1. An athlete whirls a 7.48 kg hammer tied to the end of a 1.4 m chain in a horizontal circle. The hammer moves at the rate of 1.76 rev/s. What is the centripetal acceleration of the hammer? Assume his arm length is included in the length given for the chain. Answer in units of m/s 2. Equations I am pretty sure I need are v = 2∏r/T and ac= v2/r not sure if I need any others. 3. I tried finding v first, and I assumed the 1.76 rev/s was T, so I did 2*∏*1.4(about 8.80) and divided it by 1.76, getting about 4.99 m/s and I plugged it in to the ac equation. So I squared the 4.99, getting about 24.98, and dividng it by 1.4, which gets me about 17.843. But that answer is wrong. I don't know what the answer is. I feel like what I am doing wrong is the 1.76 rev/s is not T, or it is, but I have to change it so it's in like m/s or something like that. If that's the case, then I need help finding that because I have no idea how to do that. Thank you for any help!