  Suppose that $K$ is a field of characteristic 0, $p$ is an odd prime, $r$ a
positive integer, $q=p^r$ a prime power. Suppose that $f(x)$ is a polynomial of
degree $n > 4$ with coefficients in $K$ and without multiple roots. Let us
consider the superelliptic curve $C: y^q=f(x)$ and its jacobian $J(C)$.
Assuming that $K$ is a subfield of the field of complex numbers, we study the
(connected reductive algebraic) Hodge group $Hdg$ of the corresponding complex
abelian variety $J(C)$. In our previous paper (arXiv:0907.1563 [math.AG]) we
studied the center of $Hdg.
  In this paper we study the semisimple part (commutator subgroup) of $Hdg$.
Assuming that $p$ does not divide $n$ and $n-1$ is not divisible by $q$, the
Galois group of $f(x)$ over $K$ is either the full symmetric group $S_n$ or the
alternating group $A_n$, we prove that the semisimple part of $Hdg$ is "as
large as possible".
