  We show that if $\gamma \in \omega \cup \{\aleph_{0}\}$ and $\mathcal{A}$ is
a counterexample to the analytic Vaught conjecture having exactly $\gamma$ many
models of Scott rank $\omega_{1}$, then there exists a club $C \subseteq
\omega_{1}$ such that $\mathcal{A}$ has exactly $\gamma$ many models of Scott
rank $\alpha$, for each $\alpha \in C$.
