3 friends james, david and charlie divide $ 1230 amongs them in such a way that if $ 5, $ 10 and $ 15 are removed from the sums that james, david and charlie received respectively, then the share of the sums that they got will be in the ratio of 9: 10: 11. how much did charlie receive?	Options:	A) $ 600	B) $ 575	C) $ 550	D) $ 580	E) $ 615
<gadget id="calculator">5 + 10</gadget>
<output>15</output>

<gadget id="calculator">15 + 15</gadget>
<output>30</output>

<gadget id="calculator">1_230 - 30</gadget>
<output>1_200</output>

<gadget id="calculator">9 + 10</gadget>
<output>19</output>

<gadget id="calculator">19 + 11</gadget>
<output>30</output>

<gadget id="calculator">1_200 / 30</gadget>
<output>40</output>

<gadget id="calculator">11 * 40</gadget>
<output>440</output>

<gadget id="calculator">440 + 15</gadget>
<output>455</output>

<gadget id="calculator">455 + 40</gadget>
<output>495</output>

<gadget id="calculator">495 + 40</gadget>
<output>535</output>

<gadget id="calculator">535 + 40</gadget>
<output>575</output>

<gadget id="calculator">575 + 40</gadget>
<output>615</output>

<result>E</result>
3 friends james, david and charlie divide $ 1230 amongs them in such a way that if $ 5, $ 10 and $ 15 are removed from the sums that james, david and charlie received respectively, then the share of the sums that they got will be in the ratio of 9: 10: 11. how much did charlie receive?
add(add(add(add(add(multiply(11, divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), 15), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11))), divide(subtract(1230, add(add(5, 10), 15)), add(add(9, 10), 11)))
a + b + c = 1230 given ratio 9 : 10 : 11 let us say the shares of a , b , c deducting 5 , 1015 be a , b , c a + b + c = 1230 - 30 = 1200 = 30 k c share = ( 1200 x 30 ) / 60 = 600 c = charlie share = 600 + 15 = 615 option e