one night a certain hotel rented 3 / 5 of its rooms, including 2 / 3 of their air conditioned rooms. if 3 / 5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned? Choose the correct answer.
A) 50 %  B) 55 %  C) 60 %  D) 65 %  E) 70 %
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>

<gadget id="calculator">(1/3) * 60</gadget>
<output>20</output>

<gadget id="calculator">100 - 60</gadget>
<output>40</output>

<gadget id="calculator">20 / 40</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>

<result>A</result>
one night a certain hotel rented 3 / 5 of its rooms, including 2 / 3 of their air conditioned rooms. if 3 / 5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?
multiply(divide(multiply(subtract(const_1, divide(2, 3)), multiply(divide(3, 5), const_100)), subtract(const_100, multiply(divide(3, 5), const_100))), const_100)
the rooms which were not rented is 2 / 5 the ac rooms which were not rented is ( 1 / 3 ) * ( 3 / 5 ) = 1 / 5 the percentage of unrented rooms which were ac rooms is ( 1 / 5 ) / ( 2 / 5 ) = 1 / 2 = 50 % the answer is a .