Q: Is their Banach space such that its dual is C[a b] - continuous functions on [a b]? 
Possible Duplicate:
The Space $C(\Omega,\mathbb{R})$ has a Predual? 

Is their Banach space such that its dual is C[a b] - continuos functions on [a b] ?
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[EDIT]
Related question is: 
The Space $C(\Omega,\mathbb{R})$ has a Predual?
It seems that comment by  Jonas Meyer to this question contains a negative answer to my question. However some extension of comment is welcome - "by the Krein-Milman theorem this implies that  is not a dual space." - not very clear to me.
PS
Surprising how can similar questions come to mind of different people during the same day ?:)
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Background: 
in finite-dimensions: double dual space is isomorphic to itself.
In infinite-dimensions it is not always true. In particular for space of continuous
functions it is not true (as far as I remember). 
(See Double dual of the space $C[0,1]$ ).
Remark: Dual space of continuous functions is quite well understood - it is a space of 
measures with bounded variation. See e.g.
http://regularize.wordpress.com/2011/11/11/dual-spaces-of-continuous-functions/
