a man is 22 years older than his son. in two years, his age will be twice the age of his son. the present age of his son is:  Choices: A) 14 years B) 18 years C) 20 years D) 22 years E) 16 years
<gadget id="calculator">2 * 2</gadget>
<output>4</output>

<gadget id="calculator">4 - 2</gadget>
<output>2</output>

<gadget id="calculator">22 - 2</gadget>
<output>20</output>

<gadget id="calculator">2 - 1</gadget>
<output>1</output>

<gadget id="calculator">20 / 1</gadget>
<output>20</output>

<result>C</result>
a man is 22 years older than his son. in two years, his age will be twice the age of his son. the present age of his son is:
divide(subtract(22, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1))
"let the son ' s present age be x years . then , man ' s present age = ( x + 24 ) years . ( x + 22 ) + 2 = 2 ( x + 2 ) x + 24 = 2 x + 4 x = 20 . answer : c"