on a certain transatlantic crossing, 40 percent of a ship ’ s passengers held round - trip tickets and also took their cars abroad the ship. if 20 percent of the passengers with round - trip tickets did not take their cars abroad the ship, what percent of the ship ’ s passengers held round - trip tickets?	Answers
A) 20 %	B) 40 %	C) 50 %	D) 60 %	E) 80 %
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">40 / (4/5)</gadget>
<output>50</output>

<result>C</result>
on a certain transatlantic crossing, 40 percent of a ship ’ s passengers held round - trip tickets and also took their cars abroad the ship. if 20 percent of the passengers with round - trip tickets did not take their cars abroad the ship, what percent of the ship ’ s passengers held round - trip tickets?
divide(40, subtract(const_1, divide(20, const_100)))
"let t be the total number of passengers . let x be the number of people with round trip tickets . 0.4 t had round trip tickets and took their cars . 0.8 x had round trip tickets and took their cars . 0.8 x = 0.4 t x = 0.5 t the answer is c ."