  We argue on the basis of symmetry selection rules and Raman scattering
spectra that NaV$_2$O$_5$ undergoes a charge ordering phase transition at
T$_c$=34 K. Such a transition is characterized by the redistribution of the
charges at the phase transition and corresponds to the change of the vanadium
ions, from uniform V$^{4.5+}$ to two different V$^{4+}$ and V$^{5+}$ states. In
the low temperature phase the V$^{4+}$ ions are forming a "zig-zag" ladder
structure along the {\bf b}-axis, consistent with the symmetry of the P2/b
space group.
