the weight of a hollow sphere is directly dependent on its surface area. the surface area of a sphere is 4 π · r ^ 2, where r is the radius of the sphere. if a hollow sphere of radius 0.15 cm made of a certain metal weighs 8 grams, a hollow sphere of radius 0.3 cm made of the same metal would weigh how many grams t?
Select the correct option:	A) t = 16	B) t = 32	C) t = 64	D) 128	E) 512
<gadget id="calculator">8 * 4</gadget>
<output>32</output>

<result>B</result>
the weight of a hollow sphere is directly dependent on its surface area. the surface area of a sphere is 4 π · r ^ 2, where r is the radius of the sphere. if a hollow sphere of radius 0.15 cm made of a certain metal weighs 8 grams, a hollow sphere of radius 0.3 cm made of the same metal would weigh how many grams t?
multiply(8, 4)
"weight directly proportional to 4 pi r ^ 2 now , 4 pi is constant , so , weight is directly proportional to r ^ 2 . when radius = 0.15 , weight = 8 , so ( 0.15 ) ^ 2 proportional to 8 ; ( 0.15 ) ^ 2 * 4 proportional to 8 * 4 , solving further ( 0.15 ) ^ 2 * 2 ^ 2 = ( 0.15 * 2 ) ^ 2 = 0.3 ^ 2 ; so answer = 32 ( b )"