find large no. from below question the difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and the 30 as remainder Choices:	A) 1235	B) 1456	C) 1567	D) 1632	E) 1635
<gadget id="calculator">1_365 - 30</gadget>
<output>1_335</output>

<gadget id="calculator">6 - 1</gadget>
<output>5</output>

<gadget id="calculator">1_335 / 5</gadget>
<output>267</output>

<gadget id="calculator">267 * 6</gadget>
<output>1_602</output>

<gadget id="calculator">1_602 + 30</gadget>
<output>1_632</output>

<result>D</result>
find large no. from below question the difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and the 30 as remainder
add(multiply(divide(subtract(1365, 30), subtract(6, const_1)), 6), 30)
"let the smaller number be x . then larger number = ( x + 1365 ) . x + 1365 = 6 x + 30 5 x = 1335 x = 267 large number = 267 + 1365 = 1632 d"