the s. i. on a certain sum of money for 5 years at 6 % per annum is half the c. i. on rs. 3000 for 2 years at 15 % per annum. the sum placed on s. i. is?	Answers:
A) 1525.2
B) 1256.3
C) 1612.5
D) 1548.5
E) 1254.5
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>

<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>

<gadget id="calculator">(23/20) ** 2</gadget>
<output>529/400 = around 1.3225</output>

<gadget id="calculator">3_000 * (529/400)</gadget>
<output>7_935/2 = around 3_967.5</output>

<gadget id="calculator">(7_935/2) - 3_000</gadget>
<output>1_935/2 = around 967.5</output>

<gadget id="calculator">(1_935/2) / 2</gadget>
<output>1_935/4 = around 483.75</output>

<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>

<gadget id="calculator">5 * (3/50)</gadget>
<output>3/10 = around 0.3</output>

<gadget id="calculator">(1_935/4) / (3/10)</gadget>
<output>3_225/2 = around 1_612.5</output>

<result>C</result>
the s. i. on a certain sum of money for 5 years at 6 % per annum is half the c. i. on rs. 3000 for 2 years at 15 % per annum. the sum placed on s. i. is?
divide(divide(subtract(multiply(3000, power(add(const_1, divide(15, const_100)), 2)), 3000), const_2), multiply(5, divide(6, const_100)))
c . i . = [ 3000 * ( 1 + 15 / 100 ) 2 - 3000 ] = ( 3000 * 23 / 20 * 23 / 20 - 3000 ) = rs . 967.5 . sum = ( 483.75 * 100 ) / ( 5 * 6 ) = rs . 1612.5 answer : c