  We derive a simple expression for the $r^{th}$ factorial moment $\mu_{(r)}$
of the geometric distribution of order $k$ with success parameter $p\in(0,1)$
(and $q=1-p$) in terms of its probability mass function $f_k(n)$. Specifically,
$\mu_{(r)} = r!f_k((r+1)k+r)/((qp^k)^{r+1})$.
