6 persons in an organization including x and y were to be divided in two groups of 3 members each. the total number of groups containing both x and y is what fraction of the total number of groups which can be formed?
Options:
A) 1 / 4
B) 1 / 70
C) 3 / 14
D) 3 / 10
E) 11 / 14
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>

<gadget id="calculator">6 - 1</gadget>
<output>5</output>

<gadget id="calculator">5 * 4</gadget>
<output>20</output>

<gadget id="calculator">6 / 20</gadget>
<output>3/10 = around 0.3</output>

<result>D</result>
6 persons in an organization including x and y were to be divided in two groups of 3 members each. the total number of groups containing both x and y is what fraction of the total number of groups which can be formed?
divide(factorial(3), multiply(subtract(6, const_1), const_4))
the fraction is nothing but the probability . . number to choose 3 out of 6 = 6 c 3 number to choose x and y and 2 from remaining 4 = 4 c 2 . . prob of a and b choosen = 4 c 2 / 6 c 3 = 3 / 10 answer : d