the membership of a committee consists of 3 english teachers, 4 mathematics teachers, and 2 social studies teachers. if 2 committee members are to be selected at random to write the committee ’ s report, what is the probability that the two members selected will both be social teachers? Options.
A) 2 / 3
B) 1 / 12
C) 2 / 9
D) 1 / 2
E) 1 / 24
<gadget id="calculator">3 + 4</gadget>
<output>7</output>

<gadget id="calculator">7 + 2</gadget>
<output>9</output>

<gadget id="calculator">3 / 9</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">9 - 1</gadget>
<output>8</output>

<gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">(1/3) * (1/4)</gadget>
<output>1/12 = around 0.083333</output>

<result>B</result>
the membership of a committee consists of 3 english teachers, 4 mathematics teachers, and 2 social studies teachers. if 2 committee members are to be selected at random to write the committee ’ s report, what is the probability that the two members selected will both be social teachers?
multiply(divide(3, add(add(3, 4), 2)), divide(2, subtract(add(add(3, 4), 2), const_1)))
"probability of first member an english teacher = 3 / 9 probability of second member an english teacher = 2 / 8 probability of both being english teacher = 3 / 9 x 2 / 8 = 1 / 12 ( b )"