  We give lower bounds for the problem of stable sparse recovery from
/adaptive/ linear measurements. In this problem, one would like to estimate a
vector $x \in \R^n$ from $m$ linear measurements $A_1x,..., A_mx$. One may
choose each vector $A_i$ based on $A_1x,..., A_{i-1}x$, and must output $x*$
satisfying |x* - x|_p \leq (1 + \epsilon) \min_{k\text{-sparse} x'} |x - x'|_p
with probability at least $1-\delta>2/3$, for some $p \in \{1,2\}$. For $p=2$,
it was recently shown that this is possible with $m = O(\frac{1}{\epsilon}k
\log \log (n/k))$, while nonadaptively it requires $\Theta(\frac{1}{\epsilon}k
\log (n/k))$. It is also known that even adaptively, it takes $m =
\Omega(k/\epsilon)$ for $p = 2$. For $p = 1$, there is a non-adaptive upper
bound of $\tilde{O}(\frac{1}{\sqrt{\epsilon}} k\log n)$. We show:
  * For $p=2$, $m = \Omega(\log \log n)$. This is tight for $k = O(1)$ and
constant $\epsilon$, and shows that the $\log \log n$ dependence is correct.
  * If the measurement vectors are chosen in $R$ "rounds", then $m = \Omega(R
\log^{1/R} n)$. For constant $\epsilon$, this matches the previously known
upper bound up to an O(1) factor in $R$.
  * For $p=1$, $m = \Omega(k/(\sqrt{\epsilon} \cdot \log k/\epsilon))$. This
shows that adaptivity cannot improve more than logarithmic factors, providing
the analog of the $m = \Omega(k/\epsilon)$ bound for $p = 2$.
