is two years older than b who is twice as old as c. if the total of the ages of a, b and c be 32, then how old is b?	Select the correct option:
A) 7  B) 8  C) 9  D) 10  E) 12
<gadget id="calculator">32 - 2</gadget>
<output>30</output>

<gadget id="calculator">3 + 2</gadget>
<output>5</output>

<gadget id="calculator">30 / 5</gadget>
<output>6</output>

<gadget id="calculator">6 * 2</gadget>
<output>12</output>

<result>E</result>
is two years older than b who is twice as old as c. if the total of the ages of a, b and c be 32, then how old is b?
multiply(divide(subtract(32, const_2), add(const_3, const_2)), const_2)
"let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 32 5 x = 30 = > x = 6 hence , b ' s age = 2 x = 12 years . answer : e"