  A $q$-\emph{equitable coloring} of a graph $G$ is a proper $q$-coloring such
that the sizes of any two color classes differ by at most one. In contrast with
ordinary coloring, a graph may have an equitable $q$-coloring but has no
equitable $(q+1)$-coloring. The \emph{equitable chromatic threshold} is the
minimum $p$ such that $G$ has an equitable $q$-coloring for every $q\geq p.$
  In this paper, we establish the notion of $p(q: n_1,\ldots, n_k)$ which can
be computed in linear-time and prove the following. Assume that
$K_{n_1,\ldots,n_k}$ has an equitable $q$-coloring. Then $p(q: n_1,\ldots,
n_k)$ is the minimum $p$ such that $K_{n_1,\ldots,n_k}$ has an equitable
$r$-coloring for each $r$ satisfying $p \leq r \leq q.$ Since
$K_{n_1,\ldots,n_k}$ has an equitable $(n_1+\cdots+n_k)$-coloring, the
equitable chromatic threshold of $K_{n_1,\ldots,n_k}$ is $p(n_1+\cdots+n_k:
n_1,\ldots, n_k).$
  We find out later that the aforementioned immediate consequence is exactly
the same as the formula of Yan and Wang \cite{YW12}. Nonetheless, the notion of
$p(q: n_1,\ldots, n_k)$ can be used for each $q$ in which $K_{n_1,\ldots,n_k}$
has an equitable $q$-coloring and the proof presented here is much shorter.
