I have attached the graphs. I don't think the first one is useful, but i needed to plot the data and find the heat of vaporization. Hence, the reason for the second graph. I know that the slope is equal to the heat of vaporization/RT but I don't think I am getting the right answer.
Convert the temperarure values to Kelvin by the addition of 273. take ln of the vapor pressure values and plot. ...
The solution explains each step and provides all mathematical steps.