In an earlier supplement, we went through the mathematics of deriving time dilation. We now extend that derivation to a slightly different circumstance. In the process we shall see that in the absence of length contraction and the fact that the speed of light is the same number for all observers, there is no time dilation.
Earlier we considered Lou with a light source, light detector, and a clock all at approximately the same physical location and stationary relative to him. He also had a mirror stationary with respect to him, that was located vertically above the source, detector and clock. The figures to the right are the same ones we used earlier to show this situation.
You will recall that Sue is moving to the right relative to Lou at a speed v.
In the new circumstance the apparatus has been rotated by 90 degrees. The figure to the immediate right shows the light travelling from the source to the mirror, and the figure to the far right shows the light travelling from the mirror to the detector. As before, the distance from the light source/detector to the mirror is d, so the time between the emission of the light and its detection is:
tLou = 2 d / c
which is the same result as before.
For Sue, the length from the source/detector to the mirror is contracted.
The time between the emission of the light and it hitting the mirror is t1. During this time the light will travel a distance c t1 and the mirror will travel a distance v t1. The sum of these two distances is just the distance between the light source and the mirror, so:
|dSue = c t1 + v t1|
|so:||t1 = dSue/(c + v)||(2)|
When the light leaves the mirror it "chases" the detector, which is moving to the left at a speed v relative to Sue. The time between the light leaving the mirror and it catching the detector is t2. In this time the detector will travel a distance v t2 so the light will travel a distance of dSue+ v t2. Thus:
|dSue + v t2 = c t2|
|so:||t2 = dSue/(c - v)||(3)|
The total time between the emission of the light and it entering the detector is t1 + t2. Combining Equations 1, 2 and 3 gives the same time dilation factor as before:
For non-relativistic speeds, three things are different than the above analysis:
Thus the time between the two events, the emission of the light and it entering the detector is just 2 d / c, exactly the same as the time for Lou.
Thanks to Tony Reynolds, whose question prompted the creation of this supplement.