You are a helpful assistant that can solve the given question step by step with the help of the wikipedia search tool and python interpreter tool. Given a question, you need to first think about the reasoning process in the mind and then provide the answer. During thinking, you can invoke the wikipedia search tool to search and python interpreter tool to calculate the math problem for fact information about specific topics if needed. The reasoning process and answer are enclosed within <think> </think> and <answer> </answer> tags respectively, and the search query and result are enclosed within <search> </search> and <result> </result> tags respectively. For example, <think> This is the reasoning process. </think> <search> search query here </search> <result> search result here </result> <think> This is the reasoning process. </think> <python> python code here </python> <result> python interpreter result here </result> <think> This is the reasoning process. </think> <answer> The final answer is \[ oxed{answer here} \] </answer>. In the last part of the answer, the final exact answer is enclosed within oxed{} with latex format.
system
求具有下述性质的最小正常数 c：对任意一个简单图 G=G(V,E)，只要 |E|\geq c|V|，则 G 一定含有两个无公共顶点的圈，并且其中之一是带弦圈.注：图 G(V,E) 的圈是指一个两两不同的顶点序列 \{v_1,v_2,\cdots,v_n\}\subseteq V，其中 v_iv_{i+1}\in E(1\leq i\leq n) （这里 n\geq 3,v_{n+1}=v_1）；带弦圈是指一个圈 \{v_1,v_2,\cdots,v_n\}，且存在 i,j，1<i-j<n-1，满足 v_iv_j\in E.
user
4
rule
求具有下述性质的最小正常数 c：对任意一个简单图 G=G(V,E)，只要 |E|\geq c|V|，则 G 一定含有两个无公共顶点的圈，并且其中之一是带弦圈.注：图 G(V,E) 的圈是指一个两两不同的顶点序列 \{v_1,v_2,\cdots,v_n\}\subseteq V，其中 v_iv_{i+1}\in E(1\leq i\leq n) （这里 n\geq 3,v_{n+1}=v_1）；带弦圈是指一个圈 \{v_1,v_2,\cdots,v_n\}，且存在 i,j，1<i-j<n-1，满足 v_iv_j\in E.
train