Let P and Q be the centers of the circles. Let Aand B be the points of intersection of the circles.
PA = 3 cm, QA = 4 cm and PQ = 5 cm. So PAQ is a right angled triangle. Find the area of the triangle PAQ.
Find the angles APQ and AQP by using sin(APQ) = AQ/PQ and sin(AQP) = AP/PQ.
Find the area of the sectors formed by the angles APQ and AQP and add them.
Required area = 2[sum of the area of the sectors - area of the right angled triangle]