how many numbers between 100 and 798 are divisible by 2, 3, and 7 together?  Select the correct option:  A) 112  B) 77  C) 267  D) 17  E) 99
<gadget id="calculator">2 * 3</gadget>
<output>6</output>

<gadget id="calculator">6 * 7</gadget>
<output>42</output>

<gadget id="calculator">798 / 42</gadget>
<output>19</output>

<gadget id="calculator">100 / 42</gadget>
<output>50/21 = around 2.380952</output>

<gadget id="calculator">19 - (50/21)</gadget>
<output>349/21 = around 16.619048</output>

<result>D</result>
how many numbers between 100 and 798 are divisible by 2, 3, and 7 together?
subtract(divide(798, multiply(multiply(2, 3), 7)), divide(100, multiply(multiply(2, 3), 7)))
explanation : as the division is by 2 , 3 , 7 together , the numbers are to be divisible by : 2 * 3 * 7 = 42 the limits are 100 and 798 the first number divisible is 42 * 3 = 126 to find out the last number divisible by 42 within 798 : 798 / 42 = 19 hence , 42 * 19 = 798 is the last number divisible by 42 within 798 hence , total numbers divisible by 2 , 3 , 7 together are ( 19 â € “ 2 ) = 17 answer : d