  Given a uniformly quasiregular mapping, there is typically no reason to
assume any relationship between linearizers at different repelling periodic
points. However, in the current paper we prove that in the case where the uqr
map arises as a solution of a Schr\"oder equation then, with some further
natural assumptions, if $L$ is a linearizer at one repelling periodic point,
then $L\circ T$ is a linearizer at another repelling periodic point, where $T$
is a translation. In this sense we say $L$ simultaneously linearizes $f$. In
the plane, an example would be that $e^z$ simultaneously linearizes $z^2$. Our
methods utilize generalized derivatives for quasiregular mappings, including a
chain rule and inverse derivative formula, which may be of independent
interest.
