a certain characteristic in a large population has a distribution that is symmetric about the mean m. if 66 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d? Choose the most appropriate option
A) 16 %  B) 32 %  C) 83 %  D) 84 %  E) 92 %
<gadget id="calculator">100 - 66</gadget>
<output>34</output>

<gadget id="calculator">34 / 2</gadget>
<output>17</output>

<gadget id="calculator">100 - 17</gadget>
<output>83</output>

<result>C</result>
a certain characteristic in a large population has a distribution that is symmetric about the mean m. if 66 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d?
subtract(const_100, divide(subtract(const_100, 66), const_2))
"this is easiest to solve with a bell - curve histogram . m here is equal to µ in the gaussian normal distribution and thus m = 50 % of the total population . so , if 66 % is one st . dev , then on either side of m we have 66 / 2 = 33 % . so , 33 % are to the right and left of m ( = 50 % ) . in other words , our value m + d = 50 + 33 = 83 % goingfrom the mean m , to the right of the distributionin the bell shaped histogram . . this means that 83 % of the values are below m + d . like i said , doing it on a bell - curve histogram is much easier to fullygethow this works , or you could apply gmat percentile jargon / theory to it c"