a rectangular photograph is surrounded by a border that is 1 inch wide on each side. the total area of the photograph and the border is m square inches. if the border had been 3 inches wide on each side, the total area would have been ( m + 64 ) square inches. what is the perimeter of the photograph, in inches?	Choose the correct choice from the following answers
A) 16	B) 24	C) 32	D) 40	E) 48
<gadget id="calculator">3 * 2</gadget>
<output>6</output>

<gadget id="calculator">6 ** 2</gadget>
<output>36</output>

<gadget id="calculator">1 * 2</gadget>
<output>2</output>

<gadget id="calculator">2 ** 2</gadget>
<output>4</output>

<gadget id="calculator">36 - 4</gadget>
<output>32</output>

<gadget id="calculator">64 - 32</gadget>
<output>32</output>

<gadget id="calculator">32 / 2</gadget>
<output>16</output>

<result>A</result>
a rectangular photograph is surrounded by a border that is 1 inch wide on each side. the total area of the photograph and the border is m square inches. if the border had been 3 inches wide on each side, the total area would have been ( m + 64 ) square inches. what is the perimeter of the photograph, in inches?
divide(subtract(64, subtract(power(multiply(3, const_2), const_2), power(multiply(1, const_2), const_2))), const_2)
let x and y be the width and length of the photograph . ( x + 2 ) ( y + 2 ) = m and so ( 1 ) xy + 2 x + 2 y + 4 = m ( x + 6 ) ( y + 6 ) = m and so ( 2 ) xy + 6 x + 6 y + 36 = m + 64 let ' s subtract equation ( 1 ) from equation ( 2 ) . 4 x + 4 y + 32 = 64 2 x + 2 y = 16 , which is the perimeter of the photograph . the answer is a .