  Let $G$ be a finite 2-generated soluble group and suppose that $\langle
a_1,b_1\rangle=\langle a_2,b_2\rangle=G$. If either $G^\prime$ is of odd order
or $G^\prime$ is nilpotent, then there exists $b \in G$ with $\langle
a_1,b\rangle=\langle a_2,b\rangle=G.$ We construct a soluble 2-generated group
$G$ of order $2^{10}\cdot 3^2$ for which the previous result does not hold.
However a weaker result is true for every finite soluble group: if $\langle
a_1,b_1\rangle=\langle a_2,b_2\rangle=G$, then there exist $c_1, c_2$ such that
$\langle a_1, c_1\rangle = \langle c_1, c_2\rangle =\langle c_2, a_2\rangle=G.$
