  The vector potential operator, $\hat{\boldsymbol A}$, is transformed and
rewritten in terms of cosine and sine functions in order to get a clear picture
of how the photon states relate to the $\boldsymbol A$ field. The phase
operator, defined by $\hat E = \exp(-i \hat \phi)$, is derived from this
picture. The result has a close resemblance with the known Susskind-Glogower
(SG) operator, which is given by $\hat E_{SG}=(\hat a_{\boldsymbol k} \hat
a_{\boldsymbol k}^\dagger)^{-1/2} \hat a_{\boldsymbol k}$. It will be shown
that $\hat a_{\boldsymbol k}$ should be replaced by $(\hat a_{\boldsymbol k} +
\hat a_{-\boldsymbol k}^\dagger)$ instead to yield $\hat E = ((\hat
a_{\boldsymbol k} + \hat a_{-\boldsymbol k}^\dagger ) (\hat a_{\boldsymbol
k}^\dagger + \hat a_{-\boldsymbol k}))^{-1/2} (\hat a_{\boldsymbol k} + \hat
a_{-\boldsymbol k}^\dagger)$, which makes the operator unitary. $\hat E$ will
also be analyzed when restricted to the space of only forward moving photons
with wave vector $\boldsymbol k$. The resulting phase operator, $\hat E_+$,
will turn out to resemble the SG operator as well, but with a small correction:
Whereas $E_{SG}$ can be equivalently written as $\hat E_{SG} =
\sum_{n=0}^{\infty} |n\rangle \langle n+1 |$, the operator, $\hat E_+$, is
instead given by $\hat E_+ = \sum_{n=0}^{\infty} a_n |n \rangle \langle n+1|$,
where $a_n = (n+1/2)!/(n! \sqrt{n+1})$. The sequence, $(a_n)_{n \in \lbrace 0,
1, 2, \ldots \rbrace}$, converges to $1$ from below for $n$ going to infinity.
