a certain list consists of 21 different numbers. if n is in the list and n is 4 times the average ( arithmetic mean ) of the other 20 numbers in the list, then n is what fraction e of the sum of the 21 numbers in the list?
Answers.
A) 1 / 20  B) 1 / 6  C) 1 / 5  D) 4 / 21  E) 5 / 21
<gadget id="calculator">1 * 1</gadget>
<output>1</output>

<gadget id="calculator">20 / 4</gadget>
<output>5</output>

<gadget id="calculator">5 + 21</gadget>
<output>26</output>

<gadget id="calculator">26 / 4</gadget>
<output>13/2 = around 6.5</output>

<gadget id="calculator">(13/2) * 2</gadget>
<output>13</output>

<gadget id="calculator">13 - 4</gadget>
<output>9</output>

<gadget id="calculator">9 - 3</gadget>
<output>6</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<result>B</result>
a certain list consists of 21 different numbers. if n is in the list and n is 4 times the average ( arithmetic mean ) of the other 20 numbers in the list, then n is what fraction e of the sum of the 21 numbers in the list?
divide(multiply(const_1, const_1), subtract(subtract(multiply(divide(add(divide(20, 4), 21), 4), const_2), 4), const_3))
"this is how i used to calculate which i think works pretty well : if you let the average of the 20 other numbers equal a , can you write this equation for sum of the list ( s ) n + 20 a = s the question tells us that n = 4 a plug this back into the first equation and you get that the sum is 24 a 4 a + 20 a = 24 a therefore fraction e of n to the total would be 4 a / 24 a or 1 / 6 answer b"