there are 3 red shoes & 7 green shoes. if two of red shoes are drawn what is the probability of getting red shoes
Select.
A) 1 / 13
B) 1 / 14
C) 1 / 12
D) 1 / 15
E) 1 / 16
<gadget id="calculator">binomial(3, 2)</gadget>
<output>3</output>

<gadget id="calculator">3 + 7</gadget>
<output>10</output>

<gadget id="calculator">binomial(10, 2)</gadget>
<output>45</output>

<gadget id="calculator">3 / 45</gadget>
<output>1/15 = around 0.066667</output>

<result>D</result>
there are 3 red shoes & 7 green shoes. if two of red shoes are drawn what is the probability of getting red shoes
divide(choose(3, const_2), choose(add(3, 7), const_2))
"taking 2 red shoe the probablity is 3 c 2 from 10 shoes probablity of taking 2 red shoe is 3 c 2 / 10 c 2 = 1 / 15 answer : d"