  This work explores Navier-Stokes equation with no gravitational forces. In
short, it shows that any smooth solution that decays quickly must take the form
  $$ \textbf{u}(x,t)- \dfrac{1}{4\pi}\textbf{Curl}\Biggl(
\int_{\mathbb{R}^3}^{}{\dfrac{\textbf{Curl} (\textbf{u}
(x^\prime,t))}{|x-x^\prime|}}dV^\prime\Biggr) = -\int_{0}^{t}{\dfrac{1}{\rho}
\textbf{Grad}\big(\Gamma(x,s)\big)}ds.$$ Consequently, any curl free solution
must be written as $$\textbf{u}(x,t) = -\dfrac{1}{\rho}
\textbf{Grad}\biggl(\int_{0}^{t}{\Gamma(x,s) ds}\biggr)$$ with $\Gamma$ a known
function which is related to the heat equation. Even further it shows if there
exist a value $k\in \mathbb{N}$ such that
$$\textbf{curl}^k\biggl((\textbf{u}\cdot \nabla
)\textbf{u}\biggr)(x,t)=\textbf{0}$$ for all $t^\prime\le t$ then
$$\textbf{u}(x,t) = \textbf{H}^{k+1}(\xi_1,\xi_2,\xi_3,t)
-\int_{0}^{t}{\dfrac{1}{\rho} \textbf{Grad}\big(\Gamma(x,s)\big)}ds, ~~~~~ t\in
[t^\prime,\infty)$$ with $$\xi_i(x,t):=
\int_{\mathbb{R}^3}^{}{\alpha(x-y,\dfrac{t}{\nu})v^k_i(x,0)}dy, ~~~~~
v^k_i(x,0) = \biggl(\textbf{curl}^k(\textbf{u}(x,0))\biggr)_i, ~~~~~ 1\le i\le
3$$ and $\textbf{H}^k$ the $k^{th}$ application of Helmholtz operator. Hence,
if there is another solution where the non-linear term is infinitly curlable
then the solution is not unique. If the solution is unique, then this is the
only possible solution.
