  Within the framework of the Faddeev formalism in configuration space, we
investigate bound states in the $\phi NN$ system with total isospin $T=0$ and
$T=1$. The recently proposed lattice HAL QCD $\phi N$ potential in the
$^{4}S_{3/2}$ channel does not support either $\phi N$ or $\phi NN$ bound
states. The HAL QCD $\phi N$ potential in the $^{2}S_{1/2}$ channel suggests
the bound states for $\phi N$ and $\phi NN (S=0)$ systems. However, the binding
energies are highly sensitive to variations of the enhancement factor $\beta$,
and the $\phi NN$ system is extremely strongly bound in the state $S=0$.
Considering a spin-averaged potential %$(\frac{1}{3}V_{\phi
N}^{1/2}+\frac{2}{3}V_{\phi N}^{3/2})$ for the state $S=1$ yields a bound state
for $^3_\phi$H $(S=1)$ hypernucleus with the binding energy (BE) 14.9 MeV when
$\beta = 6.9$. The evaluation of the BE for the $S=1$, $T=1$ three-body state
results in 5.47 MeV. %Also, We evaluated the BE for the $S=1$, $T=1$ three-body
state as 5.47 MeV. Additionally, calculations using our approach confirm the
bound states for the $\phi NN$ ($S=2,T=0$ and $S=1, T=1$) system previously
predicted with the Yukawa-type potential motivated by the QCD van der Waals
attractive force, mediated by multi-gluon exchanges.
