  Let K be a field with a valuation $\nu$ and let L = K(x) be a transcendental
extension of K, then any valuation $\mu$ of L which extends $\nu$ is determined
by its restriction to the polynomial ring K[x]. We know how to associate to
this valuation $\mu$ a family of valuations A = ($\mu$i)i$\in$I of K[x], called
the associated admise family, which converges in a certain sense towards the
valuation $\mu$. Although the definition of this family, as well as the notion
of convergence, essentially imply the structure of the polynomial ring, in
particular the degree of polynomials, we show in this note that the family A of
valuations of L do not depend on the chosen generator x.
