how many kilograms of sugar costing rs. 9 per kg must be mixed with 27 kg of sugar costing rs. 7 per kg so that there may be a gain of 10 % by selling the mixture at rs. 9.24 per kg?
Pick one.
A) 33	B) 39	C) 38	D) 63	E) 01
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>

<gadget id="calculator">9.24 / (11/10)</gadget>
<output>8.4</output>

<gadget id="calculator">27 * 8.4</gadget>
<output>226.8</output>

<gadget id="calculator">27 * 7</gadget>
<output>189</output>

<gadget id="calculator">226.8 - 189</gadget>
<output>37.8</output>

<gadget id="calculator">9 - 8.4</gadget>
<output>0.6</output>

<gadget id="calculator">37.8 / 0.6</gadget>
<output>63</output>

<result>D</result>
how many kilograms of sugar costing rs. 9 per kg must be mixed with 27 kg of sugar costing rs. 7 per kg so that there may be a gain of 10 % by selling the mixture at rs. 9.24 per kg?
divide(subtract(multiply(27, divide(9.24, add(divide(10, const_100), const_1))), multiply(27, 7)), subtract(9, divide(9.24, add(divide(10, const_100), const_1))))
by the rule of alligation : c . p . of 1 kg sugar of 1 st kind c . p . of 1 kg sugar of 2 nd kind { \ color { blue } \ therefore } ratio of quantities of 1 st and 2 nd kind = 14 : 6 = 7 : 3 . let x kg of sugar of 1 st kind be mixed with 27 kg of 2 nd kind . then , 7 : 3 = x : 27 or x = ( 7 x 27 / 3 ) = 63 kg . answer : d ) 63 kg