  For each generic $(3\mbox{-}j)$ the column parities, $2(j \pm m)$, define $3$
intrinsic parities: $\alpha, \beta,\gamma$. In algebra $so(3)$ only
$(3\mbox{-}j)\_{\alpha}$ exists whereas super-algebra $osp(1|2)$ admits $3$
kinds of super-symbols $(3\mbox{-}j)^{S}\_{\alpha}, (3\mbox{-}j)^{S}\_{\beta},
(3\mbox{-}j)^{S}\_{\gamma}$. Instead of 4 for $\{6\mbox{-}j\}$ symbols, Regge
symmetry this time produces 5 partitions ${\tt S}\_{\boldsymbol{\wr}}(0), {\tt
S}\_{\boldsymbol{\wr}}(1), {\tt S}\_{\boldsymbol{\wr}}(2), {\tt
S}\_{\boldsymbol{\wr}}(4), {\tt S}\_{\boldsymbol{\wr}}(5)$, with ${\tt
S}\_{\boldsymbol{\wr}}(3) = \emptyset$. Valid for $(3\mbox{-}j)\_{\alpha},
(3\mbox{-}j)^{S}\_{\alpha,\gamma}$ they reduce to 2 for
$(3\mbox{-}j)^{S}\_{\beta}$ with ${\tt S}\_{\boldsymbol{\wr}}(0), {\tt
S}\_{\boldsymbol{\wr}}(1)$. Unexpectedly a symbol $(3\mbox{-}j)^{S}\_{\beta}$
and its 'Regge-transformed' may be opposite in sign. In terms of integer parts
and super-triangle $\triangle^{S}$ a formula similar to that of a
$(3\mbox{-}j)$ is obtained for the $(3\mbox{-}j)^{S}$. Some forbidden
$(3\mbox{-}j)^{S}\_{\beta}$ require an analytic prolongation, consistent with
Regge $\beta$-partitions.
