  Every Kauffman state \sigma of a link diagram D(K) naturally defines a state
surface S_\sigma whose boundary is K. For a homogeneous state \sigma, we show
that K is a fibered link with fiber surface S_\sigma if and only if an
associated graph G'_\sigma is a tree. As a corollary, it follows that for an
adequate knot or link, the second and next-to-last coefficients of the Jones
polynomial are obstructions to certain state surfaces being fibers for K.
  This provides a dramatically simpler proof of a theorem from
[arXiv:1108.3370].
