if 6 men and 8 women can do a piece of work in 10 days while 26 men and 48 women can do the same in 2 days, the time taken by 15 men and 20 women in doing the same type of work will be?
Choose the correct choice from the following answers:  A) 5  B) 4  C) 6  D) 7  E) 8
<gadget id="calculator">48 * 2</gadget>
<output>96</output>

<gadget id="calculator">8 * 10</gadget>
<output>80</output>

<gadget id="calculator">96 - 80</gadget>
<output>16</output>

<gadget id="calculator">6 * 10</gadget>
<output>60</output>

<gadget id="calculator">26 * 2</gadget>
<output>52</output>

<gadget id="calculator">60 - 52</gadget>
<output>8</output>

<gadget id="calculator">16 / 8</gadget>
<output>2</output>

<gadget id="calculator">8 / 2</gadget>
<output>4</output>

<gadget id="calculator">4 + 6</gadget>
<output>10</output>

<gadget id="calculator">10 * 10</gadget>
<output>100</output>

<gadget id="calculator">20 / 2</gadget>
<output>10</output>

<gadget id="calculator">10 + 15</gadget>
<output>25</output>

<gadget id="calculator">100 / 25</gadget>
<output>4</output>

<result>B</result>
if 6 men and 8 women can do a piece of work in 10 days while 26 men and 48 women can do the same in 2 days, the time taken by 15 men and 20 women in doing the same type of work will be?
divide(multiply(add(divide(8, divide(subtract(multiply(48, 2), multiply(8, 10)), subtract(multiply(6, 10), multiply(26, 2)))), 6), 10), add(divide(20, divide(subtract(multiply(48, 2), multiply(8, 10)), subtract(multiply(6, 10), multiply(26, 2)))), 15))
let 1 man ' s 1 day ' s work = x and 1 women ' s 1 day ' s work = y . then , 6 x + 8 y = 1 and 26 x + 48 y = 1 . 10 2 solving these two equations , we get : x = 1 and y = 1 . 100 200 ( 15 men + 20 women ) ' s 1 day ' s work = 15 + 20 = 1 . 100 200 4 15 men and 20 women can do the work in 4 days . hence answer will be b