at a monthly meeting, 1 / 3 of the attendees were males and 4 / 5 of the male attendees arrived on time. if 5 / 6 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?  Select the correct option
A) 1 / 6 B) 2 / 15 C) 3 / 20 D) 7 / 30 E) 8 / 45
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>

<gadget id="calculator">1 - (5/6)</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">(1/6) * (2/3)</gadget>
<output>1/9 = around 0.111111</output>

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">(1/5) * (1/3)</gadget>
<output>1/15 = around 0.066667</output>

<gadget id="calculator">(1/9) + (1/15)</gadget>
<output>8/45 = around 0.177778</output>

<result>E</result>
at a monthly meeting, 1 / 3 of the attendees were males and 4 / 5 of the male attendees arrived on time. if 5 / 6 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?
add(multiply(subtract(const_1, divide(5, 6)), subtract(const_1, divide(1, 3))), multiply(subtract(const_1, divide(4, 5)), divide(1, 3)))
"males who did not arrive on time are 1 / 5 * 1 / 3 = 1 / 15 of the attendees . females who did not arrive on time are 1 / 6 * 2 / 3 = 1 / 9 of the attendees . the fraction of all attendees who did not arrive on time is 1 / 15 + 1 / 9 = 8 / 45 the answer is e ."