on a trip, a cyclist averaged 11 miles per hour for the first 22 miles and 10 miles per hour for the remaining 20 miles. if the cyclist returned immediately via the same route and took a total of 9 hours for the round trip, what was the average speed ( in miles per hour ) for the return trip?  Pick:
A) 7.6
B) 7.8
C) 8
D) 8.2
E) 8.4
<gadget id="calculator">22 + 20</gadget>
<output>42</output>

<gadget id="calculator">22 / 11</gadget>
<output>2</output>

<gadget id="calculator">20 / 10</gadget>
<output>2</output>

<gadget id="calculator">2 + 2</gadget>
<output>4</output>

<gadget id="calculator">9 - 4</gadget>
<output>5</output>

<gadget id="calculator">42 / 5</gadget>
<output>42/5 = around 8.4</output>

<result>E</result>
on a trip, a cyclist averaged 11 miles per hour for the first 22 miles and 10 miles per hour for the remaining 20 miles. if the cyclist returned immediately via the same route and took a total of 9 hours for the round trip, what was the average speed ( in miles per hour ) for the return trip?
divide(add(22, 20), subtract(9, add(divide(22, 11), divide(20, 10))))
the time to go 42 miles was 22 / 11 + 20 / 10 = 2 + 2 = 4 hours . the average speed for the return trip was 42 miles / 5 hours = 8.4 mph . the answer is e .