one fourth of a solution that was 10 % sugar by weight was replaced with by a second solution resulting in a solution that was 16 percent sugar by weight. the second solution was what percent sugar by weight?	Choose the correct choice from the following:
A) 34 %  B) 24 %  C) 22 %  D) 18 %  E) 8.5 %
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>

<gadget id="calculator">100 * (4/25)</gadget>
<output>16</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>

<gadget id="calculator">100 - 25</gadget>
<output>75</output>

<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">75 * (1/10)</gadget>
<output>15/2 = around 7.5</output>

<gadget id="calculator">16 - (15/2)</gadget>
<output>17/2 = around 8.5</output>

<gadget id="calculator">(17/2) / 25</gadget>
<output>17/50 = around 0.34</output>

<gadget id="calculator">(17/50) * 100</gadget>
<output>34</output>

<result>A</result>
one fourth of a solution that was 10 % sugar by weight was replaced with by a second solution resulting in a solution that was 16 percent sugar by weight. the second solution was what percent sugar by weight?
multiply(divide(subtract(multiply(const_100, divide(16, const_100)), multiply(subtract(const_100, multiply(divide(const_1, const_4), const_100)), divide(10, const_100))), multiply(divide(const_1, const_4), const_100)), const_100)
"say the second solution ( which was 1 / 4 th of total ) was x % sugar , then 3 / 4 * 0.1 + 1 / 4 * x = 1 * 0.16 - - > x = 0.34 . alternately you can consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.1 + 25 * x = 100 * 0.16 - - > x = 0.34 . answer : a ."