if twice of a number divided by 3 d gives 20 as the remainder, and 5 times of the same number gives 32 as the remainder. what will be the value of d? Choose the correct choice from the following choices
A) 11
B) 12
C) 15
D) 14
E) 18
<gadget id="calculator">32 / 5</gadget>
<output>32/5 = around 6.4</output>

<gadget id="calculator">(32/5) * 2</gadget>
<output>64/5 = around 12.8</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">(64/5) - (1/4)</gadget>
<output>251/20 = around 12.55</output>

<result>B</result>
if twice of a number divided by 3 d gives 20 as the remainder, and 5 times of the same number gives 32 as the remainder. what will be the value of d?
subtract(multiply(divide(32, 5), const_2), divide(const_1, const_4))
remainder in second case is , 32 . so , 3 d > = 33 . so , minimum value of d should 11 . if number = 28 . double of number = 56 and take d = 12 so 56 / 36 remainder = 20 . now 5 times of number = 140 . so 140 / 36 remainder = 32 . that is , 3 d = 36 satisfy the conditions . so d = 12 . answer : b