a 6 litre sol is 40 % alcohol. how many litres of pure alcohol must be added to produce a sol that is 50 % alcohol? Options:	A) a . 0.6	B) b . 1.2	C) c . 2.1	D) d . 3	E) e . 5.4
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">(2/5) * 6</gadget>
<output>12/5 = around 2.4</output>

<gadget id="calculator">2 * (12/5)</gadget>
<output>24/5 = around 4.8</output>

<gadget id="calculator">6 - (24/5)</gadget>
<output>6/5 = around 1.2</output>

<result>B</result>
a 6 litre sol is 40 % alcohol. how many litres of pure alcohol must be added to produce a sol that is 50 % alcohol?
subtract(6, multiply(const_2, multiply(divide(40, const_100), 6)))
"40 % of 6 = 2.4 50 % of 6 = 3 shortage is 0.6 so we need to have 0.6 / 50 % to get 50 % alcohol content . = 1.2 b"