what is the probability that the sum of two dice will yield a 6, and then when both are thrown again, their sum will again yield a 6? assume that each die has 5 sides with faces numbered 1 to 5.
Choose the correct choice from the following answers.
A) 1 / 144 B) 1 / 25 C) 1 / 12 D) 1 / 6 E) 1 / 3
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>

<gadget id="calculator">5 / 25</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">(1/5) * (1/5)</gadget>
<output>1/25 = around 0.04</output>

<result>B</result>
what is the probability that the sum of two dice will yield a 6, and then when both are thrown again, their sum will again yield a 6? assume that each die has 5 sides with faces numbered 1 to 5.
multiply(divide(5, power(5, const_2)), divide(5, power(5, const_2)))
solution - rolling dices is an independent event . the combinations to get 6 are ( 1,5 ) , ( 5,1 ) , ( 2,4 ) , ( 4,2 ) , ( 3,3 ) and total combinations of both dices is 25 . the probability of getting 6 in first attempt is 5 / 25 = 1 / 5 . probability of getting 6 again in second attempt = ( 1 / 5 ) * ( 1 / 5 ) = 1 / 25 . ans b