1 PYF12 3/21/05 8:04 PM Page 191 Chapter 12 Gene expression and regulation Bacterial genomes usually contain several thousand different genes. Some of the gene products are required by the cell under all growth conditions and are called housekeeping genes. These include the genes that encode such proteins as DNA polymerase, RNA polymerase, and DNA gyrase. Many other gene products are required under specific growth conditions. These include enzymes that synthesize amino acids, break down specific sugars, or respond to a specific environmental condition such as DNA damage. Housekeeping genes must be expressed at some level all of the time. Frequently, as the cell grows faster, more of the housekeeping gene products are needed. Even under very slow growth, some of each housekeeping gene product is made. The gene products required for specific growth conditions are not needed all of the time. These genes are frequently expressed at extremely low levels, or not expressed at all when they are not needed and yet made when they are needed. This chapter will examine gene regulation or how bacteria regulate the expression of their genes so that the genes that are being expressed meet the needs of the cell for a specific growth condition. Gene regulation can occur at three possible places in the production of an active gene product. First, the transcription of the gene can be regulated. This is known as transcriptional regulation. When the gene is transcribed and how much it is transcribed influences the amount of gene product that is made. Second, if the gene encodes a protein, it can be regulated at the translational level. This is known as translational regulation. How often the mrna is translated influences the amount of gene product that is made. Third, gene products can be regulated after they are completely synthesized by either post-transcriptional or post-translational regulation mechanisms. Both RNA and protein can be regulated by degradation to control how much active gene product is present. Both can also be subjected to modifications such as the methylation of nucleosides in rrna, the extensive modifications made to trnas (over 80 modified nucleosides have been described), or the phosphorylation of response-regulator proteins (see below). These modifications can play a major role in the function of the gene product. In general, every step that is required to make an active gene product can be the focus of a regulatory event. In practice, most bacterial regulation occurs at the transcriptional level. Transcriptional regulation is thought to be more frequent because it would be a waste to make the RNA if neither the RNA nor its encoded protein is needed. The first three systems discussed repression of the lac operon by Lac
2 PYF12 3/21/05 8:04 PM Page Chapter 12 repressor, activation of the lac operon by camp-cap, and control of the trp operon by attenuation describe classic transcriptional regulation mechanisms. The last three systems regulation of the heat shock genes, regulation of the SOS response, and regulation of capsule synthesis rely on different combinations of transcriptional, post-transcriptional, and post-translational regulatory mechanisms and will be used to demonstrate how several regulatory mechanisms can be integrated to fine-tune gene expression. The players in the regulation game Fig The four major steps of transcription. (a) RNA polymerase recognizes the promoter. (b) RNA polymerase moves to the start site and begins polymerizing RNA. (c) RNA polymerase moves along the DNA template, elongating the RNA. (d) RNA polymerase stops RNA synthesis. The newly synthesized RNA disassociates from RNA polymerase and RNA polymerase disassociates from the DNA. RNA polymerase transcribes mrna, rrna, and trna. Ribonucleic acid, or RNA, exists as messenger RNA (mrna), transfer RNA (trna), and ribosomal RNA (rrna). In most cases, RNA is a single-stranded, rather than a doublestranded, molecule. RNA participates in both genetic and functional activities. As mrna, it allows the genetic information stored in the DNA molecule to be transmitted into proteins. As trna, it transfers amino acids during translation. As rrna, it maintains the structure of the ribosome and helps carry out translation. RNA is chemically synthesized by the action of RNA polymerase in a process called transcription. There are four identifiable steps during transcription: promoter recognition; chain initiation; chain elongation; and chain termination (Fig. 12.1). RNA polymerase catalyzes the formation of phosphodiester bonds between ribonucleotides using DNA as a template. Unlike DNA polymerase, RNA polymerase does not require a primer to begin synthesis of the RNA molecule (see Chapter 2 for details of DNA synthesis). Growth of the RNA chain, like the growth of a DNA chain, is in the 5 to 3 direction because RNA polymerase can only add a new nucleotide to a free 3 group. The order in which the different ribonucleotides are added to a free 3 is determined by a double-stranded DNA molecule in which one strand acts as the template (a) site Promoter (b) RNA polymerase (c) (d) (e) RNA polymerase mrna mrna mrna Start RNA polymerase Terminator mrna Stop RNA polymerase DNA (Fig. 12.2). The template strand is complementary to the RNA. The nontemplate or coding strand contains the same sequence as the RNA except for the substitution of uracil for thymine. Core RNA polymerase is a complex composed of the proteins b, b and two subunits of a (Fig. 12.3a). Core RNA polymerase is responsible for the synthesis of RNA, but it imparts no specificity as to where the start of the RNA occurs. Core RNA polymerase is converted to holoenzyme when one additional protein, sigma factor (s) is associated with it (Fig.
3 PYF12 3/21/05 8:04 PM Page 193 Gene Expression and Regulation a). s factor directs RNA polymerase to specific sequences in the DNA called promoters so that transcription initiates at the proper place. Bacteria can contain more than one s factor. In E. coli, the major s factor present under normal growth conditions is called sigma 70 or s 70. s 70 recognizes promoters 3' that have a specific DNA sequence and directs the RNA polymerase molecule that it is part of to begin transcription near these specific sequences. s 70 was named for its molecular weight, which is 70 kilodaltons. Different s factors recognize different sequences as promoters. For example, when cells are exposed to an increase in temperature or heat shock a group of genes is induced to cope with this stress (see below). The expression of the heatshock genes is controlled by an alternative s factor and all of the heat-shock genes have a common promoter sequence that is recognized by the alternative s factor. The heat-shock promoter sequence is different from the promoter sequence recognized by s 70. Promoters contain two distinct sequence motifs that reside ~10 bases and ~35 bases upstream of the transcriptional start site or first base of the RNA. The transcriptional start site is known as the +1 site. All of the bases following the +1 site are transcribed into RNA and are numbered consecutively with positive numbers (Fig. 12.3b). The bases prior to the +1 site are numbered consecutively with negative numbers. The motif at ~10 bases upstream of the +1 site is called the -10 region and the motif at ~35 bases upstream of the +1 is called the -35 region. s 70 recognizes promoters with a consensus sequence consisting of TAATAT at the -10 region and TTGACA at the - Non-template or coding strand 5' 3' ATCCTGTCTACGTATAAATACGC TAGGACAGATGCATATTTATGCG Template strand mrna 5' 3' AUCCUGUCUACGUAUAAAUACGC 5' Fig The mrna is synthesized using one strand of the DNA as a template. This makes the mrna complementary to the template strand. When the DNA sequence encoding a gene is shown, by convention the DNA strand that is the same sequence as the mrna (except for T to U) is usually shown. (a) α α β' β α α β' β σ Core RNA polymerase Holoenzyme (b) TTGACA TAATAT σ 70 promoter consensus sequence A T C T A A C G T T A +1 site +1 site Fig The structure of RNA polymerase and the regions in the promoter it binds to. (a) RNA polymerase has two forms. Core RNA polymerase synthesizes RNA in vitro but starts at many places on the DNA. Holoenzyme also synthesizes RNA in vitro but it starts only at promoters. (b) The general organization of the signals used by RNA polymerase. RNA polymerase recognizes promoters, which consist of a -10 region and a -35 region. RNA polymerase begins synthesis of RNA at the +1 base. RNA polymerase containing s 70 recognizes specific sequences at the -10 and -35 regions. The closer a sequence is to the consensus, the better s 70 is at recognizing it as a promoter and the more times it will be transcribed into RNA. If any of the bases are changed, s 70 may still recognize the sequence as a promoter but it will do so with a lower affinity.
4 PYF12 3/21/05 8:04 PM Page Chapter region (Fig. 12.3b). Promoters are defined according to their strength. This means that the stronger the promoter, the stronger the interaction between that promoter sequence and RNA polymerase. A general rule of thumb is that the closer the -10 and -35 sequences of a promoter are to the consensus sequence, the stronger the promoter. RNA polymerase holoenzyme binds to promoter sequences and covers approximately 75 bases of the DNA from -55 to +20. Once bound, RNA polymerase initiates transcription by causing the double-stranded DNA template to open, effectively melting the hydrogen bonds that hold the two DNA strands together in the promoter region (Fig. 12.4). As RNA polymerase starts transcribing at the +1 site, it continues to open the double-stranded DNA molecule, creating a short region of single-stranded DNA. After RNA polymerase has passed through the opened DNA, this region will reform hydrogen bonds to give a closed DNA molecule. Approximately two turns of the double helix or 17 base pairs are unwound at any given time during the elongation phase of transcription. Although s factor is needed for RNA polymerase to bind to the right promoter sequences, it is not needed during the elongation phase of transcription. After a short RNA transcript is synthesized, s factor dissociates from RNA polymerase and core RNA polymerase continues to elongate the RNA transcript. Transcription continues until core RNA polymerase encounters a transcription termination signal or (a) RNA polymerase binds to the promoter RNA polymerase (b) RNA polymerase opens the double helix (c) RNA polymerase begins transcription at the +1 site +1 (d) As RNA polymerase moves down the DNA the double helix reforms behind it Fig The beginning steps of transcription. RNA polymerase opens a 17 base pair bubble in the DNA to gain access to the DNA template. mrna
5 PYF12 3/21/05 8:04 PM Page 195 Gene Expression and Regulation 195 terminator where RNA polymerase and the newly synthesized RNA dissociate from the DNA to end transcription. Inverted repeat sequences are often found as part of a terminator along with a stretch of uracils found at the end of the RNA transcript (Fig. 12.5). The inverted repeat sequences are able to hydrogen bond with each other and create a stretch of double-stranded Template strand 5' 3' TAGCCTAATCCGATACAGACGGATACAAAAA U A G U C U U C G G C G C A U U A AUCGGAU UGUUUUU mrna RNA. When this secondary structure forms in the RNA, it takes on the appearance of a stem loop structure. Terminating transcription can either involve a protein called Rho or be Rho independent, depending on the sequence comprising the terminator. Terminators that do not involve Rho rely on the stem loop structure that forms at the end of the RNA to halt RNA polymerase s forward motion along the DNA. In contrast, Rho-dependent terminators rely on both Rho and the formation of the stem loop structure at the end of the RNA to halt transcription. Initiation of a new round of transcription does not require that the previous round be terminated. This means that there can be several RNA polymerase complexes transcribing the same template DNA at the same time (Fig. 12.6). Multiple RNA polymerases, because of the size of RNA polymerase, must be spread at least 75 nucleotides apart. In bacteria, translation of an mrna into its corresponding polypeptide does not require that the entire mrna be synthesized or transcription be terminated before translation is initiated. Ribosomes are able to bind the ribosome binding site (RBS) or Shine Dalgarno sequence in the mrna and initiate translation at the 3' Fig Termination of transcription takes place at specific sites. Frequently, a hairpin structure is part of the termination site. Inverted repeats form the base of the hairpin. The hairpin is frequently followed by a stretch of uracils. Ribosome Protein +1 site RBS RNA polymerase mrna Terminator Template Fig Multiple rounds of transcription and translation take place at the same time. As RNA polymerase moves along the DNA template, the mrna becomes accessible to ribosomes. The ribosomes bind to the RBS and initiate translation at the AUG start codon.
6 PYF12 3/21/05 8:04 PM Page Chapter 12 FYI 12.1 Coupled transcription and translation in different species In bacteria, transcription and translation can take place on the same mrna molecule at the same time. This is possible because bacteria do not have a membrane surrounding their DNA and all of the proteins needed for both processes have access to the DNA. The situation is quite different in eukaryotic cells that do have a membrane, called the nuclear membrane, surrounding their DNA. The proteins needed for transcription are inside the nuclear membrane but the proteins needed for translation are located outside of the nuclear membrane. Thus, coupled transcription and translation cannot happen in eukaryotic cells. A second difference between bacteria and eukaryotes is that while bacteria make many polycistronic mrnas, eukaryotes only encode one protein per mrna. starting methionine codon (AUG) even if RNA polymerase is still transcribing the mrna. In transcriptional regulation, DNA sequences called control regions or operators are found adjacent to or overlapping the -35 and -10 regions of the promoter. Specific DNA binding proteins recognize these control regions and exert an effect on holoenzyme s ability to initiate transcription. Regulatory proteins can bind to their control region and prevent transcription. This is known as repression. Regulatory proteins can also bind to their control regions and promote RNA polymerase binding to the promoter. This effect is known as activation. The regulatory mechanisms controlling gene expression are typically discovered by mutational analysis. Mutations that eliminate the regulation or make the regulation even better usually localize to one of two places (Fig. 12.7). The mutations can be in the genes encoding the repressors or activators. The mutations can also be in the nucleotide sequences that these regulatory proteins bind to. Operons and regulons An adaptive response, metabolic pathway, or developmental program usually requires more than one gene. Frequently, the genes for a given process are regulated in a similar manner. Genes that need to be coordinately regulated can be located right next to each other or spread around the chromosome. An operon is a group of genes physically linked on the chromosome and under the control of the same promoter(s) (Fig. 12.8a). In an operon, the linked genes give rise to a single mrna that is trans- (a) No R made RNA polymerase P R gene R P S O S gene S R R P R gene R P S O S gene S (b) R cannot bind to OS R RNA polymerase P R gene R P S O S gene S Fig Regulatory mechanisms are frequently studied by mutational analysis. Two classes of mutations are possible. (a) Mutations in the R gene or R gene promoter result in no R protein being produced. (b) Mutations in the operator (O) DNA sequence can result in the R protein not being able to bind to the DNA and carry out regulation.
7 PYF12 3/21/05 8:04 PM Page 197 Gene Expression and Regulation 197 (a) An operon P O Z Y A (b) A regulon P O A P O B C R R P O X R R P R Fig There are two widely used organizational schemes in bacteria for multiple genes that are coordinately regulated. (a) In an operon, all of the genes are physically linked and under the control of one promoter. (b) In a regulon, the genes are in different places on the chromosome but they all have promoters that respond to the same regulators. lated into the different gene products. This type of mrna is called a polycistronic mrna (Fig. 12.9). A regulon is a group of genes all needed for the same process but physically located in different parts of the chromosome and containing their own promoter(s) (Fig. 12.8b). In a regulon, the promoters are all regulated in the same fashion and allow for coordinate expression of the necessary genes. DNA Polycistronic mrna P A B C A B C Repression of the lac operon The metabolism of the sugar, lactose, requires at least two proteins in E. coli. The lactose permease, encoded by the lacy gene, transports lactose into the cell. The enzyme b-galactosidase, called b-gal for short and encoded by the lacz gene, catalyzes the cleavage of the b1,4-glycosidic linkage in lactose resulting in the monosaccharides, galactose and glucose (Fig a). When a compound is broken down, the process is called catabolic. The lac operon expresses genes whose products catabolize lactose. Analogs are available that mimic lactose s ability to either be a substrate for b-gal (Xgal, ONPG) or converted to an inducer of the lac operon (IPTG) (Fig b). This has made the study of the lac operon and its regulation amenable to examination in the laboratory. These analogs are frequently used in DNA cloning experiments as described in Chapters 13 and 14. lacz, lacy, and one other gene, laca, are linked on the E. coli chromosome (Fig ). laca encodes a detoxifying enzyme called b-galactoside transacetylase. The intracellular concentrations of b-gal and Lac permease are very low in E. coli cells grown Fig Polycistronic mrnas are translated into more than one protein. In this example, gene A, gene B, and gene C are encoded on one mrna and will all be translated from this one mrna.
8 PYF12 3/21/05 8:04 PM Page Chapter 12 (a) CH 2 Lactose CH 2 HO O 1 b O 4 O (D-galactose) (D-glucose) CH 2 CH 2 HO O O D-galactose HO D-glucose (b) CH 2 Xgal H N HO O O Cl Br colorless cleavage blue CH 2 ONPG NO 2 HO O O Fig (a) Cleavage of lactose by b-galactosidase. (b) Lactose analogs that are used to study the lac operon. X-gal is converted from a colorless compound to a dark blue compound when it is cleaved by b-galactosidase. ONPG is converted from a colorless compound to a yellow compound. IPTG cannot be cleaved by b-galactosidase but it can bind to LacI and induce the lac operon. CH 2 CH 3 O HO S CHCH 3 IPTG colorless cleavage yellow Cannot be cleaved by b-galactosidase
9 PYF12 3/21/05 8:04 PM Page 199 Gene Expression and Regulation 199 in medium that does not contain lactose (Table 12.1). If lactose is added to the medium, b-gal, Lac permease, and transacetylase appear at the same time in E. coli cells. After lactose is transported into the cell, some of it is converted to allolactose (1 6-O-b-galactopyranosyl-D-glucose) by the few molecules of b-gal found in uninduced cells. Allolactose is a rearranged lactose molecule and an inducer of the lac operon. lacz, lacy, and laca are coordinately expressed from one Repressor promoter called lacp that directs expression of a polycistronic mrna (Fig ). lacp is located upstream of lacz. laci encodes the lactose repressor protein and is located upstream of lacp. laci has its own promoter and is constitutively expressed. Lac Repressor or LacI binds to the DNA at the lac operator site called laco. laco is located between laci and lacz. In the absence of inducer, Lac repressor is bound to laco, preventing expression of the operon (Fig a). In the presence of inducer, inducer binds to Lac repressor and prevents repressor from binding to laco, leading to transcription of the operon (Fig b). How lac operon induction takes place and the players that control this induction were elucidated in the extensive genetic analyses undertaken by Francois Jacob, Jacques Monod, and their coworkers. Table 12.1 describes a few of the lac mutants isolated by Jacob and Monod and the effect the inducer has on the activity of b-gal and transacetylase. For example, Class I mutations eliminate the inducibility of the lac operon resulting in b-gal and transacetylase activity being detectable in the absence of lactose (uninduced). This class of mutation results in a constitutive Lac + phenotype and maps to either the laci gene or to laco. laci - mutations are recessive or have no phenotype in the presence of a wild-type lac operon. Enough LacI is made from the wild-type laci gene to repress both copies of the lac operon. Class II mutations result in a super-repressed Lac - phenotype. Super-repressed mutants have no b-gal or transacetylase activity in the presence of inducer. These mutations map to the laci P laci P O lacz lacy laca b-galactosidase Lactose permease Transacetylase Fig The genes that encode the proteins used to transport and degrade lactose form an operon. The operon is regulated by LacI. The laci gene is located just upstream of lacz, lacy, and laca. LacI is expressed from its own promoter that is on all of the time. Table 12.1 Some classes of E. coli lac mutant isolated by Jacob and Monod and the effect inducer has on the relative concentrations of ß-galactosidase and transacetylase in the mutant backgrounds. The mutations were examined when they resided in the chromosome in one copy and in merodiploids containing a second copy of the lac operon on an F. Class Genotype ß-galactosidase (lacz) Transacetylase (laca) Uninduced Induced Uninduced Induced WT lacz A I I lacz A I lacz A I - /F lacz A I II lacz A I s lacz A I s /F lacz A I III lacz A O c lacz - A O /F lacz A - O c II + III lacz A O I s F lacz A O c I
10 PYF12 3/21/05 8:04 PM Page Chapter 12 (a) P (b) P LacI LacI laci P O lacz lacy laca LacI Allolactose laci P O lacz lacy laca gene and result in a repressor that can no longer be inactivated by inducer. Super-repressor mutants are dominant to wild type because the mutant LacI can bind to both copies of the lac operon and turn them off. Class III mutations are in laco and prevent Lac repressor from binding and turning off the operon. laco c mutants are dominant to wild type because wild-type LacI from either copy of the operon cannot repress the lac operon containing the laco c mutant. When super-repressor mutants are combined with laco c mutants, laco c mutants are dominant to super-repressor mutants because the super-repressor still cannot bind the mutant laco. Fig A model for the regulation of the lac operon. The Lac repressor or LacI binds to the lac operator DNA (laco) and prevents transcription of lacz, lacy, and laca. If lactose is present inside the cell, it is converted to allolactose. Allolactose binds to LacI and prevents its interaction with laco. This allows expression of the lacz, lacy, and laca genes. Activation of the lac operon by cyclic AMP and the CAP protein If lactose and glucose are added to a culture of wild-type E. coli cells, the lac operon is not induced. No lac mrna or gene products are made. This effect of glucose is the result of a second regulatory mechanism, catabolite repression. Catabolite repression affects not only lac gene expression but also other operons that catabolize specific sugars such as galactose, arabinose, and maltose. Contrary to its name, catabolite repression describes an activating mechanism, involving a complex between camp (cyclic adenosine monophosphate) and the catabolite activator protein (CAP; also called cyclic AMP receptor protein or CRP) (Fig ). If given the choice of sugars to metabolize, E. coli will use glucose first and then other sugars. When levels of glucose are high, there is no need to express high levels of the enzymes needed for the metabolism of lactose or other sugars, which yield less energy than glucose. High levels of intracellular glucose result in low levels of camp. Low levels of camp mean very few camp CAP complexes. When intracellular levels of glucose drop and other sugars must be metabolized, levels of camp increase. Increased camp levels mean there are more camp CAP complexes. camp CAP binds to a specific site on the DNA that is located adjacent to the promoter for the lac genes (Fig ) and adjacent to promoters controlling the expression of other sugar metabolizing operons affected by camp CAP. The -10 and -35 motifs in the promoter sequence for lac are not a perfect match to the consensus sequence for s 70 promoters. camp CAP bound to the CAP binding site increases the binding of s 70 RNA polymerase to the lac promoter. By having two mechanisms controlling the expression of the lac operon, cells ensure that the lac gene products are only made when needed. Regulation of the tryptophan biosynthesis operon by attenuation The biosynthesis of the aromatic amino acid tryptophan requires the activity of three enzymes, anthranilate synthetase (trpe) complexed with phosphoribosylanthranilate transferase (trpd), phosphoribosyl-anthranilate isomerase (trpc), and tryptophan synthetase (trpa and trpb) to convert chorismate to tryptophan. The five trp structural genes encoding the three tryptophan biosynthetic enzymes are physically linked and coordinately regulated as an operon. The trp genes are arranged in the
11 PYF12 3/21/05 8:04 PM Page 201 Gene Expression and Regulation 201 Fig Catabolite repression of the lactose operon. (a) High levels of glucose mean low levels of camp. There is not enough camp to complex with CAP and no induction of the lac operon takes place. LacI remains bound to laco. (b) Low levels of glucose lead to high levels of camp. camp complexes with CAP and binds in front of lacp. If there is lactose present, it is converted to allolactose, allolactose complexes with LacI and prevents LacI from binding to laco. This leads to induction of the lac operon. End of laci Start of lacz Promoter Operator mrna GGAAAGCGGGCAGTGAGCGCAACGCAATTAATGTGAGTTAGCTCACTCATTAGGCACCCCAGGCTTTACACTTTATGCTTCCGGCTCGTATGTTGTGTGGAATTGTGAGCGGATAACAATTTCACACAGGAAACAGCTATGACCATG CCTTTCGCCCGTCACTCGCGTTGCGTTAATTACACTCAATCGAGTGAGTAATCCGTGGGGTCCGAAATGTGAAATACGAAGGCCGAGCATACAACACACCTTAACACTCGCCTATTGTTAAAGTGTGTCCTTTGTCGATACTGGTAC CAP camp binding site RNA polymerase binding site LacI binding site Fig The binding sites for CAP camp, RNA polymerase, and LacI in the lac operon of E. coli. order that their encoded enzymes function in the biosynthetic pathway (Fig ). The goal of a biosynthetic or anabolic pathway is to synthesize the end product only when it is needed. In 1959, Cohen and Jacob made the observation that addition of tryptophan to an actively dividing E. coli culture repressed the synthesis of tryptophan synthetase. The trp operon is repressed by TrpR, a transcriptional repressor,
12 PYF12 3/21/05 8:04 PM Page Chapter 12 Fig The structure of the trp operon and the enzymatic activities encoded by the trp genes. The regulator of the trp operon, TrpR, is encoded by a gene that is not linked to the rest of the operon. The structural genes, trp EDCBA, are positioned in the operon in the same order as the enzymes they encode are used in tryptophan synthesis. when levels of tryptophan are high in the cell (Fig ). The gene encoding the TrpR repressor is not located near the trp operon. Even though expression of both the lac and trp operons are regulated by repression, the mechanism by which the LacI and TrpR repressors work is very different. The LacI repressor when bound to its effector molecule (i.e. lactose) cannot repress transcription. In contrast, the TrpR repressor must be bound by an effector molecule, in this case tryptophan, for it to repress transcription. The repression mechanism for the trp operon can be viewed as a coarse control mechanism; an all or none approach to gene expression. However, another regulatory mechanism, attenuation, is available to fine-tune gene expression of some biosynthetic operons, especially during times of extremely short supply of end products. Attenuation was first proposed by Charles Yanofsky and coworkers who observed that under normal growth conditions approximately nine out of 10 trp mrna transcripts terminate before they reach the structural genes of the trp operon. This means that even when repression is lifted and transcription is initiated from the trp promoter, RNA polymerase abruptly halts, failing to elongate the trp mrna across the structural genes. During conditions of severe tryptophan starvation, the premature termination of transcription is abolished, allowing expression of the trp operon at 10- fold higher levels than under normal growth conditions. What is happening to cause early termination of the trp mrna? The answer lies in the regulatory sequence in front of the trp structural genes. Downstream from the trp promoter and the TrpR repressor binding site but upstream of the trp structural genes, are 162 base pairs. The 162 base pair sequence is called the leader sequence or trpl (Fig a). trpl contains a ribosome binding site adjacent to an AUG translational start codon. This means there are two RBS sites and two AUG translational start codons located after the trp promoter but in front of the first trp structural gene (trpe). The trp leader sequence, after it is transcribed into mrna, can be translated into a short polypeptide consisting of 14 amino acids. Of these 14 amino acids, two are trp residues that are located next to each other. The presence of two tandem trp residues is very rare. Most E. coli proteins contain one trp per every 100 amino acids. At the end of trpl is a Rho-independent terminator. This signal resides approximately 40 base pairs
13 PYF12 3/21/05 8:04 PM Page 203 Gene Expression and Regulation 203 (a) Rho-independent terminator P 1 O RBS trpl RBS trpe trpd AUG AUG AUG 162 bp mrna Translation begins before the mrna is completely synthesized 2:3 (b) 1:2 U A A A G A A A C G 100 Stop 70 G CG G C U U A AAGUUCAC CC G Pause A A 90 U GU Ser G C C 10 U C hairpin A A A UC A C G A Thr G80 U A 3:4 U A A U A C G A G UA U A A A U U U A 110 Arg GA G C G 60 C G G U C U C 80 G C G G CU 120 C G A A Trp G C C G U U A C G130 G C 20 A Trp G C C G G C U Met Lys Ala Ile Phe Val Leu Lys Gly G C 90 G C Trp Trp Arg Thr Ser Stop G C CGACAAUGAAAGCAAUUUUCGUACUGAAAGGUU A AUCAGAUACCCA UUUUUUUU... UGGUGGCGCACUUCCUGAAAC GCCUAA U A G C Pause C G 100 G A U A A Fig The features of the leader region of the trp operon. (a) trpl is transcribed into mrna. (b) The trpl mrna can form three different stem loop structures depending on the prevalence of charged trp trnas inside the cell (see text and Fig for details). upstream of the signals that control the translation of the trp structural genes. The DNA sequence in this region suggests that the encoded mrna has a very high probability of forming stem loop secondary structures. There are three combinations of stem loops that can form. They have been named the pause loop (1:2), the terminator loop (3:4), and the anti-terminator loop (2:3) (Fig b). Attenuation of the trp operon uses the secondary structures in the mrna to determine the amount of tryptophan in the cell (Fig ). RNA polymerase initiates transcription at the trp promoter after the TrpR repressor has been removed. Because translation can be initiated before the mrna is completed, a ribosome loads at the trpl RBS and initiates translation of TrpL (Fig step 1). As RNA polymerase elongates the trpl mrna, stem loop structures will form in the mrna. The first secondary structure that can form is the 1:2 pause loop. This large hairpin structure is called the pause loop because it forms behind the transcribing RNA polymerase and causes RNA polymerase s forward movement along the DNA template to pause (Fig step 2). Pausing transcription allows the translating ribosome to stay close to the transcribing RNA polymerase. This ensures that these two complexes stay in close communication during crucial times of abruptly changing levels of tryptophan. As the translating ribosome advances on the mrna, the ribosome breaks apart the pause loop freeing RNA polymerase to continue transcribing trpl (Fig step 3). At this time, the ribosome
14 PYF12 3/21/05 8:04 PM Page Chapter 12 Rho-independent terminator P 1 O RBS trpl AUG RBS trpe AUG RNA polymerase DNA Step 1 AUG Step 2 AUG 1 2 Step UGGUGG trp trp Step UGGUGG 3 4 Alternate step 4 1 UGGUGG Alternate step 5 1 UGGUGG RBS trpe Fig The predictions of the attenuation model. (Step 1) Coupled transcription/translation takes place as for any bacterial gene. (Step 2) RNA polymerase pauses and 1 :2 stem loop forms. (Step 3) The ribosome disrupts the 1 :2 stem loop and encounters the two trp codons. (Step 4) If enough tryptophan is present, charged trp trnas will be present and the ribosomes will translate trpl. This causes RNA polymerase to stop at the terminator composed of a 3 :4 stem loop. (Alternate Step 4) If not enough trp is found in the cell, the ribosome stalls at the two trp codons, while RNA polymerase continues. The 2 :3 stem loop forms. (Alternate Step 5) The 3 : 4 terminator cannot form and RNA polymerase continues transcribing into the trp structural genes. This exposes the RBS upstream of trpe, allowing translation of trpe.
15 PYF12 3/21/05 8:04 PM Page 205 Gene Expression and Regulation 205 encounters the two trp codons. If there are two charged tryptophanyl trnas to pass tryptophan to the ribosome to add to the growing TrpL polypeptide, then the ribosome does not stall, and it is able to stay close to the transcribing RNA polymerase (Fig step 4). If they stay close, very few bases of the mrna transcript will separate the ribosome from the RNA polymerase and only the 3:4 terminator loop structure is predicted to form. The 3:4 loop is a Rho-independent transcription terminator. If two charged tryptophanyl trnas are not available to pass tryptophan to the translating ribosome, then the ribosome stalls in its attempt to synthesize the TrpL polypeptide (Fig alternate step 4). The transcribing RNA polymerase continues to move away from the stalled ribosome, creating a longer stretch of bases that separate these two complexes. Because of the longer distance between RNA polymerase and the ribosome, the larger 2:3 anti-terminator stem loop structure forms. The 2:3 loop is not a transcription termination signal and RNA polymerase continues its forward motion, transcribing the trp structural genes (Fig alternate step 5). Thus, the leader peptide plays a decisive role in determining if transcription of the trp operon will terminate early or will continue into the structural genes. Other E. coli biosynthetic operons, including those that synthesize phe, his, leu, thr, and ilv, are controlled by attenuation. Of this group of operons, only trp has a repressor in addition to attenuation. Regulation of the heat-shock regulon by an alternate sigma factor, mrna stability, and proteolysis The coordinately regulated genes of an operon are physically linked and controlled by the same promoter. In contrast, the coordinately regulated genes of a regulon are physically located in different parts of the chromosome and are controlled by their own promoters yet are regulated by the same mechanisms. Regulons are also called multigene systems or global regulatory systems. Table 12.2 describes a few of the regulons identified in bacteria. Three bacterial regulons, heat shock, SOS and eps, will be used to illustrate the regulatory mechanisms and components associated with regulons. Cells respond to an abrupt increase in temperature by inducing synthesis of a specific group of proteins to cope with this stress. This heat-shock response has been documented in many different cell types and extensively studied at the molecular level in prokaryotic cells such as E. coli. E. coli is a mesophile, which means its normal growth temperature is between 20 C and 37 C. Shifts in temperature within this range result in very little stress for the bacterium and there is no noticeable adjustment in its gene expression. E. coli responds to an abrupt increase in temperature from 30 C to 42 C by producing a set of ~30 different proteins (Table 12.3). These proteins are collectively called the heat-shock proteins (Hsps). Within 5 minutes after a 30 C to 42 C temperature shift, the Hsp proteins increase by 10-fold. After this transient increase, the amount of the Hsp proteins decreases slightly to a steady-state level. The steady-state level is maintained as long as the cells remain at the elevated temperature. Once the temperature is decreased from 42 C to 30 C, the levels of Hsp proteins decrease abruptly, approximately a 10-fold decrease within 5 minutes. Besides a change in temperature, other agents such as ethanol, organic solvents, or certain DNA damaging agents can induce heat-shock gene expression. This suggests that the members of the heat shock regulon deal with cellular damage that can occur in several different ways. Many of the hsp genes encode either proteases or chaperones. Proteases are proteins that degrade proteins especially those that may be abnormal. Abnormal proteins
16 PYF12 3/21/05 8:04 PM Page Chapter 12 Table 12.2 Examples of regulons identified in E. coli. Multigene system Stimulus Regulator Regulated genes Heat shock Shift to high temperature s 32 (htpr = rpoh) ~30 heat-shock proteins (Hsps) including proteases and chaperones ph shock Acid tolerance CadC Several gene products needed for protection from acid damage SOS response Extensive DNA damage LexA repressor ~20 gene products needed for DNA repair Oxidation response H 2 O 2 OxyR repressor ~12 gene products needed for protection from H 2 O 2 and other oxidants Porin response High osmolarity Sensor EnvZ Porin genes regulator OmpR Catabolite repression Carbon utilization Crp-cAMP Many different sugar catabolizing operons Table 12.3 Heat-shock proteins in E. coli and their corresponding functions. Regulon Hsp protein Function s 32 DnaK Chaperone DnaJ Chaperone GroEL Chaperone GroES Chaperone GrpE Nucleotide exchange factor Lon Protease ClpX Protease ClpP Protease HflB Protease RpoD Sigma factor s 70 HtpR Heat-shock sigma factor s 32 HtpG Chaperone GapA Dehydrogenase ClpB Chaperone HtrM Epimerase IbpB Chaperone IbpA Chaperone ClpY Protease s E DegP Protease s E Sigma factor s 32 Sigma factor unknown LysU Lysyl-tRNA synthetase s 32 regulated Hsps whose function is unknown: HtpY, HslA, HslC, HslK, HtpX, FtsJ, HslO, HslP, HslV, HtrC, HslW, HslX, HslY, HslZ, HtpK, HtpT. s 32 regulated Hsps whose function and regulation are unknown: PspA, HslE, HslF, HslG, HslI, HslJ, HslM, HslQ, HslR.
17 PYF12 3/21/05 8:04 PM Page 207 Gene Expression and Regulation 207 include incompletely synthesized proteins and proteins that are not folded correctly. Chaperones are proteins that bind to abnormal proteins, unfold them, and try to let them refold into an active configuration. Frequently, if a chaperone cannot fix an abnormal protein, it will target the abnormal protein for degradation by a protease. From looking at the genes that are part of the heat-shock regulon, it is interesting that they mainly deal with misfolded proteins. This suggests that misfolding of proteins is the predominant damage to cells at high temperatures. The genes encoding Hsps are scattered around the chromosome but are coordinately regulated. Thus, the hsp genes constitute a regulon. The regulator of the heatshock response is an alternative sigma factor, named sigma 32 or s 32. s 32 is a 32 kilodalton protein and the gene encoding s 32 is rpoh (for RNA polymerase subunit heat shock). s 32 directed RNA polymerase recognizes the distinctive sequences of heat-shock promoters. The heat shock promoters have different -10 (CCCCAT) and -35 (CTTGAAA) consensus sequences than promoters recognized by s 70. All of the hsp genes have a heat-shock promoter. In fact, once the E. coli genome was sequenced, heat-shock promoter sequences were used to identify novel potential Hsps. s 32 is made at all temperatures yet the hsp gene products are not. s 32 is an unstable protein and at low temperatures it has a half-life of about one minute. At high temperatures, 10 times more s 32 protein is made and the s 32 that is made is five times more stable than the s 32 made at low temperatures. The regulation of the rpoh gene is at the translational level. There is a significant amount of rpoh mrna in cells at low temperatures yet translation of this mrna is inhibited. At high temperatures, translational inhibition is relieved and s 32 protein is made. Two regions of the rpoh mrna are required for translational inhibition, a region near the +1 site and a region internal to the rpoh gene between nucleotides 150 and 250 in the mrna. How these two regions of the mrna inhibit translation at low temperatures is not well understood. The two regions are capable of forming a stem loop structure and this may prevent the ribosome from loading at the RBS and inhibit translation in addition to possibly increasing the stability of this mrna. s 32 is degraded by a specific protease called HflB. Degradation of s 32 at 30 C also requires a chaperone composed of three proteins, DnaK, DnaJ, and GrpE. Degradation of s 32 at 30 C is decreased ~ 10-fold by mutations in any one of the genes that encode HflB, DnaK, DnaJ, or GrpE. All four of these proteins are part of the heat-shock regulon and so their expression is induced by heat shock. If more chaperone proteins are present at higher temperatures to help degrade s 32, then how does s 32 ever interact with core RNA polymerase to activate the heat-shock genes? While the precise answer to this question is unknown, recent experiments suggest that the interactions between DnaK and s 32 are temperature dependent and only occur at low temperatures. When the temperature is raised, DnaK and s 32 no longer interact yet interaction between s 32 and core RNA polymerase remains unchanged. It is possible that this temperature-dependent interaction of DnaK and s 32 plays a role in s 32 stability at high temperatures. If the temperature is lowered from 42 C to 30 C, translational inhibition of the mrna returns and s 32 again becomes sensitive to degradation. The heat-shock response can be turned off as quickly as it was turned on. A second heat-induced regulon is controlled by a second alternative sigma factor, s E. At temperatures around 50 C, s E controlled promoters are very active. Deletions of the gene encoding s E are temperature sensitive at 42 C, whereas deletions of the gene encoding s 32 are temperature sensitive at 20 C. s E responds to misfolded outer membrane proteins and s 32 responds to misfolded cytoplasmic proteins. The s 32 gene also has a s E promoter so that all of the Hsps are induced by a cascade effect when s E regu-
18 PYF12 3/21/05 8:04 PM Page Chapter 12 FYI 12.2 Weigle reactivation If a lysate of lambda is UV irradiated, the DNA in many of the phage is damaged and these phage are not capable of growth. If this irradiated lysate is used to infect a population of E. coli that have also been irradiated, many of the damaged phage now survive. This basic observation is known as the Weigle effect or Weigle reactivation. At first it was not clear why two doses of irradiation (one to the phage and one to the bacterium) should fix the damage caused by one dose of irradiation. We now know that irradiating the bacteria induces the SOS response and induces the synthesis of DNA repair enzymes. When the damaged l DNA is introduced into the SOS induced bacteria, the l DNA is repaired and is used to produce more phage. lated genes are expressed. It is thought that the s E regulon provides proteins that are needed at more extreme conditions. Given what we know, it is possible to induce the s 32 regulon by itself or the s 32 and s E regulons together. Having several overlapping regulons that respond to different degrees of one condition gives the cell more flexibility in how it responds. Cells can make large amounts of very specific gene products without wasting resources by making gene products that they don t need. Regulation of the SOS regulon by proteolytic cleavage of the repressor The SOS regulon permits a rapid response to severe or lethal levels of DNA damage. The goal is to quickly activate DNA repair proteins and deal with the DNA damage in a swift manner. Speed is of the essence to save the cell by restoring its chromosome to an intact double-stranded state. The DNA repair enzymes that are induced result in a higher level of mistakes than normally seen but this is balanced by their speed in repairing the majority of the chromosome. During the SOS response, cell division is halted so that damaged chromosomes are not segregated into daughter cells. Thus, in addition to DNA repair enzymes, a cell division inhibitor protein is also expressed at high levels during the SOS response. Table 12.4 describes the genes and proteins of the SOS regulon. The SOS genes are expressed at low levels during normal cell growth. They are induced to high-level expression upon extensive DNA damage. Weigle and coworkers first reported from their observations of reactivated UVirradiated l that some DNA repair systems are inducible (see FYI12.2). Many of these repair mechanisms are activated as part of the SOS regulon. Like the heat-shock regulon, the SOS regulon has a mechanism for signaling when the regulon should be on or off. The SOS genes contain a common sequence that in some cases overlaps the promoter region and in other cases is adjacent to the promoter region. This common sequence is bound by a repressor protein called LexA. SOS promoters bound by LexA cannot be used to initiate transcription. As a result of significant DNA damage, the LexA repressor is inactivated and removed so that the SOS genes are expressed. How is the LexA repressor inactivated and removed from the promoters of SOS genes? Upon exposure to DNA damaging agents, large amounts of single-stranded DNA accumulate (Fig a). Single-stranded DNA is bound by the RecA protein (Fig b). RecA participates in homologous recombination (see Chapter 5) and in Table 12.4 Known SOS genes, proteins, and corresponding functions in E. coli. Gene Protein Function lexa LexA Represses transcription of SOS genes reca RecA LexA activator and major homologous recombination protein recn RecN Binds ATP; RecBCD substitute ruvab Ruv Branch migration and resolution sula (sfia) SulA Cell division inhibitor umuc UmuC Mutagenesis umud UmuD Mutagenesis uvra UvrA Excision repair uvrb UvrB Excision repair uvrd UvrD Excision repair
19 PYF12 3/21/05 8:04 PM Page 209 Gene Expression and Regulation 209 (a) or (b) RecA (c) RecA (d) P P LexA LexA binding site SOS induced genes Fig The SOS response. (a) DNA damage leads to singlestranded DNA. (b) RecA binds to the ssdna. (c) RecA ssdna binds to LexA. (d) Lex A undergoes autocleavage, relieving repression of the SOS genes. post replication DNA repair (see Chapter 4). In the case of extensive DNA damage, RecA complexed to single-stranded DNA binds to LexA and induces LexA to cleave itself (Fig c). Since LexA, with help from the RecA ssdna complex, cleaves itself, LexA is said to autocleave. Autocleavage of LexA takes place between two specific amino acids that separate the repressor into two domains, the DNA binding domain and the dimerization domain. Two LexA molecules bind to the sequence found in SOS regulon promoters. The disruption of dimerization results in the removal of LexA from the SOS promoters (Fig d). Once LexA is removed, SOS genes are expressed at high levels. Eventually the induction signal, RecA complexed to single-stranded DNA, drops because of DNA repair, and LexA is no longer able to undergo autocleavage. This returns the regulon to its prestimulus or uninduced state. Two-component regulatory systems: signal transduction and the cps regulon Bacteria continually monitor their environment so as to set in motion a proper response to detected changes. There are molecular mechanisms that pick up signals from the environment and transmit this information to the appropriate regulators. This is the concept of signal transduction. The molecular mechanism associated with this process in bacteria is the two-component system. The two-component
20 PYF12 3/21/05 8:04 PM Page Chapter 12 Table 12.5 Examples of two component systems in E. coli. System Nitrogen limitation Phophorus limitation Oxygen limitation Osmotic upshift Capsule expression Porin regulation Two-component response-regulator/sensor-kinase NtrC regulator/ntrb sensor PhoR regulator/phob sensor ArcA regulator/arcb sensor KdpD regulator/kdpe sensor RcsB regulator/rcsc sensor OmpR regulator/envz sensor Fig Regulation of the cps genes. (Step 1) Reduced levels of MDOs (membrane-derived oligosaccharides) result in autophosphorylation of RcsC (Step 2). (Step 3) The phosphate group is transferred to RcsB. (Step 4) RcsB binds to RcsA. (Step 5) This complex acts on the cps promoter and activates transcription of the cps genes. RcsA is also an unstable protein that is degraded by Lon protease. When RcsA is in a complex with RcsB, it is protected from degradation. Expression of cps genes is controlled by several different mechanisms to ensure that the capsule in only made when needed. signal transduction system consists of a sensor-kinase protein and a response-regulator protein (see Fig. 11.4). This system has been identified as a regulatory mechanism for many operons and regulons, including induction of competency in B. subtilis (see Chapter 11). The basic components of two-component signal transduction systems are described in Chapter 11. Two-component systems are found in many different bacteria. In E. coli there are at least 50 different examples of this type of regulation. Table 12.5 describes a few of these systems. We will use the E. coli cps system, which controls synthesis of an exopolysaccharide capsule, to illustrate two-component signal transduction. E. coli produces a number of different types of exopolysaccharides. Exopolysaccharides are polymers consisting of sugars linked together, often in a lattice-type structure. They are located on the outside of the bacterial cell and while some remain attached to the bacterial cell, others do not. They often protect bacteria from harsh environments, toxic chemicals, or bacteriophage. Some exopolysaccharides serve as matrices to link a number of different bacteria into a community or biofilm. Other bacterial exopolysaccharides cause health problems 1 Reduced levels of MDOs in humans. An extensively studied E. coli exopolysaccharide is 2 RcsC RcsC Inner membrane the colanic acid capsule. The genes encoding the enzymes P that make this poly- mer are named cps (colanic 3 P acid polysaccharide). The RcsB RcsB majority of the cps genes are arranged in a single operon. 4 The regulation of the cps genes involves several different regulatory mecha- P Lon RcsA nisms (Fig ). One A B Active Inactive such mechanism is a twocomponent system involv- 5 ing the sensor-kinase P protein, RcsC (regulator of A B capsule synthesis), and the response-regulator protein, P Genes for colanic acid capsule biosynthesis RcsB. This two-component system can be activated by
MICROBIAL GENETICS Gene Regulation: The Operons Pradeep Kumar Burma Reader Department of Genetics University of Delhi South Campus Benito Juarez Road New Delhi-110021 E-mail: firstname.lastname@example.org 05-May-2006
Module 3 Questions Section 1. Essay and Short Answers. Use diagrams wherever possible 1. With the use of a diagram, provide an overview of the general regulation strategies available to a bacterial cell.
Gene Regulation -- The Lac Operon Specific proteins are present in different tissues and some appear only at certain times during development. All cells of a higher organism have the full set of genes:
Gene Transcription in Prokaryotes Operons: in prokaryotes, genes that encode protein participating in a common pathway are organized together. This group of genes, arranged in tandem, is called an OPERON.
What makes cells different from each other? How do cells respond to information from environment? Regulation of: - Transcription - prokaryotes - eukaryotes - mrna splicing - mrna localisation and translation
Chapter 18 Regulation of Gene Expression 18.1. Gene Regulation Is Necessary By switching genes off when they are not needed, cells can prevent resources from being wasted. There should be natural selection
Transcription and Translation of DNA Genotype our genetic constitution ( makeup) is determined (controlled) by the sequence of bases in its genes Phenotype determined by the proteins synthesised when genes
AP * BIOLOGY GENE REGULATION Teacher Packet AP* is a trademark of the College Entrance Examination Board. The College Entrance Examination Board was not involved in the production of this material. Pictures
DNA and Genetics 1. Which of the following correctly organizes genetic material from the broadest category to the most specific category? A. genome chromosome gene DNA molecule B. genome chromosome DNA
RNA Structure, Function, and Synthesis RNA RNA differs from DNA in both structural and functional respects. RNA has two major structural differences: each of the ribose rings contains a 2 -hydroxyl, and
DNA, RNA, Protein Synthesis Keystone 1. During the process shown above, the two strands of one DNA molecule are unwound. Then, DNA polymerases add complementary nucleotides to each strand which results
Chem 465 Biochemistry II Name: 2 points Multiple choice (4 points apiece): 1. Formation of the ribosomal initiation complex for bacterial protein synthesis does not require: A) EF-Tu. B) formylmethionyl
Translation Study Guide This study guide is a written version of the material you have seen presented in the replication unit. In translation, the cell uses the genetic information contained in mrna to
DNA Replication & Protein Synthesis This isn t a baaaaaaaddd chapter!!! The Discovery of DNA s Structure Watson and Crick s discovery of DNA s structure was based on almost fifty years of research by other
Transcription in prokaryotes Elongation and termination After initiation the σ factor leaves the scene. Core polymerase is conducting the elongation of the chain. The core polymerase contains main nucleotide
Chapter 8 Microbial Genetics Structure and Function of the Genetic Material Chromosomes are cellular structures made up of genes that carry hereditary information. Genetics is the study of how genes carry
RNA & Protein Synthesis Genes send messages to cellular machinery RNA Plays a major role in process Process has three phases (Genetic) Transcription (Genetic) Translation Protein Synthesis RNA Synthesis
Protein Synthesis Protein Synthesis How Genes Become Constituent Molecules Mendel and The Idea of Gene What is a Chromosome? A chromosome is a molecule of DNA 50% 50% 1. True 2. False True False Protein
STO-143 Gene Switches Teacher Information Summary Kit contains How do bacteria turn on and turn off genes? Students model the action of the lac operon that regulates the expression of genes essential for
Transcription: RNA Synthesis, Processing & Modification 1 Central dogma DNA RNA Protein Reverse transcription 2 Transcription The process of making RNA from DNA Produces all type of RNA mrna, trna, rrna,
1 2.1 Nucleic acids the molecules of life Nucleic acids information molecules of the cells form new cells stored in chromosomes in nucleus of the cell in the form of a code in DNA / parts of the code are
PART A: MULTIPLE CHOICE QUESTIONS PRACTICE TEST QUESTIONS DNA & PROTEIN SYNTHESIS B 1. One of the functions of DNA is to A. secrete vacuoles. B. make copies of itself. C. join amino acids to each other.
Chapter 6 DNA Replication Each strand of the DNA double helix contains a sequence of nucleotides that is exactly complementary to the nucleotide sequence of its partner strand. Each strand can therefore
Nucleotides and Nucleic Acids Brief History 1 1869 - Miescher Isolated nuclein from soiled bandages 1902 - Garrod Studied rare genetic disorder: Alkaptonuria; concluded that specific gene is associated
Protein Trafficking/Targeting (8.1) Lecture 8 Protein Trafficking/Targeting Protein targeting is necessary for proteins that are destined to work outside the cytoplasm. Protein targeting is more complex
Chem 121 Chapter 22. Nucleic Acids 1. Any given nucleotide in a nucleic acid contains A) two bases and a sugar. B) one sugar, two bases and one phosphate. C) two sugars and one phosphate. D) one sugar,
Tutorial II Gene expression: mrna translation and protein synthesis Piergiorgio Percipalle, PhD Program Control of gene transcription and RNA processing mrna translation and protein synthesis KAROLINSKA
Lab #5: DNA, RNA & Protein Synthesis Heredity & Human Affairs (Biology 1605) Spring 2012 DNA Stands for : Deoxyribonucleic Acid Double-stranded helix Made up of nucleotides Each nucleotide= 1. 5-carbon
Basic Concepts of DNA, Proteins, Genes and Genomes Kun-Mao Chao 1,2,3 1 Graduate Institute of Biomedical Electronics and Bioinformatics 2 Department of Computer Science and Information Engineering 3 Graduate
DNA, RNA, replication, translation, and transcription Overview Recall the central dogma of biology: DNA (genetic information in genes) RNA (copies of genes) proteins (functional molecules) DNA structure
Translation Translation: Assembly of polypeptides on a ribosome Living cells devote more energy to the synthesis of proteins than to any other aspect of metabolism. About a third of the dry mass of a cell
Genetics Module B, Anchor 3 Key Concepts: - An individual s characteristics are determines by factors that are passed from one parental generation to the next. - During gamete formation, the alleles for
Chapter 25 DNA Metabolism Multiple Choice Questions 1. DNA replication Page: 977 Difficulty: 2 Ans: C The Meselson-Stahl experiment established that: A) DNA polymerase has a crucial role in DNA synthesis.
Regulation of Protein Synthesis (6.1) Lecture 6 Regulation of Protein Synthesis at the Translational Level Comparison of EF-Tu-GDP and EF-Tu-GTP conformations EF-Tu-GDP EF-Tu-GTP Next: Comparison of GDP
(6) 1. Compare and contrast operon vs gene fusions: (a) Draw a simple diagram showing each type of fusion with transcription and translation start and stop sites the mrna transcript expected the expected
HEREDITY = passing on of characteristics from parents to offspring How?...DNA! I. DNA, Chromosomes, Chromatin, and Genes DNA = blueprint of life (has the instructions for making an organism) Chromatin=
OpenStax-CNX module: m44488 1 DNA Replication in Prokaryotes OpenStax College This work is produced by OpenStax-CNX and licensed under the Creative Commons Attribution License 3.0 By the end of this section,
Basic Characteristics of Cells Cell Structure and Function Chapter 3 Smallest living subdivision of the human body Diverse in structure and function Small Basic Characteristics of Cells Each Cell Has Three
Name Period This is going to be a very long journey, but it is crucial to your understanding of biology. Work on this chapter a single concept at a time, and expect to spend at least 6 hours to truly master
Lecture 36: Basics of DNA Cloning-II Note: Before starting this lecture students should have completed Lecture 35 Sequential steps involved in DNA cloning using plasmid DNA as vector: Molecular cloning
DNA, RNA, Protein synthesis, and Mutations Chapters 12-13.3 1A)Identify the components of DNA and explain its role in heredity. DNA s Role in heredity: Contains the genetic information of a cell that can
Ch 4: Energy and Cellular Metabolism Energy as it relates to Biology Chemical reactions Enzymes and how they speed rxs Metabolism and metabolic pathways Catabolism (ATP production) Anabolism (Synthesis
AP Biology Review Packet 4: Viruses, Bacteria and Expression & DNA Technology 3A1- DNA, and in some cases RNA, is the primary source of heritable information. 3B1- Gene Regulation results in differential
ISTEP+: Biology I End-of-Course Assessment Released Items and Scoring Notes Page 1 of 22 Introduction Indiana students enrolled in Biology I participated in the ISTEP+: Biology I Graduation Examination
1. A recombinant DNA molecules is one that is a. produced through the process of crossing over that occurs in meiosis b. constructed from DNA from different sources c. constructed from novel combinations
BCOR101 Midterm II Wednesday, October 26, 2005 Name Key Please show all of your work. 1. A donor strain is trp+, pro+, met+ and a recipient strain is trp-, pro-, met-. The donor strain is infected with
Protein Structure Polypeptide: Protein: Therefore: Example: Single chain of amino acids 1 or more polypeptide chains All polypeptides are proteins Some proteins contain >1 polypeptide Hemoglobin (O 2 binding
Section 1 Workbook (unit 2) ANSWERS Complete the following table: nucleotide DNA RN Name: B5. Describe DNA replication 1) Label each base given in the diagram below and describe the 4 primary characteristics
The Flow of Genetic Information The information content of DNA is in the form of specific sequences of nucleotides The DNA inherited by an organism leads to specific traits by dictating the synthesis of
2006 7.012 Problem Set 3 KEY Due before 5 PM on FRIDAY, October 13, 2006. Turn answers in to the box outside of 68-120. PLEASE WRITE YOUR ANSWERS ON THIS PRINTOUT. 1. Which reaction is catalyzed by each
Chapter 4 Cellular Metabolism Metabolic processes all chemical reactions that occur in the body Two types of metabolic reactions Anabolism larger molecules are made requires energy Catabolism larger molecules
Name lass Date RN and Protein Synthesis Information and Heredity Q: How does information fl ow from DN to RN to direct the synthesis of proteins? 13.1 What is RN? WHT I KNOW SMPLE NSWER: RN is a nucleic
the nature and importance of biomacromolecules in the chemistry of the cell: synthesis of biomacromolecules through the condensation reaction lipids and their sub-units; the role of lipids in the plasma
1. True or False? A typical chromosome can contain several hundred to several thousand genes, arranged in linear order along the DNA molecule present in the chromosome. True 2. True or False? The sequence
Unit 2 Metabolism and Survival Summary 1 Metabolism pathways and their control (a) Introduction to metabolic pathways This involves integrated and controlled pathways of enzymecatalysed reactions within
Lab Next Week Announcements Help Session: Monday 6pm LSS 277 Office Hours Chapter 15 and Translation Proteins: Function Proteins: Function Enzymes Transport Structural Components Regulation Communication
13.2 Ribosomes & Protein Synthesis Introduction: *A specific sequence of bases in DNA carries the directions for forming a polypeptide, a chain of amino acids (there are 20 different types of amino acid).
Alison Stewart 11/12/06 Prokaryotic Cells, Eukaryotic cells and HIV: Structures, Transcription and Transport Section Handout Discussion Week #7 Compare and contrast the organization of eukaryotic, prokaryotic
Chapter 11: Molecular Structure of DNA and RNA Student Learning Objectives Upon completion of this chapter you should be able to: 1. Understand the major experiments that led to the discovery of DNA as
CHAPTER 2 STRUCTURES OF NUCLEIC ACIDS What is the chemical structure of a deoxyribonucleic acid (DNA) molecule? DNA is a polymer of deoxyribonucleotides. All nucleic acids consist of nucleotides as building
Nucleus Control center of the cell contains the genetic library encoded in the sequences of nucleotides in molecules of DNA code for the amino acid sequences of all proteins determines which specific proteins
Protein Synthesis Protein synthesis is simply the "making of proteins." Although the term itself is easy to understand, the multiple steps that a cell in a plant or animal must go through are not. In order
Common Course Topics Biology 1406: Cell and Molecular Biology 1. Introduction to biology --the scientific study of organisms --properties of life --assumptions, methods and limitations of science --underlying
Questions- Proteins & Enzymes A. A peptide with 12 amino acids has the following amino acid composition: 2 Met, 1 Tyr, 1 Trp, 2 Glu, 1 Lys, 1 Arg, 1 Thr, 1 Asn, 1 Ile, 1 Cys Reaction of the intact peptide
From Gene to Protein Transcription and Translation i How do the genes in our DNA influence our characteristics? For example, how can a gene determine whether a person is an albino with very pale skin and
Provincial Exam Questions Unit: Cell Biology: Protein Synthesis (B7 & B8) 2010 Jan 3. Describe the process of translation. (4 marks) 2009 Sample 8. What is the role of ribosomes in protein synthesis? A.
LECTURE PRESENTATIONS For CAMPBELL BIOLOGY, NINTH EDITION Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson Chapter 18 Regulation of Gene Expression
Induction of Enzyme Activity in Bacteria:The Lac Operon Preparation for Laboratory: Web Tutorial - Lac Operon - submit questions I. Background: For the last week you explored the functioning of the enzyme
Educational Goals Chapter 14 Lecture Notes: Nucleic Acids 1. Know the three chemical components of a nucleotide: a monosaccharide residue (either ribose or deoxyribose), at least one phosphate group, and
BCOR 011, Exam 3 Name KEY Section Multiple Choice: Select the best possible answer. 1. A parent cell divides to form two genetically identical daughter cells in the nuclear process of mitosis. For mitosis
Dynamics of Biological Systems Part I - Biological background and mathematical modelling Paolo Milazzo (Università di Pisa) Dynamics of biological systems 1 / 53 Introduction The recent developments in
Cellular Respiration Worksheet 1 1. What are the 3 phases of the cellular respiration process? Glycolysis, Krebs Cycle, Electron Transport Chain. 2. Where in the cell does the glycolysis part of cellular
OBJECTIVES: 1. Compare and contrast the major divisions of metabolism, in terms of a general descriptive sentence, additional descriptive terms, how energy is involved, whether bonds or formed or broken,
Lecture 26: Overview of deoxyribonucleic acid (DNA) and ribonucleic acid (RNA) structure Nucleic acids play an important role in the storage and expression of genetic information. They are divided into
Conceptual Questions C1. Answer: It is a double-stranded structure that follows the AT/GC rule. C2. Answer: Bidirectional replication refers to DNA replication in both directions starting from one origin.
13.4 Gene Regulation and Expression Lesson Objectives Describe gene regulation in prokaryotes. Explain how most eukaryotic genes are regulated. Relate gene regulation to development in multicellular organisms.
Cell Structure and Organization 1. All living things must possess certain characteristics. They are all composed of one or more cells. They can grow, reproduce, and pass their genes on to their offspring.
1 DNA Coloring - Transcription & Translation Transcription RNA, Ribonucleic Acid is very similar to DNA. RNA normally exists as a single strand (and not the double stranded double helix of DNA). It contains