in a certain pond, 80 fish were caught, tagged, and returned to the pond. a few days later, 50 fish were caught again, of which 2 were found to have been tagged. if the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
Choose the correct choice from the following answers:
A) 400 B) 625 C) 1,250 D) 2,000 E) 10,000
<gadget id="calculator">2 / 50</gadget>
<output>1/25 = around 0.04</output>

<gadget id="calculator">80 / (1/25)</gadget>
<output>2_000</output>

<result>D</result>
in a certain pond, 80 fish were caught, tagged, and returned to the pond. a few days later, 50 fish were caught again, of which 2 were found to have been tagged. if the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?
divide(80, divide(2, 50))
this is a rather straight forward ratio problem . 1 . 80 fish tagged 2 . 2 out of the 50 fish caught were tagged thus 2 / 50 2 / 50 = 80 / x thus , x = 2000 think of the analogy : 2 fish is to 50 fish as 50 fish is to . . . ? you ' ve tagged 50 fish and you need to find what that comprises as a percentage of the total fish population - we have that information with the ratio of the second catch . d