  We give simple proofs that for a continuous local martingale M_t:
  1) \liminf_{\epsilon->0} \epsilon \log Ee^{(1-\epsilon) <M>_\infty /2} <
\infty
  ==> E\exp(M_\infty - <M>_\infty /2) = 1, 2) \liminf_{\epsilon->0} \epsilon
\log\sup_{t>=0} Ee^{(1-\epsilon)M_t/2} < \infty
  ==> E\exp(M_\infty - <M>_\infty /2) = 1 .
