  Suppose that $\{a_j\}\in \ell^1$, and suppose that for any sequence $(t_n)$
of integers there exits a constant $C_1>0$ such that
$$\sharp\left\{k\in\mathbb{Z}:\sup_{n\geq 1}\left|\sum_{i\in \mathcal{B}_n-t_n}
\!\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}\;
\frac{a_{k+i}}{i}\right|>\lambda\right\}\\ \leq
C_1\sharp\left\{k\in\mathbb{Z}:\sup_{n\geq 1}\left|\sum_{i\in \mathcal{B}_n}
\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}\;
\frac{a_{k+i}}{i}\right|>\lambda\right\},$$ for all $\lambda >0$, where
$\mathcal{B}_n=\{-n, -(n-1), -(n-2),\dots , n-2, n-1, n\}$. Then there is a
constant $C_2>0$ which does not depend on the sequence $\{a_j\}$ such that
$$\sum_{n=1}^\infty\sharp\left\{k\in\mathbb{Z}:\left|\sum_{i=-n}^{n}
\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}\;
\frac{a_{k+i}}{i}\right|>\lambda\right\}\leq\frac{C_2}{\lambda}\sum_{i=-\infty}^{\infty}|a_i|$$
for all $\lambda>0$.
  Let $(X,\mathscr{B},\mu )$ be a measure space, $\tau :X\to X$ an invertible
measure-preserving transformation, and suppose that $f\in L^1(X)$ such that for
any sequence $(t_n)$ of integers there exists a constant $C_1>0$ such that
$$\mu\left\{ x: \sup_{n\geq 1}\left|\sum_{i\in
\mathcal{B}_n-t_n}\!\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}\;
\frac{f(\tau^ix)}{i}\right| >\lambda \right\}\leq C_1\mu\left\{x: \sup_{n\geq
1}\left|\sum_{i\in \mathcal{B}_n}\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}\;
\frac{f(\tau^i x)}{i}\right|>\lambda \right\} $$ for all $\lambda >0$, where
$\mathcal{B}_n=\{-n, -(n-1), -(n-2),\dots , n-2, n-1, n\}$. Then there exists a
constant $C_2>0$ which does not depend on $f$ such that
$$\sum_{n=1}^\infty\mu\left\{x:\left|\sum_{i=-n}^{n}\!\!\raise{1.9ex}\hbox{$\scriptsize\prime$}
\;\frac{f(\tau^ix)}{i}\right|>\lambda\right\}\leq\frac{C_2}{\lambda}\|f\|_1$$
for all $\lambda >0$.
