1. The problem statement, all variables and given/known data It takes a minimum distance of 41.14 m to stop a car moving at 11.0 m/s by applying the brakes (without locking the wheels). Assume that the same frictional forces apply and find the minimum stopping distance when the car is moving at 25.0 m/s. 2. Relevant equations I'm using: d=1/2(Vf + Vi) * T and: v^2 = u^2 + 2as 3. The attempt at a solution So here we go, I'm going to calculate the time to stop using the first formula: 41.14 = 1/2(0+11) * T T = 7.48 Cool, makes sense, alright. Now I'm going to use that number to get the acceleration: 0^2 = 11^2 + (2 * a * 7.48) a = -8.088 Makes plenty of logical sense, am I right? Sweet, Now I'm taking the acceleration and figuring out the stopping time of the faster moving vehicle like so 0^2 = 25^2+(2*-8.088*t) t=38.64 This is weird, it takes 38 seconds for the car to stop, oh well let's see the distance d = 1/2(Vf + Vi) * t d = 1/2(0+25) * 38.64 d = 483 meters Yeah no way....plug it in as the answer and no dice. What am I doing wrong? Am I completely off here? Help!