if an integer n is to be selected at random from 1 to 100, inclusive, what is probability n ( n + 1 ) will be divisible by 32?
Choose the correct choice from the following answers: A) 2 / 7 B) 3 / 7 C) 1 / 16 D) 1 / 14 E) 1 / 12
<gadget id="calculator">2 / 32</gadget>
<output>1/16 = around 0.0625</output>

<result>C</result>
if an integer n is to be selected at random from 1 to 100, inclusive, what is probability n ( n + 1 ) will be divisible by 32?
divide(const_2, 32)
"because n ( n + 1 ) is always an even product of even * odd or odd * even factors , there is a probability of 1 that that it will be divisible by 2 , and , thus , a probability of 1 / 2 that it will be divisible by 4 and , thus , a probability of 1 / 4 that it will be divisible by 8 and , thus , a probability of 1 / 8 that it will be divisible by 16 and , thus , a probability of 1 / 16 that it will be divisible by 32 1 * 1 / 16 = 1 / 16 answer : c"