20 litres of mixture contains 40 % alcohol and the rest water. if 8 litres of water be mixed with it, the percentage of alcohol in the new mixture would be?  Pick
A) 26.32 %
B) 35.14 %
C) 28.57 %
D) 25 %
E) 31.14 %
<gadget id="calculator">20 + 8</gadget>
<output>28</output>

<gadget id="calculator">100 - 40</gadget>
<output>60</output>

<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">(3/5) * 20</gadget>
<output>12</output>

<gadget id="calculator">12 + 8</gadget>
<output>20</output>

<gadget id="calculator">28 - 20</gadget>
<output>8</output>

<gadget id="calculator">8 / 28</gadget>
<output>2/7 = around 0.285714</output>

<gadget id="calculator">(2/7) * 100</gadget>
<output>200/7 = around 28.571429</output>

<result>C</result>
20 litres of mixture contains 40 % alcohol and the rest water. if 8 litres of water be mixed with it, the percentage of alcohol in the new mixture would be?
multiply(divide(subtract(add(20, 8), add(multiply(divide(subtract(const_100, 40), const_100), 20), 8)), add(20, 8)), const_100)
"alcohol in the 20 litres of mix . = 40 % of 20 litres = ( 40 * 20 / 100 ) = 8 litres water in it = 20 - 8 = 12 litres new quantity of mix . = 20 + 8 = 28 litres quantity of alcohol in it = 8 litres percentage of alcohol in new mix . = 8 * 100 / 28 = 50 / 3 = 28.57 % answer is c"