if x and y are integers such that x ^ 2 = 2 y and xy = 32, then x – y =?	Choose the correct choice from the following answers
A) - 30
B) - 20
C) - 5
D) - 4
E) 20
<gadget id="calculator">32 * 2</gadget>
<output>64</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>

<gadget id="calculator">32 / 4</gadget>
<output>8</output>

<gadget id="calculator">4 - 8</gadget>
<output>-4</output>

<result>D</result>
if x and y are integers such that x ^ 2 = 2 y and xy = 32, then x – y =?
subtract(power(multiply(32, 2), const_0_33), divide(32, power(multiply(32, 2), const_0_33)))
"here x and y are integers . x ^ 2 = 2 y , xy = 32 . substitute ( x ^ 2 ) / 2 = y in xy = > x ^ 3 = 32 * 2 = > x ^ 3 = 64 . here x 3 is positive , x is also positive . x = 4 then y = 8 . x - y = - 4 so option d is correct"