a mixture of sand and cement contains, 3 parts of sand and 5 parts of cement. how much of the mixture must be substituted with sand to make the mixture half sand and half cement? Pick one:
A) 1 / 3 B) 1 / 4 C) 1 / 5 D) 1 / 7 E) 1 / 8
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">1 + (3/5)</gadget>
<output>8/5 = around 1.6</output>

<gadget id="calculator">5 + 3</gadget>
<output>8</output>

<gadget id="calculator">(8/5) / 8</gadget>
<output>1/5 = around 0.2</output>

<result>C</result>
a mixture of sand and cement contains, 3 parts of sand and 5 parts of cement. how much of the mixture must be substituted with sand to make the mixture half sand and half cement?
divide(add(const_1, divide(3, 5)), add(5, 3))
we have total of 8 parts : 3 parts of sand and 5 parts of cement . in order there to be half sand and half cement ( 4 parts of sand and 4 parts of cement ) , we should remove 1 part of cement . with 1 part of cement comes 3 / 5 parts of sand , so we should remove 1 + 3 / 5 = 8 / 5 part of the mixture , which is ( 8 / 5 ) / 8 = 1 / 5 of the mixture . answer : c .