I need to graph these lines on a graph x+y=-6 and 4x-5y=3
Put each line in the form y=mx +b where m=slope and b= y-intercept (where the line crosses the y-axis).
Line 1: x+y=-6 becomes y=-x-6 such that m=-1 and y-intercept = -6
Line 2: 4x-5y=3 becomes y=-4/5x+3 where m= 4/5 and y-intercept = -3/5
The slope m is the rise over run, or (y2-y1)/(x2-x1) where (x1,y1) and (x2,y2) are any two coordinates on the line.
To graph, start drawing each line at the respective y-intercept so one line 1 at (0,-6) and line 2 at (0,-3/5).
Then for line 1, the slope is -1 so go down one and right one from (0,-6) to arrive at (1,-7) and proceed the same way in both directions (first point in opposite direction is (-1, -5) ).
For line 2, you are at (0,-3/5) [the y-intercept] and the slope is 4/5 so go up 4 and over 5, your next point on line 2 will be ( 5, 3.4), the point in the opposite direction is (-5, -4.6).
Let me know if that's clear or if you need more information, Brenda