if a and b together can finish a work in 16 days. a can finish same work alone in 24 days then b alone can finish same work alone in how many days?  Select.
A) 30 days	B) 48 days	C) 40 days	D) 36 days	E) 50 days
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>

<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>

<gadget id="calculator">(1/16) - (1/24)</gadget>
<output>1/48 = around 0.020833</output>

<gadget id="calculator">1 / (1/48)</gadget>
<output>48</output>

<result>B</result>
if a and b together can finish a work in 16 days. a can finish same work alone in 24 days then b alone can finish same work alone in how many days?
inverse(subtract(inverse(16), inverse(24)))
( a + b ) work in 1 day = 1 / 16 , a work in 1 day = 1 / 24 b work in 1 day = [ 1 / 16 - 1 / 24 ] = 1 / 48 . b alone can finish same work in 48 days . answer b