a man is 30 years older than his son. in two years, his age will be twice the age of his son. the present age of the son is Pick one:
A) 14 years
B) 28 years
C) 20 years
D) 22 years
E) none
<gadget id="calculator">2 * 2</gadget>
<output>4</output>

<gadget id="calculator">4 - 2</gadget>
<output>2</output>

<gadget id="calculator">30 - 2</gadget>
<output>28</output>

<gadget id="calculator">2 - 1</gadget>
<output>1</output>

<gadget id="calculator">28 / 1</gadget>
<output>28</output>

<result>B</result>
a man is 30 years older than his son. in two years, his age will be twice the age of his son. the present age of the son is
divide(subtract(30, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1))
"solution let the son ' s present age be x years . then , man ' s present age = ( x + 30 ) years . then â € ¹ = â € º ( x + 30 ) + 2 = 2 ( x + 2 ) â € ¹ = â € º x + 32 = 2 x + 4 x = 28 . answer b"