Step 3: Enter your full question details hereA particle moves along
a straight line and its position at time t is given by s(t)= 2t^3 -
24 t^2 + 90 t where s is measured in feet and t in seconds.
Find the velocity (in ft/sec) of the particle at time t=0:
The particle stops moving (i.e. is in a rest) twice, once when t=A
and again when t=B where A < B. A is
and B is
What is the position of the particle at time 16?
Finally, what is the TOTAL distance the particle travels between
time 0 and time 16