if the difference between the length and breadth of a rectangle is 23 m and its perimeter is 206 m, what is its area?
Choose one
A) 2520  B) 2510  C) 2525  D) 2025  E) 2020
<gadget id="calculator">2 * 23</gadget>
<output>46</output>

<gadget id="calculator">206 - 46</gadget>
<output>160</output>

<gadget id="calculator">160 / 4</gadget>
<output>40</output>

<gadget id="calculator">40 + 23</gadget>
<output>63</output>

<gadget id="calculator">63 * 40</gadget>
<output>2_520</output>

<result>A</result>
if the difference between the length and breadth of a rectangle is 23 m and its perimeter is 206 m, what is its area?
rectangle_area(add(divide(subtract(206, multiply(const_2, 23)), const_4), 23), divide(subtract(206, multiply(const_2, 23)), const_4))
l - b = 23 . . . ( 1 ) perimeter = 206 2 ( l = b ) = 206 l + b = 103 . . . ( 2 ) ( 1 ) + ( 2 ) 2 l = 23 + 103 = 126 l = 126 / 2 = 63 metre substituting the value of l in ( 1 ) , we get 63 - b = 23 b = 63 - 23 = 40 metre area = lb = 63 ã — 40 = 2520 m 2 answer : a