1. The problem statement, all variables and given/known data A pair of masses M1, M2 is suspended vertically by a pair of spring, with spring constant k1, k2. ( see the attachment for the picture) a.A downward force F is applied to bottom mass. Find the downward displacements d1 and d 2 of the equilibrium positions of the Mass M1and M2 due to the force. Note that effect of gravity is already taken into account in determing the equilibrium positions. b.At time t =0, the downward force is removed. What are the equation of motion and initial conditions that determine the displacements d1(t) and d2(t) for t greater than 0? You need not solve the equations. 2. Relevant equations m2g=k2x2 k2x2 + m2g+ m1g=k1x1 then i added them, I get 2m2g +m1g=k1x1 F=-kx 3. The attempt at a solution m2g=k2x2 k2x2 + m2g+ m1g=k1x1 then i added them, I get 2m2g +m1g=k1x1. after this, I hav no idea how to solve this! please help!