  We completely solve the Diophantine equation $x^2+2^k11^\ell19^m=y^n$ in
integers $x,y\geq 1;~ k,\ell, m\geq 0~$ and $n\geq 3$ with $\gcd(x,y)=1$,
except the case $2\mid k, 2\nmid \ell m$ and $5\mid n$. We use this result to
recover some earlier results in the same direction.
