a truck covers a distance of 288 km at a certain speed in 8 hours. how much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 90 km more than that travelled by the truck?
Answers
A) 6 hours B) 5 hours C) 7 hours D) 8 hours E) none
<gadget id="calculator">288 + 90</gadget>
<output>378</output>

<gadget id="calculator">288 / 8</gadget>
<output>36</output>

<gadget id="calculator">36 + 18</gadget>
<output>54</output>

<gadget id="calculator">378 / 54</gadget>
<output>7</output>

<result>C</result>
a truck covers a distance of 288 km at a certain speed in 8 hours. how much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 90 km more than that travelled by the truck?
divide(add(288, 90), add(divide(288, 8), 18))
"explanation : speed of the truck = distance / time = 288 / 8 = 36 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 36 + 18 ) = 54 kmph distance travelled by car = 288 + 90 = 378 km time taken by car = distance / speed = 378 / 54 = 7 hours . answer – c"