find the least number of complete years in which a sum of money put out at 25 % compound interest will be more than double of itself?
Choose the correct choice from the following options:
A) 6 years
B) 9 years
C) 5 years
D) 4 years
E) 6 years
<gadget id="calculator">log(2)</gadget>
<output>log(2) = around 0.693147</output>

<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>

<gadget id="calculator">log(5/4)</gadget>
<output>log(5/4) = around 0.223144</output>

<gadget id="calculator">log(2) / log(5/4)</gadget>
<output>log(2)/log(5/4) = around 3.106284</output>

<gadget id="calculator">(log(2)/log(5/4)) + 1</gadget>
<output>1 + log(2)/log(5/4) = around 4.106284</output>

<gadget id="calculator">floor(1 + log(2)/log(5/4))</gadget>
<output>4</output>

<result>D</result>
find the least number of complete years in which a sum of money put out at 25 % compound interest will be more than double of itself?
floor(add(divide(log(const_2), log(add(const_1, divide(25, const_100)))), const_1))
"4 years answer : d"