a is two years older than b who is twice as old as c. if the total of the ages of a, b and c be 27, the how old is b?	Select:  A) 7  B) 9  C) 8  D) 11  E) 10
<gadget id="calculator">27 - 2</gadget>
<output>25</output>

<gadget id="calculator">25 * 2</gadget>
<output>50</output>

<gadget id="calculator">4 + 1</gadget>
<output>5</output>

<gadget id="calculator">50 / 5</gadget>
<output>10</output>

<result>E</result>
a is two years older than b who is twice as old as c. if the total of the ages of a, b and c be 27, the how old is b?
divide(multiply(subtract(27, const_2), const_2), add(const_4, const_1))
"explanation : let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 27 ⇒ 5 x = 25 ⇒ x = 5 . hence , b ' s age = 2 x = 10 years . answer : e"