Posted by Mota on Friday, January 22, 2010 at 7:49am.
find the exact values when :
x^2+2x >= 5
- math - bobpursley, Friday, January 22, 2010 at 8:57am
Well, the issue is what are the factors on the left.
Using the quadratic equation
x=(-2+- sqrt (4+4*5))/2=-1+-sqrt6
Well, for the left side to be > 0, both factors have to be positive or negative.
Take x=-100000. That works. So negative x have to be considered.
x+1-sqrt 6<0 And x+1+sqrt6<0
x<-1+sqrt6 AND x<=-1-sqrt6
Since it has to be AND
Now, when are both positive:
x+1-sqrt6>=0 AND x+1-sqrt6>=0
x>-1+sqrt6 AND x>-1+sqrt6
Since that is AND, then
So finally, the exact values are
Check my logic.
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