compound interest of rs. 2000 at 10 % per annum for 1 1 / 2 years will be ( interest compounded half yearly ).	Choose the correct choice from the following choices:	A) rs . 473	B) rs . 374	C) rs . 495	D) rs . 315	E) none of the above
<gadget id="calculator">10 / 2</gadget>
<output>5</output>

<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>

<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>

<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>

<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>

<gadget id="calculator">(21/20) ** 3</gadget>
<output>9_261/8_000 = around 1.157625</output>

<gadget id="calculator">2_000 * (9_261/8_000)</gadget>
<output>9_261/4 = around 2_315.25</output>

<gadget id="calculator">(9_261/4) - 2_000</gadget>
<output>1_261/4 = around 315.25</output>

<result>D</result>
compound interest of rs. 2000 at 10 % per annum for 1 1 / 2 years will be ( interest compounded half yearly ).
subtract(multiply(2000, power(add(1, divide(divide(10, 2), const_100)), multiply(add(1, divide(1, 2)), 2))), 2000)
"10 % interest per annum will be 5 % interest half yearly for 3 terms ( 1 1 / 2 years ) so compound interest = 2000 [ 1 + ( 5 / 100 ) ] ^ 3 - 2000 = 2000 [ ( 21 / 20 ) ^ 3 - 1 ] = 2000 ( 9261 - 8000 ) / 8000 = 2 * 1261 / 8 = 315 answer : d"