Michael Fowler, Physics Dept., U.Va.
We are now ready to move on to Newton’s Laws of Motion, which for the first time presented a completely coherent analysis of motion, making clear that the motion in the heavens could be understood in the same terms as motion of ordinary objects here on earth.
The crucial Second Law, as we shall see below, links the acceleration of a body with the force acting on the body. To understand what it says, it is necessary to be completely clear what is meant by acceleration, so let us briefly review.
Speed is just how fast something’s moving, so is fully specified by a positive number and suitable units, such as 55 mph or 10 meters per second.
Velocity, on the other hand, means to a scientist more than speed---it also includes a specification of the direction of the motion, so 55 mph to the northwest is a velocity. Usually wind velocities are given in a weather forecast, since the direction of the wind affects future temperature changes in a direct way. The standard way of representing a velocity in physics is with an arrow pointing in the appropriate direction, its length representing the speed in suitable units. These arrows are called “vectors”.
(WARNING: Notice, though, that for a moving object such as a projectile, both its position at a given time (compared with where it started) and its velocity at that time can be represented by vectors, so you must be clear what your arrow represents!)
Acceleration: as we have stated, acceleration is defined as rate of change of velocity.
It is not defined as rate of change of speed. A body can have nonzero acceleration while moving at constant speed!
Let us look at how its velocity changes over a period of one second. (Actually, in the diagram below we exaggerate how far it would move in one second, the distance would in fact be one-five thousandth of the distance around the circle, impossible to draw.)
Here we show the cannonball (greatly exaggerated in size!) at two points in its orbit, and the velocity vectors at those points. On the right, we show the two velocity vectors again, but we put their ends together so that we can see the difference between them, which is the small dashed vector.
In other words, the small dashed vector is the velocity that has to be added to the first velocity to get the second velocity: it is the change in velocity on going around that bit of the orbit.
Now, if we think of the two points in the orbit as corresponding to positions of the cannonball one second apart, the small dashed vector will represent the change in velocity in one second, and that is—by definition—the acceleration. The acceleration is the rate of change of velocity, and that is how much the velocity changes in one second (for motions that change reasonably smoothly over the one-second period, which is certainly the case here. To find the rate of change of velocity of a fly’s wing at some instant, we obviously would have to measure its velocity change over some shorter interval, maybe a thousandth of a second).
So we see that, with our definition of acceleration as the rate of change of velocity, which is a vector, a body moving at a steady speed around a circle is accelerating towards the center all the time, although it never gets any closer to it. If this thought makes you uncomfortable, it is because you are still thinking that acceleration must mean a change of speed, and just changing direction doesn’t count.
It is possible to find an explicit expression for the magnitude of the acceleration towards the center (sometimes called the centripetal acceleration) for a body moving on a circular path at speed v. Look again at the diagram above showing two values of the velocity of the cannonball one second apart. As is explained above, the magnitude a of the acceleration is the length of the small dashed vector on the right, where the other two sides of this long narrow triangle have lengths equal to the speed v of the cannonball. We’ll call this the “vav” triangle, because those are the lengths of its sides. What about the angle between the two long sides? That is just the angle the velocity vector turns through in one second as the cannonball moves around its orbit. Now look over at the circle diagram on the left showing the cannonball’s path. Label the cannonball’s position at the beginning of the second A, and at the end of the second B, so the length AB is how far the cannonball travels in one second, that is, v. (It’s true that the part of the path AB is slightly curved, but we can safely ignore that very tiny effect.) Call the center of the circle C. Draw the triangle ACB. (The reader should sketch the figure and actually draw these triangles!) The two long sides AC and BC have lengths equal to the radius of the circular orbit. We could call this long thin triangle an “rvr” triangle, since those are the lengths of its sides.
The important point to realize now is that the “vav” triangle and the “rvr” triangle are similar, because since the velocity vector is always perpendicular to the radius line from the center of the circle to the point where the cannonball is in orbit, the angle the velocity vector rotates by in one second is the same as the angle the radius line turns through in one second. Therefore, the two triangles are similar, and their corresponding sides are in the same ratios, that is, a/v = v/r. It follows immediately that the magnitude of the acceleration a for an object moving at steady speed v in a circle of radius r is v2/r directed towards the center of the circle.
This result is true for all circular motions, even those where the moving body goes round a large part of the circle in one second. To establish it in a case like that, recall that the acceleration is the rate of change of velocity, and we would have to pick a smaller time interval than one second, so that the body didn’t move far around the circle in the time chosen. If, for example, we looked at two velocity vectors one-hundredth of a second apart, and they were pretty close, then the acceleration would be given by the difference vector between them multiplied by one-hundred, since acceleration is defined as what the velocity change in one second would be if it continued to change at that rate. (In the circular motion situation, the acceleration is of course changing all the time. To see why it is sometimes necessary to pick small time intervals, consider what would happen if the body goes around the circle completely in one second. Then, if you pick two times one second apart, you would conclude the velocity isn’t changing at all, so there is no acceleration.)
We’ve stated before that a ball thrown vertically upwards has constant downward acceleration of 10 meters per second in each second, even when it’s at the very top and isn’t moving at all. The key point here is that acceleration is rate of change of velocity. You can’t tell what the rate of change of something is unless you know its value at more than one time. For example, speed on a straight road is rate of change of distance from some given point. You can’t get a speeding ticket just for being at a particular point at a certain time—the cop has to prove that a short time later you were at a point well removed from the first point, say, three meters away after one-tenth of a second. That would establish that your speed was thirty meters per second, which is illegal in a 55 m.p.h. zone. In just the same way that speed is rate of change of position, acceleration is rate of change of velocity. Thus to find acceleration, you need to know velocity at two different times. The ball thrown vertically upwards does have zero velocity at the top of its path, but that is only at a single instant of time. One second later it is dropping at ten meters per second. One millionth of a second after it reached the top, it is falling at one hundred-thousandth of a meter per second. Both of these facts correspond to a downward acceleration, or rate of change of velocity, of 10 meters per second in each second. It would only have zero acceleration if it stayed at rest at the top for some finite period of time, so that you could say that its velocity remained the same—zero—for, say, a thousandth of a second, and during that period the rate of change of velocity, the acceleration, would then of course be zero. Part of the problem is that the speed is very small near the top, and also that our eyes tend to lock on to a moving object to see it better, so there is the illusion that it comes to rest and stays there, even if not for long.
Galileo’s analysis of projectile motion was based on two concepts:
1. Naturally accelerated motion, describing the vertical component of motion, in which the body picks up speed at a uniform rate.
2. Natural horizontal motion, which is motion at a steady speed in a straight line, and happens to a ball rolling across a smooth table, for example, when frictional forces from surface or air can be ignored.
Therefore the point Newton is making is that the essential difference between Galileo’s natural steady speed horizontal motion and the natural accelerated vertical motion is that vertically, there is always the force of gravity acting, and without that—for example far into space—the natural motion (that is, with no forces acting) in any direction would be at a steady speed in a straight line.
(Actually, it took
To put it in his own words (although actually he wrote it in Latin, this is from an 1803 translation):
Every body perseveres in its state of rest, or of uniform motion in a right line, unless it is compelled to change that state by forces impressed thereon.
He immediately adds, tying this in precisely with Galileo’s work:
Projectiles persevere in their motions, so far as they are not retarded by the resistance of the air, or impelled downwards by the force of gravity.
Notice that here “persevere in their motions” must mean in steady speed straight line motions, because he is adding the gravitational acceleration on to this.
This is sometimes called “The Law of Inertia”: in the absence of an external force, a body in motion will continue to move at constant speed and direction, that is, at constant velocity.
So any acceleration, or change in speed (or direction of motion), of a body signals that it is being acted on by some force.
The alteration of motion is ever proportional to the motive force impressed; and is made in the direction of the right line in which that force is impressed.
Another rather obvious point he doesn’t bother to make is that for a given force, such as, for example, the hardest you can push, applied to two different objects, say a wooden ball and a lead ball of the same size, with the lead ball weighing seven times as much as the wooden ball, then the lead ball will only pick up speed at one-seventh the rate the wooden one will.
Now let us consider the significance of this law for falling bodies. Neglecting air resistance, bodies of all masses accelerate downwards at the same rate. This was Galileo’s discovery.
Let us put this well established fact together with
Consider two falling bodies, one having twice the mass of the other. Since their acceleration is the same, the
body having twice the mass must be experiencing a gravitational force which is
twice as strong. Of course, we are well
aware of this, all it’s saying is that two bricks weigh twice as much as one
brick. Any weight measuring device, such
as a bathroom scales, is just measuring the force of gravity. However, this proportionality of mass and
weight is not a completely trivial point.
Masses can be measured against each other without using gravity at
all, for example far into space, by comparing their relative accelerations
when subject to a standard force, a push.
If one object accelerates at half the rate of another when subject to
our standard push, we conclude it has twice the mass. Thinking of the mass in this way as a measure
of resistance to having velocity changed by an outside force,
To return to the concept of mass, it is really just a measure of the amount of stuff. For a uniform material, such as water, or a uniform solid, the mass is the volume multiplied by the density—the density being defined as the mass of a unit of volume, so water, for example, has a density of one gram per cubic centimeter, or sixty-two pounds per cubic foot.
Hence, from Galileo’s discovery of the uniform acceleration of all falling bodies, we conclude that the weight of a body, which is the gravitational attraction it feels towards the earth, is directly proportional to its mass, the amount of stuff it’s made of.
All the statements above about force, mass and acceleration are statements about proportionality. We have said that for a body being accelerated by a force acting on it the acceleration is proportional to the (total) external force acting on the body, and, for a given force, inversely proportional to the mass of the body.
If we denote the force, mass and acceleration by F, m and a respectively (bearing in mind that really F and a are vectors pointing in the same direction) we could write this:
F is proportional to ma
To make any progress in applying
The unit of force is that force which causes a unit mass (one kilogram) to accelerate with unit acceleration (one meter per second per second).
This unit of force is named, appropriately, the newton.
If we now agree to measure forces in newtons, the statement of proportionality above can be written as a simple equation:
F = ma
which is the usual statement of
If a mass is now observed to accelerate, it is a trivial matter to find the total force acting on it. The force will be in the direction of the acceleration, and its magnitude will be the product of the mass and acceleration, measured in newtons. For example, a 3 kilogram falling body, accelerating downwards at 10 meters per second per second, is being acted on by a force ma equal to 30 newtons, which is, of course, its weight.
Having established that a force—the action of another body—was necessary to cause a body to change its state of motion, Newton made one further crucial observation: such forces always arise as a mutual interaction of two bodies, and the other body also feels the force, but in the opposite direction.
To every action there is always opposed an equal and opposite reaction: or the mutual actions of two bodies upon each other are always equal, and directed to contrary parts.
Whatever draws or presses another is as much drawn or pressed by that other. If you press a stone with your finger, the finger is also pressed by the stone. If a horse draws a stone tied to a rope, the horse (if I may so say) will be equally drawn back towards the stone: for the distended rope, by the same endeavour to relax or unbend itself, will draw the horse as much towards the stone, as it does the stone towards the horse, and will obstruct the progress of the one as much as it advances that of the other. If a body impinge upon another, and by its force change the motion of the other, that body also (because of the equality of the mutual pressure) will undergo an equal change, in its own motion, towards the contrary part. The changes made by these actions are equal, not in the velocities but in the motions of bodies; that is to say, if the bodies are not hindered by any other impediments. For, because the motions are equally changed, the changes of the velocities made towards contrary parts are reciprocally proportional to the bodies. This law takes place also in attractions.
All this maybe sounds kind of obvious.
Anyone who’s had a dog on a leash, especially a big dog, is well aware
that tension in a rope pulls both ways. If
you push against a wall, the wall is pushing you back. If that’s difficult to visualize, imagine
what would happen if the wall suddenly evaporated.
The Second Law states that if a body is accelerating, there must be an external force acting on it. It’s not always obvious what this external force is even in the most trivial everyday occurrences. Suppose you’re standing still, then begin to walk. What was the external force that caused you to accelerate? Think about that for a while. Here’s a clue: it’s very hard to start walking if you’re wearing smooth-bottomed shoes and standing on smooth ice. You tend to skid around in the same place. If you understand that, you also know what external force operates when a car accelerates.
The reason the external force causing the acceleration may not be
immediately evident is that it may not be what’s doing the work. Consider the following scenario: you are
standing on level ground, on rollerskates, facing a wall with your palms
pressed against it. You push against the
wall, and roll away backwards. You
accelerated. Clearly, you did the work
that caused the acceleration. But from
Now imagine two people on roller skates, standing close facing each other,
palms raised and pushing the other person away.
According to Newton’s discussion above following his Third Law, the two
bodies involved will undergo equal changes of motion, but to contrary parts,
that is, in opposite directions. That
sounds reasonable. They obviously both
move off backwards. Notice, however,
Roller skates actually provide a pretty good example of the necessity of generating an external force if you want to accelerate. If you keep the skates pointing strictly forwards, and only the wheels are in contact with the ground, it’s difficult to get going. The way you start is to turn the skates some, so that there is some sideways push on the wheels. Since the wheels can’t turn sideways, you are thus able to push against the ground, and therefore it is pushing you—you’ve managed to generate the necessary external force to accelerate you. Note that if the wheels were to be replaced by ball bearings somehow, you wouldn’t get anywhere, unless you provided some other way for the ground to push you, such as a ski pole, or maybe twisting your foot so that some fixed part of the skate contacted the ground.
We have now reached the last sentence in
Let us now put together what we know about the gravitational force:
1. The gravitational force on a body (its weight, at the Earth’s surface) is proportional to its mass.
2. If a body A attracts a body B with a gravitational force of a given strength, then B attracts A with a force of equal strength in the opposite direction.
3. The gravitational attraction between two bodies decreases with distance, being proportional to the inverse square of the distance between them. That is, if the distance is doubled, the gravitational attraction falls to a quarter of what it was.
One interesting point here—think about how the earth is gravitationally
attracting you. Actually, all the
different parts of the earth are attracting you!
Let’s denote the gravitational attractive force between two bodies A and B (as mentioned in item 2 above) by F. The forces on the two bodies are really equal and opposite vectors, each pointing to the other body, so our letter F means the length of these vectors, the strength of the force of attraction.
Now, item 1 tells us that the gravitational attraction between the earth and
a mass m is proportional to m.
This is an immediate consequence of the experimental fact that falling
bodies accelerate at the same rate, usually written g (approximately 10
meters per second per second), and the definition of force from
F is proportional to mass m
for the earth’s gravitational attraction on a body (often written weight W
= mg), and
From the symmetry of the force (item 2 above) and the proportionality to the mass (item 1), it follows that the gravitational force between two bodies must be proportional to both masses. So, if we double both masses, say, the gravitational attraction between them increases by a factor of four. We see that if the force is proportional to both masses, let’s call them M and m, it is actually proportional to the product Mm of the masses. From item 3 above, the force is also proportional to 1/r2, where r is the distance between the bodies, so for the gravitational attractive force between two bodies
F is proportional to Mm/r2
This must mean that by measuring the gravitational force on something, we should be able to figure out the mass of the Earth! But there’s a catch—all we know is that the force is proportional to the Earth’s mass. From that we could find, for instance, the ratio of the mass of the Earth to the mass of Jupiter, by comparing how fast the Moon is “falling” around the Earth to how fast Jupiter’s moons are falling around Jupiter. For that matter, we could find the ratio of the Earth’s mass to the Sun’s mass by seeing how fast the planets swing around the Sun. Still, knowing all these ratios doesn’t tell us the Earth’s mass in tons. It does tell us that if we find that out, we can then find the masses of the other planets, at least those that have moons, and the mass of the Sun.
So how do we measure the mass of the Earth? The only way is to compare the
Earth’s gravitational attraction with that of something we already know the
mass of. We don’t know the masses of any
of the heavenly bodies. What this really
means is that we have to take a known mass, such as a lead ball, and measure
how strongly it attracts a smaller lead ball, say, and compare that force with
the earth’s attraction for the smaller lead ball. This is very difficult to accomplish because
the forces are so small, but it was done successfully in 1798, just over a
In other words, Cavendish took two lead weights M and m, a few kilograms each, and actually detected the tiny gravitational attraction between them (of order of magnitude millionths of a newton)! This was a sufficiently tough experiment that even now, two hundred years later, it’s not easy to give a lecture demonstration of the effect.
Making this measurement amounts to finding the constant of proportionality in the statement about F above, so that we can sharpen it up from a statement about proportionality to an actual useable equation,
F = GMm/r2
where the constant G is what Cavendish measured, and found to be 6.67
x 10-11 in the appropriate units, where the masses are in kilograms,
the distance in meters and the force in newtons. (Notice here that we can’t get rid of the
constant of proportionality G, as we did in the equation F = ma,