in a box of 11 pens, a total of 3 are defective. if a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Pick one
A) 28 / 55 B) 19 / 33 C) 7 / 11 D) 4 / 7 E) 3 / 5
<gadget id="calculator">11 - 3</gadget>
<output>8</output>

<gadget id="calculator">8 / 11</gadget>
<output>8/11 = around 0.727273</output>

<gadget id="calculator">8 - 1</gadget>
<output>7</output>

<gadget id="calculator">11 - 1</gadget>
<output>10</output>

<gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>

<gadget id="calculator">(8/11) * (7/10)</gadget>
<output>28/55 = around 0.509091</output>

<result>A</result>
in a box of 11 pens, a total of 3 are defective. if a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
multiply(divide(subtract(11, 3), 11), divide(subtract(subtract(11, 3), const_1), subtract(11, const_1)))
"p ( neither pen is defective ) = 8 / 11 * 7 / 10 = 28 / 55 the answer is a ."