posted by unknown .
tan theta= 15/8 and pi< theta<3pi/2
a. Sin(- theta)
c. sin( theta - 3pi/4)
can someone explain to me how do you find the exact value for these?
the angle is in the 3rd quadrant.
So, draw a diagram where the hypotenuse extends down to the left from (0,0)
Since tan = y/x, this means that y = -15 and x = -8. So the hypotenuse of your triangle goes from (0,0) to (-8,-15), length=17
Now you are ready to go.
sin theta = y/h = -15/17
cos theta = x/h = -8/17
Use these values in your double-angle, half-angle, and sum/difference formulas.