In an activated sludge process wastewater treatment plant, in which there is no primary sedimentation tank, the mix of coffee processing wastewater and domestic wastewater is treated. The flow rate of coffee processing wastewater is 40%, and domestic wastewater is 60%. The concentrations of BOD5, Total Nitrogen (TN) and Total Phosphorus (TP) in the coffee processing wastewater are 840 mg/L, 6 mg/L and 0 mg/L; and the concentrations of BOD5, Total Nitrogen (TN) and Total Phosphorus (TP) in the domestic wastewater are 200 mg/L, 35 mg/L and 6 mg/L. If the required proportion of the nutrients in influent for the activated sludge process is BOD5 : TN : TP = 100 : 5 :1. Are the TN and TP in the mixed wastewater enough? _____(Please fill in “Yes” or “No”). If “No”, _____ mg/L NH4NO3 and _____ mg/L KH2PO4 are needed to dose into the mixed wastewater?