if n is an integer and 101 n ^ 2 is less than or equal to 10000, what is the greatest possible value of n?	Choices.
A) 7 B) 8 C) 9 D) 10 E) 11
<gadget id="calculator">10_000 / 101</gadget>
<output>10_000/101 = around 99.009901</output>

<gadget id="calculator">(10_000/101) ** (1/2)</gadget>
<output>100*sqrt(101)/101 = around 9.950372</output>

<gadget id="calculator">floor(100*sqrt(101)/101)</gadget>
<output>9</output>

<result>C</result>
if n is an integer and 101 n ^ 2 is less than or equal to 10000, what is the greatest possible value of n?
floor(sqrt(divide(10000, 101)))
"101 * n ^ 2 < = 10000 n ^ 2 < = 10000 / 101 which will be less than 100 since 10000 / 100 = 100 which is the square of 9 next closest value of n where n ^ 2 < = 100 is 9 ans c"