in one year, the population, of a village increased by 10 % and in the next year, it decreased by 10 %. if at the end of 2 nd year, the population was 7920, what was it in the beginning?	Choose one
A) 8008
B) 8000
C) 8022
D) 8021
E) 8022
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>

<gadget id="calculator">7_920 / (9/10)</gadget>
<output>8_800</output>

<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>

<gadget id="calculator">8_800 / (11/10)</gadget>
<output>8_000</output>

<result>B</result>
in one year, the population, of a village increased by 10 % and in the next year, it decreased by 10 %. if at the end of 2 nd year, the population was 7920, what was it in the beginning?
divide(divide(7920, subtract(const_1, divide(10, const_100))), add(const_1, divide(10, const_100)))
"x * 110 / 100 * 90 / 100 = 7920 x * 0.99 = 7920 x = 7920 / 0.99 = > 8000 answer : b"