Is there a continuous periodic function which is not trigonometric. if yes, what?
Yes there are very many. Define a continuous function on [a,b] where f(a)=f(b) then define f outside of [a,b] so that f(x+(b-a))=f(x). A simple example that is not trigonometric (even though it looks like it is) is Arccos(cos(x)).
f(x) = Arccos(cos(x)) = x, the identity function is periodic. Now besides this one and the trig functions, are there other non "man-made" (i.e. cut and pasted according to the process described by lurflurf) that are periodic?
I don't know any functions that aren't "man-made"!
No, the inverse cosine function returns values in a specific interval (which I can't remember atm), so you can't have arccos(cos(x)) = x for all x.
That is right Arccos(cos(x))=x on [0,pi], it is also periodic with period pi, so it repeats all those values. I use Arccos with the capital A to make clear that I am using the principle value of Arccos not just any value that gives the needed value. This is a general way to write periodic functions. let f(x) be diffined and continuous on [a,b] with f(a)=f(b) then
is a periodic extension of f that is f=g on [a,b] and g(x+2n(b-a))=g(x)
when n is an integer.
remenber the definition of a periodic function is a function is periodic with period p if
f(x+p)=f(x) for all x.
Modulus is periodic, any real number to the power of any other real number + an imaginary variable is periodic.
For example, there is:
Every function is man-made. Not every function is "man-made".
every function is man-made yaar....mathematics itself is man-made ;) functions are infinite...i can define a function rite now 2 suit ur needs...lemme see...
f(x)=x-2n for x belonging to [2n, 2n+1) where n is any integer
= (2n+2)-x for x belonging to [2n+1, 2n+2]
check this out...if i havent made any silly mistakes...it shud come out 2 be continuous and periodic...ive modelled it on the sin graph + on the [x] graph..lol...cudnt think of a better example sorry....cheers! ;)
Separate names with a comma.