mr. karan borrowed a certain amount at 6 % per annum simple interest for 9 years. after 9 years, he returned rs. 8010 / -. find out the amount that he borrowed.  Choose the correct choice from the following:
A) s . 5266
B) s . 5269
C) s . 5228
D) s . 5201
E) s . 52192
<gadget id="calculator">6 * 9</gadget>
<output>54</output>

<gadget id="calculator">54 / 100</gadget>
<output>27/50 = around 0.54</output>

<gadget id="calculator">1 + (27/50)</gadget>
<output>77/50 = around 1.54</output>

<gadget id="calculator">8_010 / (77/50)</gadget>
<output>400_500/77 = around 5_201.298701</output>

<result>D</result>
mr. karan borrowed a certain amount at 6 % per annum simple interest for 9 years. after 9 years, he returned rs. 8010 / -. find out the amount that he borrowed.
divide(8010, add(const_1, divide(multiply(6, 9), const_100)))
"explanation : let us assume mr . karan borrowed amount is rs . a . ( the principal ) by formula of simple interest , s . i . = prt / 100 where p = the principal , r = rate of interest as a % , t = time in years s . i . = ( p * 6 * 9 ) / 100 = 54 p / 100 amount = principal + s . i . 8010 = p + ( 54 p / 100 ) 8010 = ( 100 p + 54 p ) / 100 8010 = 154 p / 100 p = ( 8010 * 100 ) / 154 = rs . 5201.298 answer : d"