  Every word in a free group $F$ induces a probability measure on every finite
group in a natural manner. It is an open problem whether two words that induce
the same measure on every finite group, necessarily belong to the same orbit of
$\mathrm{Aut}F$. A special case of this problem, when one of the words is the
primitive word $x$, was settled positively by the third author and
Parzanchevski [arXiv:1202.3269]. Here we extend this result to the case where
one of the words is $x^d$ or $\left[x,y\right]^{d}$ for an arbitrary
$d\in\mathbb{Z}$.
