a certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. if a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?  Choose the correct choice:
A) 0	B) 1 / 9	C) 2 / 9	D) 1 / 3	E) 1
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">(1/3) ** 3</gadget>
<output>1/27 = around 0.037037</output>

<gadget id="calculator">6 * (1/27)</gadget>
<output>2/9 = around 0.222222</output>

<result>C</result>
a certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. if a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?
multiply(factorial(3), power(divide(1, 3), 3))
"probability = ( favorable cases ) / ( total number of cases ) total number of ways in which a person can ride car = 3 * 3 * 3 = 27 ( in first ride he has 3 options to sit , in second right again he has 3 seats available to sit and so on ) number of favorable cases , i . e . , when he rides on different cars ; he can choose seat car in 3 ways in his 1 st ride . he can choose seat car in 2 ways in his 2 nd ride . he can choose seat car in 1 ways in his 3 rd ride . so , 3 * 2 * 1 = 6 ways thus , probability of choosing different seats = 6 / 27 = 2 / 9 answer : c"