a monkey start climbing up a tree 18 ft tall. each hour it hops 3 ft and slips back 2 ft. how much time would it take the monkey to reach the top.	Choices.
A) 15 hrs B) 18 hrs C) 19 hrs D) 17 hrs E) 16 hrs
<gadget id="calculator">3 - 2</gadget>
<output>1</output>

<gadget id="calculator">18 / 1</gadget>
<output>18</output>

<gadget id="calculator">18 - 2</gadget>
<output>16</output>

<result>E</result>
a monkey start climbing up a tree 18 ft tall. each hour it hops 3 ft and slips back 2 ft. how much time would it take the monkey to reach the top.
subtract(divide(18, subtract(3, 2)), 2)
"if monkey hops 3 ft and slips back 2 ft in a hour , it means the monkey hops ( 3 ft - 2 ft ) = 1 ft / hr . similarly in 15 hrs it wil be 15 ft . bt since the height of the tree is 18 ft , so if the monkey hops up the tree in the next hr i . e 16 th hr then it reaches at the top of the tree . hence it takes 16 hrs for monkey to reach at the top answer : e"