in an exam 80 % of the boys and 40 % of the girls passed. the number of girls who passed is 120, which is 2 / 3 rd of the number of boys who failed. what is the total number of students who appeared for the exam?	Select.
A) 1200	B) 380	C) 3800	D) 2180	E) 3180
<gadget id="calculator">100 - 80</gadget>
<output>20</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">(1/5) * (2/3)</gadget>
<output>2/15 = around 0.133333</output>

<gadget id="calculator">120 / (2/15)</gadget>
<output>900</output>

<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">120 / (2/5)</gadget>
<output>300</output>

<gadget id="calculator">900 + 300</gadget>
<output>1_200</output>

<result>A</result>
in an exam 80 % of the boys and 40 % of the girls passed. the number of girls who passed is 120, which is 2 / 3 rd of the number of boys who failed. what is the total number of students who appeared for the exam?
add(divide(120, multiply(divide(subtract(const_100, 80), const_100), divide(2, 3))), divide(120, divide(40, const_100)))
let the number of boys = x , number of girls = y 40 y / 100 = 120 y = 300 120 = 2 / 3 * 20 x / 100 = 2 x / 15 x = 900 total = x + y = 300 + 900 = 1200 answer : a