a man cycling along the road noticed that every 15 minutes a bus overtakes him and every 5 minutes he meets an oncoming bus. if all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses?
Options
A) 5 minutes
B) 6 minutes
C) 8 minutes
D) 9 minutes
E) 15 / 2 minutes
<gadget id="calculator">5 + 15</gadget>
<output>20</output>

<gadget id="calculator">15 - 5</gadget>
<output>10</output>

<gadget id="calculator">20 / 10</gadget>
<output>2</output>

<gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>

<gadget id="calculator">15 - (15/2)</gadget>
<output>15/2 = around 7.5</output>

<gadget id="calculator">(15/2) / 1</gadget>
<output>15/2 = around 7.5</output>

<result>E</result>
a man cycling along the road noticed that every 15 minutes a bus overtakes him and every 5 minutes he meets an oncoming bus. if all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses?
divide(subtract(15, divide(15, divide(add(5, 15), subtract(15, 5)))), const_1)
"let ' s say the distance between the buses is d . we want to determine interval = \ frac { d } { b } , where b is the speed of bus . let the speed of cyclist be c . every 15 minutes a bus overtakes cyclist : \ frac { d } { b - c } = 15 , d = 15 b - 15 c ; every 5 minutes cyclist meets an oncoming bus : \ frac { d } { b + c } = 4 , d = 4 b + 4 c ; d = 15 b - 15 c = 5 b + 5 c , - - > b = 2 c , - - > d = 15 b - 15 b / 2 = 15 b / 2 . interval = \ frac { d } { b } = \ frac { 15 / 2 b } { b } = 15 / 2 answer : e ( 15 / 2 minutes ) ."