what is the greater of the two numbers whose product is 2496, given that the sum of the two numbers exceeds their difference by 64?
Choose the correct choice from the following answers.
A) 96
B) 108
C) 110
D) 78
E) of these
<gadget id="calculator">2 ** 4</gadget>
<output>16</output>

<gadget id="calculator">16 * 2</gadget>
<output>32</output>

<gadget id="calculator">2_496 / 32</gadget>
<output>78</output>

<result>D</result>
what is the greater of the two numbers whose product is 2496, given that the sum of the two numbers exceeds their difference by 64?
divide(2496, multiply(power(const_2, const_4), const_2))
"let the greater and the smaller number be g and s respectively . gs = 2496 g + s exceeds g - s by 64 i . e . , g + s - ( g - s ) = 64 i . e . , 2 s = 64 = > s = 32 . g = 2496 / s = 78 . answer : d"