a man speaks truth 3 out of 4 times. he throws a die and reports it to be a 6. what is the probability of it being a 6?  Choose the most appropriate option.
A) 3 / 5
B) 1 / 2
C) 3 / 4
D) 3 / 8
E) 3 / 6
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">(3/4) * (1/6)</gadget>
<output>1/8 = around 0.125</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>

<gadget id="calculator">(1/4) * (5/6)</gadget>
<output>5/24 = around 0.208333</output>

<gadget id="calculator">(1/8) + (5/24)</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">(1/8) / (1/3)</gadget>
<output>3/8 = around 0.375</output>

<result>D</result>
a man speaks truth 3 out of 4 times. he throws a die and reports it to be a 6. what is the probability of it being a 6?
divide(multiply(divide(3, 4), divide(const_1, 6)), add(multiply(divide(3, 4), divide(const_1, 6)), multiply(divide(const_1, const_4), divide(const_5, 6))))
explanation : there are two cases 1 ) he is telling truth that the die reports 6 , its probability = 3 / 4 * 1 / 6 = 1 / 8 2 ) he is telling lie that the die reports 6 , its probability = 1 / 4 * 5 / 6 = 5 / 24 so required probability = ( 1 / 8 ) / ( 1 / 8 ) + ( 5 / 24 ) = ( 1 / 8 ) / ( 1 / 3 ) = 3 / 8 hencer ( d ) is the correct answer answer : d