from a group of 4 boys and 4 girls, 4 children are to be randomly selected. what is the probability that 2 boys and 2 girls will be selected?
Choose the correct answer:
A) 12 / 29
B) 14 / 31
C) 16 / 33
D) 18 / 35
E) 20 / 37
<gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>

<gadget id="calculator">6 * 6</gadget>
<output>36</output>

<gadget id="calculator">4 + 4</gadget>
<output>8</output>

<gadget id="calculator">binomial(8, 4)</gadget>
<output>70</output>

<gadget id="calculator">36 / 70</gadget>
<output>18/35 = around 0.514286</output>

<result>D</result>
from a group of 4 boys and 4 girls, 4 children are to be randomly selected. what is the probability that 2 boys and 2 girls will be selected?
divide(multiply(choose(4, const_2), choose(4, const_2)), choose(add(4, 4), 4))
"the total number of ways to choose 4 children from 8 is 8 c 4 = 70 the number of ways to choose 2 boys and 2 girls is 4 c 2 * 4 c 2 = 6 * 6 = 36 p ( 2 boys and 2 girls ) = 36 / 70 = 18 / 35 the answer is d ."