x varies inversely as square of y. given that y = 3 for x = 1. the value of x for y = 5 will be equal to: Pick:
A) 3
B) 6
C) 1 / 9
D) 1 / 3
E) 9 / 25
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>

<gadget id="calculator">1 * 9</gadget>
<output>9</output>

<gadget id="calculator">5 ** 2</gadget>
<output>25</output>

<gadget id="calculator">9 / 25</gadget>
<output>9/25 = around 0.36</output>

<result>E</result>
x varies inversely as square of y. given that y = 3 for x = 1. the value of x for y = 5 will be equal to:
divide(multiply(1, power(3, const_2)), power(5, const_2))
"explanation : solution : given x = k / y ^ 2 , where k is constant . now , y = 3 and x = 1 gives k = 9 . . ' . x = 9 / y ^ 2 = > x = 9 / 5 ^ 2 = 9 / 25 answer : e"