  Let $p>3$ be a prime and $m,n\in\Bbb Z$ with $p\nmid mn$. Built on the work
of Morton, in the paper we prove the uniform congruence:
$$&\sum_{x=0}^{p-1}\Big(\frac{x^3+mx+n}p\Big) \equiv {-(-3m)^{\frac{p-1}4}
\sum_{k=0}^{p-1}\binom{-\frac 1{12}}k\binom{-\frac 5{12}}k
(\frac{4m^3+27n^2}{4m^3})^k\pmod p&\t{if $4\mid p-1$,}
\frac{2m}{9n}(\frac{-3m}p)(-3m)^{\frac{p+1}4} \sum_{k=0}^{p-1}\binom{-\frac
1{12}}k\binom{-\frac 5{12}}k (\frac{4m^3+27n^2}{4m^3})^k\pmod p&\text{if $4\mid
p-3$,}$$ where $(\frac ap)$ is the Legendre symbol. We also establish many
congruences for $x\pmod p$, where $x$ is given by $p=x^2+dy^2$ or
$4p=x^2+dy^2$, and pose some conjectures on supercongruences modulo $p^2$
concerning binary quadratic forms.
