  A subset of an abelian group is {\em sequenceable} if there is an ordering
$(x_1, \ldots, x_k)$ of its elements such that the partial sums $(y_0, y_1,
\ldots, y_k)$, given by $y_0 = 0$ and $y_i = \sum_{j=1}^i x_i$ for $1 \leq i
\leq k$, are distinct, with the possible exception that we may have $y_k = y_0
= 0$. We demonstrate the sequenceability of subsets of size $k$ of
$\mathbb{Z}_n \setminus \{ 0 \}$ when $n = mt$ in many cases, including when
$m$ is either prime or has all prime factors larger than $k! /2$ for $k \leq
11$ and $t \leq 5$ and for $k=12$ and $t \leq 4$. We obtain similar, but
partial, results for $13 \leq k \leq 15$. This represents progress on a variety
of questions and conjectures in the literature concerning the sequenceability
of subsets of abelian groups, which we combine and summarize into the
conjecture that if a subset of an abelian group does not contain 0 then it is
sequenceable.
