if 9! / 3 ^ x is an integer, what is the greatest possible value of x?  Answers
A) 3  B) 4  C) 5  D) 6  E) 7
<gadget id="calculator">9 / 3</gadget>
<output>3</output>

<gadget id="calculator">3 / 3</gadget>
<output>1</output>

<gadget id="calculator">3 + 1</gadget>
<output>4</output>

<result>B</result>
if 9! / 3 ^ x is an integer, what is the greatest possible value of x?
add(divide(9, 3), divide(3, divide(9, 3)))
9 - 3 * 3 6 - 2 * 3 3 - 1 * 3 hence max of 3 ^ 4 is allowed . imo b .