peter invests a sum of money and gets back an amount of $ 810 in 3 years. david invests an equal amount of money and gets an amount of $ 854 in 4 years. if both amounts were invested at the same rate ( simple interest ) what was the sum of money invested?
Select the correct option:
A) 670
B) 683
C) 698
D) 744
E) 700
<gadget id="calculator">854 - 810</gadget>
<output>44</output>

<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>

<gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>

<gadget id="calculator">(1/25) - (3/100)</gadget>
<output>1/100 = around 0.01</output>

<gadget id="calculator">44 / (1/100)</gadget>
<output>4_400</output>

<gadget id="calculator">4_400 * (3/100)</gadget>
<output>132</output>

<gadget id="calculator">810 - 132</gadget>
<output>678</output>

<result>B</result>
peter invests a sum of money and gets back an amount of $ 810 in 3 years. david invests an equal amount of money and gets an amount of $ 854 in 4 years. if both amounts were invested at the same rate ( simple interest ) what was the sum of money invested?
subtract(810, multiply(divide(subtract(854, 810), subtract(divide(4, const_100), divide(3, const_100))), divide(3, const_100)))
since both peter and david invested the same amount of money at the same rate , they would earn same interest per year . david invested for one year more than peter and hence he got interest amount for one more year . interest earned per year = amount received by david - amount received by peter = 854 - 810 = 44 interest earned for 3 years = 44 * 3 = 132 amount invested = 815 - 132 = 683 answer : b