peter invested a certain sum of money in a simple interest bond whose value grew to $ 400 at the end of 3 years and to $ 600 at the end of another 2 years. what was the rate of interest in which he invested his sum?
Pick one:
A) 100 %	B) 12.5 %	C) 67 %	D) 25 %	E) 33 %
<gadget id="calculator">600 - 400</gadget>
<output>200</output>

<gadget id="calculator">200 / 2</gadget>
<output>100</output>

<gadget id="calculator">100 * 3</gadget>
<output>300</output>

<gadget id="calculator">400 - 300</gadget>
<output>100</output>

<gadget id="calculator">100 / 100</gadget>
<output>1</output>

<gadget id="calculator">1 * 100</gadget>
<output>100</output>

<result>A</result>
peter invested a certain sum of money in a simple interest bond whose value grew to $ 400 at the end of 3 years and to $ 600 at the end of another 2 years. what was the rate of interest in which he invested his sum?
multiply(divide(divide(subtract(600, 400), 2), subtract(400, multiply(divide(subtract(600, 400), 2), 3))), const_100)
"lets assume the principal amount ( initial amount invested ) to be p rate of interest to berand time as t . we need to find r now after a time of 3 years the principal p amounts to $ 400 and after a time of 5 years ( question says after another 5 years so 3 + 2 ) p becomes $ 600 . formulating the above data amount ( a 1 ) at end of 3 years a 1 = p ( 1 + 3 r / 100 ) = 400 amount ( a 2 ) at end of 8 years a 2 = p ( 1 + 5 r / 100 ) = 600 dividing a 2 by a 1 we get ( 1 + 5 r / 100 ) / ( 1 + 3 r / 100 ) = 6 / 8 after cross multiplication we are left with r = 100 option : a"