i know this is a lot , but if someone can even give me an explation where I can begin this that would be a lot of help but if you can go trhough it all with me that would be great. I am very confused.
Take the elapsed time between its launch date and its contact-loss date. Then multiply that by its velocity, (make sure units match).
To calculate the position of pioneer 10 as of Janurary 2009, you take the elapsed time between the launch date and Janurary 2009, then take that and multiply it by the velocity to get the distance. (make sure units match)
The same methods can be applied for the other questions.
As for the logarithmic scale, I believe you either have learned to do that in class or in the past posts have learned it from other user's posts.
Pioneer 10 launch date = 3/2/1972
Days between this date and 1/22/2003 = 11,284 days = 270,816 hrs = 974,937,600 seconds
Assuming that the rate of 12.24 km/s is the constant rate ( which is probably not constant)....the distance that Pioneer 10 was from the Sun on 1/22/2003 =
Time * Rate = Distance
974, 937,600 s * 12.24 km / s ≈ 11,933,236,224 km
So multiplying this by 1000 for the number of meters we get
Days between launch date and 1/1/2009 = 13455 days = 1,162,512,000 seconds
So....the distance from the Sun to Pioneer 10 as of Jan 2009 ≈
Rate * Time = Distance
12.24 km /s * 1,162,512,000 s = 14.229.146,880 km
Jenny....just add three 0's to this to get the number of meters....!!!
Aldebaran is about 65 light years from the Sun (Wikipedia)
Number of meters in one light year ≈ 9,460,730,472,580,800 m
So.....the number of approx. meters from the Sun to Aldebaran ≈
9460730472580800 * 65 =
for the last part that says to make the logarithmic scale, how wuld i go forth in doing that ?
Not asking you to create the whole graph for me but as it goes for x and y axis, I can try my best to figure out the rest. Thank you
I just wanna make sure I know what im doing
I.m not sure about the log graph....but I might go about it this way:
We can create a semi-log graph with the years being on the x axis (linear) and the distances (as base 10 logs) are on the y axis
Let 1972 be year 0
Let 2003 be year 20
Let 2009 be year 26
The distance from the Sun to the Earth (the launch site of Pioneer 10) in 1972 is 140,000,000,000 m
Expressing this as 10 raised to a power wehave that log 140,000,000,000 = 11.14
So ....the first point on the graph would be (0, 11.14)
In 2003, Pioneer 10 was 11,933,236,224,000 m from the Sun
So..... log 11,933,236,224,000 ≈ 13.08
So....the point (20, 13.08) would be on this graph
In 2009 Pioneer 10 was 14.229.146,880,000 m from the Sun
So....log 14,229146,880,000 ≈ 13.15
So....the point (26, 13.15) would be on this graph
One last thng..... the distance from the Sun to Aldebaran = 614,947,480,717,752,000 m
So....Log 614,947,480,717,752,000 = 17.78
This will not have a point associated with it.....so.....I'll leave it to your discretion as how you want to show this
You would need to label the x axis as "Years Since 1972"
Label the y axis as " Base 10 Log Distances "
Here's the graph (you would need to draw a curve through these points.....I don't know how to do that in Desmos)
That's about the best I can do with this !!!
Time in years for Pioneer 10 to go from Earth to Aldebaran =
Distance from Earth to Aldebaran =
Distance from Sun to Aldebaran - Distance from Sun to Earth =
614,947,480,717,752,000 m - 140,000,000,000 m =
So the number of seconds that it will take to travel from Earth to Aldebaran =
Distance / Rate = Time
(The rate that Pioneer travels = 12.24 km/ s = 12240m / s )
614947480717752000 m / 12240 (m/s) ≈ 50240795810274 sec
The number of seconds in a year = (3600/ hr * 24hrs/day * 365 days)
To find the time in years we have
Time in Seconds / Number of Seconds in one year =
50240795810274 / (3600 * 24 *365) = 1,593,125 years!!!!