1. The problem statement, all variables and given/known data A wheel of diameter 45.0 cm starts from rest and rotates with a constant angular acceleration of 2.50 rad/s2 . At the instant the wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways. 1 Using the relationship aredial=ω2r. 2 From the relationship aredial=v2/r. 2. Relevant equations v=ωr rotational kinematics aredial=ω2r aredial=v2/r. 3. The attempt at a solution α= 2.5 it says second rotation so θ= 2π*2 = 12.57 θ = ωt + ½ α t2 12.57 = ½ 2.5 t2 t= 3.171 ω = ω + α t ω = 2.5 (3.171) ω = 7.927 aredial=ω2r a = 7.9272 * 22.5 = 1413.716694 2 should be the same answer since the equations are equal why is my answer wrong?