  Suppose that a random n-bit number V is multiplied by an odd constant M,
greater than or equal to 3, by adding shifted versions of the number V
corresponding to the 1s in the binary representation of the constant M. Suppose
further that the additions are performed by carry-save adders until the number
of summands is reduced to two, at which time the final addition is performed by
a carry-propagate adder. We show that in this situation the distribution of the
length of the longest carry-propagation chain in the final addition is the same
(up to terms tending to 0 as n tends to infinity) as when two independent n-bit
numbers are added, and in particular the mean and variance are the same (again
up to terms tending to 0). This result applies to all possible orders of
performing the carry-save additions.
