three pipes of same capacity can fill a tank in 8 hours. if there are only two pipes of same capacity, the tank can be filled in. Options:
A) 11 hours	B) 12 hours	C) 15 hours	D) 16 hours	E) 17 hours
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>

<gadget id="calculator">(2/3) * (1/8)</gadget>
<output>1/12 = around 0.083333</output>

<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>

<result>B</result>
three pipes of same capacity can fill a tank in 8 hours. if there are only two pipes of same capacity, the tank can be filled in.
inverse(multiply(divide(const_2, const_3), divide(const_1, 8)))
the part of the tank filled by three pipes in one hour = 1 / 8 = > the part of the tank filled by two pipes in 1 hour = 2 / 3 * 1 / 8 = 1 / 12 . the tank can be filled in 12 hours . answer : b