  Let $\mathbb F_q^d$ be the $d$-dimensional vector space over the finite field
$\mathbb F_q$ with $q$ elements. Given $k$ sets $E_j\subset \mathbb F_q^d$ for
$j=1,2,\ldots, k$, the generalized $k$-resultant modulus set, denoted by
$\Delta_k(E_1,E_2, \ldots, E_k)$, is defined by $$ \Delta_k(E_1,E_2, \ldots,
E_k)=\left\{\|{\bf x}^1+{\bf x}^2+\cdots+{\bf x}^k\|\in \mathbb F_q:{\bf
x}^j\in E_j,\, j=1,2,\ldots, k\right\},$$ where $\|{\bf y}\|={\bf y}_1^2+
\cdots + {\bf y}_d^2$ for ${\bf y}=({\bf y}_1, \ldots, {\bf y}_d)\in \mathbb
F_q^d.$ We prove that if $\prod\limits_{j=1}^3 |E_j| \ge C
q^{3\left(\frac{d+1}{2} -\frac{1}{6d+2}\right)}$ for $d=4,6$ with a
sufficiently large constant $C>0$, then $|\Delta_3(E_1,E_2,E_3)|\ge cq$ for
some constant $0<c\le 1,$ and if $\prod\limits_{j=1}^4 |E_j| \ge C
q^{4\left(\frac{d+1}{2} -\frac{1}{6d+2}\right)}$ for even $d\ge 8,$ then
$|\Delta_4(E_1,E_2,E_3, E_4)|\ge cq.$ This generalizes the previous result in
\cite{CKP16}. We also show that if $\prod\limits_{j=1}^3 |E_j| \ge C
q^{3\left(\frac{d+1}{2} -\frac{1}{9d-18}\right)}$ for even $d\ge 8,$ then
$|\Delta_3(E_1,E_2,E_3)|\ge cq.$ This result improves the previous work in
\cite{CKP16} by removing $\varepsilon>0$ from the exponent.
