david works at a science lab that conducts experiments on bacteria. the population of the bacteria multiplies at a constant rate, and his job is to notate the population of a certain group of bacteria each hour. at 1 p. m. on a certain day, he noted that the population was 600 and then he left the lab. he returned in time to take a reading at 4 p. m., by which point the population had grown to 4,800. now he has to fill in the missing data for 2 p. m. and 3 p. m. what was the population at 3 p. m.? Choose the correct choice
A) 2400  B) 3600  C) 3000  D) 2800  E) 2500
<gadget id="calculator">2 * 4</gadget>
<output>8</output>

<gadget id="calculator">8 * 600</gadget>
<output>4_800</output>

<gadget id="calculator">4_800 / 600</gadget>
<output>8</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">8 ** (1/3)</gadget>
<output>2</output>

<gadget id="calculator">2 * 600</gadget>
<output>1_200</output>

<gadget id="calculator">1_200 * 2</gadget>
<output>2_400</output>

<result>A</result>
david works at a science lab that conducts experiments on bacteria. the population of the bacteria multiplies at a constant rate, and his job is to notate the population of a certain group of bacteria each hour. at 1 p. m. on a certain day, he noted that the population was 600 and then he left the lab. he returned in time to take a reading at 4 p. m., by which point the population had grown to 4,800. now he has to fill in the missing data for 2 p. m. and 3 p. m. what was the population at 3 p. m.?
multiply(multiply(power(divide(multiply(multiply(2, 4), 600), 600), const_0_33), 600), power(divide(multiply(multiply(2, 4), 600), 600), const_0_33))
let the rate be x , then population of the bacteria after each hour can be given as 600,600 x , 600 ( x ^ 2 ) , 600 ( x ^ 3 ) now population at 4 pm = 4800 thus we have 600 ( x ^ 3 ) = 4800 = 8 thus x = 2 therefore population at 3 pm = 600 ( 4 ) = 2400 answer : a