  In the context of abstract elementary classes (AECs) with a monster model,
several possible definitions of superstability have appeared in the literature.
Among them are no long splitting chains, uniqueness of limit models, and
solvability. Under the assumption that the class is tame and stable, we show
that (asymptotically) no long splitting chains implies solvability and
uniqueness of limit models implies no long splitting chains. Using known
implications, we can then conclude that all the previously-mentioned
definitions (and more) are equivalent:
  $\mathbf{Corollary}$
  Let $K$ be a tame AEC with a monster model. Assume that $K$ is stable in a
proper class of cardinals. The following are equivalent:
  1) For all high-enough $\lambda$, $K$ has no long splitting chains.
  2) For all high-enough $\lambda$, there exists a good $\lambda$-frame on a
skeleton of $K_\lambda$.
  3) For all high-enough $\lambda$, $K$ has a unique limit model of cardinality
$\lambda$.
  4) For all high-enough $\lambda$, $K$ has a superlimit model of cardinality
$\lambda$.
  5) For all high-enough $\lambda$, the union of any increasing chain of
$\lambda$-saturated models is $\lambda$-saturated.
  6) There exists $\mu$ such that for all high-enough $\lambda$, $K$ is
$(\lambda, \mu)$-solvable.
  This gives evidence that there is a clear notion of superstability in the
framework of tame AECs with a monster model.
