  We define the (Hadamard) product $s\odot t := (s_\alpha\cdot
t_\alpha)_{\alpha\in\mathbb{N}_0^n}$ of two sequences $s =
(s_\alpha)_{\alpha\in\mathbb{N}_0^n}$ and $t =
(t_\alpha)_{\alpha\in\mathbb{N}_0^n}$. If $s$ is represented by a measure $\mu$
and $t$ by a measure $\nu$, i.e., both are moment sequences, then we give an
explicit measure $\mu\odot\nu$ that represents $s\odot t$, i.e., $s\odot t$ is
a moment sequence. We pick a result from Moment-sequence transforms (J. Eur.
Math. Soc. 24 (2022), 3109--3160) and show how the multiplication $s\odot t$ of
moment sequences simplifies the proof and also gives deeper insight by
providing the representing measure $\mu\odot\nu$.
