n = 1! + 2! + 3!..... + 10!. what is the last digit of n ^ n? Choose the correct option.
A) 3 B) 4 C) 5 D) 6 E) 7
<gadget id="calculator">10 - 3</gadget>
<output>7</output>

<gadget id="calculator">7 ** 1</gadget>
<output>7</output>

<result>E</result>
n = 1! + 2! + 3!..... + 10!. what is the last digit of n ^ n?
power(subtract(10, 3), const_1)
as you see 5 ! till 10 ! each unit digit is zero . so 1 ! + 2 ! + 3 ! + 4 ! = 33 so unit digit 3 + 0 = 3 n = 3 n ^ n = 3 ^ 3 = 27 so last digit is 7 . answer : e