  It is shown that if $\alpha ,\zeta $ are ordinals such that $1\leq \zeta
<\alpha <\zeta \omega ,$ then there is an operator from $C(\omega ^{\omega
^\alpha })$ onto itself such that if $Y$ is a subspace of $C(\omega ^{\omega
^\alpha })$ which is isomorphic to $C(\omega ^{\omega ^\alpha })$ $,$ then the
operator is not an isomorphism on $Y.$ This contrasts with a result of J.
Bourgain that implies that there are uncountably many ordinals $\alpha $ for
which any operator from $C(\omega ^{\omega ^\alpha })$ onto itself there is a
subspace of $C(\omega ^{\omega ^\alpha })$ which is isomorphic to $% C(\omega
^{\omega ^\alpha })$ on which the operator is an isomorphism.
