in an election contested by two parties, party d secured 12 % of the total votes more than party r. if party r got 132000 votes, by how many votes did it lose the election? Choose the correct choice from the following choices
A) 240000
B) 300000
C) 168000
D) 36000
E) 24,000
<gadget id="calculator">100 - 12</gadget>
<output>88</output>

<gadget id="calculator">88 / 2</gadget>
<output>44</output>

<gadget id="calculator">132_000 / 44</gadget>
<output>3_000</output>

<gadget id="calculator">3_000 * 12</gadget>
<output>36_000</output>

<result>D</result>
in an election contested by two parties, party d secured 12 % of the total votes more than party r. if party r got 132000 votes, by how many votes did it lose the election?
multiply(divide(132000, divide(subtract(const_100, 12), const_2)), 12)
explanatory answer let the percentage of the total votes secured by party d be x % then the percentage of total votes secured by party r = ( x - 12 ) % as there are only two parties contesting in the election , the sum total of the votes secured by the two parties should total up to 100 % i . e . , x + x - 12 = 100 2 x - 12 = 100 or 2 x = 112 or x = 56 % . if party d got 56 % of the votes , then party got ( 56 - 12 ) = 44 % of the total votes . 44 % of the total votes = 132,000 i . e . , 44 / 100 * t = 132,000 = > t = 132000 * 100 / 44 = 300,000 votes . the margin by which party r lost the election = 12 % of the total votes = 12 % of 300,000 = 36,000 . the correct choice is ( d )