in a 500 m race, the ratio of the speeds of two contestants a and b is 3: 4. a has a start of 155 m. then, a wins by:	Answers.
A) 60 m
B) 20 m
C) 40 m
D) 20 m
E) 23 m
<gadget id="calculator">500 - 155</gadget>
<output>345</output>

<gadget id="calculator">345 * 4</gadget>
<output>1_380</output>

<gadget id="calculator">1_380 / 3</gadget>
<output>460</output>

<gadget id="calculator">500 - 460</gadget>
<output>40</output>

<result>C</result>
in a 500 m race, the ratio of the speeds of two contestants a and b is 3: 4. a has a start of 155 m. then, a wins by:
subtract(500, divide(multiply(subtract(500, 155), 4), 3))
"to reach the winning post a will have to cover a distance of ( 500 - 155 ) m , i . e . , 345 m . while a covers 3 m , b covers 4 m . while a covers 345 m , b covers 4 x 345 / 3 m = 460 m . thus , when a reaches the winning post , b covers 460 m and therefore remains 40 m behind . a wins by 40 m . answer : c"