from a pack of cards, two cards are drawn one after the other, with replacement. what is the probability that the first card is a club and the second card is a red king?  Pick: A) 1 / 13 B) 1 / 15 C) 1 / 26 D) 1 / 52 E) 1 / 104
<gadget id="calculator">3 * 4</gadget>
<output>12</output>

<gadget id="calculator">12 + 1</gadget>
<output>13</output>

<gadget id="calculator">13 / 52</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">2 / 52</gadget>
<output>1/26 = around 0.038462</output>

<gadget id="calculator">(1/4) * (1/26)</gadget>
<output>1/104 = around 0.009615</output>

<result>E</result>
from a pack of cards, two cards are drawn one after the other, with replacement. what is the probability that the first card is a club and the second card is a red king?
multiply(divide(add(multiply(const_3, const_4), const_1), const_52), divide(const_2, const_52))
p ( club ) = 1 / 4 p ( red king ) = 1 / 26 p ( club then a red king ) = 1 / 4 * 1 / 26 = 1 / 104 the answer is e .