An object is released from a height of 50m. How far has the object travelled during the 3rd second of fall?
d = Vi*T + 1/2at^2
Doesn't work though - answer provided is 24.5m.
The Attempt at a Solution
I did a simple distance at 3 seconds with 9.81 m/s^2 as acceleration, got 29.43m. Using the formula above I got 44.45m - again, not 24.5m as provided for answer.
Thanks a lot!