x and y are both integers. if x / y = 59.40, then what is the sum of all the possible two digit remainders of x / y?	Pick
A) 450	B) 616	C) 672	D) 900	E) 1024
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>

<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>

<gadget id="calculator">2 + 3</gadget>
<output>5</output>

<gadget id="calculator">5 * 59.4</gadget>
<output>297</output>

<gadget id="calculator">297 + 3</gadget>
<output>300</output>

<gadget id="calculator">150 + 300</gadget>
<output>450</output>

<result>A</result>
x and y are both integers. if x / y = 59.40, then what is the sum of all the possible two digit remainders of x / y?
add(multiply(divide(const_3, const_2), const_100), add(multiply(add(const_2, const_3), 59.4), const_3))
remainder = 0.40 - - > 40 / 100 - - > can be written as ( 40 / 4 ) / ( 100 / 4 ) = 10 / 25 so remainders can be 10 , 20 , 30 , 40 , . . . . . 90 . we need the sum of only 2 digit remainders - - > 10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 = 450 answer : a