If a cone is cut into two parts by a horizontal plane passing through the mid-point of its axis, what is the ratio of the volumes of the upper part and the cone?
Asked by | 28th Dec, 2011, 12:15: PM
When the cone is cut like said in the question, let us suppose the radius of small cone is r and of original cone is R. Let us suppose their heights are h and H respectively.
Now, these two cones will be similar, hence r/R = h/H = 1/2
Now ratio of volume of small cone and big cone will be
?r2h/?R2H = (r2/R2)(h/H) = 1/8
Answered by | 28th Dec, 2011, 12:42: PM
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