in a simultaneous throw of pair of dice. find the probability of getting the total more than 7	Choose one:	A) 5 / 7	B) 4 / 7	C) 5 / 12	D) 4 / 7	E) 1 / 6
<gadget id="calculator">7 + 4</gadget>
<output>11</output>

<gadget id="calculator">11 + 4</gadget>
<output>15</output>

<gadget id="calculator">4 + 2</gadget>
<output>6</output>

<gadget id="calculator">6 * 6</gadget>
<output>36</output>

<gadget id="calculator">15 / 36</gadget>
<output>5/12 = around 0.416667</output>

<result>C</result>
in a simultaneous throw of pair of dice. find the probability of getting the total more than 7
divide(add(add(7, const_4), const_4), multiply(add(const_4, const_2), add(const_4, const_2)))
here n ( s ) = ( 6 * 6 ) = 36 let e = event of getting a total more than 7 = { ( 2,6 ) , ( 3,5 ) , ( 3,6 ) , ( 4,4 ) , ( 4,5 ) , ( 4,6 ) , ( 5,3 ) , ( 5,4 ) , ( 5,5 ) , ( 5,6 ) , ( 6,2 ) , ( 6,3 ) , ( 6,4 ) , ( 6,5 ) , ( 6,6 ) } p ( e ) = n ( e ) / n ( s ) = 15 / 36 = 5 / 12 option c