot,</p>

<blockquote>
  <p>In shallow water, the water particles near the crest move forward faster than those below them. Similarly, the particles near the trough move backward faster than those above them. </p>
</blockquote>

<p>the highest velocities are encountered at the top of the wave and therefore a good rule of thumb is, if the surface fluid velocity aproaches the wave speed, i.e $F \to 1$, then the wave will topple over.</p>

<p>The question is what values of $F$ give rise to that perfect tube feeling that surfers yearn for and so perfectly exemplified by your picture.</p>

<p>Of course, since $F &gt; 1$ implies that the wave amplitude is large, linear theory is no longer helpful. We may have to wait until we can get some definite answers from DNS 3D simulations of oceanic scale wave breaking phenomena.</p>

CC BY-SA 3.0
2014-11-15T06:04:17.477Z
2014-11-15T06:04:17.477Z
Isopycnal Oscillation
<p>It is called refraction.
Unlike most other waves, which refract at a change of media, water waves refract at a change of depth.</p>
<p>As it gets shallower than 1/2 the wavelength,  waves begin to refract.  1/2 wavelength is the measure if the wave base. When the wave base touches the floor , the wave begins to refract, reducing its wavelength and speed, but increasing its amplitude.  If it continues to get increasingly shallower, refraction will peak and the wave will break , releasing its energy,  when the ratio between wavelength/amplitude  has reached 7:1</p>

CC BY-SA 4.0
2023-08-04T15:34:00.067Z
2023-08-04T15:34:00.067Z
Rafael Garcia
<p>The physical process you describe is known as <a href="http://en.wikipedia.org/wiki/Wave_shoaling">wave shoaling</a>. </p>

<p>At the basic level, waves propagating into shallow water become shorter and higher, and consequently, steeper. In shallow water, the water particles near the crest move <strong>forward</strong> faster than those below them. Similarly, the particles near the trough move <strong>backward</strong> faster than those above them. This causes strong shearing of the near-surface body of water, eventually forming a plunging breaker, or a surf wave. For small-slope (linear) and inviscid (no friction) waves, the above is a consequence of the bottom boundary condition for the water velocity to be zero at the sea floor. </p>

<p>There are two fundamental and related properties of water waves that contribute to shoaling. One is the wave frequency $\omega$ remaining constant as the depth $d$ decreases. Think of this as the conservation of wave crests at any fixed point. However, the wavenumber $k$ (wavelength $\lambda$) must increase (decrease) with decreasing depth, as per the <a href="http://en.wikipedia.org/wiki/Dispersion_%28water_waves%29">dispersion relationship</a> of water waves (neglecting the effects of viscosity):</p>

<p>$$\omega^{2} = gk\tanh{(kd)}$$</p>

<p>where $g$ is gravitational acceleration. In shallow water, the dispersion relationship reduces to:</p>

<p>$$\omega = \sqrt{gd}k $$</p>

<p>and phase speed $C_p$ and group velocity $C_g$ are both proportional to the square root of the water depth:</p>

<p>$$ C_p = \dfrac{\omega}{k} = \sqrt{gd} $$</p>

<p>$$ C_g = \dfrac{\partial\omega}{\partial k} = \sqrt{gd} $$</p>

<p>Individual wave crests propagate with phase speed $C_p$. Wave groups and wave energy propagate with group velocity $C_g$. Thus, waves entering shallow water become <strong>shorter</strong> and <strong>slower</strong>. The second important property leading to shoaling is the conservation of wave energy flux, which is proportional to the group velocity and wave energy: </p>

<p>$$\dfrac{\partial(C_{g}E)}{\partial x}=0$$</p>

<p>Because the group velocity decreases, the wave energy (read: height) must increase (locally). This causes the waves to grow in height as they enter shallow water. As pointed out by @IsopycnalOscillation in a comment above, the separation of water particles from the wave crests happen because the individual orbital velocities at the top of the crest exceed by far the phase speed of the wave.</p>

<p>Although bottom friction is significant and non-negligible in shallow water, it does not cause shoaling. Mathematically, wave shoaling can occur for completely inviscid and small-slope (linear) waves that propagate into water of decreasing depth.</p>

CC BY-SA 4.0
2024-05-08T15:21:44.450Z
1) Isn't the principal motion in a water wave up and down, rather than forward and backward? Doesn't this suggest that there is something else at work here... something other than crest particles moving forward relative to trough particles which are "held back" by the no-slip condition at the sea floor?
2) Would waves break in shallow water if the sea floor were infinitely slippery (in other words, NO no-slip condition - the water can slip along the sea floor without any resistance). What would waves look like in this situation as they approach the shore?
VeryStableGenius
CC BY-SA 3.0
2014-04-23T01:16:11.987Z
+1 for mention of dispersion.
Neo
CC BY-SA 3.0
2014-04-23T01:15:00.723Z
2014-04-24T15:35:00.220Z
2014-04-24T15:35:00.220Z
milancurcic
<p>We all know that as waves approach the shallow shores, the waves begin to form a characteristic shape.  The upper portion of these breaking waves appears to curl forward and downwards over the bottom segment of the wave, before breaking into "white wash". The image below illustrates what this characteristic shape looks like:</p>

<p><img src="https://i.sstatic.net/N130G.gif" alt="enter image description here"></p>

<p>So why do waves form this characteristic breaking shape as they approach the shallow shores?</p>

CC BY-SA 3.0
2014-04-22T11:20:59.073Z
At a very basic level, the bottom of the wave gets slowed by bed friction, causing the steepness of the wave's slope to increase, and there's a limit to how steep a wave can be before it falls over. But I'm sure somebody will give a much fuller answer.
Semidiurnal Simon
CC BY-SA 3.0
2014-04-23T01:16:41.970Z
@Geodude Though bed friction is significant in shallow water, it is not quite what causes the waves to shoal. See my answer below.
milancurcic
CC BY-SA 3.0
2014-04-23T03:23:40.163Z
@SimonW The effect of friction is mostly confined to the boundary layer, the viscous effects will diffuse into the top layer altering its vorticity, but that contribution is relatively small. Check IRO-bot.
Isopycnal Oscillation
CC BY-SA 3.0
2014-04-23T03:51:39.027Z
By the way, the reason a wave breaks is because the maximum horizontal fluid velocity due to the wave, U, that is the speed that an orbiting particle possesses as the wave advances, is greater than the wavespeed, c. So if the Froude number = U/c > 1 the orbital velocity of a fluid particle exceeds the wave speed and the wave topples over.
Isopycnal Oscillation
CC BY-SA 3.0
2014-04-23T05:19:16.463Z
I stand corrected - thank you :-) In particular, I had never made the connection to Froude number, although it seems obvious now that you mention it.
Semidiurnal Simon
CC BY-SA 3.0
2014-04-23T05:21:45.893Z
@IsopycnalOscillation, thanks for your contribution.  Hopefully when we eventually get latex perhaps you could turn it into an answer?
Kenshin
CC BY-SA 3.0
2014-04-23T05:56:23.307Z
@Geodude Sure, np.
Isopycnal Oscillation
<ocean><waves>
What causes waves to form the characteristic "breaking" shape as they approach the shoreline?
Kenshin
# What causes waves to form the characteristic "breaking" shape as they approach the shoreline?

(Asked by: username_0 on 2014-04-22)

We all know that as waves approach the shallow shores, the waves begin to form a characteristic shape. The upper portion of these breaking waves appears to curl forward and downwards over the bottom segment of the wave, before breaking into "white wash". The image below illustrates what this characteristic shape looks like:

![enter image description here](https://i.sstatic.net/N130G.gif)

So why do waves form this characteristic breaking shape as they approach the shallow shores?

**Tags:** ocean, waves

> **Comments:**
> **username_1**: At a very basic level, the bottom of the wave gets slowed by bed friction, causing the steepness of the wave's slope to increase, and there's a limit to how steep a wave can be before it falls over. But I'm sure somebody will give a much fuller answer.  
> **username_2**: @Geodude Though bed friction is significant in shallow water, it is not quite what causes the waves to shoal. See my answer below.  
> **username_3**: @SimonW The effect of friction is mostly confined to the boundary layer, the viscous effects will diffuse into the top layer altering its vorticity, but that contribution is relatively small. Check IRO-bot.  
> **username_3**: By the way, the reason a wave breaks is because the maximum horizontal fluid velocity due to the wave, U, that is the speed that an orbiting particle possesses as the wave advances, is greater than the wavespeed, c. So if the Froude number = U/c > 1 the orbital velocity of a fluid particle exceeds the wave speed and the wave topples over.  
> **username_1**: I stand corrected - thank you :-) In particular, I had never made the connection to Froude number, although it seems obvious now that you mention it.  
> **username_0**: @username_3, thanks for your contribution.  Hopefully when we eventually get latex perhaps you could turn it into an answer?  
> **username_3**: @Geodude Sure, np.  

---

## 3 answers

### Answer by username_2 on 2014-04-23. Score: 19 | Accepted answer

The physical process you describe is known as [wave shoaling](http://en.wikipedia.org/wiki/Wave_shoaling).

At the basic level, waves propagating into shallow water become shorter and higher, and consequently, steeper. In shallow water, the water particles near the crest move **forward** faster than those below them. Similarly, the particles near the trough move **backward** faster than those above them. This causes strong shearing of the near-surface body of water, eventually forming a plunging breaker, or a surf wave. For small-slope (linear) and inviscid (no friction) waves, the above is a consequence of the bottom boundary condition for the water velocity to be zero at the sea floor.

There are two fundamental and related properties of water waves that contribute to shoaling. One is the wave frequency $\omega$ remaining constant as the depth $d$ decreases. Think of this as the conservation of wave crests at any fixed point. However, the wavenumber $k$ (wavelength $\lambda$) must increase (decrease) with decreasing depth, as per the [dispersion relationship](http://en.wikipedia.org/wiki/Dispersion_%28water_waves%29) of water waves (neglecting the effects of viscosity):

$$\omega^{2} = gk\tanh{(kd)}$$

where $g$ is gravitational acceleration. In shallow water, the dispersion relationship reduces to:

$$\omega = \sqrt{gd}k $$

and phase speed $C\_p$ and group velocity $C\_g$ are both proportional to the square root of the water depth:

$$ C\_p = \dfrac{\omega}{k} = \sqrt{gd} $$

$$ C\_g = \dfrac{\partial\omega}{\partial k} = \sqrt{gd} $$

Individual wave crests propagate with phase speed $C\_p$. Wave groups and wave energy propagate with group velocity $C\_g$. Thus, waves entering shallow water become **shorter** and **slower**. The second important property leading to shoaling is the conservation of wave energy flux, which is proportional to the group velocity and wave energy:

$$\dfrac{\partial(C\_{g}E)}{\partial x}=0$$

Because the group velocity decreases, the wave energy (read: height) must increase (locally). This causes the waves to grow in height as they enter shallow water. As pointed out by @username_3 in a comment above, the separation of water particles from the wave crests happen because the individual orbital velocities at the top of the crest exceed by far the phase speed of the wave.

Although bottom friction is significant and non-negligible in shallow water, it does not cause shoaling. Mathematically, wave shoaling can occur for completely inviscid and small-slope (linear) waves that propagate into water of decreasing depth.

> **Comments:**
> **username_6**: +1 for mention of dispersion.  
> **username_5**: 1) Isn't the principal motion in a water wave up and down, rather than forward and backward? Doesn't this suggest that there is something else at work here... something other than crest particles moving forward relative to trough particles which are "held back" by the no-slip condition at the sea floor? 2) Would waves break in shallow water if the sea floor were infinitely slippery (in other words, NO no-slip condition - the water can slip along the sea floor without any resistance). What would waves look like in this situation as they approach the shore?  

---

### Answer by username_3 on 2014-11-15. Score: 8

One thing that I would add is a discussion of a physical parameter that is a simple measure of whether a wave is going to topple or not. The Froude number is defined as the ratio of the maximum absolute fluid velocity, $U$, and the wavespeed, $c$:

$F = U/c$

Because of the mechanism explained by IRO-bot,

> In shallow water, the water particles near the crest move forward faster than those below them. Similarly, the particles near the trough move backward faster than those above them.

the highest velocities are encountered at the top of the wave and therefore a good rule of thumb is, if the surface fluid velocity aproaches the wave speed, i.e $F \to 1$, then the wave will topple over.

The question is what values of $F$ give rise to that perfect tube feeling that surfers yearn for and so perfectly exemplified by your picture.

Of course, since $F > 1$ implies that the wave amplitude is large, linear theory is no longer helpful. We may have to wait until we can get some definite answers from DNS 3D simulations of oceanic scale wave breaking phenomena.


---

### Answer by username_4 on 2023-08-04. Score: 1

It is called refraction.
Unlike most other waves, which refract at a change of media, water waves refract at a change of depth.

As it gets shallower than 1/2 the wavelength, waves begin to refract. 1/2 wavelength is the measure if the wave base. When the wave base touches the floor , the wave begins to refract, reducing its wavelength and speed, but increasing its amplitude. If it continues to get increasingly shallower, refraction will peak and the wave will break , releasing its energy, when the ratio between wavelength/amplitude has reached 7:1


---

