A compact car, mass 735 kg, is moving at 1.00*10^2 km/h toward the east. The driver of the compact car suddenly applies the brakes hard for 2.0 s. As a result, an average force of 5.1*10^3 N is exerted on the car to slow it.
(b) Determine the new momentum of the car.
(c) What is the velocity of the car now?
a) As per Newton's second law : Applied force = Rate of change of momentum
Or F = d(mv)/dt or Impulse d(mv) = Fdt = -5.1x10^3 x ...
Step by step solution provided.