5 years ago, the average age of a, b, c and d was 45 years. with e joining them now, the average of all the 5 is 50 years. the age of e is?	Select.
A) 50  B) 47  C) 48  D) 49  E) 46
<gadget id="calculator">50 * 5</gadget>
<output>250</output>

<gadget id="calculator">2 * 2</gadget>
<output>4</output>

<gadget id="calculator">45 * 4</gadget>
<output>180</output>

<gadget id="calculator">5 * 4</gadget>
<output>20</output>

<gadget id="calculator">180 + 20</gadget>
<output>200</output>

<gadget id="calculator">250 - 200</gadget>
<output>50</output>

<result>A</result>
5 years ago, the average age of a, b, c and d was 45 years. with e joining them now, the average of all the 5 is 50 years. the age of e is?
subtract(multiply(50, 5), add(multiply(45, multiply(const_2, const_2)), multiply(5, const_4)))
solution 5 years ago average age of a , b , c , d = 45 years = > 5 years ago total age of a , b , c , d = 45 x 4 = 180 years = > total present age of a , b , c , d = 180 + 5 x 4 = 200 years if e ' s present age is x years = 200 + x / 5 = 50 x = 50 years . answer a