  Let $f:S^q\sqcup S^q\to S^m$ be a link (i.e. an embedding).
  How does (the isotopy class of) the knot $S^q\to S^m$ obtained by embedded
connected sum of the components of $f$ depend on $f$?
  Define a link $\sigma f:S^q\sqcup S^q\to S^m$ as follows. The first component
of $\sigma f$ is the `standardly shifted' first component of $f$. The second
component of $\sigma f$ is the embedded connected sum of the components of $f$.
How does (the isotopy class of) $\sigma f$ depend on $f$?
  How does (the isotopy class of) the link $S^q\sqcup S^q\to S^m$ obtained by
embedded connected sum of the last two components of a link $g:S^q_1\sqcup
S^q_2\sqcup S^q_3\to S^m$ depend on $g$?
  We give the answers for the `first non-trivial case' $q=4k-1$ and $m=6k$. The
first answer was used by S. Avvakumov for classification of linked 3-manifolds
in $S^6$.
