rhonda picked 2 pen from the table, if there were 7 pens on the table and 5 belongs to jill, what is the probability that the 2 pen she picked does not belong to jill?.	Choose the correct option.
A) 5 / 42 B) 2 / 42 C) 7 / 42 D) 2 / 7 E) 5 / 7
<gadget id="calculator">7 - 5</gadget>
<output>2</output>

<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>

<gadget id="calculator">2 - 1</gadget>
<output>1</output>

<gadget id="calculator">7 - 1</gadget>
<output>6</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">(2/7) * (1/6)</gadget>
<output>1/21 = around 0.047619</output>

<result>B</result>
rhonda picked 2 pen from the table, if there were 7 pens on the table and 5 belongs to jill, what is the probability that the 2 pen she picked does not belong to jill?.
multiply(divide(subtract(7, 5), 7), divide(subtract(subtract(7, 5), const_1), subtract(7, const_1)))
since jill owns 5 of the pen , the subset from which the 2 pens hould be chosen are the 2 pens not owned by jill fom the universe of 7 . the first pen can be one of the 2 from the 7 with probability 2 / 7 . the second pen can be one of the 1 from the 6 remaining with probability 1 / 6 , the total probability will be 2 / 7 × 1 / 6 . on cancellation , this comes to 2 / 42 . thus , the answer is b - 2 / 42 .