the price of commodity x increases by 30 cents every year, while the price of commodity y increases by 20 cents every year. if in 2001, the price of commodity x was $ 4.20 and the price of commodity y was $ 4.40, in which year will commodity x cost 80 cents more than the commodity y?	Select the correct option:
A) 2010 .	B) 2011 .	C) 2012 .	D) 2013 .	E) 2014 .
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">4.4 - 4.2</gadget>
<output>0.2</output>

<gadget id="calculator">(4/5) + 0.2</gadget>
<output>1</output>

<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>

<gadget id="calculator">(3/10) - 0.2</gadget>
<output>0.1</output>

<gadget id="calculator">1 / 0.1</gadget>
<output>10</output>

<gadget id="calculator">2_001 + 10</gadget>
<output>2_011</output>

<result>B</result>
the price of commodity x increases by 30 cents every year, while the price of commodity y increases by 20 cents every year. if in 2001, the price of commodity x was $ 4.20 and the price of commodity y was $ 4.40, in which year will commodity x cost 80 cents more than the commodity y?
add(2001, divide(add(divide(80, const_100), subtract(4.40, 4.20)), subtract(divide(30, const_100), subtract(4.40, 4.20))))
"the cost of commodity x increases by 10 cents per year relative to commodity y . the price of x must gain 20 + 80 = $ 1.00 cents on commodity y , which will take 10 years . the answer is b ."