  In this work we firstly answer to a question raised by Khoshnevisan in
\cite[Open Problem 4]{khoshnevisan2007slices} by proving that almost surely
there is no projection of big enough rank changing the Hausdorff dimension of
the zeros of the Brownian sheet. Secondly, we prove that almost surely for
every projection whose rank isn't matching the aforementioned condition, the
projection of the zero set is the entirety of the projective space. Key words:
Brownian sheet, zeros set, Hausdorff dimension, orthogonal projection.
