  Consider triangulations of $\mathbb R P^2$ whose all vertices have valency
six except three vertices of valency $4$. In this chapter we prove that the
number $f(n)$ of such triangulations with no more than $n$ triangles grows as
$C\cdot n^2+ O(n^{3/2})$ where $C = \frac{1}{20} \sqrt{3} \cdot L(
\frac{\pi}{3} ) \zeta^{-1}(4) \zeta(Eis, 2) \approx 0.2087432125056015...$,
where $L$ is the Lobachevsky function and $\zeta(Eis,2)
=\sum\limits_{(a,b)\in\mathbb Z^2\setminus 0}{\frac{1}{|a+b\omega^2|^4}}$, and
$\omega^6=1$.
