if a certain coin is flipped, the probability that the coin will land heads is 1 / 2. if the coin is flipped 5 times, what is the probability that it will land heads up on the first 3 flips and not on the last 2 flips?
Pick
A) 3 / 5 B) 1 / 2 C) 1 / 5 D) 1 / 8 E) 1 / 32
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">(1/2) ** 5</gadget>
<output>1/32 = around 0.03125</output>

<result>E</result>
if a certain coin is flipped, the probability that the coin will land heads is 1 / 2. if the coin is flipped 5 times, what is the probability that it will land heads up on the first 3 flips and not on the last 2 flips?
power(divide(1, 2), 5)
"on the first three flips , you must get heads . whats the probability of getting heads ? its 1 / 2 so for the first three flips , your probability is ( 1 / 2 ) ^ 3 = 1 / 8 now for the last two , you want to get tails only . whats the prob of getting tails ? well , its the same as prob of getting a heads , namely , 1 / 2 for the last two flips , your probability is ( 1 / 2 ) ^ 2 = 1 / 4 so your overall probability for the event in question is 1 / 8 * 1 / 4 = 1 / 32 answer : e"