a is 30 % more efficient than b. how much time they will working together take to complete a job which a alone could have done in 23 days?
Pick:
A) 25 days  B) 13 days  C) 14 days  D) 20 days  E) 15 days
<gadget id="calculator">1 / 23</gadget>
<output>1/23 = around 0.043478</output>

<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>

<gadget id="calculator">(3/10) + 1</gadget>
<output>13/10 = around 1.3</output>

<gadget id="calculator">(13/10) * 23</gadget>
<output>299/10 = around 29.9</output>

<gadget id="calculator">1 / (299/10)</gadget>
<output>10/299 = around 0.033445</output>

<gadget id="calculator">(1/23) + (10/299)</gadget>
<output>1/13 = around 0.076923</output>

<gadget id="calculator">1 / (1/13)</gadget>
<output>13</output>

<result>B</result>
a is 30 % more efficient than b. how much time they will working together take to complete a job which a alone could have done in 23 days?
inverse(add(divide(const_1, 23), divide(const_1, multiply(add(divide(30, const_100), const_1), 23))))
"the ratio of times taken by a and b = 100 : 130 = 10 : 13 suppose b can do work in x days then 10 : 13 : : 23 : x x = ( 23 * 13 ) / 10 x = 299 / 10 a ' s 1 day ' s work = 1 / 23 b ' s 1 day ' s work = 10 / 299 ( a + b ) ' s 1 day ' s work = 1 / 23 + 10 / 299 = 23 / 299 = 1 / 13 a and b together can do work in 13 days answer ( b )"