  Lee homology (a variant of Khovanov homology) over $\mathbb{Q}$ possesses the
"canonical generators" as its basis. The generators (Lee's classes) $[\alpha(D,
o)]$ are constructed combinatorially from an oriented link diagram $D$, one for
each alternative orientation $o$ on $D$. Let $R$ be an integral domain. There
exists a family of link homology theory $\{ H_c(-; R) \}_{c \in R}$, where
Khovanov's theory corresponds to $c = 0$ and Lee's theory corresponds to $c =
2$. For each $c \in R \setminus 0$, Lee's classes $[\alpha(D, o)]$ can be
defined as elements in $H_c(D; R)$, but when $c$ is not invertible then they do
not form a basis; in fact they are divisible by $c$-powers. We define the
$c$-divisibility $k_c(D)$ of $[\alpha(D, o)]$ with $o$ the given orientation of
$D$. For any link $L$ and its diagram $D$, we prove that $\bar{s}_c(L) :=
2k_c(D) + w(D) - r(D) + 1$ is a link invariant, where $w$ is the writhe, and
$r$ is the number of Seifert circles. We pose the question whether $\bar{s}_c$
coincides with Rasmussen's $s$-invariant. There are several evidences that
support the affirmative answer. For instance, $\bar{s}_c$ is a link concordance
invariant, and the Milnor conjecture can be reproved using $\bar{s}_c$. Also
for the special case $(R, c) = (\mathbb{Q}[h], h)$, our $\bar{s}_c$ actually
coincides with $s$ as knot invariants.
