Calculate the volume of carbon dioxide formed when the required amount of calcium carbonate interacts with 100 g of a solution of 6, 3% nitric acid.
The reaction of dissolving calcium carbonate in nitric acid is described by the following chemical reaction equation:
CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O;
When 1 mol of calcium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of nitric acid.
Let’s calculate the chemical amount of a substance containing in 100 grams of a 6.3% solution of nitric acid.
M HNO3 = 1 + 14 + 16 x 3 = 63 grams / mol;
N HNO3 = 100 x 0.063 / 63 = 0.1 mol;
With this amount of acid, 0.05 mol of calcium carbonate will dissolve and 0.05 mol of carbon dioxide is synthesized.
Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
V CO2 = 0.05 x 22.4 = 1.12 liters;
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