  We consider the following two closed sets in $C^n$. One is the diagonal D
given by $ (z, z, z,...z_)$. The other is $A = \{(z_1,z_2,z_3,...z_n):.$
$.e^{z_1} + e^{z_2} +e^{z_3} +...+ e^{z_n}=0\}$. Clearly $D \cap A$ is empty.
One can ask what is the distance between them.
  In this connection, Stolarsky [1] proved that the distance $d$ is given by
$d^2 = (\log \ n)^2 + O (1)$. Some simple calculations will make one believe
that the point $(k, 0, 0,..0)$ with $k = \log \ (n-1) + \pi i$ which lies on
$A$ is one of the closest point to the diagaonal. We prove that this is indeed
the case, atleast for sufficiently large $n$. This gives $d^2 = |k|^2 (1-1/n)$.
