if the sample interest on a sum of money 10 % per annum for 2 years is $ 1200, find the compound interest on the same sum for the same period at the same rate? Pick one
A) $ 1260 B) $ 1520 C) $ 1356 D) $ 1440 E) $ 1210
<gadget id="calculator">1_200 * 100</gadget>
<output>120_000</output>

<gadget id="calculator">10 * 2</gadget>
<output>20</output>

<gadget id="calculator">120_000 / 20</gadget>
<output>6_000</output>

<gadget id="calculator">6_000 * 10</gadget>
<output>60_000</output>

<gadget id="calculator">60_000 / 100</gadget>
<output>600</output>

<gadget id="calculator">6_000 + 600</gadget>
<output>6_600</output>

<gadget id="calculator">6_600 * 10</gadget>
<output>66_000</output>

<gadget id="calculator">66_000 / 100</gadget>
<output>660</output>

<gadget id="calculator">660 + 6_600</gadget>
<output>7_260</output>

<gadget id="calculator">7_260 - 6_000</gadget>
<output>1_260</output>

<result>A</result>
if the sample interest on a sum of money 10 % per annum for 2 years is $ 1200, find the compound interest on the same sum for the same period at the same rate?
subtract(add(divide(multiply(add(divide(multiply(1200, const_100), multiply(10, 2)), divide(multiply(divide(multiply(1200, const_100), multiply(10, 2)), 10), const_100)), 10), const_100), add(divide(multiply(1200, const_100), multiply(10, 2)), divide(multiply(divide(multiply(1200, const_100), multiply(10, 2)), 10), const_100))), divide(multiply(1200, const_100), multiply(10, 2)))
rate = 10 % time = 2 years s . i . = $ 1200 principal = 100 * 1200 / 10 * 2 = $ 6000 amount = 6000 ( 1 + 10 / 100 ) ^ 2 = $ 7260 c . i . = 7260 - 6000 = $ 1260 answer is a