A surveyor locating the corners of a triangular piece of property started at one corner
and walked 480ft in the direction N36°W to reach the next corner.
The surveyor turned and walked S21°W to get to the next corner of the property.
Finally, the surveyor walked in the direction N82°E to get back to the starting point.
What is the perimeter of this piece of property to the nearest foot?
can someone help me sketch out this? I tried by myself but always end up with the wrong answer.
when i first read the problem, i sketched the triangle base on a regular law of sines one.
It says the 36 degree is on North west and I put it in that direction in the triangle, same goes with the other two.
Then did the math, and since it asked for the perimeter I added all 3 sides after
i used law of sines to find the sides. Basically I got a really big answer, (the answer is 1425 ft).
later found out about bearing and did this
I tried to make sense of it, but the wording really confuses me