  In this paper we present a new proof of the following 2010 result of
Dubickas, Novikas, and Siurys:
  Let $(a,b)\in \mathbb{Z}^2$ and let $(x_n)_{n\ge 0}$ be the sequence defined
by some initial values $x_0$ and $x_1$ and the second order linear recurrence
\begin{equation*} x_{n+1}=ax_n+bx_{n-1} \end{equation*} for $n\ge 1$. Suppose
that $b\neq 0$ and $(a,b)\neq (2,-1), (-2, -1)$. Then there exist two
relatively prime positive integers $x_0$, $x_1$ such that $|x_n|$ is a
composite integer for all $n\in \mathbb{N}$.
  The above theorem extends a result of Graham who solved the problem when
$(a,b)=(1,1)$.
