  For a given blocklength we determine the number of interleavers which have
spread equal to two. Using this, we find out the probability that a randomly
chosen interleaver has spread two. We show that as blocklength increases, this
probability increases but very quickly converges to the value $1-e^{-2} \approx
0.8647$. Subsequently, we determine a lower bound on the probability of an
interleaver having spread at least $s$. We show that this lower bound converges
to the value $e^{-2(s-2)^{2}}$, as the blocklength increases.
