  Let ${\mathcal A}$ be a nonempty real central arrangement of hyperplanes and
${\rm \bf Ch}$ be the set of chambers of ${\mathcal A}$. Each hyperplane $H$
defines a half-space $H^{+} $ and the other half-space $H^{-}$. Let $B = \{+,
-\}$. For $H\in {\mathcal A}$, define a map $\epsilon_{H}^{+} : {\rm \bf Ch}
\to B$ by $\epsilon_{H}^{+} (C)=+ \text{(if} C\subseteq H^{+}) \text{and}
\epsilon_{H}^{+} (C)= - \text{(if} C\subseteq H^{-}).$ Define
$\epsilon_{H}^{-}=-\epsilon_{H}^{+}.$ Let ${\rm \bf Ch}^{m} = {\rm \bf
Ch}\times{\rm \bf Ch}\times...\times{\rm \bf Ch} (m\text{times}).$ Then the
maps $\epsilon_{H}^{\pm}$ induce the maps $\epsilon_{H}^{\pm} : {\rm \bf
Ch}^{m} \to B^{m} $. We will study the admissible maps $\Phi : {\rm \bf Ch}^{m}
\to {\rm \bf Ch}$ which are compatible with every $\epsilon_{H}^{\pm}$. Suppose
$|{\mathcal A}|\geq 3$ and $m\geq 2$. Then we will show that ${\mathcal A}$ is
indecomposable if and only if every admissible map is a projection to a
omponent. When ${\mathcal A}$ is a braid arrangement, which is indecomposable,
this result is equivalent to Arrow's impossibility theorem in economics. We
also determine the set of admissible maps explicitly for every nonempty real
central arrangement.
