a certain characteristic in a large population has a distribution that is symmetric about the mean m. if 68 percent of the distribution lies within one standard deviation d of the mean, what percent e of the distribution is less than m + d?  Choose the correct answer:  A) 16 %  B) 32 %  C) 48 %  D) 84 %  E) 92 %
<gadget id="calculator">100 - 68</gadget>
<output>32</output>

<gadget id="calculator">32 / 2</gadget>
<output>16</output>

<gadget id="calculator">100 - 16</gadget>
<output>84</output>

<result>D</result>
a certain characteristic in a large population has a distribution that is symmetric about the mean m. if 68 percent of the distribution lies within one standard deviation d of the mean, what percent e of the distribution is less than m + d?
subtract(const_100, divide(subtract(const_100, 68), const_2))
d the prompt says that 68 % of the population lies between m - d and m + d . thus , 32 % of the population is less than m - d or greater than m + d . since the population is symmetric , half of this 32 % is less than m - d and half is greater than m + d . thus , e = ( 68 + 16 ) % or ( 100 - 16 ) % of the population is less than m + d . d