if f ( f ( n ) ) + f ( n ) = 2 n + 3 and f ( 0 ) = 1, what is the value of f ( 2012 )?  Pick one:
A) 222  B) 2787  C) 2013  D) 2778  E) 10222
<gadget id="calculator">1 + 2_012</gadget>
<output>2_013</output>

<result>C</result>
if f ( f ( n ) ) + f ( n ) = 2 n + 3 and f ( 0 ) = 1, what is the value of f ( 2012 )?
add(1, 2012)
"put n = 0 then f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 ⇒ ⇒ f ( 1 ) + 1 = 3 ⇒ ⇒ f ( 1 ) = 2 put n = 1 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 ⇒ ⇒ f ( 2 ) + 2 = 5 ⇒ ⇒ f ( 2 ) = 3 put n = 2 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 ⇒ ⇒ f ( 3 ) + 3 = 7 ⇒ ⇒ f ( 3 ) = 4 . . . . . . f ( 2012 ) = 2013 answer : c"