Q: Relationship between continuous spectra of operators and the spectra of their adjoints Suppose that $A$ is a bounded linear operator on a Hilbert space $\mathcal{H}$ over the complex numbers $\mathbb{C}$, and that $A^*$ denotes its adjoint. The residual spectrum of $A^*$, $\sigma_r(A^*)$, has a nice relationship with the point spectrum of $A$ in that $\sigma_r(A^*) \subseteq \overline{\sigma_p(A)}$, where
$$
\begin{align*}
\overline{\sigma_p(A)} = \left\{\overline{\lambda}:\lambda\in\sigma_p(A)\right\}
\end{align*}
$$
Is there a similar relationship between the continuous spectrum of $A^*$ and the spectrum of $A$? I know that $\sigma(A^*) = \overline{\sigma(A)}$ so the conjugates of the elements of the continous spectrum of $A^*$ are contained somewhere in $\sigma(A)$, but can we say more than that?

A: Here is an answer that I believe works: it can be shown that
$$
\sigma_c(A) = \overline{\sigma_c\left(A^*\right)}
$$
For a bounded linear operator $A$ on a Hilbert space, we have the following facts:


*

*$\rho(A) = \overline{\rho(A^*)}$ (Hunter and Nachtergaele 239)

*$\sigma_r(A)\subseteq\overline{\sigma_p(A^*)}$ (Hunter and Nachtergaele 223)

*$\lambda\in\sigma_p\left(A^*\right) \Longrightarrow \overline{\lambda}\notin\sigma_c(A)$ (can't find a source that directly states this but it comes from a question in the same textbook as the previous two citations)


Let $\lambda\in\sigma_c(A)$. As a corollary to (1), $\sigma(A) = \overline{\sigma(A^*)}$, so $\overline{\lambda}\in\sigma(A^*)$. By (3), $\overline{\lambda}\notin\sigma_p(A^*)$, and so $\overline{\lambda}\in\sigma_c(A^*)\cup\sigma_r(A^*)$. But $\overline{\lambda}\in\sigma_r(A^*)\Longrightarrow\overline{\overline{\lambda}}=\lambda\in\sigma_p(A^{**}) = \sigma_p(A)$ by (2), contradicting $\lambda\in\sigma_c(A)$.
It follows that $\lambda\in\sigma_c(A)\Longrightarrow\overline{\lambda}\in\sigma_c(A^*)$, and since $\overline{\lambda}\in\sigma_c(A)\Longrightarrow\overline{\overline{\lambda}}=\lambda\in\sigma_c(A^{**}) = \sigma_c(A)$, the continuous spectrum of $A$ is the same as the conjugate of the continuous spectrum of its adjoint, i.e. $\lambda\in\sigma_c(A)\Longleftrightarrow\overline{\lambda}\in\sigma_c(A^*)$, QED.
Can anybody verify this?
References:


*

*Hunter, John K., and Bruno Nachtergaele. Applied Analysis. World Scientific, 2007. 

