a 4 digit number divisible by 7 becomes divisible by 3 when 19 is added to it. the largest such number is:	Choose the most appropriate option: A) 4461 B) 4473 C) 4479 D) 4487 E) 4491
<gadget id="calculator">4 * 7</gadget>
<output>28</output>

<gadget id="calculator">3 * 19</gadget>
<output>57</output>

<gadget id="calculator">28 * 57</gadget>
<output>1_596</output>

<gadget id="calculator">1_596 * 2</gadget>
<output>3_192</output>

<gadget id="calculator">2 * 100</gadget>
<output>200</output>

<gadget id="calculator">1_596 - 200</gadget>
<output>1_396</output>

<gadget id="calculator">3_192 + 1_396</gadget>
<output>4_588</output>

<result>D</result>
a 4 digit number divisible by 7 becomes divisible by 3 when 19 is added to it. the largest such number is:
add(multiply(multiply(multiply(4, 7), multiply(3, 19)), const_2), subtract(multiply(multiply(4, 7), multiply(3, 19)), multiply(const_2, const_100)))
out of all the 5 options , only 4487 is not divisible by 3 . all others are divisible so answer = d ( no further calculation required ) addition of any two non - divisible numbers by 3 gives the resultant divisible by 3 19 is non - divisible by 3 ; we are adding a number to that so that the resultant becomes divisible by 3 applying the above rule , it means that the number which we are going to add should be non - divisible by 3 so comes the answer = 4487 answer : d