there has been successive increases of 20 % and then 10 % in the price of gas from the previous month. by what percentage should a driver reduce gas consumption so that the expenditure does not change?
Select the correct option.
A) 16 % B) 20 % C) 24 % D) 28 % E) 32 %
<gadget id="calculator">100 + 20</gadget>
<output>120</output>

<gadget id="calculator">120 * 10</gadget>
<output>1_200</output>

<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>

<gadget id="calculator">120 + 12</gadget>
<output>132</output>

<gadget id="calculator">100 / 132</gadget>
<output>25/33 = around 0.757576</output>

<gadget id="calculator">1 - (25/33)</gadget>
<output>8/33 = around 0.242424</output>

<gadget id="calculator">(8/33) * 100</gadget>
<output>800/33 = around 24.242424</output>

<result>C</result>
there has been successive increases of 20 % and then 10 % in the price of gas from the previous month. by what percentage should a driver reduce gas consumption so that the expenditure does not change?
multiply(subtract(const_1, divide(const_100, add(add(const_100, 20), divide(multiply(add(const_100, 20), 10), const_100)))), const_100)
"let p be the original price per unit of gas . let x be the original gas consumption . let y be the reduced gas consumption . y * 1.1 * 1.2 * p = x * p y = x / ( 1.1 * 1.2 ) which is about 0.76 x which is a decrease of about 24 % . the answer is c ."