what is the smallest integer t greater than 1 that leaves a remainder of 1 when divided by any of the integers 6, 8, and 10?	Options.
A) 21 B) 41 C) t = 121 D) 241 E) 481
<gadget id="calculator">lcm(6, 8)</gadget>
<output>24</output>

<gadget id="calculator">lcm(24, 10)</gadget>
<output>120</output>

<gadget id="calculator">120 + 1</gadget>
<output>121</output>

<result>C</result>
what is the smallest integer t greater than 1 that leaves a remainder of 1 when divided by any of the integers 6, 8, and 10?
add(lcm(lcm(6, 8), 10), 1)
or u can just use the answer choices here . since the answers are already arranged in ascending order , the first number which gives remainder t as 1 for all three is the correct answer . in the given question , the first number which gives a remainder of 1 for 6,8 and 10 is 121 . c