  Let $\mu,\nu$ be Radon measures on $\mathbb{R}$, with $\mu$ non-atomic and
$\nu$ doubling, and write $\mu = \mu_{a} + \mu_{s}$ for the Lebesgue
decomposition of $\mu$ relative to $\nu$. For an interval $I \subset
\mathbb{R}$, define $\alpha_{\mu,\nu}(I) := \mathbb{W}_{1}(\mu_{I},\nu_{I})$,
the Wasserstein distance of normalised blow-ups of $\mu$ and $\nu$ restricted
to $I$. Let $\mathcal{S}_{\nu}$ be the square function
$$\mathcal{S}^{2}_{\nu}(\mu) = \sum_{I \in \mathcal{D}}
\alpha_{\mu,\nu}^{2}(I)\chi_{I},$$ where $\mathcal{D}$ is the family of dyadic
intervals of side-length at most one. I prove that $\mathcal{S}_{\nu}(\mu)$ is
finite $\mu_{a}$ almost everywhere, and infinite $\mu_{s}$ almost everywhere. I
also prove a version of the result for a non-dyadic variant of the square
function $\mathcal{S}_{\nu}(\mu)$. The results answer the simplest "$n = d =
1"$ case of a problem of J. Azzam, G. David and T. Toro.
