Bipolar (BJT) Transistor NPN 30V mA MHz mW Through Hole TO 7 May File under Discrete Semiconductors, SC Sep DISCRETE SEMICONDUCTORS. 2N; 2NA. NPN switching transistors. A. Ptot. Total Power Dissipation at Tamb ≤ 25 °C for 2N and 2N for 2N and 2N at Tc as e ≤ 25 °C for 2N and 2N for 2N and.
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So if you looking for an NPN 2n2219 that could switch loads or for decent amplification then 2N 2n2219 the right choice for your project. Since transistor is of NPN the load to be 2n22199 should be connected to the collector and the emitter should be connected to 2n2219 ground as show in the figure below.
But it 2n2219 in a metal can package and can operate on voltages slightly 2n2219 than what n22219 2N can handle. Complete Technical Details can be 2n2219 at the datasheet given at the end of this page.
2N2219 NPN Transistor
To make this current flow through the transistor 2n2219 value of base current I B can be calculated using 2n2219 below formula:. The maximum amount of current that could flow through the Collector pin is mA, hence we cannot connect loads that consume more than mA using this 2n2219.
In our case 2n2219 a collector current of mA we 2n219 to pass a base current of 16mA. So the value if R B will be.
So to calculate 2n2219 resistor value of the base we can use the formulae. Current Drains out through emitter, normally connected to ground.
However this vale 2n2219 not be very accurate because the transistor will 2n2219 an internal voltage drop across the collector 2n2219, so it mostly experimental to get the maximum current from the transistor.
Current flows in through collector, normally connected to load. Overall it is just another small signal transistor which is commonly used in 2n2219 and amplifying circuits. Top menu About Us Contact.
When base current is removed the transistor becomes fully off, 2n2219 stage is called as the Cut-off Region and the Base Emitter voltage could 2n2219 around mV.
The 2n2219 is a 2n2219 transistor and is normally used as a switch in many circuits. Another important thing to keep in mind, while using a transistor as switch is the base resistor.
To bias a transistor we have to supply current to base pin, this current I B should 2n2219 limited to 5mA by using a transistor to the base pin. This stage is called Saturation Region. As we know the transistor is 2n2219 current controlled device meaning, we have pass some current I B thorough the base 2n2219 the transistor to turn it on.
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The value of this current can be calculated by the required amount of 2n22219 that will be consumed by the load. Top menu About Us Advertise. Next Article Timer 2n2219. Where 2n2219 is the voltage on which the load 2n2219 and V BE is the voltage across the Base and Emitter which in our case according to the data sheet 1.
This resistor is connected to the base pin of the transistor to 2n2219 the current flowing through the base. When this transistor is fully biased then it can allow a maximum 2n2219 mA to flow across the collector and 2n2219. 2n219
2n2219 But this calculation will lead to the closest value to start with. Here lets us assume the load here consumes around mA maximum so our collector current I C mA. Where h FE, 2n2219 the current gain of the transistor 2n2219 in our case is