a store sells 2 kinds of jelly beans mixes ( a and b ) both made up of red and yellow beans. if b contains 20 % more red beans than a but 10 % fewer yellow beans. and jar a contains twice as many red beans as yellow by what percent is the number of beans in jar b larger than the number in jar a
Pick one:  A) 5  B) 6  C) 8  D) 9  E) 10
<gadget id="calculator">100 + 20</gadget>
<output>120</output>

<gadget id="calculator">100 - 10</gadget>
<output>90</output>

<gadget id="calculator">120 + 90</gadget>
<output>210</output>

<gadget id="calculator">210 / 100</gadget>
<output>21/10 = around 2.1</output>

<gadget id="calculator">(21/10) - 2</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>

<result>E</result>
a store sells 2 kinds of jelly beans mixes ( a and b ) both made up of red and yellow beans. if b contains 20 % more red beans than a but 10 % fewer yellow beans. and jar a contains twice as many red beans as yellow by what percent is the number of beans in jar b larger than the number in jar a
multiply(subtract(divide(add(add(const_100, 20), subtract(const_100, 10)), const_100), const_2), const_100)
a has 10 yellows 20 reds total = 30 so b has 1.2 x 20 = 24 reds 0.9 x 10 = 9 yellows total = 33 difference = 3 / 30 = 10 % answer : e