in a box of 9 pens, a total of 2 are defective. if a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?  Choose the correct choice
A) 4 / 7 B) 5 / 9 C) 6 / 11 D) 7 / 12 E) 8 / 15
<gadget id="calculator">9 - 2</gadget>
<output>7</output>

<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>

<gadget id="calculator">7 - 1</gadget>
<output>6</output>

<gadget id="calculator">9 - 1</gadget>
<output>8</output>

<gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>

<gadget id="calculator">(7/9) * (3/4)</gadget>
<output>7/12 = around 0.583333</output>

<result>D</result>
in a box of 9 pens, a total of 2 are defective. if a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
multiply(divide(subtract(9, 2), 9), divide(subtract(subtract(9, 2), const_1), subtract(9, const_1)))
"# defective pens = 2 # good pens = 7 probability of the 1 st pen being good = 7 / 9 probability of the 2 nd pen being good = 6 / 8 total probability = 7 / 9 * 6 / 8 = 7 / 12 the answer is d ."