  The difference between observed cross sections of the evaporation residues
(ER) of the $^{34}$S+$^{208}$Pb and $^{36}$S+$^{206}$Pb reactions formed in the
2n and 3n channels has been explained by two reasons related with the entrance
channel characteristics of these reactions. The first reason is that the
capture cross section of the latter reaction is larger than the one of the
$^{34}$S+$^{208}$Pb reaction since the nucleus-nucleus potential is more
attractive in the $^{36}$S+$^{206}$Pb reaction due to two more neutrons in
isotope $^{36}$S. The second reason is the difference in the heights of the
intrinsic fusion barrier $B^*_{\rm fus}$ appearing on the fusion trajectory by
nucleon transfer between nuclei of the DNS formed after the capture. The value
of $B^*_{\rm fus}$ calculated for the $^{34}$S+$^{208}$Pb reaction is higher
than the one obtained for the $^{36}$S+$^{206}$Pb reaction. This fact has been
caused by the difference between the $N/Z$-ratios in the light fragments of the
DNS formed during the capture in these reactions. The $N/Z$-ratio has been
found by solution of the transport master equations for the proton and neutron
distributions between fragments of the DNS formed at capture with the different
initial neutron numbers $N=18$ and $N=20$ for the reactions with the $^{34}$S
and $^{36}$S, respectively.
