a shopkeeper bought 600 oranges and 400 bananas. he found 15 % of oranges and 7 % of bananas were rotten. find the percentage of fruits in good condition? Choose the correct choice from the following answers
A) 92.5 %
B) 88.2 %
C) 85.2 %
D) 96.8 %
E) 78.9 %
<gadget id="calculator">600 + 400</gadget>
<output>1_000</output>

<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>

<gadget id="calculator">600 * (3/20)</gadget>
<output>90</output>

<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>

<gadget id="calculator">400 * (7/100)</gadget>
<output>28</output>

<gadget id="calculator">90 + 28</gadget>
<output>118</output>

<gadget id="calculator">1_000 - 118</gadget>
<output>882</output>

<gadget id="calculator">882 / 1_000</gadget>
<output>441/500 = around 0.882</output>

<gadget id="calculator">(441/500) * 100</gadget>
<output>441/5 = around 88.2</output>

<result>B</result>
a shopkeeper bought 600 oranges and 400 bananas. he found 15 % of oranges and 7 % of bananas were rotten. find the percentage of fruits in good condition?
multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(7, const_100)))), add(600, 400)), const_100)
"total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 7 % of 400 = 28 therefore , total number of rotten fruits = 90 + 28 = 118 therefore number of fruits in good condition = 1000 - 118 = 882 therefore percentage of fruits in good condition = ( 882 / 1000 × 100 ) % = ( 88200 / 1000 ) % = 88.2 % answer : b"