if the angles of an n sided polygon are in a. p and a > = 20 and d > = 20 then wat is the maximum possible value of n?	Pick one.
A) 12  B) 14  C) 21  D) 25  E) cant determine
<gadget id="calculator">20 - 3</gadget>
<output>17</output>

<gadget id="calculator">17 ** 2</gadget>
<output>289</output>

<gadget id="calculator">4 * 2</gadget>
<output>8</output>

<gadget id="calculator">10 * 8</gadget>
<output>80</output>

<gadget id="calculator">80 + 100</gadget>
<output>180</output>

<gadget id="calculator">180 / 10</gadget>
<output>18</output>

<gadget id="calculator">18 * 2</gadget>
<output>36</output>

<gadget id="calculator">4 * 36</gadget>
<output>144</output>

<gadget id="calculator">289 - 144</gadget>
<output>145</output>

<gadget id="calculator">145 ** (1/2)</gadget>
<output>sqrt(145) = around 12.041595</output>

<gadget id="calculator">(sqrt(145)) + 17</gadget>
<output>sqrt(145) + 17 = around 29.041595</output>

<gadget id="calculator">(sqrt(145) + 17) / 2</gadget>
<output>sqrt(145)/2 + 17/2 = around 14.520797</output>

<result>B</result>
if the angles of an n sided polygon are in a. p and a > = 20 and d > = 20 then wat is the maximum possible value of n?
divide(add(sqrt(subtract(power(subtract(20, const_3), const_2), multiply(const_4, multiply(divide(add(multiply(const_10, multiply(const_4, const_2)), const_100), const_10), const_2)))), subtract(20, const_3)), const_2)
sum of interior angles of a polygon = ( n - 2 ) × 180 ° where n = number of sides there will be n angles which are in a . p . therefore , since we need to find maximum value of n , put minimum value for a and d . i . e . , take a = 20 and d = 20 then sum of the angles = n / 2 [ 2 × 20 + ( n − 1 ) 20 ] therefore , 10 n ( n + 1 ) = ( n − 2 ) 180 n = 14.52 since number of sides must be a positive integer , maximum value of n = 14 answer : b