  It is shown that equal magnitudes of the transitions $\bar \nu_e \to \bar
\nu_{\mu}$ and $\bar \nu_e \to \bar \nu_{\tau}$ in the disappearance of reactor
$\bar \nu_e$ discovered in the KamLAND experiment just follows at
$\theta_{23}=\pi/4$ and $\theta_{13}=0$ from pure symmetry of $\nu_{\mu}$ and
$\nu_{\tau}$ states relatively the mass states.
